1. D2. A3. D4.DSolution1. D2. A3. D4.D.pdf

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1. D 2. A 3. D 4.D Solution 1. D 2. A 3. D 4.D.

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Name used on OSIName Used in TCPIP networksLayer 1(Physical)L.pdf

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Monthly interest rate=12/12=1% Present value(PV) of monthly payment=(payment)/((1+i)^N) i=interest rate=1%=0.01 N=month of payment Monthly payments and PV of each monthly payment are given below: N A B=A/(1.01^N) Month Payment PV of payment 0 $2,400 2400 1 $2,300 2277.227723 2 $2,200 2156.651309 3 $2,100 2038.239311 4 $2,000 1921.960689 5 $1,900 1807.784806 6 $1,800 1695.681423 7 $1,700 1585.620693 8 $1,600 1477.573156 9 $1,500 1371.509736 10 $1,400 1267.401737 11 $1,300 1165.220833 TOTAL 21164.87142 Present value=$21,164.87 If the payment is starting with $1300 at time t=0, N A B/(1.01^N) Month Payment PV of payment 0 $1,300 1300 1 $1,400 1386.138614 2 $1,500 1470.444074 3 $1,600 1552.944237 4 $1,700 1633.666586 5 $1,800 1712.638238 6 $1,900 1789.885947 7 $2,000 1865.436109 8 $2,100 1939.314767 9 $2,200 2011.547613 10 $2,300 2082.159996 11 $2,400 2151.176922 TOTAL 20895.3531 Present Value=$20,895.35 N A B=A/(1.01^N) Month Payment PV of payment 0 $2,400 2400 1 $2,300 2277.227723 2 $2,200 2156.651309 3 $2,100 2038.239311 4 $2,000 1921.960689 5 $1,900 1807.784806 6 $1,800 1695.681423 7 $1,700 1585.620693 8 $1,600 1477.573156 9 $1,500 1371.509736 10 $1,400 1267.401737 11 $1,300 1165.220833 TOTAL 21164.87142 Solution Monthly interest rate=12/12=1% Present value(PV) of monthly payment=(payment)/((1+i)^N) i=interest rate=1%=0.01 N=month of payment Monthly payments and PV of each monthly payment are given below: N A B=A/(1.01^N) Month Payment PV of payment 0 $2,400 2400 1 $2,300 2277.227723 2 $2,200 2156.651309 3 $2,100 2038.239311 4 $2,000 1921.960689 5 $1,900 1807.784806 6 $1,800 1695.681423 7 $1,700 1585.620693 8 $1,600 1477.573156 9 $1,500 1371.509736 10 $1,400 1267.401737 11 $1,300 1165.220833 TOTAL 21164.87142 Present value=$21,164.87 If the payment is starting with $1300 at time t=0, N A B/(1.01^N) Month Payment PV of payment 0 $1,300 1300 1 $1,400 1386.138614 2 $1,500 1470.444074 3 $1,600 1552.944237 4 $1,700 1633.666586 5 $1,800 1712.638238 6 $1,900 1789.885947 7 $2,000 1865.436109 8 $2,100 1939.314767 9 $2,200 2011.547613 10 $2,300 2082.159996 11 $2,400 2151.176922 TOTAL 20895.3531 Present Value=$20,895.35 N A B=A/(1.01^N) Month Payment PV of payment 0 $2,400 2400 1 $2,300 2277.227723 2 $2,200 2156.651309 3 $2,100 2038.239311 4 $2,000 1921.960689 5 $1,900 1807.784806 6 $1,800 1695.681423 7 $1,700 1585.620693 8 $1,600 1477.573156 9 $1,500 1371.509736 10 $1,400 1267.401737 11 $1,300 1165.220833 TOTAL 21164.87142.

Monthly interest rate=1212=1Present value(PV) of monthly payment.pdf

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Lab1.java import java.util.Scanner;//package public class Lab1 {//main class public static void main(String[] args) {//main method // TODO Auto-generated method stub int number,i,numbersuplied;//instance variables Scanner keyboard= new Scanner(System.in); System.out.println(\"Please enter an number\"); numbersuplied= keyboard.nextInt();//key board inputting //logic for next prime for(number=numbersuplied+1;;number++) { for(i=2;i Solution Lab1.java import java.util.Scanner;//package public class Lab1 {//main class public static void main(String[] args) {//main method // TODO Auto-generated method stub int number,i,numbersuplied;//instance variables Scanner keyboard= new Scanner(System.in); System.out.println(\"Please enter an number\"); numbersuplied= keyboard.nextInt();//key board inputting //logic for next prime for(number=numbersuplied+1;;number++) { for(i=2;i.

Lab1.javaimport java.util.Scanner;package public class Lab1 .pdf

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In this module, you will learn some basics about operating in Object mode. This is normally the initial mode that Blender is in when you open a new document; it is the mode where you operate on whole objects, rather than on their parts. Many of the conventions involving selection and manipulation of objects or parts of objects apply to other modes as well, so this is a good place to start getting familiar with these conventions. Blender-2.5 mode menu.png Cube selected in Object mode. Open a new document, and confirm that you are in Object mode by checking the mode menu. Select the default cube by clicking on it with RMB . You will see it framed in an orange outline. Object Origin[edit] When you select an object, you will notice a round dot appears, normally in the middle of the object, the same orangey-yellow as the rest of the selection. This is the object’s origin, and it is the reference point for the object’s local coordinate system. Certain kinds of edits to the object can cause this origin to end up at a position well outside the object, in which case operations like transformations applied with reference to the origin may end up not behaving as you expect. But Blender has capabilities to deal with this, which will be explained when you need them. Multiple Selections[edit] You can select more than one object at a time. With the cube still selected, change your view until you can see both it and the default lamp; select the latter by clicking on it with SHIFT + RMB , so both it and the cube are selected. You will notice that the lamp takes on the orangey- yellow colour, but the cube now has a more reddish highlight. The active object is the last one selected; other objects can be part of the selection, but the reddish-orange highlight indicates that they are not active. The Properties window shows properties for the active object, not for the entire selection, while operations in the 3D view like moving and deleting objects will affect the entire selection. Some operations (like parenting, which you will learn about later) set up a special relationship between the active object and the rest of the selection, so for these the order of selection of objects becomes important. You can remove the active object from the selection with SHIFT + RMB ; the little spot indicating the origin of the object’s geometry stays highlighted in the yellow-orange colour, even though the rest of the object loses the selection highlight. If you do this to an inactive object, it will make that object active. Pressing CTRL + I inverts the selection—it deselects what was previously selected, and selects everything else instead. It does not change the active object. Selecting Obscured Objects[edit] If multiple objects lie under the mouse, you can choose which one to select by clicking ALT + RMB : this will bring up a menu listing the names of the objects, and you can choose from this menu which one to select. Alternatively, you can add an object to the current sel.

In this module, you will learn some basics about operating in Object.pdf

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When comparing the R groups of these to amino acids, isoleucine has a non polar tail, which would hinder the solubility in water of the molecule because it can\'t Hydrogen bond with water molecules. Arginine, however, has three strongly electrophilic N atoms which each will be able to Hydrogen bond with the Hydrogen atoms of several water molecules, thus increasing the solubility. Solution When comparing the R groups of these to amino acids, isoleucine has a non polar tail, which would hinder the solubility in water of the molecule because it can\'t Hydrogen bond with water molecules. Arginine, however, has three strongly electrophilic N atoms which each will be able to Hydrogen bond with the Hydrogen atoms of several water molecules, thus increasing the solubility..

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Malonic Acid Water: Soluble Methyl Alcohol: Soluble Hexane: Insoluble Malonic Acid has OH and so does methanol and water. Biphenyl Water: insoluble Methyl Alcohol: inoluble Hexane: soluble Nonpolar with no functional group. Hexane is nonpolar. Like dissolves like Solution Malonic Acid Water: Soluble Methyl Alcohol: Soluble Hexane: Insoluble Malonic Acid has OH and so does methanol and water. Biphenyl Water: insoluble Methyl Alcohol: inoluble Hexane: soluble Nonpolar with no functional group. Hexane is nonpolar. Like dissolves like.

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It is true that ionization energy is required to ionize the metal /non metal atoms. But at the same time due to gain of electrons energy is released ; [electron affinity] There is net release of energy . Solution It is true that ionization energy is required to ionize the metal /non metal atoms. But at the same time due to gain of electrons energy is released ; [electron affinity] There is net release of energy ..

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Ionic compounds form when the electronegativity difference between two elements is so great, the metal \"takes\" the non-metal\'s electron. In general, metals have a low electronegativity while non-metals have a high electronegativity, and the periodic trend shows that electronegativity decreases down and left from Fluorine. Two examples of ionic compounds are Sodium Chloride (NaCl) and Potassium Bromide (KBr). Solution Ionic compounds form when the electronegativity difference between two elements is so great, the metal \"takes\" the non-metal\'s electron. In general, metals have a low electronegativity while non-metals have a high electronegativity, and the periodic trend shows that electronegativity decreases down and left from Fluorine. Two examples of ionic compounds are Sodium Chloride (NaCl) and Potassium Bromide (KBr)..

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Chalcones can be prepared by an aldol condensation between a benzaldehyde and an acetophenone in the presence of sodium hydroxide as a catalyst. This reaction has been found to work without any solvent at all - a solid-state reaction. The reaction between substituted benzaldehydes and acetophenones has been used to demonstrate green chemistry in undergraduate chemistry education.In a study investigating green chemistry synthesis, chalcones were also synthesized from the same starting materials in high temperature water (200 to 350 Solution Chalcones can be prepared by an aldol condensation between a benzaldehyde and an acetophenone in the presence of sodium hydroxide as a catalyst. This reaction has been found to work without any solvent at all - a solid-state reaction. The reaction between substituted benzaldehydes and acetophenones has been used to demonstrate green chemistry in undergraduate chemistry education.In a study investigating green chemistry synthesis, chalcones were also synthesized from the same starting materials in high temperature water (200 to 350.

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B. tetrahedral Sulfur has two lone pairs, so it\'s analogous to water. Four things around sulfur makes its electron-pair arrangement tetrahedral (and since two are lone pairs, the molecular shape is bent). Solution B. tetrahedral Sulfur has two lone pairs, so it\'s analogous to water. Four things around sulfur makes its electron-pair arrangement tetrahedral (and since two are lone pairs, the molecular shape is bent)..

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Capsicum annum (pepper) belongs to the family Solanaceae. The fruits of this plant (pepper) acquire attractive color as they become ripen, which attract the birds. Birds eat the fruits and disperse the seeds. The unpleasant taste (burning sensation) of these fruits does not affect birds. Mechanical dispersion by humans is another route of seed dispersion of pepper. Solution Capsicum annum (pepper) belongs to the family Solanaceae. The fruits of this plant (pepper) acquire attractive color as they become ripen, which attract the birds. Birds eat the fruits and disperse the seeds. The unpleasant taste (burning sensation) of these fruits does not affect birds. Mechanical dispersion by humans is another route of seed dispersion of pepper..

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