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Moles = massmolar mass Moles of ( liqiud indium) = 475114.82=4.1.pdf

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Moles = mass/molar mass Moles of ( liqiud indium) = 475/114.82=4.12 Moles of ( solid indium) =511/114.82=4.45 Temperature 276C=549K : 157=430K Q(of liqiud indium) = mass* specific heat*change in temperature =4.12 mol * 29.5 J/Kmol * (549-430)K =14463.26J this heat is lost by the liquid indium which is gain by the solid indium Q(Solid Indium) = moles * heat of fusion 14463.26=4.45*heat of fusion Hest of fusion = 14463.26/4.45=3250.17 J/mol =3.25 Kj/mol Solution Moles = mass/molar mass Moles of ( liqiud indium) = 475/114.82=4.12 Moles of ( solid indium) =511/114.82=4.45 Temperature 276C=549K : 157=430K Q(of liqiud indium) = mass* specific heat*change in temperature =4.12 mol * 29.5 J/Kmol * (549-430)K =14463.26J this heat is lost by the liquid indium which is gain by the solid indium Q(Solid Indium) = moles * heat of fusion 14463.26=4.45*heat of fusion Hest of fusion = 14463.26/4.45=3250.17 J/mol =3.25 Kj/mol.

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Moles = mass/molar mass Moles of ( liqiud indium) = 475/114.82=4.12 Moles of ( solid indium) =511/114.82=4.45 Temperature 276C=549K : 157=430K Q(of liqiud indium) = mass* specific heat*change in temperature =4.12 mol * 29.5 J/Kmol * (549-430)K =14463.26J this heat is lost by the liquid indium which is gain by the solid indium Q(Solid Indium) = moles * heat of fusion 14463.26=4.45*heat of fusion Hest of fusion = 14463.26/4.45=3250.17 J/mol =3.25 Kj/mol Solution Moles = mass/molar mass Moles of ( liqiud indium) = 475/114.82=4.12 Moles of ( solid indium) =511/114.82=4.45 Temperature 276C=549K : 157=430K Q(of liqiud indium) = mass* specific heat*change in temperature =4.12 mol * 29.5 J/Kmol * (549-430)K =14463.26J this heat is lost by the liquid indium which is gain by the solid indium
Q(Solid Indium) = moles * heat of fusion 14463.26=4.45*heat of fusion Hest of fusion = 14463.26/4.45=3250.17 J/mol =3.25 Kj/mol

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Moles = massmolar mass Moles of ( liqiud indium) = 475114.82=4.1.pdf

  • 1. Moles = mass/molar mass Moles of ( liqiud indium) = 475/114.82=4.12 Moles of ( solid indium) =511/114.82=4.45 Temperature 276C=549K : 157=430K Q(of liqiud indium) = mass* specific heat*change in temperature =4.12 mol * 29.5 J/Kmol * (549-430)K =14463.26J this heat is lost by the liquid indium which is gain by the solid indium Q(Solid Indium) = moles * heat of fusion 14463.26=4.45*heat of fusion Hest of fusion = 14463.26/4.45=3250.17 J/mol =3.25 Kj/mol Solution Moles = mass/molar mass Moles of ( liqiud indium) = 475/114.82=4.12 Moles of ( solid indium) =511/114.82=4.45 Temperature 276C=549K : 157=430K Q(of liqiud indium) = mass* specific heat*change in temperature =4.12 mol * 29.5 J/Kmol * (549-430)K =14463.26J this heat is lost by the liquid indium which is gain by the solid indium
  • 2. Q(Solid Indium) = moles * heat of fusion 14463.26=4.45*heat of fusion Hest of fusion = 14463.26/4.45=3250.17 J/mol =3.25 Kj/mol