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It is used as the solvent Solution It is used as the solvent.
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molality = mole / wt of solvent 0.11 = mole / 217 mole = 0.11*217 = 23.87mole Solution molality = mole / wt of solvent 0.11 = mole / 217 mole = 0.11*217 = 23.87mole.
molality = mole wt of solvent 0.11 = mole 21.pdf
molality = mole wt of solvent 0.11 = mole 21.pdf
anujmkt
NaF would be having highest melting point because melting point increases with ionic character F is more electronegative and Na is more electro positive and hence NaF is more ionic Solution NaF would be having highest melting point because melting point increases with ionic character F is more electronegative and Na is more electro positive and hence NaF is more ionic.
NaF would be having highest melting point because.pdf
NaF would be having highest melting point because.pdf
anujmkt
The four bases in DNA are Adenine, Guanine, Cytosine and Thymine. Adenine and Guanine are Purines (2 ring structure). Cytosine and Thymine are Pyrimidines (single ring structure). Adenine pairs with Thymine through 2 hydrogen bonds. Guanine pairs with Cytosine through 3 hydrogen bonds. Since all base pairs contain a Purine and a Pyrimidine, they have the same molecular dimensions. Solution The four bases in DNA are Adenine, Guanine, Cytosine and Thymine. Adenine and Guanine are Purines (2 ring structure). Cytosine and Thymine are Pyrimidines (single ring structure). Adenine pairs with Thymine through 2 hydrogen bonds. Guanine pairs with Cytosine through 3 hydrogen bonds. Since all base pairs contain a Purine and a Pyrimidine, they have the same molecular dimensions..
The four bases in DNA are Adenine, Guanine, Cytos.pdf
The four bases in DNA are Adenine, Guanine, Cytos.pdf
anujmkt
b) HNO2,NO2^+ as when H+ will leave then NO2- will be left as conjucate base and not NO2+ Solution b) HNO2,NO2^+ as when H+ will leave then NO2- will be left as conjucate base and not NO2+.
b) HNO2,NO2^+ as when H+ will leave then NO2- wil.pdf
b) HNO2,NO2^+ as when H+ will leave then NO2- wil.pdf
anujmkt
CO3 Solution CO3.
CO3 Sol.pdf
CO3 Sol.pdf
anujmkt
Number of moles of Calcium = 0.05 Number of equivalents of calcium = Number of moles / Valency = 0.05 / 2 = 0.025 Normality = 0.025 / 1 = 0.025 Ea /L Solution Number of moles of Calcium = 0.05 Number of equivalents of calcium = Number of moles / Valency = 0.05 / 2 = 0.025 Normality = 0.025 / 1 = 0.025 Ea /L.
Number of moles of Calcium = 0.05Number of equivalents of calcium .pdf
Number of moles of Calcium = 0.05Number of equivalents of calcium .pdf
anujmkt
A) d B) a, b, c Solution A) d B) a, b, c.
A) d B) a, b, c Solution .pdf
A) d B) a, b, c Solution .pdf
anujmkt
While doing capital investment, CFO analyze all the risk related to project. There are several methods that can be used by CFO for project evaluation, but the best method should consider the project risks while calculating net present value of cashflow generated by the project. If I were a CFO of an organization then I will consider risk adjusted discount rate because it calculate NPV while considering the risk factors. There are many advantages of using these method which are as follows: 1. It can be used for the calculation for different time period and one can use different discount rate for risk factors for specific time period. 2. One can adjust the risk by incresing the time period. 3. While evaluating the risk for any project, it is the easiest one. Risk adjusted discount rate method produces most accurate result at differing levels of project risk and at the same time it is easiest to implement. One needs to calculate the risk factors before using this method. Solution While doing capital investment, CFO analyze all the risk related to project. There are several methods that can be used by CFO for project evaluation, but the best method should consider the project risks while calculating net present value of cashflow generated by the project. If I were a CFO of an organization then I will consider risk adjusted discount rate because it calculate NPV while considering the risk factors. There are many advantages of using these method which are as follows: 1. It can be used for the calculation for different time period and one can use different discount rate for risk factors for specific time period. 2. One can adjust the risk by incresing the time period. 3. While evaluating the risk for any project, it is the easiest one. Risk adjusted discount rate method produces most accurate result at differing levels of project risk and at the same time it is easiest to implement. One needs to calculate the risk factors before using this method..
While doing capital investment, CFO analyze all the risk related to .pdf
While doing capital investment, CFO analyze all the risk related to .pdf
anujmkt
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molality = mole / wt of solvent 0.11 = mole / 217 mole = 0.11*217 = 23.87mole Solution molality = mole / wt of solvent 0.11 = mole / 217 mole = 0.11*217 = 23.87mole.
molality = mole wt of solvent 0.11 = mole 21.pdf
molality = mole wt of solvent 0.11 = mole 21.pdf
anujmkt
NaF would be having highest melting point because melting point increases with ionic character F is more electronegative and Na is more electro positive and hence NaF is more ionic Solution NaF would be having highest melting point because melting point increases with ionic character F is more electronegative and Na is more electro positive and hence NaF is more ionic.
NaF would be having highest melting point because.pdf
NaF would be having highest melting point because.pdf
anujmkt
The four bases in DNA are Adenine, Guanine, Cytosine and Thymine. Adenine and Guanine are Purines (2 ring structure). Cytosine and Thymine are Pyrimidines (single ring structure). Adenine pairs with Thymine through 2 hydrogen bonds. Guanine pairs with Cytosine through 3 hydrogen bonds. Since all base pairs contain a Purine and a Pyrimidine, they have the same molecular dimensions. Solution The four bases in DNA are Adenine, Guanine, Cytosine and Thymine. Adenine and Guanine are Purines (2 ring structure). Cytosine and Thymine are Pyrimidines (single ring structure). Adenine pairs with Thymine through 2 hydrogen bonds. Guanine pairs with Cytosine through 3 hydrogen bonds. Since all base pairs contain a Purine and a Pyrimidine, they have the same molecular dimensions..
The four bases in DNA are Adenine, Guanine, Cytos.pdf
The four bases in DNA are Adenine, Guanine, Cytos.pdf
anujmkt
b) HNO2,NO2^+ as when H+ will leave then NO2- will be left as conjucate base and not NO2+ Solution b) HNO2,NO2^+ as when H+ will leave then NO2- will be left as conjucate base and not NO2+.
b) HNO2,NO2^+ as when H+ will leave then NO2- wil.pdf
b) HNO2,NO2^+ as when H+ will leave then NO2- wil.pdf
anujmkt
CO3 Solution CO3.
CO3 Sol.pdf
CO3 Sol.pdf
anujmkt
Number of moles of Calcium = 0.05 Number of equivalents of calcium = Number of moles / Valency = 0.05 / 2 = 0.025 Normality = 0.025 / 1 = 0.025 Ea /L Solution Number of moles of Calcium = 0.05 Number of equivalents of calcium = Number of moles / Valency = 0.05 / 2 = 0.025 Normality = 0.025 / 1 = 0.025 Ea /L.
Number of moles of Calcium = 0.05Number of equivalents of calcium .pdf
Number of moles of Calcium = 0.05Number of equivalents of calcium .pdf
anujmkt
A) d B) a, b, c Solution A) d B) a, b, c.
A) d B) a, b, c Solution .pdf
A) d B) a, b, c Solution .pdf
anujmkt
While doing capital investment, CFO analyze all the risk related to project. There are several methods that can be used by CFO for project evaluation, but the best method should consider the project risks while calculating net present value of cashflow generated by the project. If I were a CFO of an organization then I will consider risk adjusted discount rate because it calculate NPV while considering the risk factors. There are many advantages of using these method which are as follows: 1. It can be used for the calculation for different time period and one can use different discount rate for risk factors for specific time period. 2. One can adjust the risk by incresing the time period. 3. While evaluating the risk for any project, it is the easiest one. Risk adjusted discount rate method produces most accurate result at differing levels of project risk and at the same time it is easiest to implement. One needs to calculate the risk factors before using this method. Solution While doing capital investment, CFO analyze all the risk related to project. There are several methods that can be used by CFO for project evaluation, but the best method should consider the project risks while calculating net present value of cashflow generated by the project. If I were a CFO of an organization then I will consider risk adjusted discount rate because it calculate NPV while considering the risk factors. There are many advantages of using these method which are as follows: 1. It can be used for the calculation for different time period and one can use different discount rate for risk factors for specific time period. 2. One can adjust the risk by incresing the time period. 3. While evaluating the risk for any project, it is the easiest one. Risk adjusted discount rate method produces most accurate result at differing levels of project risk and at the same time it is easiest to implement. One needs to calculate the risk factors before using this method..
While doing capital investment, CFO analyze all the risk related to .pdf
While doing capital investment, CFO analyze all the risk related to .pdf
anujmkt
What is Network security, or Securiing your data Through Network, Network security consists of the policies and practices adopted to prevent and monitor unauthorized access, misuse, modification, or denial of a computer network and network- accessible resources. Network security involves the authorization of access to data in a network, which is controlled by the network administrator. Standards for Network Security are:- The Network Security Standard provides measures to prevent, detect, and correct network compromises. The standard is based on both new practices and best practices currently in use at RIT. The Cyber Security Technical team at World Level Decides the Standards necessary for the Network to be secured. Regulations:- Cybersecurity regulation comprises directives from the Executive Branch and legislation from Congress that safeguards information technology and computer systems. The purpose of cybersecurity regulation is to force companies and organizations to protect their systems and information from cyber-attacks. Cyber-attacks include viruses, worms, Trojan horses, phishing, denial of service (DOS) attacks, unauthorized access (stealing intellectual property or confidential information) and control system attacks. Network Compilations:- The term network compliance is a broad one, and can have many meanings. The word compliance means “the state or act or conforming with or agreeing to do something, often in response to legislation, rules or regulations or court order.” Complying with all the rules, laws and orders in effect in the U.S. and other jurisdictions can be a tall order. Within the industry, the term is usually used to refer to one of the following: Laws:- There are many laws in the field of Cyber Security or we can say Network Security, and are increasing day by day, some of them are, Difference Between Laws and Regulations:- Laws are the products of written statutes, passed by either the U.S. Congress or state legislatures. The legislatures create bills that, when passed by a vote, become law. Regulations, on the other hand, are standards and rules adopted by administrative agencies that govern how laws will be enforced. So an agency like the SEC can have its own regulations for enforcing major securities laws. Thank You Solution What is Network security, or Securiing your data Through Network, Network security consists of the policies and practices adopted to prevent and monitor unauthorized access, misuse, modification, or denial of a computer network and network- accessible resources. Network security involves the authorization of access to data in a network, which is controlled by the network administrator. Standards for Network Security are:- The Network Security Standard provides measures to prevent, detect, and correct network compromises. The standard is based on both new practices and best practices currently in use at RIT. The Cyber Security Technical team at World Level Decides the Standards necessary for .
What is Network security, or Securiing your data Through Network,N.pdf
What is Network security, or Securiing your data Through Network,N.pdf
anujmkt
True Clay it the important of soil for holding plant nutrients in the soil. Clay particles have a negative surface charge. Solution True Clay it the important of soil for holding plant nutrients in the soil. Clay particles have a negative surface charge..
TrueClay it the important of soil for holding plant nutrients in t.pdf
TrueClay it the important of soil for holding plant nutrients in t.pdf
anujmkt
The statement is False Only single target target agents are sunjected to hetergeneity and clonal evolution, while the combination therapies are used to minimize the heterogeneity among the poplulation Solution The statement is False Only single target target agents are sunjected to hetergeneity and clonal evolution, while the combination therapies are used to minimize the heterogeneity among the poplulation.
The statement is FalseOnly single target target agents are sunject.pdf
The statement is FalseOnly single target target agents are sunject.pdf
anujmkt
The reactants along with the oxidation states are: Zn = 0 CuSO4: Cu = +2, S = +6, O = -2 The products along with the oxidation states are: Cu = 0 ZnSO4: Zn = +2, S= +6, O=-2 Zn went from 0 to +2 i.e. it lost electrons so it was Oxidized Cu went from +2 to 0 i.e. it gained electrons so it was Reduced. Solution The reactants along with the oxidation states are: Zn = 0 CuSO4: Cu = +2, S = +6, O = -2 The products along with the oxidation states are: Cu = 0 ZnSO4: Zn = +2, S= +6, O=-2 Zn went from 0 to +2 i.e. it lost electrons so it was Oxidized Cu went from +2 to 0 i.e. it gained electrons so it was Reduced..
The reactants along with the oxidation states are Zn = 0 CuSO4.pdf
The reactants along with the oxidation states are Zn = 0 CuSO4.pdf
anujmkt
The scanner performs lexical analysis of a precise program (in our case, the straightforward program). It reads the computer program as a sequence of characters and acknowledges \"larger\" matter units known as tokens. for instance, if the supply programs contains the characters VAR ics142: INTEGER; // variable declaration the scanner would manufacture the tokens VAR ID(ics142) COLON ID(INTEGER) punctuation to be processed in later phases of the compiler. Note that the scanner discards white house and comments between the tokens, i.e. they\'re \"filtered\" and not passed on to later phases. samples of nontokens ar tabs, line feeds, carriage returns, etc. How to use FLEX? FLEX (Fast LEXical instrument generator) may be a tool for generating scanners. In office of writing a scanner from scratch, you merely ought to establish the vocabulary of a precise language (e.g. Simple), write a specification of patterns mistreatment regular expressions (e.g. DIGIT [0-9]), and FLEX can construct a scanner for you. FLEX is mostly utilized in the way represented here: First, FLEX reads a specification of a scanner either from associate degree computer file *.lex, or from commonplace input, and it generates as output a C supply file lex.yy.c. Then, lex.yy.c is compiled associate degreed connected with the \"-lfl\" library to provide an workable a.out. Finally, a.out analyzes its input stream and transforms it into a sequence of tokens. Solution The scanner performs lexical analysis of a precise program (in our case, the straightforward program). It reads the computer program as a sequence of characters and acknowledges \"larger\" matter units known as tokens. for instance, if the supply programs contains the characters VAR ics142: INTEGER; // variable declaration the scanner would manufacture the tokens VAR ID(ics142) COLON ID(INTEGER) punctuation to be processed in later phases of the compiler. Note that the scanner discards white house and comments between the tokens, i.e. they\'re \"filtered\" and not passed on to later phases. samples of nontokens ar tabs, line feeds, carriage returns, etc. How to use FLEX? FLEX (Fast LEXical instrument generator) may be a tool for generating scanners. In office of writing a scanner from scratch, you merely ought to establish the vocabulary of a precise language (e.g. Simple), write a specification of patterns mistreatment regular expressions (e.g. DIGIT [0-9]), and FLEX can construct a scanner for you. FLEX is mostly utilized in the way represented here: First, FLEX reads a specification of a scanner either from associate degree computer file *.lex, or from commonplace input, and it generates as output a C supply file lex.yy.c. Then, lex.yy.c is compiled associate degreed connected with the \"-lfl\" library to provide an workable a.out. Finally, a.out analyzes its input stream and transforms it into a sequence of tokens..
The scanner performs lexical analysis of a precise program (in our c.pdf
The scanner performs lexical analysis of a precise program (in our c.pdf
anujmkt
Solution : Pseudoextinction refers to- D) a species evolving to the point where it is no longer recongnized as a parental species. In this type of extinction ancestral species is no longer exists and a new subspecies evolved.Pseudoextinction leads to evolution of species.Currently present species of birds and some animals are the result of evolution through pseudoextinction and their ancestral species not exist now..
Solution Pseudoextinction refers to- D) a species evolving to t.pdf
Solution Pseudoextinction refers to- D) a species evolving to t.pdf
anujmkt
Share Holder\'s Equity = Current Assets + Net Fixed Assets - Current Liabilities - Long term Debt = $ 2210 +$ 9700 - $ 1370 - $ 4020 = $ 6,520 Working Capital = Current Assets - Current Liabilities = $ 2,210 - $ 1,370 = $ 840 Solution Share Holder\'s Equity = Current Assets + Net Fixed Assets - Current Liabilities - Long term Debt = $ 2210 +$ 9700 - $ 1370 - $ 4020 = $ 6,520 Working Capital = Current Assets - Current Liabilities = $ 2,210 - $ 1,370 = $ 840.
Share Holders Equity = Current Assets + Net Fixed Assets - Current.pdf
Share Holders Equity = Current Assets + Net Fixed Assets - Current.pdf
anujmkt
The correct answer for m_1=2 is 2,3 for l Solution The correct answer for m_1=2 is 2,3 for l.
The correct answer for m_1=2 is 2,3 for lSolutionThe corre.pdf
The correct answer for m_1=2 is 2,3 for lSolutionThe corre.pdf
anujmkt
sol:importance for an organization to implement an enterprise system 1)we can easily see into main processes of various deparrtments in an organization 2)there is a keen tracking of inter department activities 3)a single report will be given which will be analyzed for all the departments 4)there is no needed installing differet software for different departments ,just install same software for all the departments 5)by using this erp we can integrate the ecommerce integration ,so by using this we can web based tracking 6)erp is an structured design so there is no need of implementing the whole software ,as it is modular software we can implement required piece of software 7)erp system are specificly used for international companies or globally dispered enterprise organizations Solution sol:importance for an organization to implement an enterprise system 1)we can easily see into main processes of various deparrtments in an organization 2)there is a keen tracking of inter department activities 3)a single report will be given which will be analyzed for all the departments 4)there is no needed installing differet software for different departments ,just install same software for all the departments 5)by using this erp we can integrate the ecommerce integration ,so by using this we can web based tracking 6)erp is an structured design so there is no need of implementing the whole software ,as it is modular software we can implement required piece of software 7)erp system are specificly used for international companies or globally dispered enterprise organizations.
solimportance for an organization to implement an enterprise system.pdf
solimportance for an organization to implement an enterprise system.pdf
anujmkt
We use the complementation principle. Clearly the 20 people can be seated in 20! ways without any restrictions. So, we now want to substract the possibility where the youngest(Y) and the oldest(O) are seated less than 3 seats appart. case1 - No seat in between - Now we can treat (OY) or (YO) as just a single person. Hence # such seatings is 19! *2 (for OY or YO ordering). Case 2 - 1 Seat in between. Now we observe that this duo can be seated in 18 ways - ie X^iOXYX^17-i ie some no of people on the left - can range from 0 to 17 no more. So, seat them in 18 ways, permute OY,YO in 2 ways(this will multiply) and then permute the 18 people in 18! ways - 2*18*18! Case 2 - 2 in between, similar analysis gives us that the left guy from O,Y can be seated in 17 ways - X^i O XX Y X^{16-i}. So i ranges from 0 to 16 ie 17 ways. ie 2* 17 * 18! So total possibilities = 20! - 2*18!(19 + 18 + 17) is the answer. The previous answer has ignored more than 3 chairs possibility. Message me if you have any doubts Solution We use the complementation principle. Clearly the 20 people can be seated in 20! ways without any restrictions. So, we now want to substract the possibility where the youngest(Y) and the oldest(O) are seated less than 3 seats appart. case1 - No seat in between - Now we can treat (OY) or (YO) as just a single person. Hence # such seatings is 19! *2 (for OY or YO ordering). Case 2 - 1 Seat in between. Now we observe that this duo can be seated in 18 ways - ie X^iOXYX^17-i ie some no of people on the left - can range from 0 to 17 no more. So, seat them in 18 ways, permute OY,YO in 2 ways(this will multiply) and then permute the 18 people in 18! ways - 2*18*18! Case 2 - 2 in between, similar analysis gives us that the left guy from O,Y can be seated in 17 ways - X^i O XX Y X^{16-i}. So i ranges from 0 to 16 ie 17 ways. ie 2* 17 * 18! So total possibilities = 20! - 2*18!(19 + 18 + 17) is the answer. The previous answer has ignored more than 3 chairs possibility. Message me if you have any doubts.
We use the complementation principle. Clearly the.pdf
We use the complementation principle. Clearly the.pdf
anujmkt
right idea but numbers are wrong all over the place Solution right idea but numbers are wrong all over the place.
right idea but numbers are wrong all over the placeSolution.pdf
right idea but numbers are wrong all over the placeSolution.pdf
anujmkt
Please follow the data and description : EBNF : In the stream of computer science, Extended Backus–Naur Form (EBNF) is a family of metasyntax notations, any of which can be used to express a context-free grammar. They are said to be the extensions of the basic Backus–Naur Form (BNF) metasyntax notation. The earliest EBNF was originally developed by Niklaus Wirth incorporating some of the concepts from Wirth syntax notation. However, many variants of EBNF are in use. The International Organization for Standardization has adopted an EBNF standard (ISO/IEC 14977). BNF : BNF is the abbrevation of Backus Normal Form or Backus–Naur Form which is one of the two main notation techniques for context-free grammars, often used to describe the syntax of languages used in computing, such as computer programming languages, document formats, instruction sets and communication protocols. They are applied wherever exact descriptions of languages are needed, for instance, in official language specifications, in manuals, and in textbooks on programming language theory. EBNF To BNF : Given, -> {b} -> a[b] a) -> {b} = Here S is a sequence of A that is optionally followed by a sequence of b and S together. -> | b ; b) -> a[b] = Here A is composed of \'a\', that is then followed by an optional \'b\', followed by another A combinedly. -> a | a b ; Hope this is helpful. Solution Please follow the data and description : EBNF : In the stream of computer science, Extended Backus–Naur Form (EBNF) is a family of metasyntax notations, any of which can be used to express a context-free grammar. They are said to be the extensions of the basic Backus–Naur Form (BNF) metasyntax notation. The earliest EBNF was originally developed by Niklaus Wirth incorporating some of the concepts from Wirth syntax notation. However, many variants of EBNF are in use. The International Organization for Standardization has adopted an EBNF standard (ISO/IEC 14977). BNF : BNF is the abbrevation of Backus Normal Form or Backus–Naur Form which is one of the two main notation techniques for context-free grammars, often used to describe the syntax of languages used in computing, such as computer programming languages, document formats, instruction sets and communication protocols. They are applied wherever exact descriptions of languages are needed, for instance, in official language specifications, in manuals, and in textbooks on programming language theory. EBNF To BNF : Given, -> {b} -> a[b] a) -> {b} = Here S is a sequence of A that is optionally followed by a sequence of b and S together. -> | b ; b) -> a[b] = Here A is composed of \'a\', that is then followed by an optional \'b\', followed by another A combinedly. -> a | a b ; Hope this is helpful..
Please follow the data and description EBNF In the stream of c.pdf
Please follow the data and description EBNF In the stream of c.pdf
anujmkt
/* Program of sorting using shell sort */ #include #define MAX 20 main() { int arr[MAX], i,j,k,n,incr; printf(\"Enter the number of elements : \"); scanf(\"%d\",&n); for(i=0;i=1) { for(j=incr;j= 0 && k < arr[i]; i = i-incr) arr[i+incr]=arr[i]; arr[i+incr]=k; } printf(\"Increment=%d \ \",incr); for (i = 0; i < n; i++) printf(\"%d \", arr[i]); printf(\"\ \"); incr=incr-2; /*Decrease the increment*/ }/*End of while*/ printf(\"Sorted list is :\ \"); for (i = 0; i < n; i++) printf(\"%d \", arr[i]); printf(\"\ \"); }/*End of main()*/ redix sort /*Program of sorting using radix sort*/ # include # include struct node { int info ; struct node *link; }*start=NULL; main() { struct node *tmp,*q; int i,n,item; printf(\"Enter the number of elements in the list : \"); scanf(\"%d\", &n); for(i=0;iinfo=item; tmp->link=NULL; if(start==NULL) /* Inserting first element */ start=tmp; else { q=start; while(q->link!=NULL) q=q->link; q->link=tmp; } }/*End of for*/ printf(\"Unsorted list is :\ \"); display(); radix_sort(); printf(\"Sorted list is :\ \"); display (); }/*End of main()*/ display() { struct node *p=start; while( p !=NULL) { printf(\"%d \", p->info); p= p->link; } printf(\"\ \"); }/*End of display()*/ radix_sort() { int i,k,dig,maxdig,mindig,least_sig,most_sig; struct node *p, *rear[10], *front[10]; least_sig=1; most_sig=large_dig(start); for(k = least_sig; k <= most_sig ; k++) { printf(\"PASS %d : Examining %dth digit from right \",k,k); for(i = 0 ; i <= 9 ; i++) { rear[i] = NULL; front[i] = NULL ; } maxdig=0; mindig=9; p = start ; while( p != NULL) { /*Find kth digit in the number*/ dig = digit(p->info, k); if(dig>maxdig) maxdig=dig; if(diglink = p ; rear[dig] = p ; p=p->link;/*Go to next number in the list*/ }/*End while */ /* maxdig and mindig are the maximum amd minimum digits of the kth digits of all the numbers*/ printf(\"mindig=%d maxdig=%d\ \",mindig,maxdig); /*Join all the queues to form the new linked list*/ start=front[mindig]; for(i=mindig;ilink=front[i+1]; else rear[i+1]=rear[i]; } rear[maxdig]->link=NULL; printf(\"New list : \"); display(); }/* End for */ }/*End of radix_sort*/ /* This function finds number of digits in the largest element of the list */ int large_dig() { struct node *p=start ; int large = 0,ndig = 0 ; while(p != NULL) { if(p ->info > large) large = p->info; p = p->link ; } printf(\"Largest Element is %d , \",large); while(large != 0) { ndig++; large = large/10 ; } printf(\"Number of digits in it are %d\ \",ndig); return(ndig); } /*End of large_dig()*/ /*This function returns kth digit of a number*/ int digit(int number, int k) { int digit, i ; for(i = 1 ; i <=k ; i++) { digit = number % 10 ; number = number /10 ; } return(digit); }/*End of digit()*/ Solution /* Program of sorting using shell sort */ #include #define MAX 20 main() { int arr[MAX], i,j,k,n,incr; printf(\"Enter the number of elements : \"); scanf(\"%d\",&n); for(i=0;i=1) { for(j=incr;j= 0 && k < arr[i]; i = i-incr) arr[i+incr]=arr[i]; arr[i+incr]=k; } printf(\.
Program of sorting using shell sort #include stdio.h #de.pdf
Program of sorting using shell sort #include stdio.h #de.pdf
anujmkt
The sample proportion falls between 0.4 and 0.6 Solution The sample proportion falls between 0.4 and 0.6.
The sample proportion falls between 0.4 and 0.6Solution The s.pdf
The sample proportion falls between 0.4 and 0.6Solution The s.pdf
anujmkt
namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { int monthNumber; int.TryParse(inputTextBox.Text, out monthNumber); if (monthNumber < 1 || monthNumber > 12) { MessageBox.Show(\"Please enter an integer between 1 and 12\"); inputTextBox.Focus(); return; } string monthName = ((Month)monthNumber).ToString(); MessageBox.Show(\"You entered the month number for \" + monthName); inputTextBox.Clear(); inputTextBox.Focus(); } } } Solution namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { int monthNumber; int.TryParse(inputTextBox.Text, out monthNumber); if (monthNumber < 1 || monthNumber > 12) { MessageBox.Show(\"Please enter an integer between 1 and 12\"); inputTextBox.Focus(); return; } string monthName = ((Month)monthNumber).ToString(); MessageBox.Show(\"You entered the month number for \" + monthName); inputTextBox.Clear(); inputTextBox.Focus(); } } }.
namespace MonthNamesGUI{public partial class Form1 Form{en.pdf
namespace MonthNamesGUI{public partial class Form1 Form{en.pdf
anujmkt
+0.35, as the scatter is not showing any significant relationship to generate higher values of other options Solution +0.35, as the scatter is not showing any significant relationship to generate higher values of other options.
+0.35, as the scatter is not showing any significant relationship to.pdf
+0.35, as the scatter is not showing any significant relationship to.pdf
anujmkt
Here ABE is one plane BCD is another perpendicular plane from the given details. AE lies on ABE plane and CE lies on BCD plane. Hence , perpendiculat to each other. Solution Here ABE is one plane BCD is another perpendicular plane from the given details. AE lies on ABE plane and CE lies on BCD plane. Hence , perpendiculat to each other..
Here ABE is one planeBCD is another perpendicular plane from the g.pdf
Here ABE is one planeBCD is another perpendicular plane from the g.pdf
anujmkt
For governments that implement GASB Statement No. 34, the fund financial statements will accompany Management\'s Discussion and Analysis and the government-wide statements. The fund financial statements are used to report additional detailed information about the primary government not found in the government-wide statements and focus on major funds of the primary government. The GWFS are reported using the economic resources measurement focus and the full accrual basis of accounting. GWFS report information about the government as a whole without displaying individual funds or fund types. Distinctions should be made in the GWFS between the primary government and its discretely presented component units, as well as between governmental activities and business-type activities. Fiduciary activities are not included in the GWFS. GWFS include: The Government-wide Financial Statements and Fund Financial Statements have a different measurement focus and basis of accounting. To help the user understand and assess the relationship between fund-based and government-wide financial statements, local governments will be required to present a summary reconciliationthat will show the interplay between the two types of statements. Balance sheet - The basic statement of position for governmental funds reports the difference between assets and liabilities as fund balance. Fund balance is divided into reserved and unreserved components. This is the same statement that is contained in the AUD and ST3. Statement of revenues, expenditures and changes in fund balance-The basic statement of activities for governmental funds reports revenues by source and expenditures by function just as they are currently reported. Since long-term liabilities and capital assets have been incorporated into the government-wide statements the accounts groups will no longer be reported in the statements. A revised supplemental schedule will be included in the AUD and ST3 to continue to accumulate this information. Statement of net assets- The basic statement of position for proprietary funds reports the difference between assets and liabilities as net assets. Net assets are divided into invested in capital assets, restricted and unrestricted.Statement of revenues, expenses and changes in fund net assets- The basic statement of activities for proprietary funds distinguishes operating and non-operating revenues and expenses.Statement of cash flows - This statement will now be required to be prepared on the direct method where operating cash flows will be reported by source. This is not a change for local governments since OSC has already required this method. Solution For governments that implement GASB Statement No. 34, the fund financial statements will accompany Management\'s Discussion and Analysis and the government-wide statements. The fund financial statements are used to report additional detailed information about the primary government not found in the government-wide statement.
For governments that implement GASB Statement No. 34, the fund finan.pdf
For governments that implement GASB Statement No. 34, the fund finan.pdf
anujmkt
Ethical theories are often divided into three types - 1) Consequentiolist Theories - 2) Non - Consequentialist Approach - 3) Agent - Centered Theories - Solution Ethical theories are often divided into three types - 1) Consequentiolist Theories - 2) Non - Consequentialist Approach - 3) Agent - Centered Theories -.
Ethical theories are often divided into three types -1) Consequent.pdf
Ethical theories are often divided into three types -1) Consequent.pdf
anujmkt
D. The International Organization on Computer Evidence (IOCE) was appointed to draw up international principles for the procedures relating to digital evidence. The goal was to harmonize methods and practices among nations and guarantee the capability to use digital evidence collected by one state in the courts of another state. Solution D. The International Organization on Computer Evidence (IOCE) was appointed to draw up international principles for the procedures relating to digital evidence. The goal was to harmonize methods and practices among nations and guarantee the capability to use digital evidence collected by one state in the courts of another state..
D. The International Organization on Computer Evidence (IOCE) was ap.pdf
D. The International Organization on Computer Evidence (IOCE) was ap.pdf
anujmkt
https://app.box.com/s/m9ehjx5owsaox9ykvb9qg3csa8a0jnox
TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...
TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...
Nguyen Thanh Tu Collection
APM webinar hosted by the Scotland Network on 14 May 2024. Speakers: Chris Drysdale and Peter Huggett An interactive session discussing how Project Managers can identify mental health symptoms, provide tools to help themselves and others, plus also increase the capabilities of the Project Management function. This webinar was held on 14 May 2024. The covid-19 pandemic led to concerns about a worsening of mental health & wellbeing across the world and increased awareness in both society and the workplace. This webinar looks to advise the benefits of having a Mental Health First Aid function in the workplace whilst also providing tools and techniques that can be readily used and applied to yourself and colleagues. Additionally, there are wider benefits to Project Management which will be proposed and discussed.
Including Mental Health Support in Project Delivery, 14 May.pdf
Including Mental Health Support in Project Delivery, 14 May.pdf
Association for Project Management
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What is Network security, or Securiing your data Through Network, Network security consists of the policies and practices adopted to prevent and monitor unauthorized access, misuse, modification, or denial of a computer network and network- accessible resources. Network security involves the authorization of access to data in a network, which is controlled by the network administrator. Standards for Network Security are:- The Network Security Standard provides measures to prevent, detect, and correct network compromises. The standard is based on both new practices and best practices currently in use at RIT. The Cyber Security Technical team at World Level Decides the Standards necessary for the Network to be secured. Regulations:- Cybersecurity regulation comprises directives from the Executive Branch and legislation from Congress that safeguards information technology and computer systems. The purpose of cybersecurity regulation is to force companies and organizations to protect their systems and information from cyber-attacks. Cyber-attacks include viruses, worms, Trojan horses, phishing, denial of service (DOS) attacks, unauthorized access (stealing intellectual property or confidential information) and control system attacks. Network Compilations:- The term network compliance is a broad one, and can have many meanings. The word compliance means “the state or act or conforming with or agreeing to do something, often in response to legislation, rules or regulations or court order.” Complying with all the rules, laws and orders in effect in the U.S. and other jurisdictions can be a tall order. Within the industry, the term is usually used to refer to one of the following: Laws:- There are many laws in the field of Cyber Security or we can say Network Security, and are increasing day by day, some of them are, Difference Between Laws and Regulations:- Laws are the products of written statutes, passed by either the U.S. Congress or state legislatures. The legislatures create bills that, when passed by a vote, become law. Regulations, on the other hand, are standards and rules adopted by administrative agencies that govern how laws will be enforced. So an agency like the SEC can have its own regulations for enforcing major securities laws. Thank You Solution What is Network security, or Securiing your data Through Network, Network security consists of the policies and practices adopted to prevent and monitor unauthorized access, misuse, modification, or denial of a computer network and network- accessible resources. Network security involves the authorization of access to data in a network, which is controlled by the network administrator. Standards for Network Security are:- The Network Security Standard provides measures to prevent, detect, and correct network compromises. The standard is based on both new practices and best practices currently in use at RIT. The Cyber Security Technical team at World Level Decides the Standards necessary for .
What is Network security, or Securiing your data Through Network,N.pdf
What is Network security, or Securiing your data Through Network,N.pdf
anujmkt
True Clay it the important of soil for holding plant nutrients in the soil. Clay particles have a negative surface charge. Solution True Clay it the important of soil for holding plant nutrients in the soil. Clay particles have a negative surface charge..
TrueClay it the important of soil for holding plant nutrients in t.pdf
TrueClay it the important of soil for holding plant nutrients in t.pdf
anujmkt
The statement is False Only single target target agents are sunjected to hetergeneity and clonal evolution, while the combination therapies are used to minimize the heterogeneity among the poplulation Solution The statement is False Only single target target agents are sunjected to hetergeneity and clonal evolution, while the combination therapies are used to minimize the heterogeneity among the poplulation.
The statement is FalseOnly single target target agents are sunject.pdf
The statement is FalseOnly single target target agents are sunject.pdf
anujmkt
The reactants along with the oxidation states are: Zn = 0 CuSO4: Cu = +2, S = +6, O = -2 The products along with the oxidation states are: Cu = 0 ZnSO4: Zn = +2, S= +6, O=-2 Zn went from 0 to +2 i.e. it lost electrons so it was Oxidized Cu went from +2 to 0 i.e. it gained electrons so it was Reduced. Solution The reactants along with the oxidation states are: Zn = 0 CuSO4: Cu = +2, S = +6, O = -2 The products along with the oxidation states are: Cu = 0 ZnSO4: Zn = +2, S= +6, O=-2 Zn went from 0 to +2 i.e. it lost electrons so it was Oxidized Cu went from +2 to 0 i.e. it gained electrons so it was Reduced..
The reactants along with the oxidation states are Zn = 0 CuSO4.pdf
The reactants along with the oxidation states are Zn = 0 CuSO4.pdf
anujmkt
The scanner performs lexical analysis of a precise program (in our case, the straightforward program). It reads the computer program as a sequence of characters and acknowledges \"larger\" matter units known as tokens. for instance, if the supply programs contains the characters VAR ics142: INTEGER; // variable declaration the scanner would manufacture the tokens VAR ID(ics142) COLON ID(INTEGER) punctuation to be processed in later phases of the compiler. Note that the scanner discards white house and comments between the tokens, i.e. they\'re \"filtered\" and not passed on to later phases. samples of nontokens ar tabs, line feeds, carriage returns, etc. How to use FLEX? FLEX (Fast LEXical instrument generator) may be a tool for generating scanners. In office of writing a scanner from scratch, you merely ought to establish the vocabulary of a precise language (e.g. Simple), write a specification of patterns mistreatment regular expressions (e.g. DIGIT [0-9]), and FLEX can construct a scanner for you. FLEX is mostly utilized in the way represented here: First, FLEX reads a specification of a scanner either from associate degree computer file *.lex, or from commonplace input, and it generates as output a C supply file lex.yy.c. Then, lex.yy.c is compiled associate degreed connected with the \"-lfl\" library to provide an workable a.out. Finally, a.out analyzes its input stream and transforms it into a sequence of tokens. Solution The scanner performs lexical analysis of a precise program (in our case, the straightforward program). It reads the computer program as a sequence of characters and acknowledges \"larger\" matter units known as tokens. for instance, if the supply programs contains the characters VAR ics142: INTEGER; // variable declaration the scanner would manufacture the tokens VAR ID(ics142) COLON ID(INTEGER) punctuation to be processed in later phases of the compiler. Note that the scanner discards white house and comments between the tokens, i.e. they\'re \"filtered\" and not passed on to later phases. samples of nontokens ar tabs, line feeds, carriage returns, etc. How to use FLEX? FLEX (Fast LEXical instrument generator) may be a tool for generating scanners. In office of writing a scanner from scratch, you merely ought to establish the vocabulary of a precise language (e.g. Simple), write a specification of patterns mistreatment regular expressions (e.g. DIGIT [0-9]), and FLEX can construct a scanner for you. FLEX is mostly utilized in the way represented here: First, FLEX reads a specification of a scanner either from associate degree computer file *.lex, or from commonplace input, and it generates as output a C supply file lex.yy.c. Then, lex.yy.c is compiled associate degreed connected with the \"-lfl\" library to provide an workable a.out. Finally, a.out analyzes its input stream and transforms it into a sequence of tokens..
The scanner performs lexical analysis of a precise program (in our c.pdf
The scanner performs lexical analysis of a precise program (in our c.pdf
anujmkt
Solution : Pseudoextinction refers to- D) a species evolving to the point where it is no longer recongnized as a parental species. In this type of extinction ancestral species is no longer exists and a new subspecies evolved.Pseudoextinction leads to evolution of species.Currently present species of birds and some animals are the result of evolution through pseudoextinction and their ancestral species not exist now..
Solution Pseudoextinction refers to- D) a species evolving to t.pdf
Solution Pseudoextinction refers to- D) a species evolving to t.pdf
anujmkt
Share Holder\'s Equity = Current Assets + Net Fixed Assets - Current Liabilities - Long term Debt = $ 2210 +$ 9700 - $ 1370 - $ 4020 = $ 6,520 Working Capital = Current Assets - Current Liabilities = $ 2,210 - $ 1,370 = $ 840 Solution Share Holder\'s Equity = Current Assets + Net Fixed Assets - Current Liabilities - Long term Debt = $ 2210 +$ 9700 - $ 1370 - $ 4020 = $ 6,520 Working Capital = Current Assets - Current Liabilities = $ 2,210 - $ 1,370 = $ 840.
Share Holders Equity = Current Assets + Net Fixed Assets - Current.pdf
Share Holders Equity = Current Assets + Net Fixed Assets - Current.pdf
anujmkt
The correct answer for m_1=2 is 2,3 for l Solution The correct answer for m_1=2 is 2,3 for l.
The correct answer for m_1=2 is 2,3 for lSolutionThe corre.pdf
The correct answer for m_1=2 is 2,3 for lSolutionThe corre.pdf
anujmkt
sol:importance for an organization to implement an enterprise system 1)we can easily see into main processes of various deparrtments in an organization 2)there is a keen tracking of inter department activities 3)a single report will be given which will be analyzed for all the departments 4)there is no needed installing differet software for different departments ,just install same software for all the departments 5)by using this erp we can integrate the ecommerce integration ,so by using this we can web based tracking 6)erp is an structured design so there is no need of implementing the whole software ,as it is modular software we can implement required piece of software 7)erp system are specificly used for international companies or globally dispered enterprise organizations Solution sol:importance for an organization to implement an enterprise system 1)we can easily see into main processes of various deparrtments in an organization 2)there is a keen tracking of inter department activities 3)a single report will be given which will be analyzed for all the departments 4)there is no needed installing differet software for different departments ,just install same software for all the departments 5)by using this erp we can integrate the ecommerce integration ,so by using this we can web based tracking 6)erp is an structured design so there is no need of implementing the whole software ,as it is modular software we can implement required piece of software 7)erp system are specificly used for international companies or globally dispered enterprise organizations.
solimportance for an organization to implement an enterprise system.pdf
solimportance for an organization to implement an enterprise system.pdf
anujmkt
We use the complementation principle. Clearly the 20 people can be seated in 20! ways without any restrictions. So, we now want to substract the possibility where the youngest(Y) and the oldest(O) are seated less than 3 seats appart. case1 - No seat in between - Now we can treat (OY) or (YO) as just a single person. Hence # such seatings is 19! *2 (for OY or YO ordering). Case 2 - 1 Seat in between. Now we observe that this duo can be seated in 18 ways - ie X^iOXYX^17-i ie some no of people on the left - can range from 0 to 17 no more. So, seat them in 18 ways, permute OY,YO in 2 ways(this will multiply) and then permute the 18 people in 18! ways - 2*18*18! Case 2 - 2 in between, similar analysis gives us that the left guy from O,Y can be seated in 17 ways - X^i O XX Y X^{16-i}. So i ranges from 0 to 16 ie 17 ways. ie 2* 17 * 18! So total possibilities = 20! - 2*18!(19 + 18 + 17) is the answer. The previous answer has ignored more than 3 chairs possibility. Message me if you have any doubts Solution We use the complementation principle. Clearly the 20 people can be seated in 20! ways without any restrictions. So, we now want to substract the possibility where the youngest(Y) and the oldest(O) are seated less than 3 seats appart. case1 - No seat in between - Now we can treat (OY) or (YO) as just a single person. Hence # such seatings is 19! *2 (for OY or YO ordering). Case 2 - 1 Seat in between. Now we observe that this duo can be seated in 18 ways - ie X^iOXYX^17-i ie some no of people on the left - can range from 0 to 17 no more. So, seat them in 18 ways, permute OY,YO in 2 ways(this will multiply) and then permute the 18 people in 18! ways - 2*18*18! Case 2 - 2 in between, similar analysis gives us that the left guy from O,Y can be seated in 17 ways - X^i O XX Y X^{16-i}. So i ranges from 0 to 16 ie 17 ways. ie 2* 17 * 18! So total possibilities = 20! - 2*18!(19 + 18 + 17) is the answer. The previous answer has ignored more than 3 chairs possibility. Message me if you have any doubts.
We use the complementation principle. Clearly the.pdf
We use the complementation principle. Clearly the.pdf
anujmkt
right idea but numbers are wrong all over the place Solution right idea but numbers are wrong all over the place.
right idea but numbers are wrong all over the placeSolution.pdf
right idea but numbers are wrong all over the placeSolution.pdf
anujmkt
Please follow the data and description : EBNF : In the stream of computer science, Extended Backus–Naur Form (EBNF) is a family of metasyntax notations, any of which can be used to express a context-free grammar. They are said to be the extensions of the basic Backus–Naur Form (BNF) metasyntax notation. The earliest EBNF was originally developed by Niklaus Wirth incorporating some of the concepts from Wirth syntax notation. However, many variants of EBNF are in use. The International Organization for Standardization has adopted an EBNF standard (ISO/IEC 14977). BNF : BNF is the abbrevation of Backus Normal Form or Backus–Naur Form which is one of the two main notation techniques for context-free grammars, often used to describe the syntax of languages used in computing, such as computer programming languages, document formats, instruction sets and communication protocols. They are applied wherever exact descriptions of languages are needed, for instance, in official language specifications, in manuals, and in textbooks on programming language theory. EBNF To BNF : Given, -> {b} -> a[b] a) -> {b} = Here S is a sequence of A that is optionally followed by a sequence of b and S together. -> | b ; b) -> a[b] = Here A is composed of \'a\', that is then followed by an optional \'b\', followed by another A combinedly. -> a | a b ; Hope this is helpful. Solution Please follow the data and description : EBNF : In the stream of computer science, Extended Backus–Naur Form (EBNF) is a family of metasyntax notations, any of which can be used to express a context-free grammar. They are said to be the extensions of the basic Backus–Naur Form (BNF) metasyntax notation. The earliest EBNF was originally developed by Niklaus Wirth incorporating some of the concepts from Wirth syntax notation. However, many variants of EBNF are in use. The International Organization for Standardization has adopted an EBNF standard (ISO/IEC 14977). BNF : BNF is the abbrevation of Backus Normal Form or Backus–Naur Form which is one of the two main notation techniques for context-free grammars, often used to describe the syntax of languages used in computing, such as computer programming languages, document formats, instruction sets and communication protocols. They are applied wherever exact descriptions of languages are needed, for instance, in official language specifications, in manuals, and in textbooks on programming language theory. EBNF To BNF : Given, -> {b} -> a[b] a) -> {b} = Here S is a sequence of A that is optionally followed by a sequence of b and S together. -> | b ; b) -> a[b] = Here A is composed of \'a\', that is then followed by an optional \'b\', followed by another A combinedly. -> a | a b ; Hope this is helpful..
Please follow the data and description EBNF In the stream of c.pdf
Please follow the data and description EBNF In the stream of c.pdf
anujmkt
/* Program of sorting using shell sort */ #include #define MAX 20 main() { int arr[MAX], i,j,k,n,incr; printf(\"Enter the number of elements : \"); scanf(\"%d\",&n); for(i=0;i=1) { for(j=incr;j= 0 && k < arr[i]; i = i-incr) arr[i+incr]=arr[i]; arr[i+incr]=k; } printf(\"Increment=%d \ \",incr); for (i = 0; i < n; i++) printf(\"%d \", arr[i]); printf(\"\ \"); incr=incr-2; /*Decrease the increment*/ }/*End of while*/ printf(\"Sorted list is :\ \"); for (i = 0; i < n; i++) printf(\"%d \", arr[i]); printf(\"\ \"); }/*End of main()*/ redix sort /*Program of sorting using radix sort*/ # include # include struct node { int info ; struct node *link; }*start=NULL; main() { struct node *tmp,*q; int i,n,item; printf(\"Enter the number of elements in the list : \"); scanf(\"%d\", &n); for(i=0;iinfo=item; tmp->link=NULL; if(start==NULL) /* Inserting first element */ start=tmp; else { q=start; while(q->link!=NULL) q=q->link; q->link=tmp; } }/*End of for*/ printf(\"Unsorted list is :\ \"); display(); radix_sort(); printf(\"Sorted list is :\ \"); display (); }/*End of main()*/ display() { struct node *p=start; while( p !=NULL) { printf(\"%d \", p->info); p= p->link; } printf(\"\ \"); }/*End of display()*/ radix_sort() { int i,k,dig,maxdig,mindig,least_sig,most_sig; struct node *p, *rear[10], *front[10]; least_sig=1; most_sig=large_dig(start); for(k = least_sig; k <= most_sig ; k++) { printf(\"PASS %d : Examining %dth digit from right \",k,k); for(i = 0 ; i <= 9 ; i++) { rear[i] = NULL; front[i] = NULL ; } maxdig=0; mindig=9; p = start ; while( p != NULL) { /*Find kth digit in the number*/ dig = digit(p->info, k); if(dig>maxdig) maxdig=dig; if(diglink = p ; rear[dig] = p ; p=p->link;/*Go to next number in the list*/ }/*End while */ /* maxdig and mindig are the maximum amd minimum digits of the kth digits of all the numbers*/ printf(\"mindig=%d maxdig=%d\ \",mindig,maxdig); /*Join all the queues to form the new linked list*/ start=front[mindig]; for(i=mindig;ilink=front[i+1]; else rear[i+1]=rear[i]; } rear[maxdig]->link=NULL; printf(\"New list : \"); display(); }/* End for */ }/*End of radix_sort*/ /* This function finds number of digits in the largest element of the list */ int large_dig() { struct node *p=start ; int large = 0,ndig = 0 ; while(p != NULL) { if(p ->info > large) large = p->info; p = p->link ; } printf(\"Largest Element is %d , \",large); while(large != 0) { ndig++; large = large/10 ; } printf(\"Number of digits in it are %d\ \",ndig); return(ndig); } /*End of large_dig()*/ /*This function returns kth digit of a number*/ int digit(int number, int k) { int digit, i ; for(i = 1 ; i <=k ; i++) { digit = number % 10 ; number = number /10 ; } return(digit); }/*End of digit()*/ Solution /* Program of sorting using shell sort */ #include #define MAX 20 main() { int arr[MAX], i,j,k,n,incr; printf(\"Enter the number of elements : \"); scanf(\"%d\",&n); for(i=0;i=1) { for(j=incr;j= 0 && k < arr[i]; i = i-incr) arr[i+incr]=arr[i]; arr[i+incr]=k; } printf(\.
Program of sorting using shell sort #include stdio.h #de.pdf
Program of sorting using shell sort #include stdio.h #de.pdf
anujmkt
The sample proportion falls between 0.4 and 0.6 Solution The sample proportion falls between 0.4 and 0.6.
The sample proportion falls between 0.4 and 0.6Solution The s.pdf
The sample proportion falls between 0.4 and 0.6Solution The s.pdf
anujmkt
namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { int monthNumber; int.TryParse(inputTextBox.Text, out monthNumber); if (monthNumber < 1 || monthNumber > 12) { MessageBox.Show(\"Please enter an integer between 1 and 12\"); inputTextBox.Focus(); return; } string monthName = ((Month)monthNumber).ToString(); MessageBox.Show(\"You entered the month number for \" + monthName); inputTextBox.Clear(); inputTextBox.Focus(); } } } Solution namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; namespace MonthNamesGUI { public partial class Form1 : Form { enum Month { January = 1, February, March, April, May, June, July, August, September, October, November, December }; public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { int monthNumber; int.TryParse(inputTextBox.Text, out monthNumber); if (monthNumber < 1 || monthNumber > 12) { MessageBox.Show(\"Please enter an integer between 1 and 12\"); inputTextBox.Focus(); return; } string monthName = ((Month)monthNumber).ToString(); MessageBox.Show(\"You entered the month number for \" + monthName); inputTextBox.Clear(); inputTextBox.Focus(); } } }.
namespace MonthNamesGUI{public partial class Form1 Form{en.pdf
namespace MonthNamesGUI{public partial class Form1 Form{en.pdf
anujmkt
+0.35, as the scatter is not showing any significant relationship to generate higher values of other options Solution +0.35, as the scatter is not showing any significant relationship to generate higher values of other options.
+0.35, as the scatter is not showing any significant relationship to.pdf
+0.35, as the scatter is not showing any significant relationship to.pdf
anujmkt
Here ABE is one plane BCD is another perpendicular plane from the given details. AE lies on ABE plane and CE lies on BCD plane. Hence , perpendiculat to each other. Solution Here ABE is one plane BCD is another perpendicular plane from the given details. AE lies on ABE plane and CE lies on BCD plane. Hence , perpendiculat to each other..
Here ABE is one planeBCD is another perpendicular plane from the g.pdf
Here ABE is one planeBCD is another perpendicular plane from the g.pdf
anujmkt
For governments that implement GASB Statement No. 34, the fund financial statements will accompany Management\'s Discussion and Analysis and the government-wide statements. The fund financial statements are used to report additional detailed information about the primary government not found in the government-wide statements and focus on major funds of the primary government. The GWFS are reported using the economic resources measurement focus and the full accrual basis of accounting. GWFS report information about the government as a whole without displaying individual funds or fund types. Distinctions should be made in the GWFS between the primary government and its discretely presented component units, as well as between governmental activities and business-type activities. Fiduciary activities are not included in the GWFS. GWFS include: The Government-wide Financial Statements and Fund Financial Statements have a different measurement focus and basis of accounting. To help the user understand and assess the relationship between fund-based and government-wide financial statements, local governments will be required to present a summary reconciliationthat will show the interplay between the two types of statements. Balance sheet - The basic statement of position for governmental funds reports the difference between assets and liabilities as fund balance. Fund balance is divided into reserved and unreserved components. This is the same statement that is contained in the AUD and ST3. Statement of revenues, expenditures and changes in fund balance-The basic statement of activities for governmental funds reports revenues by source and expenditures by function just as they are currently reported. Since long-term liabilities and capital assets have been incorporated into the government-wide statements the accounts groups will no longer be reported in the statements. A revised supplemental schedule will be included in the AUD and ST3 to continue to accumulate this information. Statement of net assets- The basic statement of position for proprietary funds reports the difference between assets and liabilities as net assets. Net assets are divided into invested in capital assets, restricted and unrestricted.Statement of revenues, expenses and changes in fund net assets- The basic statement of activities for proprietary funds distinguishes operating and non-operating revenues and expenses.Statement of cash flows - This statement will now be required to be prepared on the direct method where operating cash flows will be reported by source. This is not a change for local governments since OSC has already required this method. Solution For governments that implement GASB Statement No. 34, the fund financial statements will accompany Management\'s Discussion and Analysis and the government-wide statements. The fund financial statements are used to report additional detailed information about the primary government not found in the government-wide statement.
For governments that implement GASB Statement No. 34, the fund finan.pdf
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anujmkt
Ethical theories are often divided into three types - 1) Consequentiolist Theories - 2) Non - Consequentialist Approach - 3) Agent - Centered Theories - Solution Ethical theories are often divided into three types - 1) Consequentiolist Theories - 2) Non - Consequentialist Approach - 3) Agent - Centered Theories -.
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D. The International Organization on Computer Evidence (IOCE) was appointed to draw up international principles for the procedures relating to digital evidence. The goal was to harmonize methods and practices among nations and guarantee the capability to use digital evidence collected by one state in the courts of another state. Solution D. The International Organization on Computer Evidence (IOCE) was appointed to draw up international principles for the procedures relating to digital evidence. The goal was to harmonize methods and practices among nations and guarantee the capability to use digital evidence collected by one state in the courts of another state..
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It is used
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