1) Convert angstroms to cm: 4.09 angstroms x 10-8 cm/1 angstrom = 4.09 x 10-8 cm 2) Determine the volume of the unit cube: (4.09 x 10-8 cm)^3 = 6.842 10-23 cm3 3) Determine the mass of the metal in the unit cube: 10.5 g/cm3 times 6.842 x 10-23 cm3 = 7.184 x 10-22 g 4) Determine atomic weight (based on 4 atoms per unit cell): 7.184 x 10-22 g is to 4 atoms as x grams is to 6.022 x 1023 atoms. To find x, you just have to do cross multiplication. x = 108.16 g/mol, so the element is Ag Hope this helps! :-) Solution 1) Convert angstroms to cm: 4.09 angstroms x 10-8 cm/1 angstrom = 4.09 x 10-8 cm 2) Determine the volume of the unit cube: (4.09 x 10-8 cm)^3 = 6.842 10-23 cm3 3) Determine the mass of the metal in the unit cube: 10.5 g/cm3 times 6.842 x 10-23 cm3 = 7.184 x 10-22 g 4) Determine atomic weight (based on 4 atoms per unit cell): 7.184 x 10-22 g is to 4 atoms as x grams is to 6.022 x 1023 atoms. To find x, you just have to do cross multiplication. x = 108.16 g/mol, so the element is Ag Hope this helps! :-).