K1+ + CrO42- + Ag1+NO31- Now lets go through the solubility rules and cross out everythingsoluble: K1+ + CrO42- +Ag1+NO31- Group 1A metals are always soluble (Rule 1) Compounds of NO31- are always soluble (Rule2) So we are left with Ag1+ andCrO42- to react with each other asfollows: 2Ag1+(aq) +CrO42-(aq) ----->Ag2CrO4(s) Solution K1+ + CrO42- + Ag1+NO31- Now lets go through the solubility rules and cross out everythingsoluble: K1+ + CrO42- +Ag1+NO31- Group 1A metals are always soluble (Rule 1) Compounds of NO31- are always soluble (Rule2) So we are left with Ag1+ andCrO42- to react with each other asfollows: 2Ag1+(aq) +CrO42-(aq) ----->Ag2CrO4(s).