M2X3 -----> 2M+ + 3X- Convert to molarity 2.1 x 10^-17grams/L *1mol/320g = 6.563 x 10^-20 M There is a 1:2 ratio for M2X3 and 2M+ So twice the amount of concentration will form 6.563 x 10^-20 * 2= 1.31 x 10^-19M There is a 1:3 ratio for M2X3 and 3X- So 6.563 x 10^-20 *3 = 1.96 x 10^-19 Ksp = [M+]^2*[X-]^3 = (1.31x10^-19)^2(1.96x10^-19)^3 = 1.31 x 10^-94. The very small # makes sense. Hope this helped Solution M2X3 -----> 2M+ + 3X- Convert to molarity 2.1 x 10^-17grams/L *1mol/320g = 6.563 x 10^-20 M There is a 1:2 ratio for M2X3 and 2M+ So twice the amount of concentration will form 6.563 x 10^-20 * 2= 1.31 x 10^-19M There is a 1:3 ratio for M2X3 and 3X- So 6.563 x 10^-20 *3 = 1.96 x 10^-19 Ksp = [M+]^2*[X-]^3 = (1.31x10^-19)^2(1.96x10^-19)^3 = 1.31 x 10^-94. The very small # makes sense. Hope this helped.