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The answer to this question is (E) If you look at N2, you can see that as 2 moles of N2 is formed 4 moles of NH3 is reacting. Thus, since the rate of formation of N2 is 2.0 mol/(L*s), the rate of formation of NH3 is double that (2*2.0mol/(L*s))=4.0 mol/(L*s). I hope this helped! Solution The answer to this question is (E) If you look at N2, you can see that as 2 moles of N2 is formed 4 moles of NH3 is reacting. Thus, since the rate of formation of N2 is 2.0 mol/(L*s), the rate of formation of NH3 is double that (2*2.0mol/(L*s))=4.0 mol/(L*s). I hope this helped!.

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The answer to this question is (E) If you look at N2, you can see that as 2 moles of N2 is formed 4 moles of NH3 is reacting. Thus, since the rate of formation of N2 is 2.0 mol/(L*s), the rate of formation of NH3 is double that (2*2.0mol/(L*s))=4.0 mol/(L*s). I hope this helped! Solution The answer to this question is (E) If you look at N2, you can see that as 2 moles of N2 is formed 4 moles of NH3 is reacting. Thus, since the rate of formation of N2 is 2.0 mol/(L*s), the rate of formation of NH3 is double that (2*2.0mol/(L*s))=4.0 mol/(L*s). I hope this helped!

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The answer to this question is (E) If you look at.pdf

  • 1. The answer to this question is (E) If you look at N2, you can see that as 2 moles of N2 is formed 4 moles of NH3 is reacting. Thus, since the rate of formation of N2 is 2.0 mol/(L*s), the rate of formation of NH3 is double that (2*2.0mol/(L*s))=4.0 mol/(L*s). I hope this helped! Solution The answer to this question is (E) If you look at N2, you can see that as 2 moles of N2 is formed 4 moles of NH3 is reacting. Thus, since the rate of formation of N2 is 2.0 mol/(L*s), the rate of formation of NH3 is double that (2*2.0mol/(L*s))=4.0 mol/(L*s). I hope this helped!