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A TASTE OF 
MATHEMATICS
Dedicated to my 
friends
PAIRS OF EQUATIONS 
Education is what remains when one has forgotten 
everything learnt in school. 
- Albert Einstein 
Perfect numbers like perfect men are rare. 
- Rene Des Cartes 
INTRODUCTION 
An equation is a statement formed by taking two 
algebraic expressions equal. 
eg: If expressions 4x-y and 2x+y are equal in value ie, 
4x-y = 2x+y 
then the algebraic statement 4x-y = 2x+y is called an 
equation. The equation 4x-y = 2x+y consists of two 
variables (unknowns) x and y such that each variables 
used is of the first degree ( ie, power of each variable is 
one)
Mental math and letter math 
Let’s start with a problem which do can do in your head: 
Three books of same price and a pen for five rupees 
were bought for thirty five rupees. What is the price 
of one book? 
We can quickly see that the price of the three books is 
thirty rupees and so the price of each is ten rupees, right? 
Look at this problem: 
Four chairs of the same price and a table for 3150 
rupees were bought for 4950 rupees. What is the 
price of a chair? 
Here also we can mentally work out the steps; but for the 
actual computation we need pen and paper, right? 
Price of four chairs = 4950-3150 = Rs. 1800 
Price of one chair = 1800/4 = Rs. 450 
Now another problem 
 The perimeter of a rectangle is 20 centimetres; and 
its length is 2 centimetres more than the breadth. 
What is the length of each side?
Here, it is more convenient to use algebra (you can also 
try otherwise). If we denote the breadth of the rectangle 
by x, then using the given facts, we get 
2 x + 2 = 10 
and from this we find 
x = 4 
thus the breadth is 4 centimeters and length is 6 
centimeters. 
 In a box, there are black and white beads. The 
number of black beads is eight more than the number 
of white beads; and the total number of beads is four 
times the number of white beads. How many black 
and how many white beads are there in the box? 
Here we have to use algebra. If we denote the number of 
white beads as x, then using all the given facts, we can 
form the equations 
X+ (x+8) = 4x 
( do it!). From this we can find 
2x = 8 
and then 
x = 4
thus the number o f white beads is 4 and the number of 
black beads is 12 
Now try the problems below on your own. 
Exercise 
1. When five pens were bought together , the total price 
was reduced by three rupees and only seventeen 
rupees had to paid. Had they been bought one by one, 
how much would have been the price of each pen? 
2. Four added to half of a number gives hundred. What 
is the number? 
3. Two persons divide hundred rupees between them 
and one got ten rupees more than the other. How 
much did each get? 
4. A hundred rupees note was changed to ten rupee 
notes and twenty rupee notes, eight notes in all. How 
many tens and how many twenties? 
5. Raji’s age is three times that of her brother Rajan. 
After two years, Raji’s age would be two times that 
of Rajan. How old are they now?
Answers 
1. 4 
2. 192 
3. 45 and 55 
4. Ten rupee notes = 6 and Twenty rupee notes =2 
5. Rajan’s age = 2 and Raji’s age = 6

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Pairs of equations

  • 1. A TASTE OF MATHEMATICS
  • 2. Dedicated to my friends
  • 3. PAIRS OF EQUATIONS Education is what remains when one has forgotten everything learnt in school. - Albert Einstein Perfect numbers like perfect men are rare. - Rene Des Cartes INTRODUCTION An equation is a statement formed by taking two algebraic expressions equal. eg: If expressions 4x-y and 2x+y are equal in value ie, 4x-y = 2x+y then the algebraic statement 4x-y = 2x+y is called an equation. The equation 4x-y = 2x+y consists of two variables (unknowns) x and y such that each variables used is of the first degree ( ie, power of each variable is one)
  • 4. Mental math and letter math Let’s start with a problem which do can do in your head: Three books of same price and a pen for five rupees were bought for thirty five rupees. What is the price of one book? We can quickly see that the price of the three books is thirty rupees and so the price of each is ten rupees, right? Look at this problem: Four chairs of the same price and a table for 3150 rupees were bought for 4950 rupees. What is the price of a chair? Here also we can mentally work out the steps; but for the actual computation we need pen and paper, right? Price of four chairs = 4950-3150 = Rs. 1800 Price of one chair = 1800/4 = Rs. 450 Now another problem  The perimeter of a rectangle is 20 centimetres; and its length is 2 centimetres more than the breadth. What is the length of each side?
  • 5. Here, it is more convenient to use algebra (you can also try otherwise). If we denote the breadth of the rectangle by x, then using the given facts, we get 2 x + 2 = 10 and from this we find x = 4 thus the breadth is 4 centimeters and length is 6 centimeters.  In a box, there are black and white beads. The number of black beads is eight more than the number of white beads; and the total number of beads is four times the number of white beads. How many black and how many white beads are there in the box? Here we have to use algebra. If we denote the number of white beads as x, then using all the given facts, we can form the equations X+ (x+8) = 4x ( do it!). From this we can find 2x = 8 and then x = 4
  • 6. thus the number o f white beads is 4 and the number of black beads is 12 Now try the problems below on your own. Exercise 1. When five pens were bought together , the total price was reduced by three rupees and only seventeen rupees had to paid. Had they been bought one by one, how much would have been the price of each pen? 2. Four added to half of a number gives hundred. What is the number? 3. Two persons divide hundred rupees between them and one got ten rupees more than the other. How much did each get? 4. A hundred rupees note was changed to ten rupee notes and twenty rupee notes, eight notes in all. How many tens and how many twenties? 5. Raji’s age is three times that of her brother Rajan. After two years, Raji’s age would be two times that of Rajan. How old are they now?
  • 7. Answers 1. 4 2. 192 3. 45 and 55 4. Ten rupee notes = 6 and Twenty rupee notes =2 5. Rajan’s age = 2 and Raji’s age = 6