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A is the answer, because B and C is still has a double bond that is .pdf

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A is the answer, because B and C is still has a double bond that is not trans which would have been reduced by the h2 pdc, C is not optically active I checked, and D only has 7 carbons Solution A is the answer, because B and C is still has a double bond that is not trans which would have been reduced by the h2 pdc, C is not optically active I checked, and D only has 7 carbons.

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A is the answer, because B and C is still has a double bond that is not trans which would have been reduced by the h2 pdc, C is not optically active I checked, and D only has 7 carbons Solution A is the answer, because B and C is still has a double bond that is not trans which would have been reduced by the h2 pdc, C is not optically active I checked, and D only has 7 carbons

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A is the answer, because B and C is still has a double bond that is .pdf

  • 1. A is the answer, because B and C is still has a double bond that is not trans which would have been reduced by the h2 pdc, C is not optically active I checked, and D only has 7 carbons Solution A is the answer, because B and C is still has a double bond that is not trans which would have been reduced by the h2 pdc, C is not optically active I checked, and D only has 7 carbons