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Epidemiology
Causation and Causal Inference
Dr. Amita Kashyap
Sr. Prof. Community Medicine
S.M.S. Med. College, Jaipur
Concept of Sufficient Cause and
Component Causes
ā€¢ Need to define ā€œcauseā€ ā€“ if we define cause as
an antecedent event, condition or
characteristic that was necessary for the
occurrence of the disease at the moment it
occurred, given that other conditions are
fixedā€¦ā€¦
ā€¢ This definition provides only a component of a
complete causal mechanism
General Model of Causation
ā€¢ We begin life as a pragmatic philosopher,
developing a general causal theory; that some
events or states of Nature are causes having
specific effects.
ā€¢ Though rudimentary it suggests that we are
equipped with curiosity to understand, by logic,
doubt, speculation, and developing methods to
prove (experiments)
ā€¢ ? - a working knowledge of the essential
system of causal relations that enables each of
us to navigate our complex world
A ā€œSufficient Causeā€
ā€¢ A ā€œSufficient Causeā€, a complete causal mechanism ā€“
a set of minimal conditions and events that
inevitably produce disease.
ā€¢ Minimal ā€“ implies that all conditions are necessary
Ex. ā€“ Tobacco smoking and Lung cancer
ā€¢ Not all smokers get lung cancer- there are certain
individuals primed by certain unknown conditions
and just adding smoking causes lung cancer. Eg
asbestos exposure
ā€¢ ? Heavy smokers have approx. a 10% lifetime risk
developing lug cancer
U
U U
A
A B B E
E
Three Sufficient Causes of a Disease ā€“ each constellation
(I, II, and III) of component causes is sufficient to produce
the disease
Strength of Effect
II
I I III
The condition under which ā€˜Eā€™ acts as ā€œnecessary and sufficient causeā€
= ā€œpresence of A or B but not bothā€
Exposure to
component causes
Response Frequency of Exposure
(combination) 1000 each
A B E Outcome Pop. 1 Pop. 2
1 1 1 1 100 900
1 1 0 1 100 900
1 0 1 1 900 100
1 0 0 0 900 100
0 1 1 1 900 100
0 1 0 0 900 100
0 0 1 0 100 900
0 0 0 0 100 900
Exposure frequencies for three component causes
in two hypothetical populations 1 and 2
B=1, E = 1
B=1, E=0
B=0, E=1
B=0, E=0
Assumption: disease is a non recurrent event, such as death or first occurrence of disease
1 = present; 0 = absent for exposure and Response
The Proportion getting Disease = Numbers getting exposure pattern X response
B = 1, E = 1 B = 1, E = 0 B = 0, E = 1 B = 0, E = 0
CASES 1000 100 900 0
TOTAL 1000 1000 1000 1000
Proportion 1.00 0.10 0.9 0.0
Incidence proportion for combo of ā€œB and Eā€ in Population 1
Incidence proportion for combo of ā€œB and Eā€ in Population 2
B = 1, E = 1 B = 1, E = 0 B = 0, E = 1 B = 0, E = 0
CASES 1000 900 100 0
TOTAL 1000 1000 1000 1000
Proportion 1.00 0.9 0.10 0.00
Why ā€œEā€ is much stronger determinant in Population 1 ?
Interaction among Causes
ā€¢ Two component causes acting in the same
ā€˜sufficient causeā€™ may be thought of as
interacting biologically to produce disease
ā€¢ This need not to be ā€˜simultaneousā€™ ā€“ e.g. head
injury leading to Hip fracture??
ā€¢ The extent or apparent strength of biologic
interaction between two factors is dependent
on the prevalence of some other factors
A
B
C D
E
A
B
F G
H
I II III
C
A
F I
J
Proportion of Disease due to
sufficient cause
ā€¢ What fraction of disease is caused by ā€˜Uā€™ if these are
the only sufficient causes to cause a specific disease ?
ā€¢ The answer is all of it, bcz without ā€˜Uā€™ there is no
disease, itā€™s a ā€˜necessary causeā€™.
U U
A B E
E
U
A B
I II III
Induction Period ā€“ specific cause-effect
pair; not just the effect
ā€¢ If in ā€˜Sufficient Causeā€™ I, the sequence of action of the causes is ā€“ A,B,C,D,
and E and we want to study the effect of B (which acts at some narrowly
defined time)
ā€¢ Disease occurs only after the sequence is completed
ā€¢ The interval btw the action of B and the disease occurrence is the
induction period for the effect of B
A
B
C D
E
ā€˜Sufficient Causeā€™ I
Factor B
Disease
Initiation
Disease
occurrence
Disease
Detection
Induction Period
Latent Period Period
We can reduce ā€˜Latent Periodā€™ by improved methods of
disease detection BUT not the induction period as it ends
with disease occurrence.
!! ā€“ Role of Biomarkers (attempt to focus on causes
more proximal to the Disease occurrence)
Philosophy of Scientific Inference
ā€¢ Inductivism : making generalizations;
observations induce the formulation of a natural
law in scientistā€™s mind e.g. observation of lack of
smallpox in milkmaids induced in Jennerā€™s mind
the theory that cowpox confers immunity
against smallpox.
ā€¢ Based on ā€˜assumptionā€™; there is no logic or force
of necessity
ā€¢ Logical Fallacy; (after this therefore on account
of this!!!)
Philosophy of Scientific Inference
ā€¢ Refutationism :
process of elimination- conjecture and
refutation (no matter how many times we boil
water in an open flask and get boiling point as
100ļ‚°C; we cannot prove that waterā€™s boiling
point is 100ļ‚°C. but one attempt to boil water
in a closed flask or at higher altitude will
refute the preposition that water always boil
at 100ļ‚°C )
ā€¢ Since it is possible for any observation to be
consistent with many hypotheses that
themselves may be mutually in-consistent;
consistency btw an observation and
hypothesis is no proof of hypothesis
ā€¢ In contrast, a valid observation that is
inconsistent with an hypothesis refutes it- if
you wring the neck of the rooster before
sunrise; you have disproved that roosterā€™s
crowing is a necessary cause for sunrise
Bayesianism
ā€¢ In classic logic, premises of the deductive
argument need to be 100% truth e.g. ā€œif A
implies B, and B is false, then A must be falseā€
ā€¢ The conclusion from this argument ā€œA must be
falseā€ will be valid only when assumptions - ā€˜A
implies Bā€™, and ā€˜B is falseā€™ are true statements
ā€¢ All observation about physical world are
subject to some error
ā€¢ If we can assign some prior probability to our
statements we can use laws of probability to
derive certainty to the conclusion
ā€¢ Bayesian philosophy provides a methodology
for sound reasoning and, in particular,
provides many warnings against being overly
certain about ones conclusions
ā€¢ Such warnings are echoed in Refutationist
philosophy : the intensity of the conviction
that a hypothesis is true has no bearing on
whether it is true or not
ā€¢ Most epidemiologists prefer Interval
Estimates
Consensus
ā€¢ The ultimate goal of scientific inference is to
capture some objective truths about the
material world
ā€¢ We may know a theory is false bcz it
consistently fails the tests we put it through
BUT we cannot know that it is true, even if it
passes every test we can devise, for it may fail
a test yet un-devised
ā€¢ Hence any theory of inference should ideally
be evaluated by how well it leads us to detect
errors in our hypothesis and observation
Consensus
ā€¢ When confronted with a refuting observation,
a scientist faces the choice of rejecting either
the validity of the theory or its scientific
infrastructure
ā€¢ Observations that are falsifying instances of
theories may be treated as ā€œanomaliesā€,
tolerated without falsifying the theory in hope
of future explanations, e.g. observation that
shallow-inhaling smokers had higher lung
cancer rates than deep-inhaling smokers!
Causal inference in Epidemiology
ā€¢ Epidemiologic hypothesis usually are based on
vague assumptions lacking biologic knowledge
e.g. ā€œsmoking causes CVDsā€
ā€¢ To cope with this vagueness, epidemiologists
usually focus on negation of causal
hypothesis, the Null Hypothesis that exposure
does not have causal relation
ā€¢ Then, any observed association can potentially
refute the hypothesis (ensuring no biases
present)
ā€¢ Testing Competing Epidemiologic Theories
Causal Criteria
ā€¢ Since there can not be a set of sufficient
criteria, a list of causal criteria (proposed by
Bradfor Hill 1965) provide road map through
complicated territory
ā€¢ He suggested some aspects of association to
be considered in attempting to distinguish
causal from non-causal associationā€¦ā€¦
Causal Criteria
1. Strength
2. Consistency
3. Specificity
4. Temporality
5. Biologic gradient
6. Plausibility
7. Coherence
8. Experimental evidence
9. Analogy
Hillā€™s verdict ā€“ none of my nine viewpoints can bring
indisputable evidence for or against the cause and
effect hypothesis.
Conclusion
ā€¢ Science advances by a process of
elimination; ā€œconjecture and refutationā€
ā€¢ Alternative hypothesis
ā€¢ Evaluating competent causal theories
using crucial observations
A Patientā€™S Profile:
ā€¢ A 60 year old previously healthy female, research
chemist recently developed shortness of breadth and
nosebleeds.
ā€¢ Pale, pulse 110/ min, low (20%) hematocrit, elevated
(20000/ļ­l) leukocyte counts, low platelet (15000/ļ­l)
with PBF showing atypical myeloblasts
ā€¢ Hospitalized for Suspected acute myelogenous
leukemia; confirmed by bone marrow aspirate and
biopsy.
ā€¢ Chemotherapy started, about 3 weeks later, her temp.
abruptly rose to 39ļ‚°C and neutrophil count dropped to
100 /ļ­l.
ā€¢ No source of apparent infection;
Patient Profileā€¦ctd:
ā€¢ Importance of Risk assessment!!
ā€¢ How likely is it that patient has a bacterial
infection?
ā€¢ Her blood and urine cultures were taken, and
broad spectrum antibiotics administered (empiric
treatment)
ā€¢ Potential Risk of complications from delayed
antibiotic outweighed empiric use of antibiotic
ā€¢ Cultures confirmed staphylococcus aureus in blood
Measures of Disease Occurrence
Epidemiologic measures - to assess
outcomes and thereby guide decisions
ā€¢ Risk (the likelihood that a person will
contract a disease)
ā€¢ Prevalence (Load; the amount of disease
already present in the population)
ā€¢ Incidence Rate (how fast is the new
occurrence of disease)
Defined
Population
Have
Disease
Do not
have
disease
Do not have
disease at
baseline
PAR
Prevalent
cases
1. Identify
Population
3. Follow
only those
who did not
have the dis.
2. Determine
who has the Dis.
& who doesnā€™t
Do not have
disease at
baseline
Develop Dis.
Do not have
disease
Follow up for 1 year
incident
cases
Risk (cumulative incidence)
ā€¢ It is a measure of the occurrence of new cases
ā€¢ i.e. Proportion of unaffected persons (PAR) in
the population who, will contract the disease
over a specified period of time
New cases
Person at Risk
R =
ā€¢ Has no unit;
ā€¢ lies between 0 and 1
onset end
A
B
C
D
E
F
Hypothetical study of group of six subjects
1995 96 97 98 99 00 01 02 03 04
Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death
97 02
99
97
99 02
Dx,,,,,,,,,,,,,,,,,,,,,,,
97
02
What is the Risk of Dis. development within 2 years of enrolment
New cases
R =
Person at risk
= 1/6 = 0.17 OR 17%
Example of HAI in cancer patients
ā€¢ Estimate a cancer patientā€™s risk of getting HAI
from a study of 5031 patients admitted in
comprehensive cancer centre.
ā€¢ If 596 patients met criteria for Hosp. Acquired
infection
ā€¢ Risk period? - Starts 48 hrs after hospitalization
and ends 48 hrs after discharge.
New cases
R =
Person at risk
= 596/5031 = 0.12 OR 12%
ā€¢ Can we apply this risk to our patient?
ā€¢ More likelihood of infection for our patient
can come from studies on similar
subjectsā€¦having fever, and low granulocyte
countā€¦.
ā€¢ Now if 1022 such cancer patients were studied
and 530 had HAI then the Risk is 530/1022 =
0.52 i.e. 52%
Measures of Disease Occurrence ctdā€¦
ā€¢ Prevalence (Burden of Disease)ā€“
indicates number of existing cases of a disease in a
population at a time.
ā€¢ E.g. An important question in deciding antibiotic
use to the patient is the type and magnitude of
infection anticipated!!
ā€¢ We know that individuals with low neutrophil
count are susceptible to wide variety of infectionsā€¦
ā€“ S.aureus was cultured from 62 out of 96 patientā€™s
specimens
ā€¢ Prev. of S.aureus infection = 62/ 96 = 0.65 i.e. 65%
onset end
A
B
C
D
E
F
Hypothetical study of group of six subjects
1995 96 97 98 99 00 01 02 03 04
Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death
97 02
99
97
99 02
Dx,,,,,,,,,,,,,,,,,,,,,,,
97
02
What is the Prevalence of Disease in 2001
Total cases
p =
Total population
= 1/4 = 0.25 OR 25%
B
ā€¦.left
Measures of Disease Occurrence
ctdā€¦
ā€¢ Incidence Rate ā€“ measures the rapidity with
which new cases of the disease develop.
ā€¢ Estimated by observing a population and
counting the number of new cases over Net
Time (person years) i.e.
ā€¢ Incidence Rate = New cases/ person time
ā€¢ A subject at risk of disease followed for 1 yr, or
5 yrs contributes 1 or 5 person-years of
observation respectively.
onset end
A
B
C
D
E
F
Hypothetical study of group of six subjects
0 1 2 3 4 5 6 7 8 9
Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death
97 02
99
97
99 02
Dx,,,,,,,,,,,,,,,,,,,,,,,,
,,,,,,
97
02
How many person years are contributed by A, B, C, D E and F?
04
Total new cases
IR=
Total person years
= 2/22 = 0.09 cases /person years
i.e. 9 cases/ 100 person-yrs
04
04
98
Observation years
95
Example of HAI ctdā€¦
ā€¢ Those 5031 remained under observation for a
total of 127859 patient days
ā€¢ What is the average length of stay?
ā€¢ Since 596 patients developed HAI the IR would
be ā€“ 596/ 127263= 0.00468 cases/ patient days
ā€¢ Can be expressed for better readability as 4.7
cases/ 1000 patient days
ā€¢ Interpretation: among patients similar to those
studied, on average, about 0.47% patient/day
would be expected to develop a HAI
127859/5031
= 25.41
Calculation of IR for a Large Pop.
ā€¢ Calculating person-years (PT) for each individual
would be too cumbersome! Alternatively
ā€¢ PT = (Av. Size of PAR) X (Length of observation)
ā€¢ In many instances, relatively few people develop
the disease and there is no other demographic
shift hence whole Pop. Can be taken as At
Riskā€¦i.e. not excluding patients
ā€¢ PT = (Size of entire Pop.) X (Length of observation)
ā€¢ 596/127859=0.00466 while 596/127263=0.00468 !!!
Calculation of IR for a Large Pop.
ā€¢ If there are an estimated 1,91,85,836 women in
an area btw 1996 and 2000 (5 yrs period) and
2957 women were newly diagnosed with Acute
myelocytic leukimia (AML)
ā€¢ What is the annual incidence rate of AML ?
ā€¢ 1,91,85,836 women x 5 Yrs = 9,59,29,180 WY
ā€¢ IR = 2957 new cases/ 9,59,29,180 Wyrs =
3.1cases /1,00,000 WY
Characteristic Risk Prevalence Incidence Rate
What is
measured
Probability of
Disease
Proportion of
Pop. With
disease
Rapidity of
Disease
Occurrence
Units None None Cases/ person-
time
Time of disease
Dx
Newly
diagnosed
Existing cases Newly
diagnosed
Synonyms Cumulative
Incidence
- Incidence
Density
Characteristics of Risk, Prevalence & Incidence Rate
In our Hypothetical Ex. In 2001 Prev. was 25%,
2 Yr. Risk was 17% and the IR was 9cases/ 100 yrs
Problems with Incidence and
Prevalence Measurements
ā€¢ Problems with Enumerator
ā€“ The first problem is defining who has the disease.
ā€“ The next issue is Method of data collection ā€“
interview, self reporting , surveyā€¦ associated biases!!
ā€¢ Problems with Denominators
ā€“ everyone in the group represented by the
denominator must have the potential to enter the
group that is represented by the numeratorā€¦
PAR concept
ā€¢ Problems with Hospital Data
Relationship Between Incidence
and Prevalence
ā€¢ There is an important relationship between
incidence and prevalence: in a steady-state
situation, in which the rates are not changing
and in-migration equals out-migration, the
following equation applies:
ā€¢ Prevalence = Incidence Ɨ Duration of disease
Example
ā€¢ 2,000 persons are screened for tuberculosis,
Using chest x-rays: 1,000 are upper-income
(HIG) individuals and 1,000 are lower-income
(LIG) individuals.
ā€¢ X-ray findings are positive in 100 of the HIG
and in 60 of the LIG.
ā€¢ Can we therefore conclude that the risk of
tuberculosis is higher in HIG people than in
LIG people?
Screened
Population
Point Prev./
1000
Incidence
(Occurrences
/yr)
Duration
(yrs)
Hitown 100 4 25
Lotown 60 20 3
Prevalence = Incidence Ɨ Duration
20 30 40 50 60 70 80
0
100
200
300
400
20%
15%
10%
5%
0%
Annual
Rate/
100000
Percent
of
total
cases
Breast cancer incidence rates and distribution of cases by age
Age in yrs
The incidence is increasing so dramatically with
age, why are only fewer than 5% of the cases
occurring in the oldest age group of women?
Incidence increasing but prevalence
decreasing ā€“ How?
46
0
5
10
15
20
25
30
35
40
1
9
9
0
1
9
9
3
1
9
9
6
1
9
9
9
Prevalence
Incidence
Fatal, Or short duration
Incidence stable but prevalence
increasing indicates:-
47
0
5
10
15
20
25
30
35
40
45
1
9
9
0
1
9
9
3
1
9
9
6
1
9
9
9
Prevalence
Incidence
New Program or
Better Dx Test !!!
ā€¢Death is prevented
and Dis is not cured
ā€¢ Diagnosed more
ā€¢Immigration of cases
Incidence maintained but prevalence
declining means:-
48
0
5
10
15
20
25
30
35
1
9
9
0
1
9
9
2
1
9
9
4
1
9
9
6
1
9
9
8
incidence
prevalence
New effective drug!
Or Dis. Became more
Virulent/ fatal,
Emigration of cases
Incidence Rate:Expressed as-
Morbidity rate-
New cases total population at risk
Mortality rate-
No. Of deaths due to a disease/ total population
Case fatality rate-
No. Of deaths due to a disease/ total no. Of cases of that disease
Attack rate-
No. Of new cases of a disease, during a specified time/ total
population at risk for the same time
Secondary Attack Rate- No. of exposed persons developing disease
within the Range of ā€œIPā€ following exposure to a Primary Case.
Survival
ā€¢ Probability of being alive for a specific length of
time
ā€¢ For a Ch. Dis. Like cancer, 1 and 5 Yr survival
rates are often used as indicator of the severity
of the disease and the prognosis.
ā€¢ E.g. if 5-Yr survival for AML is 0.19, it means that
only 19% of patients with AML survive at least 5-
Yrs after diagnosis
ā€¢ Survival = Newly Dx Pts. ā€“ Deaths/ Newly Dx Pts.
For a specified time
Dx onset end
A
B
C
D
E
F
Hypothetical study of group of six subjects
0 1 2 3 4 5
Observation years
Patients
Censored
Death
Censored
Death
What is the 2 year survival rate?
2 year survival rate = 5/6 = 0.83 i.e. 83%
What is the 2 year Risk of Death?
2 year Risk of Death = 1/6 = 0.17 i.e. 17%
5 yr S If we assume B & E survive all 5 yrs = 4/6= 0.67=67% !
5 yr S If we assume B & E didnā€™t survive all 5 yrs = 2/6= 0.33=33% ! !
Methods to account for censored cases
ā€¢ Life Table analysis
ā€¢ Kaplan-Meier analysis AND Graphs
0 1 2 3 4 5
20
40
60
80
100
0
Survivors
Percent
Years since Dx
47%
68%
58%
? Median Survival Time
50
Case Fatality
ā€¢ The propensity of a disease to cause Death
ā€¢ If N = 15 and 5 of whom develop disease of
concern , then Risk = 5/15= 0.33 = 33%
ā€¢ If only 2 of the affected die CF = 2/5 = 0.40 = 40%
ā€¢ Survival = incident cases ā€“ death /total affected
ā€¢ = 5-3 / 5 = 3/5 = 0.6 = 60% i.e. 100 ā€“ CF = Survival
Number of Deaths
CF =
No. of Dx Cases
New cases
R =
Person at risk
onset end
A
B
C
D
E
F
Hypothetical study of group of six subjects
0 1 2 3 4 5 6 7 8 9
Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death
97 02
99
97
99 02
Dx,,,,,,,,,,,,,,,,,,,,,,,,
,,,,,,
97
02
How many person years are contributed by A, B, C, D E and F?
04
Total new cases
IR=
Total person years
= 2/22 = 0.09 cases /person years
i.e. 9 cases/ 100 person-yrs
04
04
98
Observation years
95
2 person yrs
2 person yrs
2 person yrs
3person yrs
7 person yrs
6 person yrs
Comparing disease occurrence
(in groups with different exposures )
ā€¢ To calculate the Risk that a health effect will
result from an exposure
ā€¢ Risk Difference (Excess Risk)- expressed as:-
Incidence in exposed - Incidence in un-exposed
Smoking category Stroke cases Person yrs of
observation
Stroke IR/ 100000
Person yrs
Never smoked 70 3,95,594 17.7
Ex-smoker 65 2,32,712 27.9
Smoker 139 2,80,141 49.6
total 274 9,08,447 30.2
= 49.6 ā€“ 17.7 = 39.1/ 100,000 person yrs
Comparing disease occurrence
(in groups with different exposures )
ā€¢ Attributable Fraction (exposed) ā€“ proportion
of cases that can be attributed to exposure
Incidence in exposed - Incidence in un-exposed
/ Incidence in exposed = (49.6 ā€“ 17.7/ 49.6) X 100
= 64%
Indicating 64% Risk Reduction if exposure is
removed
ā€¢ Population Attributable Risk ā€“
determine relative importance of
exposure for entire population
= incidence in total population ā€“
incidence among un-exposed / incidence
in total population
ā€¢ Relative Risk ā€“
ratio of the risk of occurrence of
disease among exposed people to that
among un-exposed people (baseline
level of exposure) e.g.
(in our Ex. = 49.6/17.7 = 2.8)
ā€¢ Good indicator of strength of
association because it is expressed
relative to baseline level of exposure
Measures of Mortality:
ā€¢ Mortality rate
ā€“Crude death rate
ā€“Cause specific death rate
ā€“Age specific death rate
ā€¢ Case-fatality rate
ā€¢ Proportionate mortality rate
ā€¢ Standardized Mortality Rates
Adjusted Rates: Standardization
ā€¢ Standardization:
ā€“ The process to derive a summary figure to
compare health outcomes of groups
ā€“The process can be used for mortality,
natality, or morbidity data, race
ā€¢ Standardization Methods
ā€“Direct
ā€“Indirect
Example: Age-Adjustment
A. Direct Method: requires ā€“
1. Age-specific rates in the sample population
a) The age of each case
b)The population-at-risk for each age group
in the sample
2. Age structure of a standard population
Summary figure is an Age-adjusted rate
Direct Age Adjustment
Population 1 Population 2
Population No. of
Deaths
Death
rate/
100000
Population No. of
Deaths
Death
rate/
100000
900000 862 96 900000 1130 126
Standard Population can be taken from outside or
both population can be clubbed to get Standard Population
Direct Age Adjustment:
Comparison of Age specific death rates
Population 1 Population 2
Age
Gr.
popula
tion
No. of
Deaths
Death
Rate/
100000
popula
tion
No. of
Deaths
Death
Rate/
100000
All
ages
900000 862 96 900000 1130 126
30-49 500000 60 12 300000 30 10
50-69 300000 396 132 400000 400 100
70+ 100000 406 406 200000 700 350
Direct Age Adjustment: using total of
two pop. As standard Population
Age
Group
Standard
Population
1996-2000
Age
specific
mortality
rates
Expected
no. of
deaths /
100000
2001-2005
Age
specific
mortality
rates
Expected
no. of
deaths /
100000
All Ages 1800000
30-49 800000 12 96
(8 x 12)
10 80
50-69 700000 132 924
(7 x 132)
100 700
70+ 300000 406 1218 350 1050
Total 2238 1830
2238 1830
Age adjusted Rate = ---------- X 100000 = 124.3, --------- X 100000 = 101.7
1800000 1800000
B. Indirect method: requires
1. Age structure of the sample population
2. Total deaths in the sample population
3. Age-specific rates for the standard
population
4. No need for stratum-specific rates of the
sample
Summary figure is a Standardized
Mortality ratio (SMR)
Indirect Standardization
ā€¢ Stratum specific Death rates of standard population are
applied to each stratum of the sample population to get
Expected Deaths
ā€¢ Overall DR of sample population from records gives
Observed Deaths
Observed
SMR = ----------------- X 100
Expected
SMR of 100 means no difference between the
number of outcomes in the sample population
and that which would be expected in the
standard population
Indirect Standardization (cont.)
Total expected deaths per year: 2,083
Total observed deaths per year: 1,464 (from Records)
SMR = 1,464 / 2,083 x 100 = 70.3% (30% less than expected)
Age
Group
Number people
(Census, 2001)
Standard Death
Rates per 1,000,000
(All Causes of Death)
Expected Number of
Deaths per 1,000,000
(1) (2) (3) = (1) X (2)/ 1,000,000
20-24 7,989 1,383 11
25-34 37,030 1,594 59
35-44 60,838 2,868 174
45-54 68,687 8,212 564
55-64 55,565 22,953 1,275
2,083
Patterns of occurrence
ā€¢ Distribution Patterns (TPP analysis)of a disease
within a population
ā€“ Who develops the disease? (Person)
ā€“ Where does the disease occur? (Place)
ā€“ When does the disease occur ? (Time)
ā€¢ Level (rate of occurrence)- Endemic or Epidemic
ā€¢ Causal Role - Genetic or environmental
Patient profile
ā€¢ A 30 yr old female domestic worker; recently
migrated from India to USA presented with 6 weeks
h/o cough, fever, night sweats, weakness, fatigue
and shortness of breath.
ā€¢ h/o two normal deliveries followed by Tubal ligation
ā€¢ Chest X-ray shows cavity lesions, sputum is AFB +ve
and mycobacterium grew on culture which was
sensitive to all drugs
ā€¢ Administered 4 drugs under DOTS
ā€¢ After 2 months put on 2 drugs 3 times a week
as she was asymptomatic with no bacilli in
sputum.
ā€¢ She resided in a low town apartment building,
tuberculin test was done on her husband and
two children
ā€¢ Results were +ve for her husband and 3 yr old
ā€¢ Although no active disease was found yet
prophylactic Tt was given to all three of them
ā€¢ Out of 54 neighbors; 1 was infected without any
evidence of clinical disease and received PT
ā€¢ None of the work place contacts were +ve
Environment Infectious Individual Susceptible
Individual
Close contacts of
infected, susceptible
people in close
spaces
Pulmonary or
Laryngeal disease
with bacilli in sputum
Compromised
immune system
Poor ventilation Forceful cough with
uncovered mouth
Predisposing disease
or condition e.g.
silicosis, cancer
Recirculation 0f
contaminated air
Less than 2-3 weeks
of appropriate anti-
microbial therapy
Lack of adequate
Nutrition
Injectable drug use
or heavy alcohol
intake
Factors that increase the probability of T.B. transmission
Thank You
Epidemiology
Observational
Epidemiology
Experimental
Epidemiology
Descriptive
Epidemiology
Analytical
Epidemiology
Hypothesis about disease causation
Leads to
Help explain descriptive patterns (possible causes)
And to improve Dis. Surveillance
Verified by Analytical/ Experimental Studies
How to Develop a Hypothesis?
Person
(disease do not occur at random!)
ā€¢ Variation of occurrence in relation to
personal characteristics reflects:
ā€“ differences in level of exposure to causal
factors,
ā€“susceptibility to causal factors,
ā€“or both.
ā€¢ Personal characteristics includeā€¦ā€¦.
946
1499
5286
4191
3147
0
1000
2000
3000
4000
5000
6000
up to 14 15-24 25-44 45-64 65+
cases
Age in Years
Number of T.B. cases by Age in a year...
? From where does such Data Comes
Notification of diseases!! List is updated as per
changing scenario/ needs. And Surveillance data.
Interpretation? Highest Risk in 25-44 yrs??
Surveillance
ā€¢ ā€œOngoing systematic collection, analysis,
and interpretation of data essential for-
ā€“ planning, implementation, and evaluation of
public health practice closely integrated with
the timely Feedback.ā€
ā€¢ Types - Passive or Active
ā€¢ Help to Know- Changes in either disease
rates or levels of environmental risk factors
Surveillance goals
ā€¢ Identification of patterns of disease
occurrence
ā€¢ Detecting disease outbreaks at nascent age
ā€¢ Development of clues for possible Risk
Factors
ā€¢ Anticipation of health service needs
ā€¢ Finding cases for further investigation
1.5
3.7
6.2 6.3
8.8
0
1
2
3
4
5
6
7
8
9
10
0-14 15-24 25-44 45-64 65+
incidence
per
100000
person
years
Age in Years
Incidence Rates for Reported T.B. Cases
Incidence among persons in oldest age group is
over 40% higher than that for 25-44 years group
Possible factors
Contributing
ā€¢Long latent period
ā€¢Elderly lived through
times when T.B. was
rampant (Birth Cohort
Effect)
ā€¢Other illness like DM
and Cancers more in
elderly
ā€¢Declined immunity in old
age
ā€¢More chances of living
in Closed settings
How to interpret ?
Higher incidence rate in
certain minority group!!
Gender Differences !!!
Place (spot maps!)
ā€¢ International
ā€¢ National
ā€¢ State and/ or
ā€¢ Local comparisons gives insight to probable
reasons
ā€“ Estimated 8 million people develop T.B. each year
worldwide
ā€“ 95% of these comes from developing world
ā€“ Most rapid rise of T.B. IR is in sub Saharan Africa!
Time
ā€¢ Usual rate of occurrence ā€“ endemic rate
ā€¢ A rapid and dramatic increase over the
endemic rate is - epidemic rate
ā€¢ Epidemic can develops in a matter of days
or weeks (few hrs for staphylococcal food
poisoning) but for chronic condition like
cancer it takes years to decades
ā€¢ Establishing linkages between RF and
Disease Occurrence become difficult if
there is greater time lag (latent period)
Endemic vs. Epidemic
Endemic Epidemic
No.
of
Cases
of
a
Disease
Time
Usually plot weekly
No rapid rise in incidence of T.B. but departure from decline!!
Correlation with Disease Occurrence
ā€¢ To develop hypothesis about possible
causes of disease,
ā€“ Presence of a suspected RF is measured
in different populations and compared
with incidence of disease (Ecologic Study)
ā€“Examine extent to which two
characteristics are related e.g. (RF and
disease occurrence)
Incidence rates of TB and AIDS in 15 States of USA
r = 0.91, coefficient of determination (r2) = 0.98
Regression equation = a + b*x
Tuberculosis IR = - 0.8 + 0.57 X AIDs IR
Ecologic fallacy!!
Migration studies
ā€¢ To clarify whether a disease of unknown
cause is determined principally by genetic
inheritance or environmental exposure
ā€¢ For diseases with long latent periods, it
may take years for the reduced rate of
occurrence
ā€¢ If environmental exposure early in life is
critical, then effects may be visible in
offspring's only!
Ways to interpret data and generate Hypothesis
Risk
Ratio
No Racial
Difference
Investigating An Outbreak
Dr. Amita kashyap
96
What is a Disease Outbreak?
ļ‚—Outbreak vs Epidemic
What does it Require?
ļ‚—A pathogen in sufficient quantities,
ļ‚—A mode of transmission,
ļ‚—And a pool of susceptible people
97
98
A Scenario!
A 23 yr old male student; presented at 10:30 pm
on 17th Jan 2014, at the emergency complaining
of a sudden onset of abdominal cramping,
nausea and diarrhea. He was weak, not
severely distressed, had no fever or vomiting.
A No. of other students, all with the same
symptoms, visited emergency over next 20 Hrs
All treated with Fluid replacement recovered
fully within 24 hrs. of the onset of illness.
Does it warrant an
investigation?
ā€¢ Why?
99
When should we Investigate?
ā€¢ Number and severity of persons
affected!
ā€¢ Uncertainty about cause!
ā€¢ Level of Public Concern/ Political
pressure!!
ā€¢ Potential for contributing to medical
knowledge! 100
101
Reasons for Outbreak Investigation
Quantifying the epidemic (Descriptive
epidemiology)
Getting at the source and reasons (Analytic
epidemiology)
for
Preventing others from becoming affected
Investigation in our scenario!
ļ‚¢Quick information revealed 47 students out of
1164 college enrollment got affected by 8 PM
on 18th Jan (20 Hrs)
ļ‚¢ What is the quantitative measure of the extent
of an outbreak?
No. of New Cases
AR = Persons at Risk
What is the AR for this period?
= 47/ 1164 X 100 = 4% 103
Hostel wise distribution of 47 known cases, AR,
population and sex of the occupants of each hostel
Hostel Sex PAR No. of
Cases
AR
1 F 80 19 23.8
2 F 62 2 3.2
3 F 89 0 0
4 F 61 1 1.6
5 F 53 5 9.4
6 M 35 0 0
7 M 63 0 0
8 F 103 4 3.9
9 M 35 1 2.9
10 M 37 0 0
11 F 34 1 2.9
12 M 62 13 21.0
13 M 32 1 3.1
14 M 10 0 0
Total - 756 47 6.2
Attack Rate (all students)
= 47/ 1164 X 100= 4%
Attack Rate (hostellers)
= 47/ 756X100= 6.2%
Attack Rate (hostel 1, 12)
= 19+13/ 80+62 = 22.5%
Attack Rate (other hostels)
= 15/ 614 = 2.4%
Risk Ratio = AR hostel (1, 12)
/ AR (Other hostels) X 100
= 22.5/ 2.4 = 9.4
? Sex difference in AR =
Further :
ļ‚¢Visit to hostels revealed that not all
students who became ill reported to
emergency.
ļ‚¢Needed un-baised data- henceā€¦
ļ‚¢Seven hostels were randomly selected for
information collection on desired areas! 105
Response to the questionnaire survey by hostels
Questionnaire returned
Selected
Hostel
Population Number Percent No. of ill St.
5 53 49 92.5 13
6 35 26 74.3 13
7 63 28 44.4 15
8 103 65 63.1 21
9 35 19 54.3 5
12 62 44 71.0 22
Nursesā€™ hostel 60 60 100 17
Unidentified - 13 - 4
Total 411 304 74.0 110
106
AR = 110/304 X100 = 36.2%
Note: initial hostel wise AR for Hostel 6, and 12 were 0% and 21%
As per survey data ! - AR (H6) =13/26X100=50% and AR (H12) =22/44X100 = 50%
ā€¢ AR of hostel 6 and 12 were 0% and 21% by
emergency data but by survey data both are
50% - Approach for data collection!
ā€¢ Was emergency data useless?
ā€¢ Is 36.2% the true AR of AGE on campus ?
ā€¢ Explain factors why AR estimated from
emergency records were low?
ā€¢ Why more cases from hostel 1 and 12 at
emergency?
107
Additional informationā€¦..
ā€¢ No large gathering of students..... hence inquiries were
made about meals eaten on 16th and 17th Jan
ā€¢ Most students ate at college cafeteria
ā€¢ How will you zero down to source of infection?
108
St. who ate specific meal St. who did not eat specific meal
Ill Well Total AR(%) Ill Well Total AR(%)
Jan 16
Breakfast 52 100 152 34.2 51 94 145 35.2
Lunch 89 150 239 37.2 20 44 64 31.3
Dinner 87 150 237 36.7 23 44 67 34.3
Jan 17
Breakfast 56 105 161 34.8 42 89 131 32.1
Lunch 106 145 251 42.2 3 49 52 5.8 RR!
Dinner 78 130 208 37.5 31 64 95 32.6
42.2/ 5.8=7.3
Can we now calculate IP?
ā€¢ Having identified the meal at which the
students most probably were exposed to the
causal pathogen and
ā€¢ Knowing each studentā€™s time of food
consumption and onset of symptoms; we can!!
109
IP(hrs) No. of Students Cumulative No. of St.
8 22 22
9 11 33
10 18 51
11 8 59
12 42 101
0
10
20
30
40
22
ļ‚£8
11
9
18
10
08
11
42
ļ‚³12
Time (hours)
Number
of
cases
0
20
40
60
80
22
ļ‚£8
33
9
51
10
59
11
100
ļ‚³12
Time (hours)
Cumulative
frequency
%
100
Median I P = 10 hrs
What next?
ļ‚¢A follow up survey to obtain information about
particular foods that 251 students ate at lunch
on Jan 17!
ļ‚¢If students were uncertain about whether they
ate or not the meal in question, they were not
included in the analysis of the particular food.
ļ‚¢ As a result total of those who ate or did not eat
each specific item did not equal 251 for all items
111
Food specific histories of students who ate lunch at
the college cafeteria on Jan 17th
Food/ beverage St. who ate Sp. Food /
Beverage
St. who did not eat Sp. Food /
Beverage
Ill Well Total AR (%) Ill Well Total AR (%)
Fish Curry 16 36 52 30.8 87 103 190 45.8
Lamb Gravy (RR = 8) 95 56 151 62.9 7 82 89 7.9
Chicken noodle 12 57 69 17.4 92 80 172 53.5
Dal Fry 58 54 112 51.8 39 69 108 36.1
Fruit salad 32 39 71 45.1 63 82 145 43.4
Cabbage salad 4 5 9 44.4 95 126 221 43.0
Plain vanilla Ice cream 19 29 48 39.6 80 102 182 44.0
Rabri 62 77 139 44.6 39 56 95 41.1
Milk 91 127 218 41.7 12 13 25 48.0
Coffee 10 31 41 24.4 89 103 192 46.4
tea 23 19 42 54.8 78 114 192 40.6
Further investigation -
ā€¢ About preparation of Lamb Gravy revealed
that it was cooked on 16th Jan, refrigerated
and warmed on the morning of 17th Jan
ā€¢ Now, even without Lab investigation we can
speculate the etiologic agent? Cl. perfringens
ā€¢ Suggesting features:-
ā€“Gastrointestinal symptoms without fever
and vomiting
ā€“Median I P is 10 Hrs
ā€“Meat Gravy Dish is the most likely food
113
115
ā€¢ This is the most common form of transmission in food-
borne disease, in which a large population is exposed
for a short period of time.
Point Source Transmission
116
ā€¢ In this case, there are several peaks, and the
incubation period cannot be identified.
Continuing Common Source or
Intermittent Exposure
Propagated Outbreaks
117
Warning Signals of an impending outbreak
ā€¢ Clustering of cases/ deaths in Time/Place
ā€¢ Unusual increase in cases/ deaths
ā€¢ Even a single case of measles , AFP, Cholera, Plague,
Dengue, or JE
ā€¢ Ac. febrile illness of unknown etiology
ā€¢ Two or more epidemiologically linked cases of
outbreak potential
ā€¢ Unusual isolates
ā€¢ Shifting in age
ā€¢ High or sudden increase in vector density
Unusual
Health Event
No
Yes
Is this an
outbreak
Etiology, Source
& Transmission
known?
No
Yes
Institute control
measures
Further Investigation
Describe outbreak
in terms of TPP
Continuedā€¦.
Develop Hypothesis regarding
Source, Transmission, Etiology & PAR
yes No
Does the
Hypothesis
Fit with facts
Institute control
measures
Special studies
Remember that outbreak is usually
a sudden & unexpected event!
There is need to act quickly.
A systematic Approach Helps
Epidemic preparedness
ā€¢ Formation & Training of RRT
ā€¢ Regular review of data
ā€¢ Alertness during known ā€˜outbreak seasonā€™
ā€¢ Identifying outbreak prone areas
ā€¢ Ensuring that these areas have necessary drugs
and materials (including transport media)
ā€¢ Identifying & strengthening the labs
ā€¢ Designating vehicles
ā€¢ Ensuring communication channels
Steps of Outbreak Investigation
ā€¢ Verification of the outbreak
ā€¢ Sending the RRT
ā€¢ Monitoring the situation
ā€¢ Response to an outbreak
ā€¢ Interim report by RRT within one week
ā€¢ Declaring the outbreak to be over
ā€¢ Final report & its Review within 10 days of the
outbreak declared to be over
Nullification of source
Minimizing transmission Protecting
the host
Response to outbreak
Analysis
ā€¢ Analyze and interpret - within 24 hours
ā€¢ Identify EWS
ā€¢ Frequency count by reporting unit helps in identifying
outbreaks or potential outbreaks
ā€¢ Analysis in terms of person, time and place will be able to
focus the intervention;.
ā€¢ During an outbreak, analysis of the data identifies the most
appropriate and timely control measures.
ā€¢ Analysis of routine data provides information for predicting
changes of disease rates over time and enables appropriate
action.
Data compilation/analysis and response should be at
all levels.
Feedback
ļ±Essential to maintain know-how, moral and
support the peripheral staff.
ļ±Monthly Feed back Report should be sent
regularly even when there are no
epidemics
ļ±Feed back report should also be provided
on the quality of data submitted to the
district surveillance officer

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Epidemiology Lectures for UG

  • 1. Epidemiology Causation and Causal Inference Dr. Amita Kashyap Sr. Prof. Community Medicine S.M.S. Med. College, Jaipur
  • 2. Concept of Sufficient Cause and Component Causes ā€¢ Need to define ā€œcauseā€ ā€“ if we define cause as an antecedent event, condition or characteristic that was necessary for the occurrence of the disease at the moment it occurred, given that other conditions are fixedā€¦ā€¦ ā€¢ This definition provides only a component of a complete causal mechanism
  • 3. General Model of Causation ā€¢ We begin life as a pragmatic philosopher, developing a general causal theory; that some events or states of Nature are causes having specific effects. ā€¢ Though rudimentary it suggests that we are equipped with curiosity to understand, by logic, doubt, speculation, and developing methods to prove (experiments) ā€¢ ? - a working knowledge of the essential system of causal relations that enables each of us to navigate our complex world
  • 4. A ā€œSufficient Causeā€ ā€¢ A ā€œSufficient Causeā€, a complete causal mechanism ā€“ a set of minimal conditions and events that inevitably produce disease. ā€¢ Minimal ā€“ implies that all conditions are necessary Ex. ā€“ Tobacco smoking and Lung cancer ā€¢ Not all smokers get lung cancer- there are certain individuals primed by certain unknown conditions and just adding smoking causes lung cancer. Eg asbestos exposure ā€¢ ? Heavy smokers have approx. a 10% lifetime risk developing lug cancer
  • 5. U U U A A B B E E Three Sufficient Causes of a Disease ā€“ each constellation (I, II, and III) of component causes is sufficient to produce the disease Strength of Effect II I I III The condition under which ā€˜Eā€™ acts as ā€œnecessary and sufficient causeā€ = ā€œpresence of A or B but not bothā€
  • 6. Exposure to component causes Response Frequency of Exposure (combination) 1000 each A B E Outcome Pop. 1 Pop. 2 1 1 1 1 100 900 1 1 0 1 100 900 1 0 1 1 900 100 1 0 0 0 900 100 0 1 1 1 900 100 0 1 0 0 900 100 0 0 1 0 100 900 0 0 0 0 100 900 Exposure frequencies for three component causes in two hypothetical populations 1 and 2 B=1, E = 1 B=1, E=0 B=0, E=1 B=0, E=0 Assumption: disease is a non recurrent event, such as death or first occurrence of disease 1 = present; 0 = absent for exposure and Response The Proportion getting Disease = Numbers getting exposure pattern X response
  • 7. B = 1, E = 1 B = 1, E = 0 B = 0, E = 1 B = 0, E = 0 CASES 1000 100 900 0 TOTAL 1000 1000 1000 1000 Proportion 1.00 0.10 0.9 0.0 Incidence proportion for combo of ā€œB and Eā€ in Population 1 Incidence proportion for combo of ā€œB and Eā€ in Population 2 B = 1, E = 1 B = 1, E = 0 B = 0, E = 1 B = 0, E = 0 CASES 1000 900 100 0 TOTAL 1000 1000 1000 1000 Proportion 1.00 0.9 0.10 0.00 Why ā€œEā€ is much stronger determinant in Population 1 ?
  • 8. Interaction among Causes ā€¢ Two component causes acting in the same ā€˜sufficient causeā€™ may be thought of as interacting biologically to produce disease ā€¢ This need not to be ā€˜simultaneousā€™ ā€“ e.g. head injury leading to Hip fracture?? ā€¢ The extent or apparent strength of biologic interaction between two factors is dependent on the prevalence of some other factors A B C D E A B F G H I II III C A F I J
  • 9. Proportion of Disease due to sufficient cause ā€¢ What fraction of disease is caused by ā€˜Uā€™ if these are the only sufficient causes to cause a specific disease ? ā€¢ The answer is all of it, bcz without ā€˜Uā€™ there is no disease, itā€™s a ā€˜necessary causeā€™. U U A B E E U A B I II III
  • 10. Induction Period ā€“ specific cause-effect pair; not just the effect ā€¢ If in ā€˜Sufficient Causeā€™ I, the sequence of action of the causes is ā€“ A,B,C,D, and E and we want to study the effect of B (which acts at some narrowly defined time) ā€¢ Disease occurs only after the sequence is completed ā€¢ The interval btw the action of B and the disease occurrence is the induction period for the effect of B A B C D E ā€˜Sufficient Causeā€™ I
  • 11. Factor B Disease Initiation Disease occurrence Disease Detection Induction Period Latent Period Period We can reduce ā€˜Latent Periodā€™ by improved methods of disease detection BUT not the induction period as it ends with disease occurrence. !! ā€“ Role of Biomarkers (attempt to focus on causes more proximal to the Disease occurrence)
  • 12. Philosophy of Scientific Inference ā€¢ Inductivism : making generalizations; observations induce the formulation of a natural law in scientistā€™s mind e.g. observation of lack of smallpox in milkmaids induced in Jennerā€™s mind the theory that cowpox confers immunity against smallpox. ā€¢ Based on ā€˜assumptionā€™; there is no logic or force of necessity ā€¢ Logical Fallacy; (after this therefore on account of this!!!)
  • 13. Philosophy of Scientific Inference ā€¢ Refutationism : process of elimination- conjecture and refutation (no matter how many times we boil water in an open flask and get boiling point as 100ļ‚°C; we cannot prove that waterā€™s boiling point is 100ļ‚°C. but one attempt to boil water in a closed flask or at higher altitude will refute the preposition that water always boil at 100ļ‚°C )
  • 14. ā€¢ Since it is possible for any observation to be consistent with many hypotheses that themselves may be mutually in-consistent; consistency btw an observation and hypothesis is no proof of hypothesis ā€¢ In contrast, a valid observation that is inconsistent with an hypothesis refutes it- if you wring the neck of the rooster before sunrise; you have disproved that roosterā€™s crowing is a necessary cause for sunrise
  • 15. Bayesianism ā€¢ In classic logic, premises of the deductive argument need to be 100% truth e.g. ā€œif A implies B, and B is false, then A must be falseā€ ā€¢ The conclusion from this argument ā€œA must be falseā€ will be valid only when assumptions - ā€˜A implies Bā€™, and ā€˜B is falseā€™ are true statements ā€¢ All observation about physical world are subject to some error ā€¢ If we can assign some prior probability to our statements we can use laws of probability to derive certainty to the conclusion
  • 16. ā€¢ Bayesian philosophy provides a methodology for sound reasoning and, in particular, provides many warnings against being overly certain about ones conclusions ā€¢ Such warnings are echoed in Refutationist philosophy : the intensity of the conviction that a hypothesis is true has no bearing on whether it is true or not ā€¢ Most epidemiologists prefer Interval Estimates
  • 17. Consensus ā€¢ The ultimate goal of scientific inference is to capture some objective truths about the material world ā€¢ We may know a theory is false bcz it consistently fails the tests we put it through BUT we cannot know that it is true, even if it passes every test we can devise, for it may fail a test yet un-devised ā€¢ Hence any theory of inference should ideally be evaluated by how well it leads us to detect errors in our hypothesis and observation
  • 18. Consensus ā€¢ When confronted with a refuting observation, a scientist faces the choice of rejecting either the validity of the theory or its scientific infrastructure ā€¢ Observations that are falsifying instances of theories may be treated as ā€œanomaliesā€, tolerated without falsifying the theory in hope of future explanations, e.g. observation that shallow-inhaling smokers had higher lung cancer rates than deep-inhaling smokers!
  • 19. Causal inference in Epidemiology ā€¢ Epidemiologic hypothesis usually are based on vague assumptions lacking biologic knowledge e.g. ā€œsmoking causes CVDsā€ ā€¢ To cope with this vagueness, epidemiologists usually focus on negation of causal hypothesis, the Null Hypothesis that exposure does not have causal relation ā€¢ Then, any observed association can potentially refute the hypothesis (ensuring no biases present) ā€¢ Testing Competing Epidemiologic Theories
  • 20. Causal Criteria ā€¢ Since there can not be a set of sufficient criteria, a list of causal criteria (proposed by Bradfor Hill 1965) provide road map through complicated territory ā€¢ He suggested some aspects of association to be considered in attempting to distinguish causal from non-causal associationā€¦ā€¦
  • 21. Causal Criteria 1. Strength 2. Consistency 3. Specificity 4. Temporality 5. Biologic gradient 6. Plausibility 7. Coherence 8. Experimental evidence 9. Analogy Hillā€™s verdict ā€“ none of my nine viewpoints can bring indisputable evidence for or against the cause and effect hypothesis.
  • 22. Conclusion ā€¢ Science advances by a process of elimination; ā€œconjecture and refutationā€ ā€¢ Alternative hypothesis ā€¢ Evaluating competent causal theories using crucial observations
  • 23.
  • 24. A Patientā€™S Profile: ā€¢ A 60 year old previously healthy female, research chemist recently developed shortness of breadth and nosebleeds. ā€¢ Pale, pulse 110/ min, low (20%) hematocrit, elevated (20000/ļ­l) leukocyte counts, low platelet (15000/ļ­l) with PBF showing atypical myeloblasts ā€¢ Hospitalized for Suspected acute myelogenous leukemia; confirmed by bone marrow aspirate and biopsy. ā€¢ Chemotherapy started, about 3 weeks later, her temp. abruptly rose to 39ļ‚°C and neutrophil count dropped to 100 /ļ­l. ā€¢ No source of apparent infection;
  • 25. Patient Profileā€¦ctd: ā€¢ Importance of Risk assessment!! ā€¢ How likely is it that patient has a bacterial infection? ā€¢ Her blood and urine cultures were taken, and broad spectrum antibiotics administered (empiric treatment) ā€¢ Potential Risk of complications from delayed antibiotic outweighed empiric use of antibiotic ā€¢ Cultures confirmed staphylococcus aureus in blood
  • 26. Measures of Disease Occurrence Epidemiologic measures - to assess outcomes and thereby guide decisions ā€¢ Risk (the likelihood that a person will contract a disease) ā€¢ Prevalence (Load; the amount of disease already present in the population) ā€¢ Incidence Rate (how fast is the new occurrence of disease)
  • 27. Defined Population Have Disease Do not have disease Do not have disease at baseline PAR Prevalent cases 1. Identify Population 3. Follow only those who did not have the dis. 2. Determine who has the Dis. & who doesnā€™t Do not have disease at baseline Develop Dis. Do not have disease Follow up for 1 year incident cases
  • 28. Risk (cumulative incidence) ā€¢ It is a measure of the occurrence of new cases ā€¢ i.e. Proportion of unaffected persons (PAR) in the population who, will contract the disease over a specified period of time New cases Person at Risk R = ā€¢ Has no unit; ā€¢ lies between 0 and 1
  • 29. onset end A B C D E F Hypothetical study of group of six subjects 1995 96 97 98 99 00 01 02 03 04 Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death 97 02 99 97 99 02 Dx,,,,,,,,,,,,,,,,,,,,,,, 97 02 What is the Risk of Dis. development within 2 years of enrolment New cases R = Person at risk = 1/6 = 0.17 OR 17%
  • 30. Example of HAI in cancer patients ā€¢ Estimate a cancer patientā€™s risk of getting HAI from a study of 5031 patients admitted in comprehensive cancer centre. ā€¢ If 596 patients met criteria for Hosp. Acquired infection ā€¢ Risk period? - Starts 48 hrs after hospitalization and ends 48 hrs after discharge. New cases R = Person at risk = 596/5031 = 0.12 OR 12%
  • 31. ā€¢ Can we apply this risk to our patient? ā€¢ More likelihood of infection for our patient can come from studies on similar subjectsā€¦having fever, and low granulocyte countā€¦. ā€¢ Now if 1022 such cancer patients were studied and 530 had HAI then the Risk is 530/1022 = 0.52 i.e. 52%
  • 32. Measures of Disease Occurrence ctdā€¦ ā€¢ Prevalence (Burden of Disease)ā€“ indicates number of existing cases of a disease in a population at a time. ā€¢ E.g. An important question in deciding antibiotic use to the patient is the type and magnitude of infection anticipated!! ā€¢ We know that individuals with low neutrophil count are susceptible to wide variety of infectionsā€¦ ā€“ S.aureus was cultured from 62 out of 96 patientā€™s specimens ā€¢ Prev. of S.aureus infection = 62/ 96 = 0.65 i.e. 65%
  • 33. onset end A B C D E F Hypothetical study of group of six subjects 1995 96 97 98 99 00 01 02 03 04 Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death 97 02 99 97 99 02 Dx,,,,,,,,,,,,,,,,,,,,,,, 97 02 What is the Prevalence of Disease in 2001 Total cases p = Total population = 1/4 = 0.25 OR 25% B ā€¦.left
  • 34. Measures of Disease Occurrence ctdā€¦ ā€¢ Incidence Rate ā€“ measures the rapidity with which new cases of the disease develop. ā€¢ Estimated by observing a population and counting the number of new cases over Net Time (person years) i.e. ā€¢ Incidence Rate = New cases/ person time ā€¢ A subject at risk of disease followed for 1 yr, or 5 yrs contributes 1 or 5 person-years of observation respectively.
  • 35. onset end A B C D E F Hypothetical study of group of six subjects 0 1 2 3 4 5 6 7 8 9 Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death 97 02 99 97 99 02 Dx,,,,,,,,,,,,,,,,,,,,,,,, ,,,,,, 97 02 How many person years are contributed by A, B, C, D E and F? 04 Total new cases IR= Total person years = 2/22 = 0.09 cases /person years i.e. 9 cases/ 100 person-yrs 04 04 98 Observation years 95
  • 36. Example of HAI ctdā€¦ ā€¢ Those 5031 remained under observation for a total of 127859 patient days ā€¢ What is the average length of stay? ā€¢ Since 596 patients developed HAI the IR would be ā€“ 596/ 127263= 0.00468 cases/ patient days ā€¢ Can be expressed for better readability as 4.7 cases/ 1000 patient days ā€¢ Interpretation: among patients similar to those studied, on average, about 0.47% patient/day would be expected to develop a HAI 127859/5031 = 25.41
  • 37. Calculation of IR for a Large Pop. ā€¢ Calculating person-years (PT) for each individual would be too cumbersome! Alternatively ā€¢ PT = (Av. Size of PAR) X (Length of observation) ā€¢ In many instances, relatively few people develop the disease and there is no other demographic shift hence whole Pop. Can be taken as At Riskā€¦i.e. not excluding patients ā€¢ PT = (Size of entire Pop.) X (Length of observation) ā€¢ 596/127859=0.00466 while 596/127263=0.00468 !!!
  • 38. Calculation of IR for a Large Pop. ā€¢ If there are an estimated 1,91,85,836 women in an area btw 1996 and 2000 (5 yrs period) and 2957 women were newly diagnosed with Acute myelocytic leukimia (AML) ā€¢ What is the annual incidence rate of AML ? ā€¢ 1,91,85,836 women x 5 Yrs = 9,59,29,180 WY ā€¢ IR = 2957 new cases/ 9,59,29,180 Wyrs = 3.1cases /1,00,000 WY
  • 39. Characteristic Risk Prevalence Incidence Rate What is measured Probability of Disease Proportion of Pop. With disease Rapidity of Disease Occurrence Units None None Cases/ person- time Time of disease Dx Newly diagnosed Existing cases Newly diagnosed Synonyms Cumulative Incidence - Incidence Density Characteristics of Risk, Prevalence & Incidence Rate In our Hypothetical Ex. In 2001 Prev. was 25%, 2 Yr. Risk was 17% and the IR was 9cases/ 100 yrs
  • 40. Problems with Incidence and Prevalence Measurements ā€¢ Problems with Enumerator ā€“ The first problem is defining who has the disease. ā€“ The next issue is Method of data collection ā€“ interview, self reporting , surveyā€¦ associated biases!! ā€¢ Problems with Denominators ā€“ everyone in the group represented by the denominator must have the potential to enter the group that is represented by the numeratorā€¦ PAR concept ā€¢ Problems with Hospital Data
  • 41. Relationship Between Incidence and Prevalence ā€¢ There is an important relationship between incidence and prevalence: in a steady-state situation, in which the rates are not changing and in-migration equals out-migration, the following equation applies: ā€¢ Prevalence = Incidence Ɨ Duration of disease
  • 42. Example ā€¢ 2,000 persons are screened for tuberculosis, Using chest x-rays: 1,000 are upper-income (HIG) individuals and 1,000 are lower-income (LIG) individuals. ā€¢ X-ray findings are positive in 100 of the HIG and in 60 of the LIG. ā€¢ Can we therefore conclude that the risk of tuberculosis is higher in HIG people than in LIG people?
  • 44. 20 30 40 50 60 70 80 0 100 200 300 400 20% 15% 10% 5% 0% Annual Rate/ 100000 Percent of total cases Breast cancer incidence rates and distribution of cases by age Age in yrs The incidence is increasing so dramatically with age, why are only fewer than 5% of the cases occurring in the oldest age group of women?
  • 45. Incidence increasing but prevalence decreasing ā€“ How? 46 0 5 10 15 20 25 30 35 40 1 9 9 0 1 9 9 3 1 9 9 6 1 9 9 9 Prevalence Incidence Fatal, Or short duration
  • 46. Incidence stable but prevalence increasing indicates:- 47 0 5 10 15 20 25 30 35 40 45 1 9 9 0 1 9 9 3 1 9 9 6 1 9 9 9 Prevalence Incidence New Program or Better Dx Test !!! ā€¢Death is prevented and Dis is not cured ā€¢ Diagnosed more ā€¢Immigration of cases
  • 47. Incidence maintained but prevalence declining means:- 48 0 5 10 15 20 25 30 35 1 9 9 0 1 9 9 2 1 9 9 4 1 9 9 6 1 9 9 8 incidence prevalence New effective drug! Or Dis. Became more Virulent/ fatal, Emigration of cases
  • 48. Incidence Rate:Expressed as- Morbidity rate- New cases total population at risk Mortality rate- No. Of deaths due to a disease/ total population Case fatality rate- No. Of deaths due to a disease/ total no. Of cases of that disease Attack rate- No. Of new cases of a disease, during a specified time/ total population at risk for the same time Secondary Attack Rate- No. of exposed persons developing disease within the Range of ā€œIPā€ following exposure to a Primary Case.
  • 49. Survival ā€¢ Probability of being alive for a specific length of time ā€¢ For a Ch. Dis. Like cancer, 1 and 5 Yr survival rates are often used as indicator of the severity of the disease and the prognosis. ā€¢ E.g. if 5-Yr survival for AML is 0.19, it means that only 19% of patients with AML survive at least 5- Yrs after diagnosis ā€¢ Survival = Newly Dx Pts. ā€“ Deaths/ Newly Dx Pts. For a specified time
  • 50. Dx onset end A B C D E F Hypothetical study of group of six subjects 0 1 2 3 4 5 Observation years Patients Censored Death Censored Death What is the 2 year survival rate? 2 year survival rate = 5/6 = 0.83 i.e. 83% What is the 2 year Risk of Death? 2 year Risk of Death = 1/6 = 0.17 i.e. 17% 5 yr S If we assume B & E survive all 5 yrs = 4/6= 0.67=67% ! 5 yr S If we assume B & E didnā€™t survive all 5 yrs = 2/6= 0.33=33% ! !
  • 51. Methods to account for censored cases ā€¢ Life Table analysis ā€¢ Kaplan-Meier analysis AND Graphs 0 1 2 3 4 5 20 40 60 80 100 0 Survivors Percent Years since Dx 47% 68% 58% ? Median Survival Time 50
  • 52. Case Fatality ā€¢ The propensity of a disease to cause Death ā€¢ If N = 15 and 5 of whom develop disease of concern , then Risk = 5/15= 0.33 = 33% ā€¢ If only 2 of the affected die CF = 2/5 = 0.40 = 40% ā€¢ Survival = incident cases ā€“ death /total affected ā€¢ = 5-3 / 5 = 3/5 = 0.6 = 60% i.e. 100 ā€“ CF = Survival Number of Deaths CF = No. of Dx Cases New cases R = Person at risk
  • 53.
  • 54. onset end A B C D E F Hypothetical study of group of six subjects 0 1 2 3 4 5 6 7 8 9 Dx ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦ā€¦Death 97 02 99 97 99 02 Dx,,,,,,,,,,,,,,,,,,,,,,,, ,,,,,, 97 02 How many person years are contributed by A, B, C, D E and F? 04 Total new cases IR= Total person years = 2/22 = 0.09 cases /person years i.e. 9 cases/ 100 person-yrs 04 04 98 Observation years 95 2 person yrs 2 person yrs 2 person yrs 3person yrs 7 person yrs 6 person yrs
  • 55. Comparing disease occurrence (in groups with different exposures ) ā€¢ To calculate the Risk that a health effect will result from an exposure ā€¢ Risk Difference (Excess Risk)- expressed as:- Incidence in exposed - Incidence in un-exposed Smoking category Stroke cases Person yrs of observation Stroke IR/ 100000 Person yrs Never smoked 70 3,95,594 17.7 Ex-smoker 65 2,32,712 27.9 Smoker 139 2,80,141 49.6 total 274 9,08,447 30.2 = 49.6 ā€“ 17.7 = 39.1/ 100,000 person yrs
  • 56. Comparing disease occurrence (in groups with different exposures ) ā€¢ Attributable Fraction (exposed) ā€“ proportion of cases that can be attributed to exposure Incidence in exposed - Incidence in un-exposed / Incidence in exposed = (49.6 ā€“ 17.7/ 49.6) X 100 = 64% Indicating 64% Risk Reduction if exposure is removed
  • 57. ā€¢ Population Attributable Risk ā€“ determine relative importance of exposure for entire population = incidence in total population ā€“ incidence among un-exposed / incidence in total population
  • 58. ā€¢ Relative Risk ā€“ ratio of the risk of occurrence of disease among exposed people to that among un-exposed people (baseline level of exposure) e.g. (in our Ex. = 49.6/17.7 = 2.8) ā€¢ Good indicator of strength of association because it is expressed relative to baseline level of exposure
  • 59. Measures of Mortality: ā€¢ Mortality rate ā€“Crude death rate ā€“Cause specific death rate ā€“Age specific death rate ā€¢ Case-fatality rate ā€¢ Proportionate mortality rate ā€¢ Standardized Mortality Rates
  • 60.
  • 61. Adjusted Rates: Standardization ā€¢ Standardization: ā€“ The process to derive a summary figure to compare health outcomes of groups ā€“The process can be used for mortality, natality, or morbidity data, race ā€¢ Standardization Methods ā€“Direct ā€“Indirect
  • 62. Example: Age-Adjustment A. Direct Method: requires ā€“ 1. Age-specific rates in the sample population a) The age of each case b)The population-at-risk for each age group in the sample 2. Age structure of a standard population Summary figure is an Age-adjusted rate
  • 63. Direct Age Adjustment Population 1 Population 2 Population No. of Deaths Death rate/ 100000 Population No. of Deaths Death rate/ 100000 900000 862 96 900000 1130 126 Standard Population can be taken from outside or both population can be clubbed to get Standard Population
  • 64. Direct Age Adjustment: Comparison of Age specific death rates Population 1 Population 2 Age Gr. popula tion No. of Deaths Death Rate/ 100000 popula tion No. of Deaths Death Rate/ 100000 All ages 900000 862 96 900000 1130 126 30-49 500000 60 12 300000 30 10 50-69 300000 396 132 400000 400 100 70+ 100000 406 406 200000 700 350
  • 65. Direct Age Adjustment: using total of two pop. As standard Population Age Group Standard Population 1996-2000 Age specific mortality rates Expected no. of deaths / 100000 2001-2005 Age specific mortality rates Expected no. of deaths / 100000 All Ages 1800000 30-49 800000 12 96 (8 x 12) 10 80 50-69 700000 132 924 (7 x 132) 100 700 70+ 300000 406 1218 350 1050 Total 2238 1830 2238 1830 Age adjusted Rate = ---------- X 100000 = 124.3, --------- X 100000 = 101.7 1800000 1800000
  • 66. B. Indirect method: requires 1. Age structure of the sample population 2. Total deaths in the sample population 3. Age-specific rates for the standard population 4. No need for stratum-specific rates of the sample Summary figure is a Standardized Mortality ratio (SMR)
  • 67. Indirect Standardization ā€¢ Stratum specific Death rates of standard population are applied to each stratum of the sample population to get Expected Deaths ā€¢ Overall DR of sample population from records gives Observed Deaths Observed SMR = ----------------- X 100 Expected SMR of 100 means no difference between the number of outcomes in the sample population and that which would be expected in the standard population
  • 68. Indirect Standardization (cont.) Total expected deaths per year: 2,083 Total observed deaths per year: 1,464 (from Records) SMR = 1,464 / 2,083 x 100 = 70.3% (30% less than expected) Age Group Number people (Census, 2001) Standard Death Rates per 1,000,000 (All Causes of Death) Expected Number of Deaths per 1,000,000 (1) (2) (3) = (1) X (2)/ 1,000,000 20-24 7,989 1,383 11 25-34 37,030 1,594 59 35-44 60,838 2,868 174 45-54 68,687 8,212 564 55-64 55,565 22,953 1,275 2,083
  • 69. Patterns of occurrence ā€¢ Distribution Patterns (TPP analysis)of a disease within a population ā€“ Who develops the disease? (Person) ā€“ Where does the disease occur? (Place) ā€“ When does the disease occur ? (Time) ā€¢ Level (rate of occurrence)- Endemic or Epidemic ā€¢ Causal Role - Genetic or environmental
  • 70. Patient profile ā€¢ A 30 yr old female domestic worker; recently migrated from India to USA presented with 6 weeks h/o cough, fever, night sweats, weakness, fatigue and shortness of breath. ā€¢ h/o two normal deliveries followed by Tubal ligation ā€¢ Chest X-ray shows cavity lesions, sputum is AFB +ve and mycobacterium grew on culture which was sensitive to all drugs ā€¢ Administered 4 drugs under DOTS
  • 71. ā€¢ After 2 months put on 2 drugs 3 times a week as she was asymptomatic with no bacilli in sputum. ā€¢ She resided in a low town apartment building, tuberculin test was done on her husband and two children ā€¢ Results were +ve for her husband and 3 yr old ā€¢ Although no active disease was found yet prophylactic Tt was given to all three of them ā€¢ Out of 54 neighbors; 1 was infected without any evidence of clinical disease and received PT ā€¢ None of the work place contacts were +ve
  • 72. Environment Infectious Individual Susceptible Individual Close contacts of infected, susceptible people in close spaces Pulmonary or Laryngeal disease with bacilli in sputum Compromised immune system Poor ventilation Forceful cough with uncovered mouth Predisposing disease or condition e.g. silicosis, cancer Recirculation 0f contaminated air Less than 2-3 weeks of appropriate anti- microbial therapy Lack of adequate Nutrition Injectable drug use or heavy alcohol intake Factors that increase the probability of T.B. transmission
  • 74. Epidemiology Observational Epidemiology Experimental Epidemiology Descriptive Epidemiology Analytical Epidemiology Hypothesis about disease causation Leads to Help explain descriptive patterns (possible causes) And to improve Dis. Surveillance Verified by Analytical/ Experimental Studies
  • 75. How to Develop a Hypothesis?
  • 76. Person (disease do not occur at random!) ā€¢ Variation of occurrence in relation to personal characteristics reflects: ā€“ differences in level of exposure to causal factors, ā€“susceptibility to causal factors, ā€“or both. ā€¢ Personal characteristics includeā€¦ā€¦.
  • 77. 946 1499 5286 4191 3147 0 1000 2000 3000 4000 5000 6000 up to 14 15-24 25-44 45-64 65+ cases Age in Years Number of T.B. cases by Age in a year... ? From where does such Data Comes Notification of diseases!! List is updated as per changing scenario/ needs. And Surveillance data. Interpretation? Highest Risk in 25-44 yrs??
  • 78. Surveillance ā€¢ ā€œOngoing systematic collection, analysis, and interpretation of data essential for- ā€“ planning, implementation, and evaluation of public health practice closely integrated with the timely Feedback.ā€ ā€¢ Types - Passive or Active ā€¢ Help to Know- Changes in either disease rates or levels of environmental risk factors
  • 79. Surveillance goals ā€¢ Identification of patterns of disease occurrence ā€¢ Detecting disease outbreaks at nascent age ā€¢ Development of clues for possible Risk Factors ā€¢ Anticipation of health service needs ā€¢ Finding cases for further investigation
  • 80. 1.5 3.7 6.2 6.3 8.8 0 1 2 3 4 5 6 7 8 9 10 0-14 15-24 25-44 45-64 65+ incidence per 100000 person years Age in Years Incidence Rates for Reported T.B. Cases Incidence among persons in oldest age group is over 40% higher than that for 25-44 years group Possible factors Contributing ā€¢Long latent period ā€¢Elderly lived through times when T.B. was rampant (Birth Cohort Effect) ā€¢Other illness like DM and Cancers more in elderly ā€¢Declined immunity in old age ā€¢More chances of living in Closed settings How to interpret ? Higher incidence rate in certain minority group!! Gender Differences !!!
  • 81. Place (spot maps!) ā€¢ International ā€¢ National ā€¢ State and/ or ā€¢ Local comparisons gives insight to probable reasons ā€“ Estimated 8 million people develop T.B. each year worldwide ā€“ 95% of these comes from developing world ā€“ Most rapid rise of T.B. IR is in sub Saharan Africa!
  • 82.
  • 83. Time
  • 84. ā€¢ Usual rate of occurrence ā€“ endemic rate ā€¢ A rapid and dramatic increase over the endemic rate is - epidemic rate ā€¢ Epidemic can develops in a matter of days or weeks (few hrs for staphylococcal food poisoning) but for chronic condition like cancer it takes years to decades ā€¢ Establishing linkages between RF and Disease Occurrence become difficult if there is greater time lag (latent period)
  • 85. Endemic vs. Epidemic Endemic Epidemic No. of Cases of a Disease Time Usually plot weekly
  • 86. No rapid rise in incidence of T.B. but departure from decline!!
  • 87. Correlation with Disease Occurrence ā€¢ To develop hypothesis about possible causes of disease, ā€“ Presence of a suspected RF is measured in different populations and compared with incidence of disease (Ecologic Study) ā€“Examine extent to which two characteristics are related e.g. (RF and disease occurrence)
  • 88. Incidence rates of TB and AIDS in 15 States of USA r = 0.91, coefficient of determination (r2) = 0.98 Regression equation = a + b*x Tuberculosis IR = - 0.8 + 0.57 X AIDs IR Ecologic fallacy!!
  • 89. Migration studies ā€¢ To clarify whether a disease of unknown cause is determined principally by genetic inheritance or environmental exposure ā€¢ For diseases with long latent periods, it may take years for the reduced rate of occurrence ā€¢ If environmental exposure early in life is critical, then effects may be visible in offspring's only!
  • 90.
  • 91.
  • 92. Ways to interpret data and generate Hypothesis
  • 94.
  • 95. Investigating An Outbreak Dr. Amita kashyap 96
  • 96. What is a Disease Outbreak? ļ‚—Outbreak vs Epidemic What does it Require? ļ‚—A pathogen in sufficient quantities, ļ‚—A mode of transmission, ļ‚—And a pool of susceptible people 97
  • 97. 98 A Scenario! A 23 yr old male student; presented at 10:30 pm on 17th Jan 2014, at the emergency complaining of a sudden onset of abdominal cramping, nausea and diarrhea. He was weak, not severely distressed, had no fever or vomiting. A No. of other students, all with the same symptoms, visited emergency over next 20 Hrs All treated with Fluid replacement recovered fully within 24 hrs. of the onset of illness.
  • 98. Does it warrant an investigation? ā€¢ Why? 99
  • 99. When should we Investigate? ā€¢ Number and severity of persons affected! ā€¢ Uncertainty about cause! ā€¢ Level of Public Concern/ Political pressure!! ā€¢ Potential for contributing to medical knowledge! 100
  • 100. 101 Reasons for Outbreak Investigation Quantifying the epidemic (Descriptive epidemiology) Getting at the source and reasons (Analytic epidemiology) for Preventing others from becoming affected
  • 101. Investigation in our scenario! ļ‚¢Quick information revealed 47 students out of 1164 college enrollment got affected by 8 PM on 18th Jan (20 Hrs) ļ‚¢ What is the quantitative measure of the extent of an outbreak? No. of New Cases AR = Persons at Risk What is the AR for this period? = 47/ 1164 X 100 = 4% 103
  • 102. Hostel wise distribution of 47 known cases, AR, population and sex of the occupants of each hostel Hostel Sex PAR No. of Cases AR 1 F 80 19 23.8 2 F 62 2 3.2 3 F 89 0 0 4 F 61 1 1.6 5 F 53 5 9.4 6 M 35 0 0 7 M 63 0 0 8 F 103 4 3.9 9 M 35 1 2.9 10 M 37 0 0 11 F 34 1 2.9 12 M 62 13 21.0 13 M 32 1 3.1 14 M 10 0 0 Total - 756 47 6.2 Attack Rate (all students) = 47/ 1164 X 100= 4% Attack Rate (hostellers) = 47/ 756X100= 6.2% Attack Rate (hostel 1, 12) = 19+13/ 80+62 = 22.5% Attack Rate (other hostels) = 15/ 614 = 2.4% Risk Ratio = AR hostel (1, 12) / AR (Other hostels) X 100 = 22.5/ 2.4 = 9.4 ? Sex difference in AR =
  • 103. Further : ļ‚¢Visit to hostels revealed that not all students who became ill reported to emergency. ļ‚¢Needed un-baised data- henceā€¦ ļ‚¢Seven hostels were randomly selected for information collection on desired areas! 105
  • 104. Response to the questionnaire survey by hostels Questionnaire returned Selected Hostel Population Number Percent No. of ill St. 5 53 49 92.5 13 6 35 26 74.3 13 7 63 28 44.4 15 8 103 65 63.1 21 9 35 19 54.3 5 12 62 44 71.0 22 Nursesā€™ hostel 60 60 100 17 Unidentified - 13 - 4 Total 411 304 74.0 110 106 AR = 110/304 X100 = 36.2% Note: initial hostel wise AR for Hostel 6, and 12 were 0% and 21% As per survey data ! - AR (H6) =13/26X100=50% and AR (H12) =22/44X100 = 50%
  • 105. ā€¢ AR of hostel 6 and 12 were 0% and 21% by emergency data but by survey data both are 50% - Approach for data collection! ā€¢ Was emergency data useless? ā€¢ Is 36.2% the true AR of AGE on campus ? ā€¢ Explain factors why AR estimated from emergency records were low? ā€¢ Why more cases from hostel 1 and 12 at emergency? 107
  • 106. Additional informationā€¦.. ā€¢ No large gathering of students..... hence inquiries were made about meals eaten on 16th and 17th Jan ā€¢ Most students ate at college cafeteria ā€¢ How will you zero down to source of infection? 108 St. who ate specific meal St. who did not eat specific meal Ill Well Total AR(%) Ill Well Total AR(%) Jan 16 Breakfast 52 100 152 34.2 51 94 145 35.2 Lunch 89 150 239 37.2 20 44 64 31.3 Dinner 87 150 237 36.7 23 44 67 34.3 Jan 17 Breakfast 56 105 161 34.8 42 89 131 32.1 Lunch 106 145 251 42.2 3 49 52 5.8 RR! Dinner 78 130 208 37.5 31 64 95 32.6 42.2/ 5.8=7.3
  • 107. Can we now calculate IP? ā€¢ Having identified the meal at which the students most probably were exposed to the causal pathogen and ā€¢ Knowing each studentā€™s time of food consumption and onset of symptoms; we can!! 109 IP(hrs) No. of Students Cumulative No. of St. 8 22 22 9 11 33 10 18 51 11 8 59 12 42 101
  • 109. What next? ļ‚¢A follow up survey to obtain information about particular foods that 251 students ate at lunch on Jan 17! ļ‚¢If students were uncertain about whether they ate or not the meal in question, they were not included in the analysis of the particular food. ļ‚¢ As a result total of those who ate or did not eat each specific item did not equal 251 for all items 111
  • 110. Food specific histories of students who ate lunch at the college cafeteria on Jan 17th Food/ beverage St. who ate Sp. Food / Beverage St. who did not eat Sp. Food / Beverage Ill Well Total AR (%) Ill Well Total AR (%) Fish Curry 16 36 52 30.8 87 103 190 45.8 Lamb Gravy (RR = 8) 95 56 151 62.9 7 82 89 7.9 Chicken noodle 12 57 69 17.4 92 80 172 53.5 Dal Fry 58 54 112 51.8 39 69 108 36.1 Fruit salad 32 39 71 45.1 63 82 145 43.4 Cabbage salad 4 5 9 44.4 95 126 221 43.0 Plain vanilla Ice cream 19 29 48 39.6 80 102 182 44.0 Rabri 62 77 139 44.6 39 56 95 41.1 Milk 91 127 218 41.7 12 13 25 48.0 Coffee 10 31 41 24.4 89 103 192 46.4 tea 23 19 42 54.8 78 114 192 40.6
  • 111. Further investigation - ā€¢ About preparation of Lamb Gravy revealed that it was cooked on 16th Jan, refrigerated and warmed on the morning of 17th Jan ā€¢ Now, even without Lab investigation we can speculate the etiologic agent? Cl. perfringens ā€¢ Suggesting features:- ā€“Gastrointestinal symptoms without fever and vomiting ā€“Median I P is 10 Hrs ā€“Meat Gravy Dish is the most likely food 113
  • 112. 115 ā€¢ This is the most common form of transmission in food- borne disease, in which a large population is exposed for a short period of time. Point Source Transmission
  • 113. 116 ā€¢ In this case, there are several peaks, and the incubation period cannot be identified. Continuing Common Source or Intermittent Exposure
  • 115. Warning Signals of an impending outbreak ā€¢ Clustering of cases/ deaths in Time/Place ā€¢ Unusual increase in cases/ deaths ā€¢ Even a single case of measles , AFP, Cholera, Plague, Dengue, or JE ā€¢ Ac. febrile illness of unknown etiology ā€¢ Two or more epidemiologically linked cases of outbreak potential ā€¢ Unusual isolates ā€¢ Shifting in age ā€¢ High or sudden increase in vector density
  • 116. Unusual Health Event No Yes Is this an outbreak Etiology, Source & Transmission known? No Yes Institute control measures Further Investigation Describe outbreak in terms of TPP Continuedā€¦.
  • 117. Develop Hypothesis regarding Source, Transmission, Etiology & PAR yes No Does the Hypothesis Fit with facts Institute control measures Special studies Remember that outbreak is usually a sudden & unexpected event! There is need to act quickly. A systematic Approach Helps
  • 118. Epidemic preparedness ā€¢ Formation & Training of RRT ā€¢ Regular review of data ā€¢ Alertness during known ā€˜outbreak seasonā€™ ā€¢ Identifying outbreak prone areas ā€¢ Ensuring that these areas have necessary drugs and materials (including transport media) ā€¢ Identifying & strengthening the labs ā€¢ Designating vehicles ā€¢ Ensuring communication channels
  • 119. Steps of Outbreak Investigation ā€¢ Verification of the outbreak ā€¢ Sending the RRT ā€¢ Monitoring the situation ā€¢ Response to an outbreak ā€¢ Interim report by RRT within one week ā€¢ Declaring the outbreak to be over ā€¢ Final report & its Review within 10 days of the outbreak declared to be over
  • 120. Nullification of source Minimizing transmission Protecting the host Response to outbreak
  • 121. Analysis ā€¢ Analyze and interpret - within 24 hours ā€¢ Identify EWS ā€¢ Frequency count by reporting unit helps in identifying outbreaks or potential outbreaks ā€¢ Analysis in terms of person, time and place will be able to focus the intervention;. ā€¢ During an outbreak, analysis of the data identifies the most appropriate and timely control measures. ā€¢ Analysis of routine data provides information for predicting changes of disease rates over time and enables appropriate action. Data compilation/analysis and response should be at all levels.
  • 122. Feedback ļ±Essential to maintain know-how, moral and support the peripheral staff. ļ±Monthly Feed back Report should be sent regularly even when there are no epidemics ļ±Feed back report should also be provided on the quality of data submitted to the district surveillance officer