Determine arithmetic mean of the numbers f(x1), f(x2) for f(x) = x/2-6 ; x1 = -8, x2 = 10
Solution
We\'ll determine the arithmatic mean of the numbers f(x1) and f(x2):
A.M. = [f(x1) + f(x2)]/2
To compute the value of A.M., we\'ll have to compute the values of f(x1) and f(x2).
For this reason, we\'ll substitute x1 and x2 in the expression of f(x).
For x1 = -8, we\'ll get:
f(-8) = -8/2 - 6
f(-8) = -4 - 6
f(-8) = -10
For x2 = 10, we\'ll get:
f(10) = 10/2 - 6
f(10) = 5 - 6
f(10) = -1
Now, we\'l substitute f(x1) and f(x2) by the values of f(-8) and f(10) in the expression of A.M.
A.M. = [f(-8) + f(10)]/2
A.M. = (-10-1)/2
A.M. = -11/2.
determine c such that f(x)= C, for o for MSI Solution .pdf
1. determine c such that f(x)= C, for o for MSI
Solution
Integration of c/x^2dx in -infinity to + infinity should be 1 for it to be density fn =>
-c/x (integration of f(x) = -c/infinity - (-c/1) = 1 (since f(x) is from 1 to infi only otherwise it is 0)
=> c =1 (Since any number/inf tends to zero)
