please answer with your work
6. True or False If Pis the transition matrix of a Markov chain, each row of P has entries that add
up to 1.
Solution
6) False. Is true for column sum.
2)
D = has tuberculosis bacilli
T = tests positive for tuberculosis bacilli
T\' = tests negative for tuberculosis bacilli
P(D) = 0.142
P(D\') = 1-0.142 = 0.858
P(T/D)=0.70
P(T\'/D\') = 0.99
P(T/D\')=1-P(T\'/D\') = .01
A)
has the disease, tests positive or doesn\'t have the disease, tests positive
P(D)P(T/D) + P(D\')P(T/D\') = (.142)(0.70) +(0.858)(.01) = .10798 (correct)
B)
P(D/T) = P(D)P(T/D) / [ P(D)P(T/D) + P(D\') P(T/D\')]
= (0.142)(0.70) / [ (0.142)(0.70) + (0.858)(0.01)] = .0994 / .10798 = 0.9205.
please answer with your work 6. True or False If Pis the transit.pdf
1. please answer with your work
6. True or False If Pis the transition matrix of a Markov chain, each row of P has entries that add
up to 1.
Solution
6) False. Is true for column sum.
2)
D = has tuberculosis bacilli
T = tests positive for tuberculosis bacilli
T' = tests negative for tuberculosis bacilli
P(D) = 0.142
P(D') = 1-0.142 = 0.858
P(T/D)=0.70
P(T'/D') = 0.99
P(T/D')=1-P(T'/D') = .01
A)
has the disease, tests positive or doesn't have the disease, tests positive
P(D)P(T/D) + P(D')P(T/D') = (.142)(0.70) +(0.858)(.01) = .10798 (correct)
B)
P(D/T) = P(D)P(T/D) / [ P(D)P(T/D) + P(D') P(T/D')]
= (0.142)(0.70) / [ (0.142)(0.70) + (0.858)(0.01)] = .0994 / .10798 = 0.9205
![please answer with your work
6. True or False If Pis the transition matrix of a Markov chain, each row of P has entries that add
up to 1.
Solution
6) False. Is true for column sum.
2)
D = has tuberculosis bacilli
T = tests positive for tuberculosis bacilli
T' = tests negative for tuberculosis bacilli
P(D) = 0.142
P(D') = 1-0.142 = 0.858
P(T/D)=0.70
P(T'/D') = 0.99
P(T/D')=1-P(T'/D') = .01
A)
has the disease, tests positive or doesn't have the disease, tests positive
P(D)P(T/D) + P(D')P(T/D') = (.142)(0.70) +(0.858)(.01) = .10798 (correct)
B)
P(D/T) = P(D)P(T/D) / [ P(D)P(T/D) + P(D') P(T/D')]
= (0.142)(0.70) / [ (0.142)(0.70) + (0.858)(0.01)] = .0994 / .10798 = 0.9205](https://image.slidesharecdn.com/pleaseanswerwithyourwork6-230325121117-c3a9de5e/85/please-answer-with-your-work-6-True-or-False-If-Pis-the-transit-pdf-1-320.jpg)
