In C language Given an IntNode struct and the operating func.pdf

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In C language Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list: 1. IntNode* IntNode_GetNth(IntNode* firstNode, int n )- Return a pointer to the nth node of the list starting at firstNode. 2. void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values. 3. int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode. Note: The code for IntNode_Create 0 provided here differs from the code shown in the book. The given main0 performs various actions to test IntNode_GetNth 0 , IntNode_PrintList 0 , and IntNode_SumList 0 . main() reads 5 integers from a user: 1. The number of nodes to be added to a new list 2. The value of the first node of the list 3. An increment between the values of two consecutive nodes. 4. A value of a new node 5. The position of a node after which the new node will be added, with 1 indicating the first node Ex: If the input is:.

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Assignment is : \"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to include comments Use meaningful identifier names (constants where appropriate) Do not work together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print- screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\" How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual Studios using the linked list below with what is being asked? Please need help Linked list : #include #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *first, *last; int num; createList(first, last); int choice; while(true) { cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\ \"; cout<<\"Enter your choice: \"; cin>>choice; switch(choice) { case 1: insertFront(first); break; case 2: insertBack(last); break; case 3: deleteFirst(first); break; case 4: deleteLast(last, first); break; case 5: printList(first); break; case 6: return 0; default: cout<<\"Invalid menu option. Try again.\"<>number; while (number != -999) { newNode = new nodeType; // create new node newNode->info = number; newNode->link = NULL; if (first == NULL) { first = newNode; last = newNode; } else { last->link = newNode; last = newNode; } cout<<\"Enter an integer (-999 to stop): \"; cin>>number; } // end of while-loop } // end of build list function void deleteFirst(nodeType*& first) { nodeType *temp; temp= first; first= temp->link; delete temp; return; } void deleteLast(nodeType*& last, nodeType* current) { nodeType *temp; while(current->link != NULL) { temp=current; current=current->link; } temp=last; current->link=NULL; delete temp; last = current; return; } void insertFront(nodeType*& front) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= front; front= newNode; return; } void insertBack(nodeType*& last) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= NULL; last->link= newNode; last = newNode; return; } void printList(nodeType*& first) { cout<<\"Inside printList...printing linked list...\ \"<info << \" \"; current = current->link; } cout< #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void dele.

Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf

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linkedlistwith animations.ppt

MuhammadShafi89

This assignment and the next (#5) involve design and development of a sequential non contiguous and dynamic datastructure called LinkedList. A linked list object is a container consisting of connected ListNode objects. As before, we are not going to use pre-fabricated classes from the c++ library, but construct the LinkedList ADT from scratch. The first step is construction and testing of the ListNode class. A ListNode object contains a data field and a pointer to the next ListNode object (note the recursive definition). #This assignment requires you to 1. Read the Assignment 4 Notes 2. Watch the Assignment 4 Support video 3. Implement the following methods of the ListNode class -custom constructor -setters for next pointer and data 4. Implement the insert and remove method in the main program 5. Scan the given template to find the above //TODO and implement the code needed //TODO in ListNodecpp.h file public: ListNode(T idata, ListNode<T> * newNext); public: void setNext(ListNode<T> * newNext); public: void setData(T newData); // TODO in main program void remove(ListNode<int> * &front,int value) void insert(ListNode<int> * &front,int value) # The driver is given ListNodeMain.cpp is given to you that does the following tests 1. Declares a pointer called front to point to a ListNode of datatype integer 2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked list. 3. Inserts ListNode with data 3 to the list 4. Removes node 1 and adds it back to test removing and adding the first element 5. Removes node 3 to test removing a middle node 6. Removes node 4 to test removing the last node 7. Attempt to remove a non existent node 8. Remove all existing nodes to empty the list 9. Insert node 4 and then node 1 to test if insertions preserve order 10.Print the list Main.cpp #include <iostream> #include "ListNodecpp.h" // REMEMBER each ListNode has two parts : a data field // and an address field. The address is either null or points to the next node //in the chain //Requires: integer value for searching, address of front //Effects: traverses the list node chain starting from front until the end comparing search value with listnode getData. Returns the original search value if found, if not adds +1 to indicate not found //Modifies: Nothing int search(ListNode<int> * front, int value); //Requires: integer value for inserting, address of front //Effects: creates a new ListNode with value and inserts in proper position (increasing order)in the chain. If chain is empty, adds to the beginning //Modifies: front, if node is added at the beginning. //Also changes the next pointer of the previous node to point to the //newly inserted list node. the next pointer of the newly inserted pointer //points to what was the next of the previous node. //This way both previous and current links are adjusted //******** NOTE the use of & in passing pointer to front as parameter - // Why do you think this is needed ?********** void insert(ListNode<int> * &fr.

This assignment and the next (#5) involve design and development of a.pdf

EricvtJFraserr

Need to be done in C Please Sorted number list implementation with linked lists Step 1: Inspect the Node.h file Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on the orange arrow next to main.cpp at the top of the coding window. The Node class has three member variables: a double data value, a pointer to the next node, and a pointer to the previous node. Each member variable is protected. So code outside of the class must use the provided getter and setter member functions to get or set a member variable. Node.h is read only, since no changes are required. Step 2: Implement the Insert() member function A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's Insert() member function. The function must create a new node with the parameter value, then insert the node into the proper sorted position in the linked list. Ex: Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList. The list is displayed after each insertion. Ex: If input is then output is: Try various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove() member function Implement the SortedNumberList class's Remove() member function. The function takes a parameter for the number to be removed from the list. If the number does not exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the number is removed from the list and true is returned. Uncomment the commented-out part in main() that reads a second input line and removes numbers from the list. Test in develop mode to ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is then output is: Main.cpp #include <iostream> #include <string> #include <vector> #include "Node.h" #include "SortedNumberList.h" using namespace std; void PrintList(SortedNumberList& list); vector<string> SpaceSplit(string source); int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin, inputLine); // Split on space character vector<string> terms = SpaceSplit(inputLine); // Insert each value and show the sorted list's contents after each insertion SortedNumberList list; for (auto term : terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl; list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin, inputLine); terms = SpaceSplit(inputLine); // Remove each value for (auto term : terms) { double number = stod(term); cout << "List after removing " << number << ": " << endl; list.Remove(number); PrintList(list); .

Need to be done in C Please Sorted number list implementation with.pdf

aathmaproducts

Need to be done in C++ Please Sorted number list implementation with linked lists Step 1: Inspect the Node.h file Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on the orange arrow next to main.cpp at the top of the coding window. The Node class has three member variables: a double data value, a pointer to the next node, and a pointer to the previous node. Each member variable is protected. So code outside of the class must use the provided getter and setter member functions to get or set a member variable. Node.h is read only, since no changes are required. Step 2: Implement the Insert() member function A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's Insert() member function. The function must create a new node with the parameter value, then insert the node into the proper sorted position in the linked list. Ex: Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList. The list is displayed after each insertion. Ex: If input is then output is: Try various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove() member function Implement the SortedNumberList class's Remove() member function. The function takes a parameter for the number to be removed from the list. If the number does not exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the number is removed from the list and true is returned. Uncomment the commented-out part in main() that reads a second input line and removes numbers from the list. Test in develop mode to ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is then output is: Main.cpp #include <iostream> #include <string> #include <vector> #include "Node.h" #include "SortedNumberList.h" using namespace std; void PrintList(SortedNumberList& list); vector<string> SpaceSplit(string source); int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin, inputLine); // Split on space character vector<string> terms = SpaceSplit(inputLine); // Insert each value and show the sorted list's contents after each insertion SortedNumberList list; for (auto term : terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl; list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin, inputLine); terms = SpaceSplit(inputLine); // Remove each value for (auto term : terms) { double number = stod(term); cout << "List after removing " << number << ": " << endl; list.Remove(number); PrintList(list).

Need to be done in C++ Please Sorted number list implementation wit.pdf

aathiauto

Inspect the class declaration for a doubly-linked list node in Node-h-.pdf

vishalateen

Ch17

Abbott

Linkedlist

Masud Parvaze

computer notes - Linked list inside computer memory

ecomputernotes

Provide copy constructor, destructor, and assignment operator for the IntList class that stores a collection of integers using linked list. class ListNode { int value; ListNode * next; }; class IntList { public: ... IntList(const IntList & other); ~IntList(); IntList& operator =( const IntList & other ) ... private: int num; //the number of ints stored. ListNode * first; }; Solution Hi, I have implemented all functionality. Please test it in your test program using namespace std; class ListNode { public: int value; ListNode * next; }; class IntList { public: IntList(); IntList(const IntList & other); ~IntList(); void operator =( const IntList & other); private: int num; //the number of ints stored. ListNode * first; }; IntList::IntList(const IntList & other){ IntList *ptr = new IntList(); ListNode *temp = other.first; ListNode *temp1 = ptr->first; ListNode *firstLocal = NULL; while(temp != NULL){ if(firstLocal == NULL){ firstLocal = temp; temp1 = firstLocal; } else{ temp1->next = temp; temp1 = temp; } temp = temp->next; } ptr->first = firstLocal; ptr->num = other.num; } IntList::~IntList(){ while(first != NULL){ ListNode *local = first; first = first->next; delete local; } } IntList::IntList(){ first = NULL; num = 0; } void IntList::operator =( const IntList & other){ first = other.first; num = other.num; } .

Provide copy constructor- destructor- and assignment operator for the.docx

todd921

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Array linked list.ppt

Waf1231

Please help solve this in C++. So the program is working fine but when submitting it, it gives me a code -11, and I believe the problem is that after inserting the numbers it removes them one by one until the last in the list, and when it tries to remove the last number in the list that is when it counters the problem. Below is the full code but you just need to change something in the SortedNumberList.h file under the bool remove function. 4.18 LAB: Sorted number list implementation with linked lists Step 1: Inspect the Node.h file Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on the orange arrow next to main.cpp at the top of the coding window. The Node class has three member variables: - a double data value, - a pointer to the next node, and - a pointer to the previous node. Each member variable is protected. So code outside of the class must use the provided getter and setter member functions to get or set a member variable. Node.h is read only, since no changes are required. Step 2: Implement the Insert() member function A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's Insert() member function. The function must create a new node with the parameter value, then insert the node into the proper sorted position in the linked list. Ex: Suppose a SortedNumberList's current list is 2347.2586, then Insert(33.5) is called. A new node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order and yielding: 2335.547.2586Step 3: Test in develop mode Code in main() takes a space- separated list of numbers and inserts each into a SortedNumberList. The list is displayed after each insertion. Ex: If input is 77154263.5 then output is: List after inserting 77 : 77 List after inserting 15 : 1577 List after inserting -42 : -421577 List after inserting 63.5: -421563.577 Try various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove() member function Implement the SortedNumberList class's Remove(0 member function. The function takes a parameter for the number to be removed from the list. If the number does not exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the number is removed from the list and true is returned. Uncomment the commented-out part in main() that reads a second input line and removes numbers from the list. Test in develop mode to ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is 841972841961 then output is: List after inserting 84: 84 List after inserting 72 : 7284 List after inserting 19: 1972 84 List after inserting 61: 1961 : 72 8 List after removing 19: 6172 84 List after removing 84: 6172Current file: main.cpp - // Insert each value and show the sorted List's contents after each insertion sortedNumberList list; for (auto term : terms) { doubl.

Please help solve this in C++ So the program is working fin.pdf

ankit11134

I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C. Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com. You can also call on +1 678 648 4277 for any assistance with C Homework.

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In the class we extensively discussed a node class called IntNode in which each linked list node contains an integer and each node is linked forward to the next element in the list. Implement a node class called DoublyIntNode in which each node contains an integer number and each node is linked not only forward to the next element in the list but also backward to the previous element in the list. Your implementation of DoublyIntNode should adapt and implement all the methods of IntNode including the following methods: Constructor for DoublyIntNode addNodeAfter, removeNodeAfter getData, setData getForeLink, setForeLink getBackLink, setBackLink listCopy listCopyWithTail listLength listPart listPosition listSearch IntNode and Node classes: public class IntNode{ private int data; private IntNode link; // methods here } public class Node { private E data; private Node link; // methods here } Solution program #include using namespace std; struct list { struct list *prev; int data; struct list *next; } *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL; class Dlist { public: void insert_beg() { list *addBeg = new list; cout << \"Enter value for the node:\" << endl; cin >> addBeg->data; if(first == NULL) { addBeg->prev = NULL; addBeg->next = NULL; first = addBeg; last = addBeg; cout << \"Linked list Created!\" << endl; } else { addBeg->prev = NULL; first->prev = addBeg; addBeg->next = first; first = addBeg; cout << \"Data Inserted at the beginning of the Linked list!\" << endl; } } void insert_end() { list *addEnd = new list; cout << \"Enter value for the node:\" << endl; cin >> addEnd->data; if(first == NULL) { addEnd->prev = NULL; addEnd->next = NULL; first = addEnd; last = addEnd; cout << \"Linked list Created!\" << endl; } else { addEnd->next = NULL; last->next = addEnd; addEnd->prev = last; last = addEnd; cout << \"Data Inserted at the end of the Linked list!\" << endl; } } void display() { node = first; cout << \"List of data in Linked list in Ascending order!\" << endl; while(node != NULL) { cout << node->data << endl; node = node->next; } node = last; cout << \"List of data in Linked list in Descending order!\" << endl; while(node != NULL) { cout << node->data << endl; node = node->prev; } } void del() { int count = 0, number, i; node = node1 = node2 = first; for(node = first; node != NULL; node = node->next) cout << \"Enter value for the node:\" << endl; count++; display(); cout << count << \" nodes available here!\" << endl; cout << \"Enter the node number which you want to delete:\" << endl; cin >> number; if(number != 1) { if(number < count && number > 0) { for(i = 2; i <= number; i++) node = node->next; for(i = 2; i <= number-1; i++) node1 = node1->next; for(i = 2; i <= number+1; i++) node2 = node2->next; node2->prev = node1; node1->next = node2; node->prev = NULL; node->next = NULL; node = NULL; } else if(number == count) { node = last; last = node->prev; last->next = NULL; node = NULL; } else cout << \"Invalid node.

In the class we extensively discussed a node class called IntNode in.pdf

arjunstores123

template <class T> struct nodeType { T data; nodeType *next; }; template <class T> class LinkedList { nodeType<T> *head, *tail; int count; public: LinkedList(); void insertFirst(T item); void insertLast(T item); void insertAt(T item, int pos); void print(); bool simplecompare(LinkedList<T> &rL) { if (count != rL.count) return false; nodeType<T> *cur, *rCur; for (cur = head, rCur = rL.head; cur != NULL; cur = cur->next, rCur = rCur->next) if (cur->data != rCur->data) return false; return true; } int compare(LinkedList<T> &rL); ~LinkedList(); }; //driver program: int main(void) { char item; LinkedList<char> list1, list2; cout << "Please enter the first list of characters" << "nPress Ctrl+Z to stop entering." << endl; cin >> item; while (!cin.eof()) { list1.insertLast(item); cin >> item; } cin.clear(); cout << "Please enter the second list of characters" << "nPress Ctrl+Z to stop entering." << endl; cin >> item; while (!cin.eof()) { list2.insertLast(item); cin >> item; } list1.print(); list2.print(); int result = list1.compare(list2); if (result == 0) cout << "The lists are same!n"; else if (result == -1) cout << "first list < second listn" << endl; else cout << "first list > second listn" << endl; return 0; } 1 Questions A simplified doublyLinkedList class is provided in lab03doublyLinkedList_template.h file on CATS. Solve the following questions by using that elass. 1. The definition of insertFirst(T item) function is missing. Complete it. 2. The definition of insertLast(T item) function is missing. Complete it. 3. The definition of insertAt(T item, int order) function is missing. Complete it. 4. Update print() function to print the list in forward direction. 5. The definition of deleteItem(T item) function is missing. Complete it. 6. Add an extractMax(T max) function to the doublyLinkedList class. The function must extract all nodes containing elements less than max from the list, and construct a new list using those nodes. After the function call, the original list must only have the nodes whose data fields are greater than max, while the new list is containing the smaller ones. The new list must be returned by the function. You're not allowed to delete and/or create new nodes. Your function must just move the subjected nodes from one list to the other. Let the following list be the original list: If the function is called as newList = myList.extractMax (30), then the newList becomes: 2 Assignment Implement a class to represent a circular linked list. You can directly adapt SinglyLinkedList class that we've already defined in linkedList.h. Only the following member functions will be defined for the class: - default constructor to set the pointer data members to NULL and count to 0 . - insertItem to insert a given item to the list. - deleteItem to remove a specific item from the list. Item may occur multiple times, thus the function must remove every occurrences of the item from the list. 1 - print to print the linked list from head to tail. .

template ltclass Tgt struct nodeType T data n.pdf

aceautomate

THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED HELP FIXING THIS CODE? THIS IS THE PROBLEM Write a program that allows the user to enter two positive integers and outputs their sum. Sounds simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a single variable. You may not assume any particular maximum number of digits. HERE IS THE CODE #include #include struct node /* Linked list node*/ { int data; struct node* next; }; struct node *newNode(int data) /* Function to create a new node with giving the data*/ { struct node *new_node = (struct node *) malloc(sizeof(struct node)); new_node->data = data; new_node->next = NULL; return new_node; } void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of the Doubly Linked List*/ { struct node* new_node = newNode(new_data); /*allocate a node*/ new_node->next = (*head_ref); /* link the old list off to the new node*/ (*head_ref) = new_node; /*move the head to point to the new node*/ } /* Adding the contents of two linked lists and return the head node of resultant list*/ struct node* addTwoLists (struct node* first, struct node* second) { struct node* res = NULL; /* res is head node of the resultant list*/ struct node *temp, *prev = NULL; int carry = 0, sum; while (first != NULL || second != NULL) /*while both the lists exists*/ { /* Calculate value of next digit in resultant list. // The next digit is sum of following things // (i) Carry // (ii) Next digit of first list (if there is a next digit) // (ii) Next digit of second list (if there is a next digit)*/ sum = carry + (first? first->data: 0) + (second? second->data: 0); carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/ sum = sum % 10; /*update sum if it is greater than 10*/ temp = newNode(sum); /*Create a new node with sum as data*/ if(res == NULL) /*if this is the first node then set it as head of the resultant list*/ res = temp; else /* If this is not the first node then connect it to the rest.*/ prev->next = temp; prev = temp; /* Set prev for next insertion*/ if (first) first = first->next; /* Move first pointers to next node*/ if (second) second = second->next; /*Move second pointer to the next node*/ } if (carry > 0) temp->next = newNode(carry); return res; /* return head of the resultant list*/ } void printList(struct node *node) /* function to print a linked list*/ { while(node != NULL) { printf(\"%d \", node->data); node = node->next; } printf(\"\ \"); } int main(void) /* program to test above function*/ { struct node* res = NULL; struct node* first = NULL; struct node* second = NULL; printf(\"Enter first positive integer: \"); scanf(\"%d\",&first); printList(first); printf(\"Enter second positive integer: \"); scanf(\"%d\",&second); printList(second); /*Add the two lists and see result*/ res = addTwoLists(first, second); printf(\"Sum is: %d\"); printList(res); return 0; } Solution #include #include typedef struct Node { int da.

THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdf

fathimahardwareelect

Loops and Arrays Objectives: Arrays are a series of elements consisting of the same type (For ex: all integers), in a contiguous chunk of memory. The elements can be individually referenced by indexing the array. You must specify the type of data stored in an array, and each element in any array must be of the same type. An array has a static size -- they cannot grow any larger than the size you tell it to be when you create it. To access the value at that index of the array: for (int i = 0; i < 10; i++){ cout<< intArray[i]<< endl; } To access the memory address of the array element: for (int i = 0; i < 10; i++){ cout << intArray + i << endl; } Creating an Array and Initializing When you declare an array, you will get an uninitialized section of memory. If you want to create an array of numbers, you would do: int intNumbers [10]; double dblNumbers[10]; Then, putting element in the array can be set up by using the index of the array element you want to change: intNumbers[0] = 3; intNumbers[1] = 5; intNumbers[2] = 6; intNumbers[3] = 8; 1. Write a program that uses a for loop. 2. Declare and initialize and array. 3. Practice the array operations print and modify. When you create an array, you do so to capture a group of items that all need to be treated separately, but also need to grouped together for some purpose. For example, when you think about a song, each note in the song is a separate sound, but they all need to be included together in a certain order to make up the song. To initialize the array: int intNum [5] = {16, 3, 20, 4, 21}; (Hint: notice the syntax difference initializing this array versus the one above) Retrieving/Adding/Changing elements To access or retrieve individual elements in an array, the syntax is square brackets and the element index (starting from 0): intNumbers[0]; will be the first item in the intNumbers array. intNumbers[1]; will be the second item in the intNumbers array. Below is an example of a basic 2D array. It shows how we access certain elements shown in the arrayName[row][column] format. This will be helpful for a future assignment. We can change the values in the array using the index of the individual items, such as Example 1: int intNumbers[2]; intNumbers[0] = 5; intNumbers[1] = 7; intNumbers[1] = intNumbers[1] * 2 cout << intNumbers[1] << endl; Example 2: //this will print the value 14 intNumber[1] = 10; Example 3: for (int i = 0; i < 10; i++){ intArray[i] = i; cout << intArray[i] << endl; //this will update the value to 10 at that index //will set what the values are in that position //will print out the value of i at each index } TO DO: Create an array in your main function 1) Create an array of 20 doubles, using a variable name of your choosing. Assign values to your array using a for loop: for (int i = 0; i < 20; i++) myDoubles[i] = i; where myDoubles is the name of the variable created. 2) Print out the values in another for loop using: cout << “Stuff to print” << endl; 3) Now, using your array an.

Loops and ArraysObjectivesArrays are a series of elements consi.pdf

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Write an algorithm that reads a list of integers from the keyboard, creates a list of them using linked list implementation, and prints the result Solution /* Algorithm: Implementation of linked list. Create a node type class which will hold an integer and next pointer to point to another node. Create a constructor which will construct an object of type node with the integer type data as the only parameter and initializing next pointer to NULL. Create LinkedList class which will only have head pointer. Create a constructor which will initialize this head pointer to NULL. Create a append method which will recieve an input of type integer from the user and append it to LinkedList using below steps: 1.Create a Node type object. 1.IF head is NULL assign a Node type object created in 1st step. 2.IF head is not NULL then traverse to the end of the linked list till you found a Node which has next pointer set to NULL. 3.Add Node type object created in first step to the next pointer of last node. Create a print method which will traverse the list from the head of the linked list to the last node(Node with next pointer NULL) and while traversing it will keep printing the node data. Get the userinput: Ask user for integer continously till user input -1 and append all the integers to the linked list. */ PROGRAM: #include using namespace std; class Node { public: int data; Node *next; Node(int data) { this->data = data; this->next = NULL; } }; class LinkedList { private: Node *head; public: LinkedList() { head = NULL; } void addToFront(int data) { Node *temp = new Node(data); if(head == NULL) head = temp; else { temp->next = head; head = temp; } } void append(int data) { Node *temp = new Node(data); Node *current = head; if(current == NULL) { head = temp; return; } while(current->next != NULL) { current = current->next; } current->next = temp; } void print() { Node *current = head; if(current == NULL) cout << \"No element in list. \ \"; while(current != NULL) { cout << current->data << \" \"; current = current->next; } cout << endl; } void deleteLinkedList() { Node *prev; Node *current = head; while(current!=NULL) { prev = current; current = current->next; delete prev; } } void deleteLastNode() { Node *current = head; Node *prev = NULL; if(current == NULL) return; while(current->next != NULL) { prev = current; current = current->next; } if(prev == NULL) { delete current; head = NULL; } else { prev->next = NULL; delete current; } } ~LinkedList() { deleteLinkedList(); } }; int main() { LinkedList list; int data; while(1) { cout << \"Enter the integer(-1 to Quit) : \"; cin >> data; if(data==-1) break; list.append(data); } cout << \"Content of LinkedList is : \"; list.print(); return 0; } OUTPUT: Enter the integer(-1 to Quit) : 1 Enter the integer(-1 to Quit) : 2 Enter the integer(-1 to Quit) : 3 Enter the integer(-1 to Quit) : 4 Enter the integer(-1 to Quit) : -1 Content of LinkedList is : 1 2 3 4.

Write an algorithm that reads a list of integers from the keyboard, .pdf

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Assignment is: \"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\" How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual Studios using the linked list below with what is being asked? Please need help Linked list : #include #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *first, *last; int num; createList(first, last); int choice; while(true) { cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\ \"; cout<<\"Enter your choice: \"; cin>>choice; switch(choice) { case 1: insertFront(first); break; case 2: insertBack(last); break; case 3: deleteFirst(first); break; case 4: deleteLast(last, first); break; case 5: printList(first); break; case 6: return 0; default: cout<<\"Invalid menu option. Try again.\"<>number; while (number != -999) { newNode = new nodeType; // create new node newNode->info = number; newNode->link = NULL; if (first == NULL) { first = newNode; last = newNode; } else { last->link = newNode; last = newNode; } cout<<\"Enter an integer (-999 to stop): \"; cin>>number; } // end of while-loop } // end of build list function void deleteFirst(nodeType*& first) { nodeType *temp; temp= first; first= temp->link; delete temp; return; } void deleteLast(nodeType*& last, nodeType* current) { nodeType *temp; while(current->link != NULL) { temp=current; current=current->link; } temp=last; current->link=NULL; delete temp; last = current; return; } void insertFront(nodeType*& front) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= front; front= newNode; return; } void insertBack(nodeType*& last) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= NULL; last->link= newNode; last = newNode; return; } void printList(nodeType*& first) { cout<<\"Inside printList...printing linked list...\ \"<info << \" \"; current = current->link; } cout< #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *firs.

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