In C language Given an IntNode struct and the operating func.pdf
•
0 likes•3 views
In C language Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list: 1. IntNode* IntNode_GetNth(IntNode* firstNode, int n )- Return a pointer to the nth node of the list starting at firstNode. 2. void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values. 3. int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode. Note: The code for IntNode_Create 0 provided here differs from the code shown in the book. The given main0 performs various actions to test IntNode_GetNth 0 , IntNode_PrintList 0 , and IntNode_SumList 0 . main() reads 5 integers from a user: 1. The number of nodes to be added to a new list 2. The value of the first node of the list 3. An increment between the values of two consecutive nodes. 4. A value of a new node 5. The position of a node after which the new node will be added, with 1 indicating the first node Ex: If the input is:.
Report
Share
Report
Share
Download to read offline
Recommended
IN C CODEGiven an IntNode struct and the operating functions for a.pdf
In C ++
Complete ReplaceLevel() to output "levelPointer is null." if levelPointer is null. Otherwise,
assign levelValue to the variable pointed to by levelPointer. End with a newline.
Ex: If the input is Y A, then the output is:
Level is A.
#include
using namespace std;
void ReplaceLevel(char* levelPointer, char levelValue) {
/* Your code goes here */
}
int main() {
char level;
char* levelPointer;
char action;
char value;
level = 'Z';
cin >> action;
cin >> value;
if (action == 'Y') {
levelPointer = &level;
}
else {
levelPointer = nullptr;
}
ReplaceLevel(levelPointer, value);
cout << "Level is " << level << "." << endl;
return 0;
}.
Given an IntNode struct and the operating functions for a linked list-.pdf
Given an IntNode struct and the operating functions for a linked list, complete the following
functions to extend the functionality of the linked list:
IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list
starting at firstNode.
void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of
the list starting at firstNode. Do not add extra space characters in between values.
int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at
firstNode.
Note: The code for IntNode_Create() provided here differs from the code shown in the book.
The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and
IntNode_SumList().
main() reads 5 integers from a user:
The number of nodes to be added to a new list
The value of the first node of the list
An increment between the values of two consecutive nodes.
A value of a new node
The position of a node after which the new node will be added, with 1 indicating the first node
Ex: If the input is:
the output is:
Here's the code
#include <stdio.h>
#include <stdlib.h>
typedef struct IntNode_struct {
int dataVal;
struct IntNode_struct* nextNodePtr;
} IntNode;
// Allocate a node for initData
IntNode* IntNode_Create (int initData) {
IntNode* newNode = (IntNode*)malloc(sizeof(IntNode));
newNode->dataVal = initData;
newNode->nextNodePtr = NULL;
return newNode;
}
/* Insert newNode after node.
Before: thisNode -- next
After: thisNode -- newNode -- next
*/
void IntNode_InsertAfter (IntNode* thisNode, IntNode* newNode) {
IntNode* tmpNext = NULL;
tmpNext = thisNode->nextNodePtr; // Remember next
thisNode->nextNodePtr = newNode; // this -- new -- ?
newNode->nextNodePtr = tmpNext; // this -- new -- next
}
// Print dataVal
void IntNode_PrintNodeData(IntNode* thisNode) {
printf("%d ", thisNode->dataVal);
}
// Grab location pointed by nextNodePtr
IntNode* IntNode_GetNext(IntNode* thisNode) {
return thisNode->nextNodePtr;
}
/* ******** New functions ********/
// Return the length of the list
int IntNode_Length(IntNode* firstNode) {
int length = 0;
IntNode* currentNode = firstNode;
while(currentNode != NULL) {
++length;
currentNode = currentNode->nextNodePtr;
}
return length;
}
// Return the Nth element of the list. First node is 1.
IntNode* IntNode_GetNth(IntNode* firstNode, int pos) {
/* Type your code here. */
}
// Print the entire list starting at firstNode
void IntNode_PrintList(IntNode* firstNode) {
/* Type your code here. */
}
// Sum the numbers in the list
int IntNode_SumList(IntNode* firstNode) {
/* Type your code here. */
}
int main(void) {
IntNode* firstNode = NULL;
IntNode* lastNode = NULL;
IntNode* newNode = NULL;
IntNode* curNode = NULL;
int listSize; // how many integers to read
int increment; // increment between consecutive node values
int firstNum; // first node value
// New node for newNum will be inserted after position newPos (first node = 1)
int newPos;
int newNum;
int i;
.
8-25 LAB- Simple linked list Given an IntNode struct and the operating.docx
8.25 LAB: Simple linked list
Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list:
IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list starting at firstNode.
void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values.
int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode.
Note: The code for IntNode_Create() provided here differs from the code shown in the book.
The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and IntNode_SumList().
main() reads 5 integers from a user:
The number of nodes to be added to a new list
The value of the first node of the list
An increment between the values of two consecutive nodes.
A value of a new node
The position of a node after which the new node will be added, with 1 indicating the first node
Ex: If the input is:
the output is:
#include <stdio.h>
#include <stdlib.h>
typedef struct IntNode_struct {
int dataVal;
struct IntNode_struct* nextNodePtr;
} IntNode;
// Allocate a node for initData
IntNode* IntNode_Create (int initData) {
IntNode* newNode = (IntNode*)malloc(sizeof(IntNode));
newNode->dataVal = initData;
newNode->nextNodePtr = NULL;
return newNode;
}
/* Insert newNode after node.
Before: thisNode -- next
After: thisNode -- newNode -- next
*/
void IntNode_InsertAfter (IntNode* thisNode, IntNode* newNode) {
IntNode* tmpNext = NULL;
tmpNext = thisNode->nextNodePtr; // Remember next
thisNode->nextNodePtr = newNode; // this -- new -- ?
newNode->nextNodePtr = tmpNext; // this -- new -- next
}
// Print dataVal
void IntNode_PrintNodeData(IntNode* thisNode) {
printf("%d ", thisNode->dataVal);
}
// Grab location pointed by nextNodePtr
IntNode* IntNode_GetNext(IntNode* thisNode) {
return thisNode->nextNodePtr;
}
/* ******** New functions ********/
// Return the length of the list
int IntNode_Length(IntNode* firstNode) {
int length = 0;
IntNode* currentNode = firstNode;
while(currentNode != NULL) {
++length;
currentNode = currentNode->nextNodePtr;
}
return length;
}
// Return the Nth element of the list. First node is 1.
IntNode* IntNode_GetNth(IntNode* firstNode, int pos) {
/* Type your code here. */
}
// Print the entire list starting at firstNode
void IntNode_PrintList(IntNode* firstNode) {
/* Type your code here. */
}
// Sum the numbers in the list
int IntNode_SumList(IntNode* firstNode) {
/* Type your code here. */
}
int main(void) {
IntNode* firstNode = NULL;
IntNode* lastNode = NULL;
IntNode* newNode = NULL;
IntNode* curNode = NULL;
int listSize; // how many integers to read
int increment; // increment between consecutive node values
int firstNum; // first node value
// New node for newNum will be inserted after pos.
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdf
In C++ please, do not alter node.h
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
77 15 -42 63.5
then output is:
List after inserting 77:
77 List after inserting 15:
15 77
List after inserting -42:
-42 15 77
List after inserting 63.5:
-42 15 63.5 77
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
84 72 19 61 19 84
then output is:
List after inserting 84:
84
List after inserting 72:
72 84
List after inserting 19:
19 72 84
List after inserting 61:
19 61 72 84
List after removing 19:
61 72 84
List after removing 84:
61 72
Code below:
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = Space.
C++ Please write the whole code that is needed for this assignment- wr.docx
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
17 linkedlist (1)
This document discusses linked lists and their implementation in C. It begins by describing the differences between array-based and linked list implementations. Specifically, it notes that linked lists use dynamic memory allocation and pointers to connect nodes rather than contiguous memory blocks. The document then covers creating and traversing linked lists using nodes with data fields and next pointers. It provides code examples for inserting, finding, deleting and destroying nodes in a singly linked list. Finally, it briefly lists some other common linked list operations like sorting, reversing and finding min/max elements.
C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdf
C++: Doubly-Linked Lists
The goal of the exercise is to implement a class List of doubly- linked lists.
My goal is to implement the class in a file doubly-linked.cpp.
The class List implements lists using the following structures for list ele- ments:
struct Node { int val ;
Node next;
Node prev; };
Each Node contains a value (an integer) and two pointers: one meant to point to the next element
of the list and one meant to point to the previous element in the list. The class provides the
following methods that you need to implement:
• A constructor and a destructor, with no arguments;
• void insert(int n): insert an integer at the end of the list;
• void reverse(): reverse the list;
• void print(): print the list to cout in the same format as the input (i.e. integers separated by
spaces);
doubly-linked.h
#ifndef __dll__
#define __dll__
#include
using namespace std;
// Basic structure to store elements of a list
struct Node {
int val; // contains the value
Node * next; // pointer to the next element in the list
Node * prev; // pointer to the previous element in the list
};
// Class List
class List {
public:
List(void); // Constructor
~List(void); // Destructor
void insert(int n); // This should insert n in the list
void reverse(void); // This should reverse the list
void print(void); // This shoiuld print the list
private:
Node * first; // Pointer to the first (if any) element in the list
};
#endif
main.cpp
#include
#include \"doubly-linked.h\"
using namespace std;
int main(void){
List l;
int n;
while(cin >> n){
l.insert(n);
}
// Print list as read from cin
l.print();
// Reverse the list and print it
l.reverse();
l.print();
// Reverse again and print it
l.reverse();
l.print();
return 0;
}
Solution
#include
using namespace std;
/* Linked list structure */
struct list {
struct list *prev;
int data;
struct list *next;
} *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class linkedlist {
public:
/* Function for create/insert node at the beginning of Linked list */
void insrt_frnt() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
/* Function for create/insert node at the end of Linked list */
void insrt_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
/* Function for Display Linked list */
void display() {
node = first;
cout << \"List of data in L.
Recommended
IN C CODEGiven an IntNode struct and the operating functions for a.pdf
In C ++
Complete ReplaceLevel() to output "levelPointer is null." if levelPointer is null. Otherwise,
assign levelValue to the variable pointed to by levelPointer. End with a newline.
Ex: If the input is Y A, then the output is:
Level is A.
#include
using namespace std;
void ReplaceLevel(char* levelPointer, char levelValue) {
/* Your code goes here */
}
int main() {
char level;
char* levelPointer;
char action;
char value;
level = 'Z';
cin >> action;
cin >> value;
if (action == 'Y') {
levelPointer = &level;
}
else {
levelPointer = nullptr;
}
ReplaceLevel(levelPointer, value);
cout << "Level is " << level << "." << endl;
return 0;
}.
Given an IntNode struct and the operating functions for a linked list-.pdf
Given an IntNode struct and the operating functions for a linked list, complete the following
functions to extend the functionality of the linked list:
IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list
starting at firstNode.
void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of
the list starting at firstNode. Do not add extra space characters in between values.
int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at
firstNode.
Note: The code for IntNode_Create() provided here differs from the code shown in the book.
The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and
IntNode_SumList().
main() reads 5 integers from a user:
The number of nodes to be added to a new list
The value of the first node of the list
An increment between the values of two consecutive nodes.
A value of a new node
The position of a node after which the new node will be added, with 1 indicating the first node
Ex: If the input is:
the output is:
Here's the code
#include <stdio.h>
#include <stdlib.h>
typedef struct IntNode_struct {
int dataVal;
struct IntNode_struct* nextNodePtr;
} IntNode;
// Allocate a node for initData
IntNode* IntNode_Create (int initData) {
IntNode* newNode = (IntNode*)malloc(sizeof(IntNode));
newNode->dataVal = initData;
newNode->nextNodePtr = NULL;
return newNode;
}
/* Insert newNode after node.
Before: thisNode -- next
After: thisNode -- newNode -- next
*/
void IntNode_InsertAfter (IntNode* thisNode, IntNode* newNode) {
IntNode* tmpNext = NULL;
tmpNext = thisNode->nextNodePtr; // Remember next
thisNode->nextNodePtr = newNode; // this -- new -- ?
newNode->nextNodePtr = tmpNext; // this -- new -- next
}
// Print dataVal
void IntNode_PrintNodeData(IntNode* thisNode) {
printf("%d ", thisNode->dataVal);
}
// Grab location pointed by nextNodePtr
IntNode* IntNode_GetNext(IntNode* thisNode) {
return thisNode->nextNodePtr;
}
/* ******** New functions ********/
// Return the length of the list
int IntNode_Length(IntNode* firstNode) {
int length = 0;
IntNode* currentNode = firstNode;
while(currentNode != NULL) {
++length;
currentNode = currentNode->nextNodePtr;
}
return length;
}
// Return the Nth element of the list. First node is 1.
IntNode* IntNode_GetNth(IntNode* firstNode, int pos) {
/* Type your code here. */
}
// Print the entire list starting at firstNode
void IntNode_PrintList(IntNode* firstNode) {
/* Type your code here. */
}
// Sum the numbers in the list
int IntNode_SumList(IntNode* firstNode) {
/* Type your code here. */
}
int main(void) {
IntNode* firstNode = NULL;
IntNode* lastNode = NULL;
IntNode* newNode = NULL;
IntNode* curNode = NULL;
int listSize; // how many integers to read
int increment; // increment between consecutive node values
int firstNum; // first node value
// New node for newNum will be inserted after position newPos (first node = 1)
int newPos;
int newNum;
int i;
.
8-25 LAB- Simple linked list Given an IntNode struct and the operating.docx
8.25 LAB: Simple linked list
Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list:
IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list starting at firstNode.
void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values.
int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode.
Note: The code for IntNode_Create() provided here differs from the code shown in the book.
The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and IntNode_SumList().
main() reads 5 integers from a user:
The number of nodes to be added to a new list
The value of the first node of the list
An increment between the values of two consecutive nodes.
A value of a new node
The position of a node after which the new node will be added, with 1 indicating the first node
Ex: If the input is:
the output is:
#include <stdio.h>
#include <stdlib.h>
typedef struct IntNode_struct {
int dataVal;
struct IntNode_struct* nextNodePtr;
} IntNode;
// Allocate a node for initData
IntNode* IntNode_Create (int initData) {
IntNode* newNode = (IntNode*)malloc(sizeof(IntNode));
newNode->dataVal = initData;
newNode->nextNodePtr = NULL;
return newNode;
}
/* Insert newNode after node.
Before: thisNode -- next
After: thisNode -- newNode -- next
*/
void IntNode_InsertAfter (IntNode* thisNode, IntNode* newNode) {
IntNode* tmpNext = NULL;
tmpNext = thisNode->nextNodePtr; // Remember next
thisNode->nextNodePtr = newNode; // this -- new -- ?
newNode->nextNodePtr = tmpNext; // this -- new -- next
}
// Print dataVal
void IntNode_PrintNodeData(IntNode* thisNode) {
printf("%d ", thisNode->dataVal);
}
// Grab location pointed by nextNodePtr
IntNode* IntNode_GetNext(IntNode* thisNode) {
return thisNode->nextNodePtr;
}
/* ******** New functions ********/
// Return the length of the list
int IntNode_Length(IntNode* firstNode) {
int length = 0;
IntNode* currentNode = firstNode;
while(currentNode != NULL) {
++length;
currentNode = currentNode->nextNodePtr;
}
return length;
}
// Return the Nth element of the list. First node is 1.
IntNode* IntNode_GetNth(IntNode* firstNode, int pos) {
/* Type your code here. */
}
// Print the entire list starting at firstNode
void IntNode_PrintList(IntNode* firstNode) {
/* Type your code here. */
}
// Sum the numbers in the list
int IntNode_SumList(IntNode* firstNode) {
/* Type your code here. */
}
int main(void) {
IntNode* firstNode = NULL;
IntNode* lastNode = NULL;
IntNode* newNode = NULL;
IntNode* curNode = NULL;
int listSize; // how many integers to read
int increment; // increment between consecutive node values
int firstNum; // first node value
// New node for newNum will be inserted after pos.
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdf
In C++ please, do not alter node.h
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
77 15 -42 63.5
then output is:
List after inserting 77:
77 List after inserting 15:
15 77
List after inserting -42:
-42 15 77
List after inserting 63.5:
-42 15 63.5 77
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
84 72 19 61 19 84
then output is:
List after inserting 84:
84
List after inserting 72:
72 84
List after inserting 19:
19 72 84
List after inserting 61:
19 61 72 84
List after removing 19:
61 72 84
List after removing 84:
61 72
Code below:
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = Space.
C++ Please write the whole code that is needed for this assignment- wr.docx
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
17 linkedlist (1)
This document discusses linked lists and their implementation in C. It begins by describing the differences between array-based and linked list implementations. Specifically, it notes that linked lists use dynamic memory allocation and pointers to connect nodes rather than contiguous memory blocks. The document then covers creating and traversing linked lists using nodes with data fields and next pointers. It provides code examples for inserting, finding, deleting and destroying nodes in a singly linked list. Finally, it briefly lists some other common linked list operations like sorting, reversing and finding min/max elements.
C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdf
C++: Doubly-Linked Lists
The goal of the exercise is to implement a class List of doubly- linked lists.
My goal is to implement the class in a file doubly-linked.cpp.
The class List implements lists using the following structures for list ele- ments:
struct Node { int val ;
Node next;
Node prev; };
Each Node contains a value (an integer) and two pointers: one meant to point to the next element
of the list and one meant to point to the previous element in the list. The class provides the
following methods that you need to implement:
• A constructor and a destructor, with no arguments;
• void insert(int n): insert an integer at the end of the list;
• void reverse(): reverse the list;
• void print(): print the list to cout in the same format as the input (i.e. integers separated by
spaces);
doubly-linked.h
#ifndef __dll__
#define __dll__
#include
using namespace std;
// Basic structure to store elements of a list
struct Node {
int val; // contains the value
Node * next; // pointer to the next element in the list
Node * prev; // pointer to the previous element in the list
};
// Class List
class List {
public:
List(void); // Constructor
~List(void); // Destructor
void insert(int n); // This should insert n in the list
void reverse(void); // This should reverse the list
void print(void); // This shoiuld print the list
private:
Node * first; // Pointer to the first (if any) element in the list
};
#endif
main.cpp
#include
#include \"doubly-linked.h\"
using namespace std;
int main(void){
List l;
int n;
while(cin >> n){
l.insert(n);
}
// Print list as read from cin
l.print();
// Reverse the list and print it
l.reverse();
l.print();
// Reverse again and print it
l.reverse();
l.print();
return 0;
}
Solution
#include
using namespace std;
/* Linked list structure */
struct list {
struct list *prev;
int data;
struct list *next;
} *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class linkedlist {
public:
/* Function for create/insert node at the beginning of Linked list */
void insrt_frnt() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
/* Function for create/insert node at the end of Linked list */
void insrt_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
/* Function for Display Linked list */
void display() {
node = first;
cout << \"List of data in L.
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is :
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Do not work
together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print-
screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\"
How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void dele.
linkedlistwith animations.ppt
This document discusses linked lists and operations on them such as insertion and removal of nodes. It begins by showing the node declarations for a linked list, where each node contains a data field and a link field pointing to the next node. It then demonstrates how to insert a new node at the front of the list by allocating a new node, setting its data and link fields, and adjusting the head pointer. The document also provides pseudocode for inserting and removing nodes from linked lists in general cases.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list);
.
Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list).
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: a double data value, a pointer to the next node, and a pointer to the previous
node. Each member variable is protected. So code outside of the class must use the provided
getter and setter member functions to get or set a member variable. Node.h is read only, since no
changes are required. Step 2: Implement the Insert() member function A class for a sorted,
doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's
Insert() member function. The function must create a new node with the parameter value, then
insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after
inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove() member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Ch17
This document describes linked lists and operations on linked lists in C++. It discusses the composition of linked lists as series of connected nodes where each node contains data and a pointer to the next node. Common linked list operations like appending, inserting, traversing and displaying nodes are presented with pseudocode algorithms and C++ code implementations. Functions for appending nodes to the end of the list, inserting nodes in the proper sorted position, and traversing the list to display node values are demonstrated through example programs.
Linkedlist
Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.
computer notes - Linked list inside computer memory
The document discusses linked lists and their implementation in C++. It contains the following key points:
1) A linked list stores data non-contiguously in memory by chaining together nodes that contain a data element and a pointer to the next node. The head pointer points to the first node.
2) To create a new node, the Node class constructor is called and passed the data element. This allocates memory and returns a pointer to the new node.
3) To insert a new node, its next pointer is set to the next node of the current node. The current node's next pointer is then set to the new node.
4) The List class manages the linked list by
Provide copy constructor- destructor- and assignment operator for the.docx
Provide copy constructor, destructor, and assignment operator for the IntList class that stores a collection of integers using linked list.
class ListNode {
int value;
ListNode * next;
};
class IntList {
public: ...
IntList(const IntList & other);
~IntList();
IntList& operator =( const IntList & other ) ...
private:
int num; //the number of ints stored.
ListNode * first;
};
Solution
Hi, I have implemented all functionality.
Please test it in your test program
using namespace std;
class ListNode {
public:
int value;
ListNode * next;
};
class IntList {
public:
IntList();
IntList(const IntList & other);
~IntList();
void operator =( const IntList & other);
private:
int num; //the number of ints stored.
ListNode * first;
};
IntList::IntList(const IntList & other){
IntList *ptr = new IntList();
ListNode *temp = other.first;
ListNode *temp1 = ptr->first;
ListNode *firstLocal = NULL;
while(temp != NULL){
if(firstLocal == NULL){
firstLocal = temp;
temp1 = firstLocal;
}
else{
temp1->next = temp;
temp1 = temp;
}
temp = temp->next;
}
ptr->first = firstLocal;
ptr->num = other.num;
}
IntList::~IntList(){
while(first != NULL){
ListNode *local = first;
first = first->next;
delete local;
}
}
IntList::IntList(){
first = NULL;
num = 0;
}
void IntList::operator =( const IntList & other){
first = other.first;
num = other.num;
}
.
C Exam Help
I am Gabriel C. I am a C Exam Expert at programmingexamhelp.com. I hold a PhD. in Business analyst of Information Technology, Montreal College of Information Technology, Canada. I have been helping students with their exams for the past 8 years. You can hire me to take your exam in C.
Visit programmingexamhelp.com or email support@programmingexamhelp.com. You can also call on +1 678 648 4277 for any assistance with the C Exam.
Array linked list.ppt
This document discusses linked lists and their implementation. It begins with an overview of linked lists and their basic operations like insertion, deletion, and traversal. It then covers the implementation of a linked list using classes for the Node and List, including methods for insertion, deletion, searching, printing, and destroying the list. Examples are provided to demonstrate how to insert and delete nodes at different positions in the linked list. The document concludes with a brief discussion of variations like circular linked lists.
Please help solve this in C++ So the program is working fin.pdf
Please help solve this in C++. So the program is working fine but when submitting it, it gives me a
code -11, and I believe the problem is that after inserting the numbers it removes them one by one
until the last in the list, and when it tries to remove the last number in the list that is when it
counters the problem. Below is the full code but you just need to change something in the
SortedNumberList.h file under the bool remove function.
4.18 LAB: Sorted number list implementation with linked lists Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on
the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: - a double data value, - a pointer to the next node, and - a pointer to the
previous node. Each member variable is protected. So code outside of the class must use the
provided getter and setter member functions to get or set a member variable. Node.h is read only,
since no changes are required. Step 2: Implement the Insert() member function A class for a
sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList
class's Insert() member function. The function must create a new node with the parameter value,
then insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 2347.2586, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 2335.547.2586Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77154263.5 then output is: List after inserting 77 : 77 List after
inserting 15 : 1577 List after inserting -42 : -421577 List after inserting 63.5: -421563.577 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove(0 member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is
841972841961 then output is: List after inserting 84: 84 List after inserting 72 : 7284 List after
inserting 19: 1972 84 List after inserting 61: 1961 : 72 8 List after removing 19: 6172 84 List after
removing 84: 6172Current file: main.cpp - // Insert each value and show the sorted List's contents
after each insertion sortedNumberList list; for (auto term : terms) { doubl.
C Homework Help
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com.
You can also call on +1 678 648 4277 for any assistance with C Homework.
In the class we extensively discussed a node class called IntNode in.pdf
In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
template ltclass Tgt struct nodeType T data n.pdf
template <class T>
struct nodeType
{
T data;
nodeType *next;
};
template <class T>
class LinkedList {
nodeType<T> *head, *tail;
int count;
public:
LinkedList();
void insertFirst(T item);
void insertLast(T item);
void insertAt(T item, int pos);
void print();
bool simplecompare(LinkedList<T> &rL)
{
if (count != rL.count)
return false;
nodeType<T> *cur, *rCur;
for (cur = head, rCur = rL.head; cur != NULL; cur = cur->next, rCur = rCur->next)
if (cur->data != rCur->data)
return false;
return true;
}
int compare(LinkedList<T> &rL);
~LinkedList();
};
//driver program:
int main(void)
{
char item;
LinkedList<char> list1, list2;
cout << "Please enter the first list of characters"
<< "nPress Ctrl+Z to stop entering." << endl;
cin >> item;
while (!cin.eof()) {
list1.insertLast(item);
cin >> item;
}
cin.clear();
cout << "Please enter the second list of characters"
<< "nPress Ctrl+Z to stop entering." << endl;
cin >> item;
while (!cin.eof()) {
list2.insertLast(item);
cin >> item;
}
list1.print();
list2.print();
int result = list1.compare(list2);
if (result == 0)
cout << "The lists are same!n";
else if (result == -1)
cout << "first list < second listn" << endl;
else cout << "first list > second listn" << endl;
return 0;
}
1 Questions A simplified doublyLinkedList class is provided in lab03doublyLinkedList_template.h
file on CATS. Solve the following questions by using that elass. 1. The definition of insertFirst(T
item) function is missing. Complete it. 2. The definition of insertLast(T item) function is missing.
Complete it. 3. The definition of insertAt(T item, int order) function is missing. Complete it. 4.
Update print() function to print the list in forward direction. 5. The definition of deleteItem(T item)
function is missing. Complete it. 6. Add an extractMax(T max) function to the doublyLinkedList
class. The function must extract all nodes containing elements less than max from the list, and
construct a new list using those nodes. After the function call, the original list must only have the
nodes whose data fields are greater than max, while the new list is containing the smaller ones.
The new list must be returned by the function. You're not allowed to delete and/or create new
nodes. Your function must just move the subjected nodes from one list to the other. Let the
following list be the original list: If the function is called as newList = myList.extractMax (30), then
the newList becomes: 2 Assignment Implement a class to represent a circular linked list. You can
directly adapt SinglyLinkedList class that we've already defined in linkedList.h. Only the following
member functions will be defined for the class: - default constructor to set the pointer data
members to NULL and count to 0 . - insertItem to insert a given item to the list. - deleteItem to
remove a specific item from the list. Item may occur multiple times, thus the function must remove
every occurrences of the item from the list. 1 - print to print the linked list from head to tail. .
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdf
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED
HELP FIXING THIS CODE?
THIS IS THE PROBLEM
Write a program that allows the user to enter two positive integers and outputs their sum. Sounds
simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a
single variable. You may not assume any particular maximum number of digits.
HERE IS THE CODE
#include
#include
struct node /* Linked list node*/
{
int data;
struct node* next;
};
struct node *newNode(int data) /* Function to create a new node with giving the data*/
{
struct node *new_node = (struct node *) malloc(sizeof(struct node));
new_node->data = data;
new_node->next = NULL;
return new_node;
}
void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of
the Doubly Linked List*/
{
struct node* new_node = newNode(new_data); /*allocate a node*/
new_node->next = (*head_ref); /* link the old list off to the new node*/
(*head_ref) = new_node; /*move the head to point to the new node*/
}
/* Adding the contents of two linked lists and return the head node of resultant list*/
struct node* addTwoLists (struct node* first, struct node* second)
{
struct node* res = NULL; /* res is head node of the resultant list*/
struct node *temp, *prev = NULL;
int carry = 0, sum;
while (first != NULL || second != NULL) /*while both the lists exists*/
{
/* Calculate value of next digit in resultant list.
// The next digit is sum of following things
// (i) Carry
// (ii) Next digit of first list (if there is a next digit)
// (ii) Next digit of second list (if there is a next digit)*/
sum = carry + (first? first->data: 0) + (second? second->data: 0);
carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/
sum = sum % 10; /*update sum if it is greater than 10*/
temp = newNode(sum); /*Create a new node with sum as data*/
if(res == NULL) /*if this is the first node then set it as head of the resultant list*/
res = temp;
else /* If this is not the first node then connect it to the rest.*/
prev->next = temp;
prev = temp; /* Set prev for next insertion*/
if (first) first = first->next; /* Move first pointers to next node*/
if (second) second = second->next; /*Move second pointer to the next node*/
}
if (carry > 0)
temp->next = newNode(carry);
return res; /* return head of the resultant list*/
}
void printList(struct node *node) /* function to print a linked list*/
{
while(node != NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
printf(\"\ \");
}
int main(void) /* program to test above function*/
{
struct node* res = NULL;
struct node* first = NULL;
struct node* second = NULL;
printf(\"Enter first positive integer: \");
scanf(\"%d\",&first);
printList(first);
printf(\"Enter second positive integer: \");
scanf(\"%d\",&second);
printList(second);
/*Add the two lists and see result*/
res = addTwoLists(first, second);
printf(\"Sum is: %d\");
printList(res);
return 0;
}
Solution
#include
#include
typedef struct Node
{
int da.
Loops and ArraysObjectivesArrays are a series of elements consi.pdf
Loops and Arrays
Objectives:
Arrays are a series of elements consisting of the same type (For ex: all integers), in a contiguous
chunk of memory. The elements can be individually referenced by indexing the array.
You must specify the type of data stored in an array, and each element in any array must be of
the same type.
An array has a static size -- they cannot grow any larger than the size you tell it to be when you
create it.
To access the value at that index of the array: for (int i = 0; i < 10; i++){
cout<< intArray[i]<< endl; }
To access the memory address of the array element: for (int i = 0; i < 10; i++){
cout << intArray + i << endl; }
Creating an Array and Initializing
When you declare an array, you will get an uninitialized section of memory. If you want to
create an array of numbers, you would do:
int intNumbers [10];
double dblNumbers[10];
Then, putting element in the array can be set up by using the index of the array element you want
to change:
intNumbers[0] = 3; intNumbers[1] = 5; intNumbers[2] = 6; intNumbers[3] = 8;
1. Write a program that uses a for loop.
2. Declare and initialize and array.
3. Practice the array operations print and modify.
When you create an array, you do so to capture a group of items that all need to be treated
separately, but also need to grouped together for some purpose. For example, when you think
about a song, each note in the song is a separate sound, but they all need to be included together
in a certain order to make up the song.
To initialize the array:
int intNum [5] = {16, 3, 20, 4, 21}; (Hint: notice the syntax difference initializing this array
versus the one above)
Retrieving/Adding/Changing elements
To access or retrieve individual elements in an array, the syntax is square brackets and the
element index (starting from 0):
intNumbers[0]; will be the first item in the intNumbers array. intNumbers[1]; will be the second
item in the intNumbers array.
Below is an example of a basic 2D array. It shows how we access certain elements shown in the
arrayName[row][column] format. This will be helpful for a future assignment.
We can change the values in the array using the index of the individual items, such as
Example 1:
int intNumbers[2];
intNumbers[0] = 5;
intNumbers[1] = 7;
intNumbers[1] = intNumbers[1] * 2 cout << intNumbers[1] << endl;
Example 2:
//this will print the value 14
intNumber[1] = 10;
Example 3:
for (int i = 0; i < 10; i++){
intArray[i] = i;
cout << intArray[i] << endl;
//this will update the value to 10 at that index
//will set what the values are in that position //will print out the value of i at each index
}
TO DO: Create an array in your main function
1) Create an array of 20 doubles, using a variable name of your choosing. Assign values to your
array using a for loop:
for (int i = 0; i < 20; i++) myDoubles[i] = i;
where myDoubles is the name of the variable created.
2) Print out the values in another for loop using: cout << “Stuff to print” << endl;
3) Now, using your array an.
Write an algorithm that reads a list of integers from the keyboard, .pdf
Write an algorithm that reads a list of integers from the keyboard, creates
a list of them using linked list implementation, and prints the result
Solution
/*
Algorithm:
Implementation of linked list.
Create a node type class which will hold an integer and next pointer to point to another node.
Create a constructor which will construct an object of type node with the integer type data as the
only parameter
and initializing next pointer to NULL.
Create LinkedList class which will only have head pointer.
Create a constructor which will initialize this head pointer to NULL.
Create a append method which will recieve an input of type integer from the user and append it
to LinkedList
using below steps:
1.Create a Node type object.
1.IF head is NULL assign a Node type object created in 1st step.
2.IF head is not NULL then traverse to the end of the linked list till you found a Node which has
next pointer
set to NULL.
3.Add Node type object created in first step to the next pointer of last node.
Create a print method which will traverse the list from the head of the linked list to the last
node(Node
with next pointer NULL) and while traversing it will keep printing the node data.
Get the userinput:
Ask user for integer continously till user input -1 and append all the integers to the linked list.
*/
PROGRAM:
#include
using namespace std;
class Node
{
public:
int data;
Node *next;
Node(int data)
{
this->data = data;
this->next = NULL;
}
};
class LinkedList
{
private:
Node *head;
public:
LinkedList()
{
head = NULL;
}
void addToFront(int data)
{
Node *temp = new Node(data);
if(head == NULL)
head = temp;
else
{
temp->next = head;
head = temp;
}
}
void append(int data)
{
Node *temp = new Node(data);
Node *current = head;
if(current == NULL)
{
head = temp;
return;
}
while(current->next != NULL)
{
current = current->next;
}
current->next = temp;
}
void print()
{
Node *current = head;
if(current == NULL)
cout << \"No element in list. \ \";
while(current != NULL)
{
cout << current->data << \" \";
current = current->next;
}
cout << endl;
}
void deleteLinkedList()
{
Node *prev;
Node *current = head;
while(current!=NULL)
{
prev = current;
current = current->next;
delete prev;
}
}
void deleteLastNode()
{
Node *current = head;
Node *prev = NULL;
if(current == NULL)
return;
while(current->next != NULL)
{
prev = current;
current = current->next;
}
if(prev == NULL)
{
delete current;
head = NULL;
}
else
{
prev->next = NULL;
delete current;
}
}
~LinkedList()
{
deleteLinkedList();
}
};
int main()
{
LinkedList list;
int data;
while(1)
{
cout << \"Enter the integer(-1 to Quit) : \";
cin >> data;
if(data==-1)
break;
list.append(data);
}
cout << \"Content of LinkedList is : \";
list.print();
return 0;
}
OUTPUT:
Enter the integer(-1 to Quit) : 1
Enter the integer(-1 to Quit) : 2
Enter the integer(-1 to Quit) : 3
Enter the integer(-1 to Quit) : 4
Enter the integer(-1 to Quit) : -1
Content of LinkedList is : 1 2 3 4.
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
In Drosophila white eyes w and yellow body y are both r.pdf
In Drosophila, white eyes (w) and yellow body (y) are both recessive X-linked mutations. The wild-
type alleles, w+ and y+, control red eyes and dark body colour, respectively. If a homozygous
yellow-body, red-eyed female is crossed with a dark-body, white-eyed male, and F1 progeny are
interbred, what will the phenotypes and ratios of the F1 and F2 be?.
In Drosophila vestigial wings is an autosomal recessive tra.pdf
In Drosophila, vestigial wings is an autosomal recessive trait and white eyes is an X-linked
recessive trait. Wild-type is long wings and red eyes. If a male with vestigial wings and white eyes
is testcrossed, what would be the phenotype of the female offspring?
options:
long wings, white eyes
long wings, red eyes
vestigial wings, white eyes
vestigial wings, red eyes
impossible to tell.
More Related Content
Similar to In C language Given an IntNode struct and the operating func.pdf
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is :
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Do not work
together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print-
screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\"
How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void dele.
linkedlistwith animations.ppt
This document discusses linked lists and operations on them such as insertion and removal of nodes. It begins by showing the node declarations for a linked list, where each node contains a data field and a link field pointing to the next node. It then demonstrates how to insert a new node at the front of the list by allocating a new node, setting its data and link fields, and adjusting the head pointer. The document also provides pseudocode for inserting and removing nodes from linked lists in general cases.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list);
.
Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list).
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: a double data value, a pointer to the next node, and a pointer to the previous
node. Each member variable is protected. So code outside of the class must use the provided
getter and setter member functions to get or set a member variable. Node.h is read only, since no
changes are required. Step 2: Implement the Insert() member function A class for a sorted,
doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's
Insert() member function. The function must create a new node with the parameter value, then
insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after
inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove() member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Ch17
This document describes linked lists and operations on linked lists in C++. It discusses the composition of linked lists as series of connected nodes where each node contains data and a pointer to the next node. Common linked list operations like appending, inserting, traversing and displaying nodes are presented with pseudocode algorithms and C++ code implementations. Functions for appending nodes to the end of the list, inserting nodes in the proper sorted position, and traversing the list to display node values are demonstrated through example programs.
Linkedlist
Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.
computer notes - Linked list inside computer memory
The document discusses linked lists and their implementation in C++. It contains the following key points:
1) A linked list stores data non-contiguously in memory by chaining together nodes that contain a data element and a pointer to the next node. The head pointer points to the first node.
2) To create a new node, the Node class constructor is called and passed the data element. This allocates memory and returns a pointer to the new node.
3) To insert a new node, its next pointer is set to the next node of the current node. The current node's next pointer is then set to the new node.
4) The List class manages the linked list by
Provide copy constructor- destructor- and assignment operator for the.docx
Provide copy constructor, destructor, and assignment operator for the IntList class that stores a collection of integers using linked list.
class ListNode {
int value;
ListNode * next;
};
class IntList {
public: ...
IntList(const IntList & other);
~IntList();
IntList& operator =( const IntList & other ) ...
private:
int num; //the number of ints stored.
ListNode * first;
};
Solution
Hi, I have implemented all functionality.
Please test it in your test program
using namespace std;
class ListNode {
public:
int value;
ListNode * next;
};
class IntList {
public:
IntList();
IntList(const IntList & other);
~IntList();
void operator =( const IntList & other);
private:
int num; //the number of ints stored.
ListNode * first;
};
IntList::IntList(const IntList & other){
IntList *ptr = new IntList();
ListNode *temp = other.first;
ListNode *temp1 = ptr->first;
ListNode *firstLocal = NULL;
while(temp != NULL){
if(firstLocal == NULL){
firstLocal = temp;
temp1 = firstLocal;
}
else{
temp1->next = temp;
temp1 = temp;
}
temp = temp->next;
}
ptr->first = firstLocal;
ptr->num = other.num;
}
IntList::~IntList(){
while(first != NULL){
ListNode *local = first;
first = first->next;
delete local;
}
}
IntList::IntList(){
first = NULL;
num = 0;
}
void IntList::operator =( const IntList & other){
first = other.first;
num = other.num;
}
.
C Exam Help
I am Gabriel C. I am a C Exam Expert at programmingexamhelp.com. I hold a PhD. in Business analyst of Information Technology, Montreal College of Information Technology, Canada. I have been helping students with their exams for the past 8 years. You can hire me to take your exam in C.
Visit programmingexamhelp.com or email support@programmingexamhelp.com. You can also call on +1 678 648 4277 for any assistance with the C Exam.
Array linked list.ppt
This document discusses linked lists and their implementation. It begins with an overview of linked lists and their basic operations like insertion, deletion, and traversal. It then covers the implementation of a linked list using classes for the Node and List, including methods for insertion, deletion, searching, printing, and destroying the list. Examples are provided to demonstrate how to insert and delete nodes at different positions in the linked list. The document concludes with a brief discussion of variations like circular linked lists.
Please help solve this in C++ So the program is working fin.pdf
Please help solve this in C++. So the program is working fine but when submitting it, it gives me a
code -11, and I believe the problem is that after inserting the numbers it removes them one by one
until the last in the list, and when it tries to remove the last number in the list that is when it
counters the problem. Below is the full code but you just need to change something in the
SortedNumberList.h file under the bool remove function.
4.18 LAB: Sorted number list implementation with linked lists Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on
the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: - a double data value, - a pointer to the next node, and - a pointer to the
previous node. Each member variable is protected. So code outside of the class must use the
provided getter and setter member functions to get or set a member variable. Node.h is read only,
since no changes are required. Step 2: Implement the Insert() member function A class for a
sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList
class's Insert() member function. The function must create a new node with the parameter value,
then insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 2347.2586, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 2335.547.2586Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77154263.5 then output is: List after inserting 77 : 77 List after
inserting 15 : 1577 List after inserting -42 : -421577 List after inserting 63.5: -421563.577 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove(0 member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is
841972841961 then output is: List after inserting 84: 84 List after inserting 72 : 7284 List after
inserting 19: 1972 84 List after inserting 61: 1961 : 72 8 List after removing 19: 6172 84 List after
removing 84: 6172Current file: main.cpp - // Insert each value and show the sorted List's contents
after each insertion sortedNumberList list; for (auto term : terms) { doubl.
C Homework Help
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com.
You can also call on +1 678 648 4277 for any assistance with C Homework.
In the class we extensively discussed a node class called IntNode in.pdf
In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
template ltclass Tgt struct nodeType T data n.pdf
template <class T>
struct nodeType
{
T data;
nodeType *next;
};
template <class T>
class LinkedList {
nodeType<T> *head, *tail;
int count;
public:
LinkedList();
void insertFirst(T item);
void insertLast(T item);
void insertAt(T item, int pos);
void print();
bool simplecompare(LinkedList<T> &rL)
{
if (count != rL.count)
return false;
nodeType<T> *cur, *rCur;
for (cur = head, rCur = rL.head; cur != NULL; cur = cur->next, rCur = rCur->next)
if (cur->data != rCur->data)
return false;
return true;
}
int compare(LinkedList<T> &rL);
~LinkedList();
};
//driver program:
int main(void)
{
char item;
LinkedList<char> list1, list2;
cout << "Please enter the first list of characters"
<< "nPress Ctrl+Z to stop entering." << endl;
cin >> item;
while (!cin.eof()) {
list1.insertLast(item);
cin >> item;
}
cin.clear();
cout << "Please enter the second list of characters"
<< "nPress Ctrl+Z to stop entering." << endl;
cin >> item;
while (!cin.eof()) {
list2.insertLast(item);
cin >> item;
}
list1.print();
list2.print();
int result = list1.compare(list2);
if (result == 0)
cout << "The lists are same!n";
else if (result == -1)
cout << "first list < second listn" << endl;
else cout << "first list > second listn" << endl;
return 0;
}
1 Questions A simplified doublyLinkedList class is provided in lab03doublyLinkedList_template.h
file on CATS. Solve the following questions by using that elass. 1. The definition of insertFirst(T
item) function is missing. Complete it. 2. The definition of insertLast(T item) function is missing.
Complete it. 3. The definition of insertAt(T item, int order) function is missing. Complete it. 4.
Update print() function to print the list in forward direction. 5. The definition of deleteItem(T item)
function is missing. Complete it. 6. Add an extractMax(T max) function to the doublyLinkedList
class. The function must extract all nodes containing elements less than max from the list, and
construct a new list using those nodes. After the function call, the original list must only have the
nodes whose data fields are greater than max, while the new list is containing the smaller ones.
The new list must be returned by the function. You're not allowed to delete and/or create new
nodes. Your function must just move the subjected nodes from one list to the other. Let the
following list be the original list: If the function is called as newList = myList.extractMax (30), then
the newList becomes: 2 Assignment Implement a class to represent a circular linked list. You can
directly adapt SinglyLinkedList class that we've already defined in linkedList.h. Only the following
member functions will be defined for the class: - default constructor to set the pointer data
members to NULL and count to 0 . - insertItem to insert a given item to the list. - deleteItem to
remove a specific item from the list. Item may occur multiple times, thus the function must remove
every occurrences of the item from the list. 1 - print to print the linked list from head to tail. .
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdf
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED
HELP FIXING THIS CODE?
THIS IS THE PROBLEM
Write a program that allows the user to enter two positive integers and outputs their sum. Sounds
simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a
single variable. You may not assume any particular maximum number of digits.
HERE IS THE CODE
#include
#include
struct node /* Linked list node*/
{
int data;
struct node* next;
};
struct node *newNode(int data) /* Function to create a new node with giving the data*/
{
struct node *new_node = (struct node *) malloc(sizeof(struct node));
new_node->data = data;
new_node->next = NULL;
return new_node;
}
void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of
the Doubly Linked List*/
{
struct node* new_node = newNode(new_data); /*allocate a node*/
new_node->next = (*head_ref); /* link the old list off to the new node*/
(*head_ref) = new_node; /*move the head to point to the new node*/
}
/* Adding the contents of two linked lists and return the head node of resultant list*/
struct node* addTwoLists (struct node* first, struct node* second)
{
struct node* res = NULL; /* res is head node of the resultant list*/
struct node *temp, *prev = NULL;
int carry = 0, sum;
while (first != NULL || second != NULL) /*while both the lists exists*/
{
/* Calculate value of next digit in resultant list.
// The next digit is sum of following things
// (i) Carry
// (ii) Next digit of first list (if there is a next digit)
// (ii) Next digit of second list (if there is a next digit)*/
sum = carry + (first? first->data: 0) + (second? second->data: 0);
carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/
sum = sum % 10; /*update sum if it is greater than 10*/
temp = newNode(sum); /*Create a new node with sum as data*/
if(res == NULL) /*if this is the first node then set it as head of the resultant list*/
res = temp;
else /* If this is not the first node then connect it to the rest.*/
prev->next = temp;
prev = temp; /* Set prev for next insertion*/
if (first) first = first->next; /* Move first pointers to next node*/
if (second) second = second->next; /*Move second pointer to the next node*/
}
if (carry > 0)
temp->next = newNode(carry);
return res; /* return head of the resultant list*/
}
void printList(struct node *node) /* function to print a linked list*/
{
while(node != NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
printf(\"\ \");
}
int main(void) /* program to test above function*/
{
struct node* res = NULL;
struct node* first = NULL;
struct node* second = NULL;
printf(\"Enter first positive integer: \");
scanf(\"%d\",&first);
printList(first);
printf(\"Enter second positive integer: \");
scanf(\"%d\",&second);
printList(second);
/*Add the two lists and see result*/
res = addTwoLists(first, second);
printf(\"Sum is: %d\");
printList(res);
return 0;
}
Solution
#include
#include
typedef struct Node
{
int da.
Loops and ArraysObjectivesArrays are a series of elements consi.pdf
Loops and Arrays
Objectives:
Arrays are a series of elements consisting of the same type (For ex: all integers), in a contiguous
chunk of memory. The elements can be individually referenced by indexing the array.
You must specify the type of data stored in an array, and each element in any array must be of
the same type.
An array has a static size -- they cannot grow any larger than the size you tell it to be when you
create it.
To access the value at that index of the array: for (int i = 0; i < 10; i++){
cout<< intArray[i]<< endl; }
To access the memory address of the array element: for (int i = 0; i < 10; i++){
cout << intArray + i << endl; }
Creating an Array and Initializing
When you declare an array, you will get an uninitialized section of memory. If you want to
create an array of numbers, you would do:
int intNumbers [10];
double dblNumbers[10];
Then, putting element in the array can be set up by using the index of the array element you want
to change:
intNumbers[0] = 3; intNumbers[1] = 5; intNumbers[2] = 6; intNumbers[3] = 8;
1. Write a program that uses a for loop.
2. Declare and initialize and array.
3. Practice the array operations print and modify.
When you create an array, you do so to capture a group of items that all need to be treated
separately, but also need to grouped together for some purpose. For example, when you think
about a song, each note in the song is a separate sound, but they all need to be included together
in a certain order to make up the song.
To initialize the array:
int intNum [5] = {16, 3, 20, 4, 21}; (Hint: notice the syntax difference initializing this array
versus the one above)
Retrieving/Adding/Changing elements
To access or retrieve individual elements in an array, the syntax is square brackets and the
element index (starting from 0):
intNumbers[0]; will be the first item in the intNumbers array. intNumbers[1]; will be the second
item in the intNumbers array.
Below is an example of a basic 2D array. It shows how we access certain elements shown in the
arrayName[row][column] format. This will be helpful for a future assignment.
We can change the values in the array using the index of the individual items, such as
Example 1:
int intNumbers[2];
intNumbers[0] = 5;
intNumbers[1] = 7;
intNumbers[1] = intNumbers[1] * 2 cout << intNumbers[1] << endl;
Example 2:
//this will print the value 14
intNumber[1] = 10;
Example 3:
for (int i = 0; i < 10; i++){
intArray[i] = i;
cout << intArray[i] << endl;
//this will update the value to 10 at that index
//will set what the values are in that position //will print out the value of i at each index
}
TO DO: Create an array in your main function
1) Create an array of 20 doubles, using a variable name of your choosing. Assign values to your
array using a for loop:
for (int i = 0; i < 20; i++) myDoubles[i] = i;
where myDoubles is the name of the variable created.
2) Print out the values in another for loop using: cout << “Stuff to print” << endl;
3) Now, using your array an.
Write an algorithm that reads a list of integers from the keyboard, .pdf
Write an algorithm that reads a list of integers from the keyboard, creates
a list of them using linked list implementation, and prints the result
Solution
/*
Algorithm:
Implementation of linked list.
Create a node type class which will hold an integer and next pointer to point to another node.
Create a constructor which will construct an object of type node with the integer type data as the
only parameter
and initializing next pointer to NULL.
Create LinkedList class which will only have head pointer.
Create a constructor which will initialize this head pointer to NULL.
Create a append method which will recieve an input of type integer from the user and append it
to LinkedList
using below steps:
1.Create a Node type object.
1.IF head is NULL assign a Node type object created in 1st step.
2.IF head is not NULL then traverse to the end of the linked list till you found a Node which has
next pointer
set to NULL.
3.Add Node type object created in first step to the next pointer of last node.
Create a print method which will traverse the list from the head of the linked list to the last
node(Node
with next pointer NULL) and while traversing it will keep printing the node data.
Get the userinput:
Ask user for integer continously till user input -1 and append all the integers to the linked list.
*/
PROGRAM:
#include
using namespace std;
class Node
{
public:
int data;
Node *next;
Node(int data)
{
this->data = data;
this->next = NULL;
}
};
class LinkedList
{
private:
Node *head;
public:
LinkedList()
{
head = NULL;
}
void addToFront(int data)
{
Node *temp = new Node(data);
if(head == NULL)
head = temp;
else
{
temp->next = head;
head = temp;
}
}
void append(int data)
{
Node *temp = new Node(data);
Node *current = head;
if(current == NULL)
{
head = temp;
return;
}
while(current->next != NULL)
{
current = current->next;
}
current->next = temp;
}
void print()
{
Node *current = head;
if(current == NULL)
cout << \"No element in list. \ \";
while(current != NULL)
{
cout << current->data << \" \";
current = current->next;
}
cout << endl;
}
void deleteLinkedList()
{
Node *prev;
Node *current = head;
while(current!=NULL)
{
prev = current;
current = current->next;
delete prev;
}
}
void deleteLastNode()
{
Node *current = head;
Node *prev = NULL;
if(current == NULL)
return;
while(current->next != NULL)
{
prev = current;
current = current->next;
}
if(prev == NULL)
{
delete current;
head = NULL;
}
else
{
prev->next = NULL;
delete current;
}
}
~LinkedList()
{
deleteLinkedList();
}
};
int main()
{
LinkedList list;
int data;
while(1)
{
cout << \"Enter the integer(-1 to Quit) : \";
cin >> data;
if(data==-1)
break;
list.append(data);
}
cout << \"Content of LinkedList is : \";
list.print();
return 0;
}
OUTPUT:
Enter the integer(-1 to Quit) : 1
Enter the integer(-1 to Quit) : 2
Enter the integer(-1 to Quit) : 3
Enter the integer(-1 to Quit) : 4
Enter the integer(-1 to Quit) : -1
Content of LinkedList is : 1 2 3 4.
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
Similar to In C language Given an IntNode struct and the operating func.pdf (20)
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a.pdf
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please Sorted number list implementation wit.pdf
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
computer notes - Linked list inside computer memory
computer notes - Linked list inside computer memory
Provide copy constructor- destructor- and assignment operator for the.docx
Provide copy constructor- destructor- and assignment operator for the.docx
Please help solve this in C++ So the program is working fin.pdf
Please help solve this in C++ So the program is working fin.pdf
In the class we extensively discussed a node class called IntNode in.pdf
In the class we extensively discussed a node class called IntNode in.pdf
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdf
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdf
Loops and ArraysObjectivesArrays are a series of elements consi.pdf
Loops and ArraysObjectivesArrays are a series of elements consi.pdf
Write an algorithm that reads a list of integers from the keyboard, .pdf
Write an algorithm that reads a list of integers from the keyboard, .pdf
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
More from adithyaups
In Drosophila white eyes w and yellow body y are both r.pdf
In Drosophila, white eyes (w) and yellow body (y) are both recessive X-linked mutations. The wild-
type alleles, w+ and y+, control red eyes and dark body colour, respectively. If a homozygous
yellow-body, red-eyed female is crossed with a dark-body, white-eyed male, and F1 progeny are
interbred, what will the phenotypes and ratios of the F1 and F2 be?.
In Drosophila vestigial wings is an autosomal recessive tra.pdf
In Drosophila, vestigial wings is an autosomal recessive trait and white eyes is an X-linked
recessive trait. Wild-type is long wings and red eyes. If a male with vestigial wings and white eyes
is testcrossed, what would be the phenotype of the female offspring?
options:
long wings, white eyes
long wings, red eyes
vestigial wings, white eyes
vestigial wings, red eyes
impossible to tell.
In Java Please Write a program AirplanSeatingAssignment.pdf
In Java Please!
Write a program (AirplanSeatingAssignment) that can be used to assign seats for a commercial
airplane. The airplane has 13 rows, with 6 seats in each row. Rows 1 and 2 are first class, rows 3
to 7 are business class, and rows 8 to 13 are economy class. Your program prompts the user to
enter the following information:
Ticket type (first class, business class, or economy class)
Desired seat
Output the seating plan in the following format:
Here, * indicates that the seat is available; X indicates that the seat has been assigned. Make this
a menu-driven program; show the users choices and allow the user to make the appropriate
choices. Your program must use 2D array and at least the following methods:
A method to initialize the seats.
A Main method with Menu driven.
A method to show the menu.
A method to show the seating plan.
A method to select a seat.
A method to assign a seat.
In addition, your program must validate all users inputs such as wrong row or seat number or if a
seat is not available.
Sample output
This program assigns seats for a commercial airplane.
The current seat assignments is as follows.
A B C D E F
Row 1 * * * * * *
Row 2 * * * * * *
Row 3 * * * * * *
Row 4 * * * * * *
Row 5 * * * * * *
Row 6 * * * * * *
Row 7 * * * * * *
Row 8 * * * * * *
Row 9 * * * * * *
Row 10 * * * * * *
Row 11 * * * * * *
Row 12 * * * * * *
Row 13 * * * * * *
* -- available seat
X -- occupied seat
Rows 1 and 2 are for first class passengers.
Rows 3 through 7 are for business class passengers.
Rows 8 through 13 are for economy class passengers
To reserve a seat enter Y/y(Yes), N/n(No):
Y
Enter ticket type: F/f (first class); (B/b) (business class); E/e (economy class): F
Enter Row number 1 - 2: 2
Enter seat number (A - F): C
This seat is reserved for you
A B C D E F
Row 1 * * * * * *
Row 2 * * X * * *
Row 3 * * * * * *
Row 4 * * * * * *
Row 5 * * * * * *
Row 6 * * * * * *
Row 7 * * * * * *
Row 8 * * * * * *
Row 9 * * * * * *
Row 10 * * * * * *
Row 11 * * * * * *
Row 12 * * * * * *
Row 13 * * * * * *
* -- available seat
X -- occupied seat
This program assigns seats for a commercial airplane.
The current seat assignments is as follows.
A B C D E F
Row 1 * * * * * *
Row 2 * * X * * *
Row 3 * * * * * *
Row 4 * * * * * *
Row 5 * * * * * *
Row 6 * * * * * *
Row 7 * * * * * *
Row 8 * * * * * *
Row 9 * * * * * *
Row 10 * * * * * *
Row 11 * * * * * *
Row 12 * * * * * *
Row 13 * * * * * *
* -- available seat
X -- occupied seat
Rows 1 and 2 are for first class passengers.
Rows 3 through 7 are for business class passengers.
Rows 8 through 13 are for economy class passengers
Reserve another seat Y/y(Yes), N/n(No):
Y
Enter ticket type: F/f (first class); (B/b) (business class); E/e (economy class): E
Enter Row number 8 - 13: 7
Enter Row number 8 - 13: 14
Enter Row number 8 - 13: 12
Enter seat number (A - F): J
Enter seat number (A - F): L
Enter seat number (A - F): E
This seat is reserved for you
A B C D E F
Row 1 * * * * * *
Row 2 * * X * * *
Row 3 *.
In java Develop a menubased shapemaker using randomly gen.pdf
In java
Develop a menu-based shape-maker, using randomly generated sizes & characters: pyramid,
inverted pyramid, diamond, and hourglass. Use functions to perform tasks, including separate
functions for generating a random integer in a range and for generating a random character in a
range.
The four different shapes are made from a randomly generated printable character and a
randomly generated maximum width between 4 and 12. Beneath the shape, print a descriptive
caption stating the symbol and the maximum width.Define the random integer and random
character functions in a separate class in a separate source code file and call these functions from
the shape maker..
IN JAVA Develop a menubased shapemaker using randomly g.pdf
The document describes developing a menu-based shape-maker program in Java that randomly generates four shapes - pyramid, inverted pyramid, diamond, and hourglass - with random sizes and characters. Functions are used to generate random integers within a range and random characters within a range. The shapes are made from a random character and width between 4-12. Captions stating the symbol and width are printed under each shape. Random functions are defined in a separate class file called by the shape maker.
In hindsight Bitcoin experienced a speculative bubble Whic.pdf
In hindsight, Bitcoin experienced a speculative bubble. Which of the following explains why
someone acting rationally might purchase bitcoin, even at a price much higher than its historical
level? A person could buy Bitcoin as part of a strategy to profit from it after the bubble bursts. Even
if the price reflects a speculative bubble, it could continue to rise for a time, enabling the owner to
sell at a profit. The buyer might have good instincts.
in Figure 233 shows the different types Filiform papillae .pdf
in Figure 23.3 shows the different types. Filiform papillae contain taste buds, which are shown in
the papillae have tapered points, are most numerous, circular furrow of a vallate papilla. and
provide a rough texture for handling the food. Fungiform papillae (label 7) are low, rounded pro-
The Salivary Glands jections scattered over the surface. Eight to twelve Saliva is secreted from
three pairs of salivary large vallate papillae occur in a V-shaped pattern glandsasshownin Figure
23.4. The parotid gland Figure 23.3 Tongue anatomy. Body of the tongue Epiglottis Filiform
papillae Fungiform papillae Lingual tonsil Palatine tonsil Root Taste buds Vallate papillae fi...ne
23.4 Maior salivary glands. Masseter muscle Opening of submandibular duct _ Openings of
sublingual ducts Parotid duct Parotid gland Sublingual gland Submandibular duct Submandibular
giand.
In his analysis of the Dell fraud for Forbes Edward Hess co.pdf
In his analysis of the Dell fraud for Forbes, Edward Hess comments: Too often, the markets
maniacal focus on creating ever-increasing quarterly earnings drives bad corporate behavior, as it
apparently did at Dell. That behavior produces non-authentic earnings that obscure what is really
happening in business. Short-termism can result in a range of corporate and financial games that
may enrich management at the expense of market integrity and efficient investor capital
allocation.4 Comment on Hesss statement from two perspectives: earnings management and
financial analysts earnings projections.
Explain the difference between financial statement fraud and disclosure fraud. How did Dell use
each one to produce materially misstated financial results?
Do you agree with the court opinion that PwC did not act with fraudulent intent, therefore, not
holding it legally liable? How can fraudulent intent be established in a case like Dell?.
In his efforts to mobilize action learning and change in th.pdf
Snider could benefit the organization by manipulating social networks, gaining consensus to influence perceptions, and improving his own credibility by establishing trustworthiness in line with Habitat's mission. Snider faced significant opposition when trying to modernize financial systems, change HR policies, and expand into uninvited areas. Habitat's overseas projects were fueled by partnerships between US affiliates, expatriates on three-year commitments, local committees, and Allan Donaldson.
In humans being a tongue roller R is dominant to being a .pdf
In humans, being a tongue roller (R) is dominant to being a non-tongue roller (r). A man who is a
tongue roller marries a woman who is also a tongue roller and who is homozygous for tongue
rolling. The man's mother was a non-roller. What is the probability that their first child will be a
non-roller? begin{tabular}{|l|} hline 100% hline 75% hline 50% hline 25% hline 0% end{tabular}.
In HBS case studies Nextel Peru and Globalization of Cost of.pdf
In HBS case studies Nextel Peru and Globalization of Cost of Capital at AES, we have two
difference contexts but a similar problem. In both cases, protagonists are tasked with determining
a risk premium to account for non-diversifiable risks in international investments. Discuss the
methods suggested in each context and elaborate on the insights gained from the analysis of the
methods..
in gibi g mesafesinin yksek olduu lkelerde alanlarn a.pdf
in gibi g mesafesinin yksek olduu lkelerde, alanlarn alglad rgtsel destek alglar, iverenlerin adalet,
destek ve cesaretlendirme gsterilerine o kadar derinden bal deildir. Fark ________.
A. iverenlerin, alanlarn zel yaamlarna katlma isteklilii
B. mali dllerin oran
C. alanlarn fazla mesai yapma istei
D. verilen tatil gnlerinin miktar
E. alanlarn beklentilerinin dzeyi.
In Figure 83 there are black squiggles in the RER compar.pdf
In Figure 8.3, there are black squiggles in the RER compartment. Chemically, what specifically is
the blackness in this picture? (see the figure to right) What is the blackness an indicator of (as
explained in the pulse-chase video)?
Autoradiography Sample Radioactive part of sample AgCl crystal Agmetal Cover with
photographic emulsion Radiation activates the closest Ag+ ions Reduce the activated Ag+ to Ag
metal | Wash away soluble Ag+ leaving insoluble Agmetal.
In early 2015 Ford Motor F had a book value of equity of .pdf
In early 2015, Ford Motor (F) had a book value of equity of billion, billion shares outstanding, and a
market price of per share. Ford also had cash of billion, and total debt of billion. Three years later,
in early , Ford had a book value of equity of billion, billion shares outstanding with a market price
of per share, cash of billion, and total debt of billion. Over this period, what was the change in
Ford's a. market capitalization? b. market-to-book ratio? c. enterprise value?.
In dogs locus B determines pigment color Bblack bbrown p.pdf
In dogs locus B determines pigment color (B-black, b-brown pigment) and locus E determines
deposition of that pigment on the hair (E- allows deposition, e-prevents deposition). A black lab
and a brown lab are mated and produce one yellow lab.
a) What are the genotypes of the parents?
b) What are the possible genotypes of the yellow lab?
c) Explain the epistatic relationship between these two loci and how you determined the black,
brown and yellow lab genotypes..
In Block 1 Week 3 there is a description of various social.pdf
In Block 1, Week 3, there is a description of various social engineering techniques in Section 3.2
as per the list below: phishing pretexting impersonation baiting quid-pro-quo water-holing tailgating
Describe briefly, any four social engineering techniques from the given list. Do your independent
research and for each technique, provide a recent example (outside of the course text) of how it
was used. References You need to reference the sources of.
In each of the following cases report the appropriate diagn.pdf
In each of the following cases, report the appropriate diagnosis code(s) and identify the principal
diagnosis code. 1. An 80 y/o male patient is admitted with congestive heart failure and pneumonia.
Patient is given IV Lasix and IV antibiotics. 2. Patient presents with syncope. Syncope is due to
arrhythmia. 3. Viral gastroenteritis with fever, abdominal pain, nausea, vomiting, diarrhea. 4. A
patient with cholecystitis was admitted to the hospital for a cholecystectomy. Prior to surgery, the
patient fell and sustained a left femur fracture. The surgery was canceled and a hip pinning was
carried out on the second day of the hospital stay. 5. A patient was discharged two days following
a hysterectomy. On the second day at home, she strained lifting a small child. She was readmitted
with wound dehiscence. 6. A patient is admitted with respiratory failure and a large iatrogenic
pneumothorax three days following outpatient thoracentesis for malignant pleural effusion. 7. A
patient is treated in an observation unit for 16 hours with an exacerbation of COPD, then admitted
as an inpatient for treatment of a pulmonary embolism discovered on chest CT. 8. Patient is
admitted following TURP as an outpatient for post- operative bleeding uncontrolled in the PACU.
9. Patient is being observed for 24 hours following lumbar kyphoplasty develops rapid atrial
fibrillation requiring admission. 10. A patient is admitted with fever, cough and treated with
antibiotics and steroids. The diagnostic statement is COPD exacerbation and pneumonia..
In Db class we have two attributesinstance variables with t.pdf
In Db class we have two attributes/instance variables with the private visibility. meaning they
cannot be accessed outside of the class. Instance variables: name: data - type: String
Visibility/Access modifier: private name: yint - type: int Visibility/Access modifier: private Methods:
insertData - lets you set the values to above encapsulated instance variables. getData - getter
method for private data getYint - getter method for private yint setData -
for example:
Db db = new Db();
db.insertData("aaa",123);
System.out.println(db.getData());//aaa
System.out.println(db.getYint());//123
db.setData("zzz");
db.setYint(200);
System.out.println(db.getData());//zzz
System.out.println(db.getYint());//200
How to Submit?
//Create and use the object of Db class
// Use scanner class to provide data parameters
Example:
Input : Insert Data:
zzz
123
Output: zzz
123
Set Data:
123
zzz
write code in:
import java.util.*;
class Main {
public static void main(String[] args) {
//Your Code Here
System.out.println(db.getYint());
System.out.println(db.getData());
scanner.close();
}
}
write code in:
class Db {
//Your Code Here.
In descriptive statistics the term standard error refers .pdf
In descriptive statistics, the term standard error refers to a value that measures the accuracy with
which a sample distribution represents a population by using standard deviation. In statistics, a
sample mean deviates from the actual mean of a populationthis deviation is the standard error of
the mean. Typically, standard error is expressed using the following equation
stderr = /
where,
s is the standard deviation of the sample.
n is the total number of sample.
In catastropheFamine phase the action required is Action r.pdf
In catastrophe/Famine phase, the action required is Action required for disaster risk reduction and
to protect livelihoods. urgent action required to revert/prevent widespread death and total collapse
of livelihoods. Urgent action required to protect livelihoods and reduce food consumption gaps.
urgent action required to save lives and livelihoods..
More from adithyaups (20)
In Drosophila white eyes w and yellow body y are both r.pdf
In Drosophila white eyes w and yellow body y are both r.pdf
In Drosophila vestigial wings is an autosomal recessive tra.pdf
In Drosophila vestigial wings is an autosomal recessive tra.pdf
In Java Please Write a program AirplanSeatingAssignment.pdf
In Java Please Write a program AirplanSeatingAssignment.pdf
In java Develop a menubased shapemaker using randomly gen.pdf
In java Develop a menubased shapemaker using randomly gen.pdf
IN JAVA Develop a menubased shapemaker using randomly g.pdf
IN JAVA Develop a menubased shapemaker using randomly g.pdf
In hindsight Bitcoin experienced a speculative bubble Whic.pdf
In hindsight Bitcoin experienced a speculative bubble Whic.pdf
in Figure 233 shows the different types Filiform papillae .pdf
in Figure 233 shows the different types Filiform papillae .pdf
In his analysis of the Dell fraud for Forbes Edward Hess co.pdf
In his analysis of the Dell fraud for Forbes Edward Hess co.pdf
In his efforts to mobilize action learning and change in th.pdf
In his efforts to mobilize action learning and change in th.pdf
In humans being a tongue roller R is dominant to being a .pdf
In humans being a tongue roller R is dominant to being a .pdf
In HBS case studies Nextel Peru and Globalization of Cost of.pdf
In HBS case studies Nextel Peru and Globalization of Cost of.pdf
in gibi g mesafesinin yksek olduu lkelerde alanlarn a.pdf
in gibi g mesafesinin yksek olduu lkelerde alanlarn a.pdf
In Figure 83 there are black squiggles in the RER compar.pdf
In Figure 83 there are black squiggles in the RER compar.pdf
In early 2015 Ford Motor F had a book value of equity of .pdf
In early 2015 Ford Motor F had a book value of equity of .pdf
In dogs locus B determines pigment color Bblack bbrown p.pdf
In dogs locus B determines pigment color Bblack bbrown p.pdf
In Block 1 Week 3 there is a description of various social.pdf
In Block 1 Week 3 there is a description of various social.pdf
In each of the following cases report the appropriate diagn.pdf
In each of the following cases report the appropriate diagn.pdf
In Db class we have two attributesinstance variables with t.pdf
In Db class we have two attributesinstance variables with t.pdf
In descriptive statistics the term standard error refers .pdf
In descriptive statistics the term standard error refers .pdf
In catastropheFamine phase the action required is Action r.pdf
In catastropheFamine phase the action required is Action r.pdf
Recently uploaded
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...National Information Standards Organization (NISO)
This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.DRUGS AND ITS classification slide share
Any substance (other than food) that is used to prevent, diagnose, treat, or relieve symptoms of a
disease or abnormal condition
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
How to Setup Warehouse & Location in Odoo 17 Inventory
In this slide, we'll explore how to set up warehouses and locations in Odoo 17 Inventory. This will help us manage our stock effectively, track inventory levels, and streamline warehouse operations.
BBR 2024 Summer Sessions Interview Training
Qualitative research interview training by Professor Katrina Pritchard and Dr Helen Williams
How to Make a Field Mandatory in Odoo 17
In Odoo, making a field required can be done through both Python code and XML views. When you set the required attribute to True in Python code, it makes the field required across all views where it's used. Conversely, when you set the required attribute in XML views, it makes the field required only in the context of that particular view.
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective UpskillingExcellence Foundation for South Sudan
Strategies for Effective Upskilling is a presentation by Chinwendu Peace in a Your Skill Boost Masterclass organisation by the Excellence Foundation for South Sudan on 08th and 09th June 2024 from 1 PM to 3 PM on each day.BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...Nguyen Thanh Tu Collection
https://app.box.com/s/y977uz6bpd3af4qsebv7r9b7s21935vdWalmart Business+ and Spark Good for Nonprofits.pdf
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analytics” feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
How to Fix the Import Error in the Odoo 17
An import error occurs when a program fails to import a module or library, disrupting its execution. In languages like Python, this issue arises when the specified module cannot be found or accessed, hindering the program's functionality. Resolving import errors is crucial for maintaining smooth software operation and uninterrupted development processes.
How to Manage Your Lost Opportunities in Odoo 17 CRM
Odoo 17 CRM allows us to track why we lose sales opportunities with "Lost Reasons." This helps analyze our sales process and identify areas for improvement. Here's how to configure lost reasons in Odoo 17 CRM
The History of Stoke Newington Street Names
Presented at the Stoke Newington Literary Festival on 9th June 2024
www.StokeNewingtonHistory.com
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
Discover the Simplified Electron and Muon Model: A New Wave-Based Approach to Understanding Particles delves into a groundbreaking theory that presents electrons and muons as rotating soliton waves within oscillating spacetime. Geared towards students, researchers, and science buffs, this book breaks down complex ideas into simple explanations. It covers topics such as electron waves, temporal dynamics, and the implications of this model on particle physics. With clear illustrations and easy-to-follow explanations, readers will gain a new outlook on the universe's fundamental nature.
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS Template 2023-2024 by: Irene S. Rueco
PCOS corelations and management through Ayurveda.
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
South African Journal of Science: Writing with integrity workshop (2024)
South African Journal of Science: Writing with integrity workshop (2024)Academy of Science of South Africa
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.Recently uploaded (20)
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
How to Setup Warehouse & Location in Odoo 17 Inventory
How to Setup Warehouse & Location in Odoo 17 Inventory
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Liberal Approach to the Study of Indian Politics.pdf
Liberal Approach to the Study of Indian Politics.pdf
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
Walmart Business+ and Spark Good for Nonprofits.pdf
Walmart Business+ and Spark Good for Nonprofits.pdf
How to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRM
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
South African Journal of Science: Writing with integrity workshop (2024)
South African Journal of Science: Writing with integrity workshop (2024)
In C language Given an IntNode struct and the operating func.pdf
- 1. In C language Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list: 1. IntNode* IntNode_GetNth(IntNode* firstNode, int n )- Return a pointer to the nth node of the list starting at firstNode. 2. void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values. 3. int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode. Note: The code for IntNode_Create 0 provided here differs from the code shown in the book. The given main0 performs various actions to test IntNode_GetNth 0 , IntNode_PrintList 0 , and IntNode_SumList 0 . main() reads 5 integers from a user: 1. The number of nodes to be added to a new list 2. The value of the first node of the list 3. An increment between the values of two consecutive nodes. 4. A value of a new node 5. The position of a node after which the new node will be added, with 1 indicating the first node Ex: If the input is: