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G.H.Raisoni College of Engineering

Submitted to :Prof kishor rambhad
Subject: Energy conversion-2
TOPIC: Multistage Compression
SUBMITTED BY: Abhishek Gawande
ROLL NO. :04
MULTISTAGE COMPRESSION:
Multi staging is simply the compression of air or gas in two or more cylinders
in place of a single cylinder compressor. It is used in reciprocating compressors
when pressure of 300 KPa and above are desired, in order to:
1) Save power
2) Limit the gas discharge temperature
3) Limit the pressure differential per cylinder
4) Prevent vaporization of lubricating oil and to prevent its ignition if the temperature becomes too high.
It is a common practice for multi-staging to cool the air or gas between stages
of compression in an intercooler, and it is this cooling that affects considerable
saving in power.
2 Stage Compressor without pressure drop in the intercooler:
Qx
Suction

1

2

3

4

Discharge

Intercooler

1st stage

2nd stage

For an ideal multistage compressor, with perfect inter-cooling and minimum
work, the cylinder were properly designed so that:
a) the work at each stage are equal
b) the air in the intercooler is cooled back to the initial temperature
c) no pressure drop occurs in the intercooler
Work of 1st stage cylinder (W1): Assuming Polytropic compression on
n−1
both stages.


n

nP1V1'
W1 =
n −1

 P2 
 
 P1 
 


− 1




P1V1' = mRT1
Work of 2nd stage cylinder (W2): Assuming Polytropic compression on
both stages.
n−1


n
nP3 V3'  P4 
  − 1
W2 =

n − 1  P3 
 




P3 V3' = mRT3
P
P4

T
5

4

PVn = C

W2
Px

P4

3

6
7

2

P1
8

4

3

W1
1

V

Px

P1

2

Qx

1
S

For perfect inter-cooling and minimum
work:
P2 P4
= ; but Px = P2 = P3 ; then
W1 = W 2
P1 P3
T1 = T3
Where:
Px = P1P4
W = W1 + W2
Px – optimum intercooler
1
W = 2W1
pressure or interstage
P2  P4  2
P2 = P3 = Px
= 
pressure
P1  P1 
 
therefore
P1V1’ = P3V3’
Then the work W for an ideal 2-stage compressor is:

2nP1V1'
W=
n −1
2nP1V1'
W=
n −1

n−1


n
 P2  − 1
 
 P1 

 




n−1


2n
 P4  − 1
 
 P1 

 





Heat losses calculation:
1. Heat loss during compression at 1st stage cylinder
Q1 = mCn(T2 – T1)
2. Heat loss during compression at 2nd stage cylinder
Q2 = mCn(T4 – T3)
3. Heat loss in the intercooler
Qx = mCp(T2 – T3)
2 Stage Compressor with pressure drop in the intercooler:
Qx

Suction

1

2

3

4

Discharge

Intercooler

1st stage

With pressure drop in the intercooler:
T1 ≠ T3 and P2 ≠ P3
W = W1 + W2
P1V1’ ≠ P3V3’

2nd stage
n−1


n
nP1V1'  P2 
  − 1
W1 =

n − 1  P1 
 




n−1


n
nP3 V3'  P4 
  − 1
W2 =

n − 1  P3 
 




P
P4

5

P2

4

PVn = C

W2
P2
P3

P4

T

6

3

7

4

2

3

W1

P1

1

8

P1

P3

2

Qx

1
S

V

3 Stage Compressor without pressure drop in the intercooler:
1

2

Qx

3

4

Qy

5

6

Suction

Discharge
HP Intercooler

LP Intercooler

1st stage

2nd stage

3rd stage
P
P6
Py

T
7

W3

PVn = C

6

Py

4

6

Px

2

4

9
8

5

W2

Px

5

2

11
10

P1

P6

3

Qy

Qx

1

3

W1

12

1

V

For perfect inter-cooling and minimum work:
T1 = T3 = T5
Px = P2 = P3
W1 = W 2 = W 3
Py = P4 = P5
W = 3W1
P1V1’ = P3V3’ = P5V5’
mRT1 = mRT3 = mRT5
Therefore:
rP1 = rP2 = rP3

S

P1
Work for each stage:
1st Stage:

2nd Stage:

n−1


n
nP1V1'  P2 
  − 1
W1 =

n − 1  P1 
 





n−1


n
nP3 V3'  P4 
  − 1
W2 =

n − 1  P3 
 





3rd Stage:

Intercooler Pressures:

n−1


n
nP5 V5'  P6 
  − 1
W3 =

n − 1  P5 
 





P2 P4 P6
= =
P1 P3 P5

or

Px Py P6
= =
P1 Px Py

hence
2
1 6

Px = P P
3

;

Py = P1P6
3

2
Total Work:
W = 3W1

n−1


3n
3nP1V1'  P6 
  − 1
W=

n − 1  P1 
 




P1V1' = mRT1

Heat Losses during compression:
Q1 = mCn(T2 – T1)
Q2 = mCn(T4 – T3)
Q3 = mCn(T6 – T5)
Heat loss in the LP and HP intercoolers:
LP Intercooler
Qx = mCp(T2 – T3)
HP Intercooler
Qy = mCp(T4 – T5)

Note:
1. For isentropic compression and expansion process, no heat loss during
compression.
2. For isothermal compression and expansion process, the loss during
compression is equivalent to the compression work, and no intercooler
is required.
For multistage compression with minimum work and perfect inter-cooling
and no pressure drop that occurs in the inter-coolers between stages, the
following conditions apply:
1. the work at each stage are equal
2. the pressure ratio between stages are equal
3. the air temperature in the inter-coolers are cooled to the original
temperature T1
4. the total work W is equal to
n−1


'
2S
SnP1V1  P2S 

 − 1
W=

n − 1  P1 







Where: s – is the number of
stages.

Note: For multistage compressor with pressure drop in the intercoolers the
equation of W above cannot be applied. The total work is equal to the sum
of the work for each stage that is computed separately.
THANK YOU!

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Multistage Compression

  • 1. G.H.Raisoni College of Engineering Submitted to :Prof kishor rambhad Subject: Energy conversion-2 TOPIC: Multistage Compression SUBMITTED BY: Abhishek Gawande ROLL NO. :04
  • 2. MULTISTAGE COMPRESSION: Multi staging is simply the compression of air or gas in two or more cylinders in place of a single cylinder compressor. It is used in reciprocating compressors when pressure of 300 KPa and above are desired, in order to: 1) Save power 2) Limit the gas discharge temperature 3) Limit the pressure differential per cylinder 4) Prevent vaporization of lubricating oil and to prevent its ignition if the temperature becomes too high. It is a common practice for multi-staging to cool the air or gas between stages of compression in an intercooler, and it is this cooling that affects considerable saving in power.
  • 3. 2 Stage Compressor without pressure drop in the intercooler: Qx Suction 1 2 3 4 Discharge Intercooler 1st stage 2nd stage For an ideal multistage compressor, with perfect inter-cooling and minimum work, the cylinder were properly designed so that: a) the work at each stage are equal b) the air in the intercooler is cooled back to the initial temperature c) no pressure drop occurs in the intercooler
  • 4. Work of 1st stage cylinder (W1): Assuming Polytropic compression on n−1 both stages.   n nP1V1' W1 = n −1  P2     P1     − 1    P1V1' = mRT1 Work of 2nd stage cylinder (W2): Assuming Polytropic compression on both stages. n−1   n nP3 V3'  P4    − 1 W2 =  n − 1  P3        P3 V3' = mRT3
  • 5. P P4 T 5 4 PVn = C W2 Px P4 3 6 7 2 P1 8 4 3 W1 1 V Px P1 2 Qx 1 S For perfect inter-cooling and minimum work: P2 P4 = ; but Px = P2 = P3 ; then W1 = W 2 P1 P3 T1 = T3 Where: Px = P1P4 W = W1 + W2 Px – optimum intercooler 1 W = 2W1 pressure or interstage P2  P4  2 P2 = P3 = Px =  pressure P1  P1    therefore P1V1’ = P3V3’
  • 6. Then the work W for an ideal 2-stage compressor is: 2nP1V1' W= n −1 2nP1V1' W= n −1 n−1   n  P2  − 1    P1         n−1   2n  P4  − 1    P1         Heat losses calculation: 1. Heat loss during compression at 1st stage cylinder Q1 = mCn(T2 – T1) 2. Heat loss during compression at 2nd stage cylinder Q2 = mCn(T4 – T3) 3. Heat loss in the intercooler Qx = mCp(T2 – T3)
  • 7. 2 Stage Compressor with pressure drop in the intercooler: Qx Suction 1 2 3 4 Discharge Intercooler 1st stage With pressure drop in the intercooler: T1 ≠ T3 and P2 ≠ P3 W = W1 + W2 P1V1’ ≠ P3V3’ 2nd stage n−1   n nP1V1'  P2    − 1 W1 =  n − 1  P1        n−1   n nP3 V3'  P4    − 1 W2 =  n − 1  P3       
  • 8. P P4 5 P2 4 PVn = C W2 P2 P3 P4 T 6 3 7 4 2 3 W1 P1 1 8 P1 P3 2 Qx 1 S V 3 Stage Compressor without pressure drop in the intercooler: 1 2 Qx 3 4 Qy 5 6 Suction Discharge HP Intercooler LP Intercooler 1st stage 2nd stage 3rd stage
  • 9. P P6 Py T 7 W3 PVn = C 6 Py 4 6 Px 2 4 9 8 5 W2 Px 5 2 11 10 P1 P6 3 Qy Qx 1 3 W1 12 1 V For perfect inter-cooling and minimum work: T1 = T3 = T5 Px = P2 = P3 W1 = W 2 = W 3 Py = P4 = P5 W = 3W1 P1V1’ = P3V3’ = P5V5’ mRT1 = mRT3 = mRT5 Therefore: rP1 = rP2 = rP3 S P1
  • 10. Work for each stage: 1st Stage: 2nd Stage: n−1   n nP1V1'  P2    − 1 W1 =  n − 1  P1        n−1   n nP3 V3'  P4    − 1 W2 =  n − 1  P3        3rd Stage: Intercooler Pressures: n−1   n nP5 V5'  P6    − 1 W3 =  n − 1  P5        P2 P4 P6 = = P1 P3 P5 or Px Py P6 = = P1 Px Py hence 2 1 6 Px = P P 3 ; Py = P1P6 3 2
  • 11. Total Work: W = 3W1 n−1   3n 3nP1V1'  P6    − 1 W=  n − 1  P1        P1V1' = mRT1 Heat Losses during compression: Q1 = mCn(T2 – T1) Q2 = mCn(T4 – T3) Q3 = mCn(T6 – T5) Heat loss in the LP and HP intercoolers: LP Intercooler Qx = mCp(T2 – T3) HP Intercooler Qy = mCp(T4 – T5) Note: 1. For isentropic compression and expansion process, no heat loss during compression. 2. For isothermal compression and expansion process, the loss during compression is equivalent to the compression work, and no intercooler is required.
  • 12. For multistage compression with minimum work and perfect inter-cooling and no pressure drop that occurs in the inter-coolers between stages, the following conditions apply: 1. the work at each stage are equal 2. the pressure ratio between stages are equal 3. the air temperature in the inter-coolers are cooled to the original temperature T1 4. the total work W is equal to n−1   ' 2S SnP1V1  P2S    − 1 W=  n − 1  P1        Where: s – is the number of stages. Note: For multistage compressor with pressure drop in the intercoolers the equation of W above cannot be applied. The total work is equal to the sum of the work for each stage that is computed separately.
  • 13.