3. DIVISIBILITY RULE OF 11
Subtract sum of even numbered places from sum of
odd number places. The difference should be a
multiple of 11 (including 0 and negatives).
For example,
53647
- Sum of odd number places – (5+6+7 = 18)
- Sum of even number places – (3+4 = 7)
- Difference = 18-7 = 11
Hence the given number is divisible by 11.
4. DIVISIBILITY RULE OF 12
Given number should be divisible by both 3 and 4.
For example,
532344
- 5+3+2+3+4+4 = 21 (divisible by 3)
- 532344 – 44(last two digit) is divisible by 4
Here, the given number is divisible by both 3 and 4.
Hence, it is divisible by 12.
5. DIVISIBILITY RULE OF 13
First, multiply the unit digit by 4, and then add the
product from the remaining digits.
If the result is divisible by 13, then the number is
divisible by 13.
These steps are repeated if given numbers are larger.
6. For example,
31369
Step1: The number is 31369; 9x4 = 36 (multiply the last digit by 4)
Step2: 3136(remaining number) + 36 = 3172 (since we don’t know
whether 3172 is divisible by 13 or not we have to proceed these steps
again)
Step3: The number is 3172; 2x4 = 8 (multiply the last digit by 4)
Step4: 317(remaining number) + 8 = 325
Step5: 325/13 = 25 ( 325 is a divisible of 13)
Thus the given number is divisible by 13.
7. DIVISIBILITY RULE OF 14
Given number should be divisible by both 2 and 7.
For example,
64358, 11046, 356706
DIVISIBILITY RULE OF 15
Given number should be divisible by both 3 and 5.
For example,
71790, 131985, 18510
8. DIVISIBILITY RULE OF 16
Last four digits of a given number should be divisible
by 16.
For example,
659696
Here, 9696/16 = 606 (solve by normal division
method); Thus the given number is divisible by 16.
9. DIVISIBILITY RULE OF 17
First, multiply the unit digit by 5, and then subtract
the product from the remaining digits.
If the difference is divisible by 17, then the number is
divisible by 17.
These steps are repeated if given numbers are larger.
10. For example,
7225
Step1: The number is 7225; 5x5 = 25 (multiply the last digit by 5)
Step2: 722(remaining number) - 25 = 697 (since we don’t know whether
697 is divisible by 17 or not we have to proceed these steps again)
Step3: The number is 697; 7x5 = 35 (multiply the last digit by 5)
Step4: 69(remaining number) - 35 = 34
Step5: 34/17 = 2 ( 34 is a divisible of 17)
Thus the given number is divisible by 17.
11. DIVISIBILITY RULE OF 18
Given number should be divisible by both 2 and 9.
For example,
143028, 29554, 42364
DIVISIBILITY RULE OF 19
First, multiply the unit digit by 2, and then add the
product from the remaining digits.
If the result is divisible by 19, then the number is
divisible by 19.
These steps are repeated if given numbers are larger.
12. For example,
4123
Step1: The number is 4123; 3x2 = 6 (multiply the last digit by 2)
Step2: 412(remaining number) + 6 = 418 (since we don’t know whether
418 is divisible by 19 or not we have to proceed these steps again)
Step3: The number is 418; 8x2 = 16 (multiply the last digit by 2)
Step4: 41(remaining number) + 16 = 57
Step5: 57/19 = 3 ( 57 is a divisible of 19)
Thus the given number is divisible by 19.
13. DIVISIBILITY RULE OF 20
Given number should be end with any of 20,40,60,80
or 00.
For example,
325420, 97860, 452100
