2. CONTINUOUS CULTIVATION
The culture environment changes continually in a batch culture.
Growth, product formation, and substrate utilization terminate after
a certain time interval, whereas, in continuous culture, fresh medium
is continually supplied to well-stirred culture, and products and cell
are simultaneously withdrawn.
Growth and product formation can be maintained for prolonged
period in continuous culture.
After a certain period of time, the system usually reaches a steady
state where cell, product, and substrate concentrations remain
constant.
Continuous culture provides constant environmental conditions for
growth and product formation and supplies uniform-quality product.
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3. SPECIFIC DEVICES FOR
CONTINUOUS CUTURE
• The primary types of continuous cultivation
devices are the
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Turbidostat
Chemostat
4. CHEMOSTAT
The name refers to constant chemical
environment.
Cellular growth is usually limited by one essential
nutrient, and other nutrients are in excess.
When a chemostat is at steady state, the nutrient,
product, and cell concentrations are constant.
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6. TURBIDOSTAT
In turbidostat the cell concentration in the culture vessel is
maintained constant by monitoring the optical density of the
culture and controlling the feed flow rate.
When the turbidity of the medium exceeds the set point, a
pump is activated and fresh medium is added.
The culture volume is kept constant by removing an equal
amount of culture fluid.
The turbidostat is less used than the chemostat, since it is
more elaborate than a chemostat because the environment is
dynamic.
It can be very useful in selecting subpopulation able to
withstand a desired environmental stress because the cell
concentration is maintained constant.
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8. THE IDEAL CHEMOSTAT
An ideal chemostat is same as a perfectly mixed
contonuous-flow, stirred-tank reactor (CFSTR).
Most chemostats require some control elements,
such as pH and dissolved oxygen contrl units, to
be useful.
Fresh sterile medium is fed to the compltely
mixed and aerated reactor, and cell suspension is
removed at the same rate.
Liquid volume in the reactor is kept constant
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10. A material balance on the cell concentration
around the chemostat yields
FX0 – FX + VRµgX – VRkdX = VR (dX/dt) …1
Where,
F is the flow rate of nutrient solution(1/h)
VR is the culture volume (1)
X is the cell concentration (g/l)
µg & kd are growth and endogenous rate
constants (h-1)
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11. If cell mass is the primary parameter, it is
difficult to differentiate cell death from
endogenous metabolism.
When we use kd we imply that endogenous
metabolism is the primary mechanism for cell
mass decrease.
With k’d we imply that cell death and lysis are
the primary mechanism of decrease in mass.
kd could only be a cell death rate
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12. Eqn 1 rearranged as
(dX/dt) =DX0 + (µg- kd –D)X …..2
Where,
D is the dilution rate and D = F/VR
D is the reciprocal of residence time
X0 =0 (death rate is negligible)
If the system at steady state(dX/dt =0), then
µg = D (if kd =0) …..3
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13. By substituting Monod’s eqn for µg in eqn 3,
µg = D = (µmS/Ks +S) ……4
Where,
S is the steady state limiting substrate
concentration(g/l)
Eqn 4 is identical to Michaelis-Menten kinetics
We can relate the substrate concentration to
dilution rate for D< µm
S = (Ks D/µm-D) ……5
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14. A material balance on the limiting substrate in in the
absence of endogenous metabolism yields
FS0-FS-VRµgX(1/YM
(X/S))-VRqpX(1/Y(P/S))=VR(dS/dt)..6
Where,
S0 &S are feed and effluent substrate concentration (g/l)
qp is the specific rate of extracellular product formation (g P/µg cells h)
YM
(X/S) and Y(P/S) are yield coefficients(g cell/g S and g P/g S)
When extracellular product formation is negligible & the system at steady state is
D(S0-S) = (µgX/YM
(X/S)) ……7
µg =D at steady state if kd = 0
X=YM
(X/S)(S0-S) ..….8
X = YM
(X/S)[S0- (KSD/µm-D)] ..9
Consider the effect the inclusion of endogeneous metabolism eqn 3 becomes
D = µg-kd = µnet ....10
µg = D + kd …11
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15. By substituting eqn 11 into 7
D(S0-S) - (1/YM
(X/S) D+kd)X = 0 …12
D((S0-S)/X) - (1/YM
(X/S) D+kd) = 0 ...13
D(1/YAP
(X/S) )-(D/YM
(X/S) )-(kd/YM
(X/S) ) = 0 ..14
(1/YM
(X/S) )+(kd/YM
(X/S) D)= (1/YAP
(X/S) ) ..15
(1/YAP
(X/S) ) = (1/YM
(X/S) )+(ms/D) ….16
Where, ms = (kd/YM
(X/S) )
Values of (YM
(X/S) ) and ms are obtained from
chemostat experiment by plotting (1/YAP
(X/S) ) and
(1/D). The slope is ms and intercept is (1/YM
(X/S) )
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17. WHY CONTINUOUS CULTIVATION IS
NOT USED IN INDUSTRIES
Secondary metabolites are produced only
during the stationary phase. Hence the
continuous cultivation is not suitable for them.
Maintenance of sterility is very difficult.
High infrastructure cost is required.
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18. ADVANTAGES
Works all time: low labor cost, good utilization
of reactor.
Often efficient: due to the autocatalytic nature
of microbial reactions,
• The productivity can be high.
• Automation may be very appealing.
• Constant product quality.
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19. DISADVANTAGES
Promised continuous production for months
fails due to
• Infection
• Spontaneous mutation of microorganism to non
producing strain
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