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1. λ=83mm=83x10-9 m=9.11x10-31kg v=?
    Ek=Ef-13.6eV
    uvršata se u jednadžbu
    Ek=mv2/2
    Ef=hc/λ
    13.6eV=21,76x10-19J
    v=6.9x105m/s
2. m=1 n=∞
   1/λ = R(1/m2-1/n2)
   nakon uvrštavanja 1/n2=1/∞2=0
   1/λ=R => λ=R-1=91,74nm=9.174x10-8m
3. a)n=2 ve=? ve = 1/2 x e2/2ε0h = 11.5x105m/s
   b) ve = 11.5x105m/s r(polumjer 1.staze)=53pm=53 x 10-12m
   v=wr => w=v/r= 2.17x1016
4. λ=? ve=0.69Mm=0.69x106m me= 9.11x10-31m
   Ek=Ef-13.6eV
   mv2/2 = hc/λ – 21,76x10-19J               /xλ
                          -19
   λmv2/2 + λx21.76x10 J = hc
   λ(mv2/2 + 21,76x10-19J) = hc              / : (mv2/2 + 21,76x10-19J)
               2              -19          -8
   λ = hc/(mv /2 + 21,76x10 J) = 7.85x10 m

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Fizika zadaća

  • 1. 1. λ=83mm=83x10-9 m=9.11x10-31kg v=? Ek=Ef-13.6eV uvršata se u jednadžbu Ek=mv2/2 Ef=hc/λ 13.6eV=21,76x10-19J v=6.9x105m/s 2. m=1 n=∞ 1/λ = R(1/m2-1/n2) nakon uvrštavanja 1/n2=1/∞2=0 1/λ=R => λ=R-1=91,74nm=9.174x10-8m 3. a)n=2 ve=? ve = 1/2 x e2/2ε0h = 11.5x105m/s b) ve = 11.5x105m/s r(polumjer 1.staze)=53pm=53 x 10-12m v=wr => w=v/r= 2.17x1016 4. λ=? ve=0.69Mm=0.69x106m me= 9.11x10-31m Ek=Ef-13.6eV mv2/2 = hc/λ – 21,76x10-19J /xλ -19 λmv2/2 + λx21.76x10 J = hc λ(mv2/2 + 21,76x10-19J) = hc / : (mv2/2 + 21,76x10-19J) 2 -19 -8 λ = hc/(mv /2 + 21,76x10 J) = 7.85x10 m