Fizika zadaća
- 1. 1. λ=83mm=83x10-9 m=9.11x10-31kg v=?
Ek=Ef-13.6eV
uvršata se u jednadžbu
Ek=mv2/2
Ef=hc/λ
13.6eV=21,76x10-19J
v=6.9x105m/s
2. m=1 n=∞
1/λ = R(1/m2-1/n2)
nakon uvrštavanja 1/n2=1/∞2=0
1/λ=R => λ=R-1=91,74nm=9.174x10-8m
3. a)n=2 ve=? ve = 1/2 x e2/2ε0h = 11.5x105m/s
b) ve = 11.5x105m/s r(polumjer 1.staze)=53pm=53 x 10-12m
v=wr => w=v/r= 2.17x1016
4. λ=? ve=0.69Mm=0.69x106m me= 9.11x10-31m
Ek=Ef-13.6eV
mv2/2 = hc/λ – 21,76x10-19J /xλ
-19
λmv2/2 + λx21.76x10 J = hc
λ(mv2/2 + 21,76x10-19J) = hc / : (mv2/2 + 21,76x10-19J)
2 -19 -8
λ = hc/(mv /2 + 21,76x10 J) = 7.85x10 m