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DESIGN OF RIGID
PAVEMENTS
PART- II
DESIGN OF SLAB THICKNESS
The Analysis of Stresses, the Design of SLAB THICKNESS and its protection
involves the following procedures.
a) Critical Stress Condition,
b) Calculation of Stresses
i. Edges Stresses,
ii. Stresses due to Temperature,
iii. Corner Stresses.
c) Design Charts,
d) Stress ratio and fatigue analysis,
e) Erosion consideration,
f) Hard Shoulder,
g) Composite Rigid Pavement,
h) Anchor Beam and Terminal Slab and
i) Recommended Design Procedure.
CRITICAL STRESS CONDITION
The Factors commonly considered for the design of Pavement
Thickness are.
a) Flexural Stresses due to TRAFFIC Loads,
b) Temperature differentials between top and
bottom of concrete slab.
c) The effect of moisture changes
The factors (a) and (b) additive and major,
The factor ( c) is opposite of Factor and very minor, hence
not considered in designing the Slab thickness.
CRITICAL STRESS CONDITION
The Concrete Pavement undergo a daily cyclic
change of temperature differential
During day TOP surface is hotter than BOTTOM
surface.
During night TOP surface is cooler than
BOTTOM surface.
Day time
WARPING STRESSES
• During day time the temperature of the top portion
of slab may be considerably greater than that of
bottom.
• The top portion of slab tends to expand more than
bottom portion.
• The resultant slab convex towards top as shown
• But the weight of slab resists the convex in concrete
slab resulting following section
WARPING STRESSES
• The fibers in top are in compression and those in
bottom are in tension.
• This condition is called “temperature wrapping
stresses” .
• This “temperature wrapping stresses” is very important
in design of cc pavement.
Night time
WARPING STRESSES
• DURING NIGHT
DESIGN OF SLAB THICKNESS
•The THREE different
regions recognized for
Pavement are
–1) SLAB INTERIOR
–2) SLAB EDGE
–3) SLAB CORNER
DESIGN OF SLAB THICKNESS
• Combination of critical Regions and Stresses
• i) Temperature stresses induced in pavement are
– A) Maximum @ Slab Interior
– B) Moderate @ Slab Edge and
– C) Negligible @ Slab Corner
ii) Load stresses induced in Pavement are
A) Negligible @ Slab Interior
B) Moderate @ Slab Edge and
C) Maximum @ Slab Corner
EDGE STRESSES
• Combination of critical Regions and Stresses
• i) Temperature stresses induced in pavement are
– A) Maximum @ Slab Interior
– B) Moderate @ Slab Edge and
– C) Negligible @ Slab Corner
ii) Load stresses induced in Pavement are
A) Negligible @ Slab Interior
B) Moderate @ Slab Edge and
C) Maximum @ Slab Corner
CALCULATION OFEDGE STRESSES
• The STRESS CHARTS
• Axles Loads for
Single Axle Loads of
6, 8, 10, 12, 14, 16, 18, 20, 22 and 24 T
Tandem Axles Loads of
12, 16, 20, 24, 28, 32, 36, 40, 42 and 44 T
• The SLAB THICKNESS for 14,16,18,20,22,24,26,28,30,32,34,36
cm.
• With k- values
6,8,10,15,30 kg/cum.cm
Are used to arrive the values of stresses for respective conditions.
STRESSES in RIGID PAVEMENTS – S.A.L. = 6.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 8.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 10.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 12.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 14.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 16.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 18.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 20.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 22.00 T
STRESSES in RIGID PAVEMENTS – S.A.L. = 24.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 12.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 16.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 20.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 24.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 28.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 32.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 36.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 40.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 42.00 T
STRESSES in RIGID PAVEMENTS – T.A.L. = 44.00 T
Stresses due to Temperature
The Temperature stress at
the CRITICAL EDGE Region, Ste
2
*** CtE
ste


Ste= Edge Warping Stress
E= Elastic Modulus of Concrete ( kg/cm2)
t= ="Maximum temperature difference between top and bottom
of slab during day time
a= Coefficient of thermal expansion
Stresses due to Temperature
C= Bradbury’s coefficient of value of L/I and B/I
L= Slab length or spacing between adjacent contraction joints.
B= Slab width or spacing between longitudinal joints ,cm
I= Radius of relative stiffness, cm
u= Poisson’s ratio
H= Thickness of concrete slab , cm
k= Modulus of subgrade reaction, kg/cum.cm.
Stresses due to Temperature
Chart showing the Values of Brodbury’s Coefficient C
Stresses due to Temperature
Chart showing Edge Temperature stresses
CORNER STRESS DUE TO LOAD
Sc= Load stress in the corner region kg/ sqcm
P= Wheel Load, kg
a= Radius of equivalent contact area , cm
The Load stress in the corner region is obtained
from the following equation
Stress Ratio and Fatigues analysis
For a given slab thickness and other design parameters,
The Flexural stress at the EDGE due to the application of
Single or Tandem Axle Loads is obtained from the appropriate STRESS
CHART.
Stress Ratio
= Flexural Stress/ Flexural Strength of Concrete
From Stress Ratio, Fatigue Life (N)
= Allowable number of Repetitions (N) is obtained
Fatigue Damage
= Expected repetitions/ Allowable number of Repetitions
Fatigue damage for each different axle loads calculated.
CUMULATIVE FATIGUE DAMAGE
SHOULD BE LESS THAN OR EQUAL TO 1.000
DESIGN PRINCIPLE OF CC PAVEMENT
• STEP 1 ( DESIGN)
• The concrete slab thickness is DESIGNED to with stand
1) the stresses due to Warping and Wheel loads at EDGE REGION.
2) The Cumulative fatigue damage obtained and should be Less than or
equal to 1.00
• STEP 2 ( CHECK)
– The concrete slab is CHECKED to the stresses at CORNER REGION, if
the dowel bars are not provided at transverse joint and if there is no
possibility of load transfer by aggregate inter-lock
DESIGN PRINCIPLE OF CC PAVEMENT
• The above Principle of Design and Check
for worst conditions will seldom takes
place, hence the methodology is likely to
result in much higher life of the pavement
than considered.
CONCRETE
1) It is strong in Compression,
2) But it is weak in Tension,
3) Its volume increases with increase of
temperature and vise-versa,
4) It shrinks with decrease in moisture
content,
5) It expands with increase in moisture
content,
6) It cracks.
JOINTS AND JOINT SPACINGS
 Joints are installed in concrete pavements to control
stresses induced by volume changes in concrete.
 These Stresses may be produced in concrete slab
because of
 1) Its CONTRACTION due to uniform temperature drop or
decrease in moisture,
 2) Its EXPANSION due to uniform temperature increase,
 3) The effect of WRAPPING of pavement due to vertical
temperature or moisture differential in the slab.
CONTRACTION STRESSES
• When the “contraction” or “ movement” of
the slab is wholly or partially prevented
TENSILE stresses are developed.
• In a pavement, resistance to movement of
slab is caused by friction between bottom of
slab and the Sub-base.
EXPANSION STRESSES
• When the Long length of concrete slab
prevented from expansion the concrete slab
may “blow up” or buckle.
• In order to prevent blow ups, relief may be
provided by the installation transversal
expansion joints.
N.B. on EXPANSION STRESSES
The EXPANSION is prevented by friction between
slab and base.
The SHRIKAGE in concrete during hardening
compensates some of expansions.
The COMPRESSIVE strength of concrete is much
higher than the stresses created by preventing
this expansion.
Hence
The EXPANSION joints may either be provided at
greater interval or may be dispensed with.
.
JOINTS DESIGN
• The Stresses effecting the Rigid Pavements
are due to
1) Moisture changes,
2) Temperature changes and
3) Wheel loadings.
The stresses will be combined effect of some or
all of the above factors.
JOINTS DESIGN
• To control the stresses resulting from the
above,
• FOUR types of joints are commonly provided
for concrete pavements.
– 1) Transverse Contraction joints,
– 2) Transverse Expansion joints and
– 3) Transverse Construction joints,
– 4) Longitudinal joints.
1)TRANVERSE CONTRACTION JOINTS
• These are “dummy” contraction joints.
• These joints control cracking of the slab,
• Also relieve he warping stresses in slab.
• These are weakened plain joints provided by creating
GROOVE of depth ¼ of Slab thickness.
• Dowel bars are provided in these joints if heavy vehicles
are expected on these roads
1)TRANVERSE CONTRACTION JOINTS
• 3 METHODS OF PROVIDING THESE JOINTS
1. 1) By inserting 6x50 mm mastic pad or thermo coal while
concrete is green or
2. 2) by pressing with MS “T” Section at right time or
3. 3) by diamond cutting within 24 hours i.e., before inherent
contraction cracks are developed.
CONTRACTION JOINT
• These are dummy groove type.
• These are to be provided to guide (by creating weak
section) the inevitable cracks in rich mixed CC
wearing coat.
SPACING OF CONTRACTION JOINTS
SLAB THICKNESS
( cm )
Maximum
contraction joint
spacing (m)
Un reinforced
Slab
15 4.5
20 4.5
25 4.5
30 5.0
35 5.0
CRACKS & CONTRACTION JOINTS
C.C. ROAD WITH IMPROPER CONTRACTION JOINTS
C.C. ROAD WITH PROPER CONTRACTION JOINTS
C.C. ROAD WITHOUT CONTRACTION JOINTS
TYPICAL CONTRACTION JOINTS
2)TRANVERSE EXPANSION JOINTS
These joints are full depth joints.
Width of these joints 19-25 mm.
Dowel bars are used in these joints if heavy
vehicles are expected on these roads.
If the contraction joints are provided as per
provisions made in, and the concrete does not
have unusual expansive qualities expansion
joints are spaced at a great interval ( 30-60m)
TYPICAL EXPANSION JOINTS
3 )TRANSVERSE CONSTRUCTION JOINTS
These joints are placed at the end of days
work or when the work is suspended for
more than 30 minutes.
These joints are provided at the regular
location of contraction joints using Dowel
bars.
4) LONGITUDINAL JOINTS
These joints run continuously along the
length of the Pavement.
These joints are provided when the width of
Pavement is more than 4.0 m.
These joints control the magnitude of
temperature warping stresses.
Tie bars are provided all along these joints to
arrest the movement of one slab w.r.t.
adjacent slabs.
DETAILS OF TIE BARS FOR LONGITUDINAL JOINT
OF TWO LANE RIGID PAVEMENTS
Slab
thickness
(cm)
Tie Bar Details
Diameter
(d) (m)
Max. Spacing (cm) Minimum Length (cm)
Plain bars Deformed
bars
Plain bars Deformed
bars
15 8 33 53 44 48
10 52 83 51 56
20 10 39 62 51 56
12 56 90 58 64
25 12 45 72 58 64
16 80 128 72 80
30 12 37 60 58 64
16 66 106 72 80
35 12 32 51 58 64
16 57 91 72 80
TYPICAL ARRENGEMENTS OF JOINTS
RECOMMENDED DIMENSIONS OF DOWEL BARS FOR
RIGID PAVEMENTS FOR AN AXILE LOAD OF 10.20 T
Slab
thickness
(cm)
Dowel bar details
Diamete
r (mm)
Length
(mm)
Spacing
(mm)
20 25 500 250
25 25 500 300
30 32 500 300
35 32 500 300
DESIGN OF SLAB THICKNESS
• The THREE different LOAD combinations
producing stresses for Pavement design are
– 1) Flexural stress due to TRAFFIC Loads,
– 2) Stress due Temperature Gradient and
– 3) Combination of Flexural stress and
Temperature stresses
DESIGN PARAMETES
• 1) Allowable Flexural Stress > 40 kg/sqcm
• 2) Elastic modulus of CC=300000 kg/sqcm.
• 3)Poisons ration of CC = 0.150
• 4) Coefficient of Thermal Expansion = 0.00001
• 5) Effective Modulus of Sub grade k-value),
• ( k- value >4 kg/sqcm/cm and < 30 kg/cucm)
• 6) Growth rate of Traffic = 7.50 %,
DESIGN PARAMETES
• 7) Traffic pattern in CVPD and Tonnage,
• Legal Axle Load for Single Axle = 10.20 T
• Legal Axle Load for Tandem Axle = 19.00 T
• Legal Axle Load for Tridem Axle = 24.00 T
• 8) Spacing of Contraction joint
• 9)Width of the Slab
• 10)Design Period,
• 11) Load safety factor
• Express ways & NH = 1.20
• State Highways & MDR = 1.10
• Residential roads = 1.00
DESIGN PARAMETES
• 12) Maximum temperature differential
of the Region.
• The Design is Trial and error Method
CHEMISTRY OF CEMENT & ENGINEERS REACTION
CEMENT CHEMISTRY(ACTION)
ENGINEERS REACTION
THANK YOU

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Rigid Pavement Design Part II

  • 2. DESIGN OF SLAB THICKNESS The Analysis of Stresses, the Design of SLAB THICKNESS and its protection involves the following procedures. a) Critical Stress Condition, b) Calculation of Stresses i. Edges Stresses, ii. Stresses due to Temperature, iii. Corner Stresses. c) Design Charts, d) Stress ratio and fatigue analysis, e) Erosion consideration, f) Hard Shoulder, g) Composite Rigid Pavement, h) Anchor Beam and Terminal Slab and i) Recommended Design Procedure.
  • 3. CRITICAL STRESS CONDITION The Factors commonly considered for the design of Pavement Thickness are. a) Flexural Stresses due to TRAFFIC Loads, b) Temperature differentials between top and bottom of concrete slab. c) The effect of moisture changes The factors (a) and (b) additive and major, The factor ( c) is opposite of Factor and very minor, hence not considered in designing the Slab thickness.
  • 4. CRITICAL STRESS CONDITION The Concrete Pavement undergo a daily cyclic change of temperature differential During day TOP surface is hotter than BOTTOM surface. During night TOP surface is cooler than BOTTOM surface.
  • 6. WARPING STRESSES • During day time the temperature of the top portion of slab may be considerably greater than that of bottom. • The top portion of slab tends to expand more than bottom portion. • The resultant slab convex towards top as shown
  • 7. • But the weight of slab resists the convex in concrete slab resulting following section WARPING STRESSES • The fibers in top are in compression and those in bottom are in tension. • This condition is called “temperature wrapping stresses” . • This “temperature wrapping stresses” is very important in design of cc pavement.
  • 10. DESIGN OF SLAB THICKNESS •The THREE different regions recognized for Pavement are –1) SLAB INTERIOR –2) SLAB EDGE –3) SLAB CORNER
  • 11. DESIGN OF SLAB THICKNESS • Combination of critical Regions and Stresses • i) Temperature stresses induced in pavement are – A) Maximum @ Slab Interior – B) Moderate @ Slab Edge and – C) Negligible @ Slab Corner ii) Load stresses induced in Pavement are A) Negligible @ Slab Interior B) Moderate @ Slab Edge and C) Maximum @ Slab Corner
  • 12. EDGE STRESSES • Combination of critical Regions and Stresses • i) Temperature stresses induced in pavement are – A) Maximum @ Slab Interior – B) Moderate @ Slab Edge and – C) Negligible @ Slab Corner ii) Load stresses induced in Pavement are A) Negligible @ Slab Interior B) Moderate @ Slab Edge and C) Maximum @ Slab Corner
  • 13. CALCULATION OFEDGE STRESSES • The STRESS CHARTS • Axles Loads for Single Axle Loads of 6, 8, 10, 12, 14, 16, 18, 20, 22 and 24 T Tandem Axles Loads of 12, 16, 20, 24, 28, 32, 36, 40, 42 and 44 T • The SLAB THICKNESS for 14,16,18,20,22,24,26,28,30,32,34,36 cm. • With k- values 6,8,10,15,30 kg/cum.cm Are used to arrive the values of stresses for respective conditions.
  • 14. STRESSES in RIGID PAVEMENTS – S.A.L. = 6.00 T
  • 15. STRESSES in RIGID PAVEMENTS – S.A.L. = 8.00 T
  • 16. STRESSES in RIGID PAVEMENTS – S.A.L. = 10.00 T
  • 17. STRESSES in RIGID PAVEMENTS – S.A.L. = 12.00 T
  • 18. STRESSES in RIGID PAVEMENTS – S.A.L. = 14.00 T
  • 19. STRESSES in RIGID PAVEMENTS – S.A.L. = 16.00 T
  • 20. STRESSES in RIGID PAVEMENTS – S.A.L. = 18.00 T
  • 21. STRESSES in RIGID PAVEMENTS – S.A.L. = 20.00 T
  • 22. STRESSES in RIGID PAVEMENTS – S.A.L. = 22.00 T
  • 23. STRESSES in RIGID PAVEMENTS – S.A.L. = 24.00 T
  • 24. STRESSES in RIGID PAVEMENTS – T.A.L. = 12.00 T
  • 25. STRESSES in RIGID PAVEMENTS – T.A.L. = 16.00 T
  • 26. STRESSES in RIGID PAVEMENTS – T.A.L. = 20.00 T
  • 27. STRESSES in RIGID PAVEMENTS – T.A.L. = 24.00 T
  • 28. STRESSES in RIGID PAVEMENTS – T.A.L. = 28.00 T
  • 29. STRESSES in RIGID PAVEMENTS – T.A.L. = 32.00 T
  • 30. STRESSES in RIGID PAVEMENTS – T.A.L. = 36.00 T
  • 31. STRESSES in RIGID PAVEMENTS – T.A.L. = 40.00 T
  • 32. STRESSES in RIGID PAVEMENTS – T.A.L. = 42.00 T
  • 33. STRESSES in RIGID PAVEMENTS – T.A.L. = 44.00 T
  • 34. Stresses due to Temperature The Temperature stress at the CRITICAL EDGE Region, Ste 2 *** CtE ste   Ste= Edge Warping Stress E= Elastic Modulus of Concrete ( kg/cm2) t= ="Maximum temperature difference between top and bottom of slab during day time a= Coefficient of thermal expansion
  • 35. Stresses due to Temperature C= Bradbury’s coefficient of value of L/I and B/I L= Slab length or spacing between adjacent contraction joints. B= Slab width or spacing between longitudinal joints ,cm I= Radius of relative stiffness, cm u= Poisson’s ratio H= Thickness of concrete slab , cm k= Modulus of subgrade reaction, kg/cum.cm.
  • 36. Stresses due to Temperature Chart showing the Values of Brodbury’s Coefficient C
  • 37. Stresses due to Temperature Chart showing Edge Temperature stresses
  • 38. CORNER STRESS DUE TO LOAD Sc= Load stress in the corner region kg/ sqcm P= Wheel Load, kg a= Radius of equivalent contact area , cm The Load stress in the corner region is obtained from the following equation
  • 39. Stress Ratio and Fatigues analysis For a given slab thickness and other design parameters, The Flexural stress at the EDGE due to the application of Single or Tandem Axle Loads is obtained from the appropriate STRESS CHART. Stress Ratio = Flexural Stress/ Flexural Strength of Concrete From Stress Ratio, Fatigue Life (N) = Allowable number of Repetitions (N) is obtained Fatigue Damage = Expected repetitions/ Allowable number of Repetitions Fatigue damage for each different axle loads calculated. CUMULATIVE FATIGUE DAMAGE SHOULD BE LESS THAN OR EQUAL TO 1.000
  • 40. DESIGN PRINCIPLE OF CC PAVEMENT • STEP 1 ( DESIGN) • The concrete slab thickness is DESIGNED to with stand 1) the stresses due to Warping and Wheel loads at EDGE REGION. 2) The Cumulative fatigue damage obtained and should be Less than or equal to 1.00 • STEP 2 ( CHECK) – The concrete slab is CHECKED to the stresses at CORNER REGION, if the dowel bars are not provided at transverse joint and if there is no possibility of load transfer by aggregate inter-lock
  • 41. DESIGN PRINCIPLE OF CC PAVEMENT • The above Principle of Design and Check for worst conditions will seldom takes place, hence the methodology is likely to result in much higher life of the pavement than considered.
  • 42. CONCRETE 1) It is strong in Compression, 2) But it is weak in Tension, 3) Its volume increases with increase of temperature and vise-versa, 4) It shrinks with decrease in moisture content, 5) It expands with increase in moisture content, 6) It cracks.
  • 43. JOINTS AND JOINT SPACINGS  Joints are installed in concrete pavements to control stresses induced by volume changes in concrete.  These Stresses may be produced in concrete slab because of  1) Its CONTRACTION due to uniform temperature drop or decrease in moisture,  2) Its EXPANSION due to uniform temperature increase,  3) The effect of WRAPPING of pavement due to vertical temperature or moisture differential in the slab.
  • 44. CONTRACTION STRESSES • When the “contraction” or “ movement” of the slab is wholly or partially prevented TENSILE stresses are developed. • In a pavement, resistance to movement of slab is caused by friction between bottom of slab and the Sub-base.
  • 45. EXPANSION STRESSES • When the Long length of concrete slab prevented from expansion the concrete slab may “blow up” or buckle. • In order to prevent blow ups, relief may be provided by the installation transversal expansion joints.
  • 46. N.B. on EXPANSION STRESSES The EXPANSION is prevented by friction between slab and base. The SHRIKAGE in concrete during hardening compensates some of expansions. The COMPRESSIVE strength of concrete is much higher than the stresses created by preventing this expansion. Hence The EXPANSION joints may either be provided at greater interval or may be dispensed with. .
  • 47. JOINTS DESIGN • The Stresses effecting the Rigid Pavements are due to 1) Moisture changes, 2) Temperature changes and 3) Wheel loadings. The stresses will be combined effect of some or all of the above factors.
  • 48. JOINTS DESIGN • To control the stresses resulting from the above, • FOUR types of joints are commonly provided for concrete pavements. – 1) Transverse Contraction joints, – 2) Transverse Expansion joints and – 3) Transverse Construction joints, – 4) Longitudinal joints.
  • 49. 1)TRANVERSE CONTRACTION JOINTS • These are “dummy” contraction joints. • These joints control cracking of the slab, • Also relieve he warping stresses in slab. • These are weakened plain joints provided by creating GROOVE of depth ¼ of Slab thickness. • Dowel bars are provided in these joints if heavy vehicles are expected on these roads
  • 50. 1)TRANVERSE CONTRACTION JOINTS • 3 METHODS OF PROVIDING THESE JOINTS 1. 1) By inserting 6x50 mm mastic pad or thermo coal while concrete is green or 2. 2) by pressing with MS “T” Section at right time or 3. 3) by diamond cutting within 24 hours i.e., before inherent contraction cracks are developed.
  • 51. CONTRACTION JOINT • These are dummy groove type. • These are to be provided to guide (by creating weak section) the inevitable cracks in rich mixed CC wearing coat.
  • 52. SPACING OF CONTRACTION JOINTS SLAB THICKNESS ( cm ) Maximum contraction joint spacing (m) Un reinforced Slab 15 4.5 20 4.5 25 4.5 30 5.0 35 5.0
  • 53. CRACKS & CONTRACTION JOINTS C.C. ROAD WITH IMPROPER CONTRACTION JOINTS C.C. ROAD WITH PROPER CONTRACTION JOINTS C.C. ROAD WITHOUT CONTRACTION JOINTS
  • 55. 2)TRANVERSE EXPANSION JOINTS These joints are full depth joints. Width of these joints 19-25 mm. Dowel bars are used in these joints if heavy vehicles are expected on these roads. If the contraction joints are provided as per provisions made in, and the concrete does not have unusual expansive qualities expansion joints are spaced at a great interval ( 30-60m)
  • 57. 3 )TRANSVERSE CONSTRUCTION JOINTS These joints are placed at the end of days work or when the work is suspended for more than 30 minutes. These joints are provided at the regular location of contraction joints using Dowel bars.
  • 58. 4) LONGITUDINAL JOINTS These joints run continuously along the length of the Pavement. These joints are provided when the width of Pavement is more than 4.0 m. These joints control the magnitude of temperature warping stresses. Tie bars are provided all along these joints to arrest the movement of one slab w.r.t. adjacent slabs.
  • 59. DETAILS OF TIE BARS FOR LONGITUDINAL JOINT OF TWO LANE RIGID PAVEMENTS Slab thickness (cm) Tie Bar Details Diameter (d) (m) Max. Spacing (cm) Minimum Length (cm) Plain bars Deformed bars Plain bars Deformed bars 15 8 33 53 44 48 10 52 83 51 56 20 10 39 62 51 56 12 56 90 58 64 25 12 45 72 58 64 16 80 128 72 80 30 12 37 60 58 64 16 66 106 72 80 35 12 32 51 58 64 16 57 91 72 80
  • 61. RECOMMENDED DIMENSIONS OF DOWEL BARS FOR RIGID PAVEMENTS FOR AN AXILE LOAD OF 10.20 T Slab thickness (cm) Dowel bar details Diamete r (mm) Length (mm) Spacing (mm) 20 25 500 250 25 25 500 300 30 32 500 300 35 32 500 300
  • 62. DESIGN OF SLAB THICKNESS • The THREE different LOAD combinations producing stresses for Pavement design are – 1) Flexural stress due to TRAFFIC Loads, – 2) Stress due Temperature Gradient and – 3) Combination of Flexural stress and Temperature stresses
  • 63. DESIGN PARAMETES • 1) Allowable Flexural Stress > 40 kg/sqcm • 2) Elastic modulus of CC=300000 kg/sqcm. • 3)Poisons ration of CC = 0.150 • 4) Coefficient of Thermal Expansion = 0.00001 • 5) Effective Modulus of Sub grade k-value), • ( k- value >4 kg/sqcm/cm and < 30 kg/cucm) • 6) Growth rate of Traffic = 7.50 %,
  • 64. DESIGN PARAMETES • 7) Traffic pattern in CVPD and Tonnage, • Legal Axle Load for Single Axle = 10.20 T • Legal Axle Load for Tandem Axle = 19.00 T • Legal Axle Load for Tridem Axle = 24.00 T • 8) Spacing of Contraction joint • 9)Width of the Slab • 10)Design Period, • 11) Load safety factor • Express ways & NH = 1.20 • State Highways & MDR = 1.10 • Residential roads = 1.00
  • 65. DESIGN PARAMETES • 12) Maximum temperature differential of the Region. • The Design is Trial and error Method
  • 66. CHEMISTRY OF CEMENT & ENGINEERS REACTION