_workshop-lrdi1.pdf

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Directions for questions 1 to 4: Answer the questions on the basis of the information given below.
Every year, Athletics World Championship takes place where each participated country represents itself
by performing well in the race. This year also, four athletes from each of the five different countries – India,
Nepal, Bhutan, Pakistan and Myanmar- participated in a 400 meters relay race. Each athlete had to run
a lap of 100 meters. Once an athlete finished the first lap, another athlete from the same team had to
continue from there for the second lap and so on following the same pattern until the team finished 400
meters race. Team which finishes the race first will be the team acquiring first position and will be awarded
with gold medal. Similarly the team which finishes the race second and third will acquire 2nd and 3rd
position respectively and will be awarded silver and bronze medal respectively.
The following was the comparison between the speeds of the runners of each country in each lap:
Lap 1: India > Nepal > Bhutan > Pakistan > Myanmar
Lap 2: Nepal > Pakistan > India > Myanmar > Bhutan
Lap 3: Pakistan > Myanmar > Nepal > Bhutan > India
Lap 4: Bhutan > India > Myanmar > Nepal > Pakistan
The following was observed at the end of the event:
(a) The fastest runner of a lap gained at least one position, with respect to the previous lap; and the
second fastest runner either gained at least one position or retained the same position, with
respect to the previous lap.
(b) The third and the fourth fastest runner can gain a maximum of one position or lose a maximum of
one position or can retain the same position, all with respect to the previous lap.
(c) The slowest runner lost at least one position with respect to the previous lap, unless he is the last
person to finish in the previous lap.
(d) Bhutan finished in the third position in the third lap and also did not win the race.
(e) No team finished at the same position in more than two laps.
(f) Indian team finished the race before Pakistan team.
1. Which of the following country ended at the last position in race?
(1) India (2) Pakistan (3) Myanmar (4) Nepal
2. If Nepal did not win the race, which country won the race?
(1) India (2) Pakistan (3) Myanmar (4) Cannot be determined
3. Which of the following is definitely true?
(1) India finished the race before Myanmar.
(2) Myanmar finished the race before Nepal.
(3) Pakistan lost the maximum number of positions in any two consecutive laps.
(4) India won the race.
LRDI - 1
Workshop
Number of Questions : 23 WSP–0016/21

LRDI - 1
4. Who was at the fourth position in the third lap?
(1) India (2) Nepal (3) Pakistan (4) Myanmar
Each of eight friends – Avinash, Bimal, Chandan, Dhruv, Emli, Farhan, Ganesh and Harjeet – belongs to
a city among Patna, Delhi, Mumbai, Chennai, Kolkata, Ranchi, Noida and Varanasi not necessarily in
that order. They are Doctor, Engineer, Teacher,Architect, Army man, Police, Manager and Businessman,
in any order and earn Rs. 50,000, Rs. 87500, Rs. 57500, Rs. 62500, Rs. 55000, Rs. 1, 25,000, Rs. 1
lakh, Rs. 1,12,500 per month not necessarily in that order. It was also know that:
I. Avinash, who is from Mumbai, is neither Architect norArmy man. Emli, who is from Kolkata, earns
double as that of the friend who is from Varanasi.
II. The sum of the earnings of Chandan and Dhruv is equal to that of Ganesh and Harjeet. Chandan is
neither from Delhi nor Noida.
III. The total earnings of the friends from Chennai and Ranchi is Rs. 1.50 lakh and they are police and
Manager in any order.
IV. The income of friend who is Manager was less than that of the friend who is police. The income of
Dhruv is less than that of Harjeet whose income is less than that of Ganesh.
V. The income of Bimal is more than that of at least three friends but less than that of at least one
friend and he is from Patna. Farhan is from Chennai.
VI. The income of an Engineer is higher than that of a Teacher which in turn is higher than that of each
of Architect and Army man.
VII. The income of Doctor and Businessman is the highest and the lowest among them.
5. The income of Farhan is
(1) Rs. 62,500 (2) Rs. 87,500 (3) Rs. 1, 12, 500 (4) Rs. 50,000
6. Who is from Ranchi?
(1) Chandan (2) Ganesh (3) Harjeet (4) Dhruv
7. For how many friends is it possible to determine their income?
(1) 5 (2) 6 (3) 7 (4) 8
8. The friend who earns Rs. 55,000 is from
(1) Delhi (2) Noida (3) Varanasi (4) Either (1) or (2)
Directions for questions 9 to 12: These questions are based on the following information.
Four salesmen – A, B, C and D – of company X, which deals in sales of cars, together sold 24 cars in a
week. The cars sold by the 4 salesmen were of types - P, Q, R and S, in no specific order.
Further, the following is known:
(i) No two types of cars are equal in number and no two salesmen sold equal number of total cars.
(ii) There are at least four cars of each type and each person sold at least four cars.
(iii) D sold eight cars and total seven cars of type S were sold.
(iv) B and D sold equal number of cars of type R, and both B and D sold at least one car of each type.
(v) A and C did not sell any car of type R.
(vi) C sold three cars of type Q and two cars of type S.
(vii) Least number of cars of type P were sold by A only.

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9. How many cars of type Q did D sell?
(1) 1 (2) 2 (3) 3 (4) Cannot be determined
10. How many total cars did B sell?
11. If D sold only one car of type S, then how many cars of type S did A sell?
(1) 0 (2) 1 (3) 2 (4) 3
12. How many cars of type P were sold by all the four salesmen taken together?
Directions for questions 13 to 15: Answer the questions on the basis of the information given below:
We are three friends— Saptarsh, Rushat and Trivendra — each has certain number of red and white balls.
I. Saptarsh has atleast one red ball and twice as many white balls as red balls.
II. Rushat has atleast one red ball and three times as many white balls as red balls.
III. Trivendra has atleast one red ball and three more white balls than red balls.
IV. When I tell you the number of balls (the number is less than 25) we have altogether, you would know
exactly how many balls I have, but would not know how many balls each of the others has”.
13. How many balls do these three people have altogether?
(1) 12 (2) 19 (3) 24 (4) 18
14. Who is the speaker of the given text?
(1) Saptarsh (2) Rushat
(3)Trivendra (4) Either Rushat or Saptarsh
15. If the number of balls with Saptarsh is three less than that with Trivendra, then what is the number
of balls with Rushat?
(1) 4
(2) 8
(3) 9
(4) Cannot be determined
There are 13 students who are members of the cultural society of a B-School. Out of 13 students, 8 are
boys – Aman, Barun, Chandan, Deepak, Eja, Fardeen, Gautam, and Hardik and rest five are girls –
Princy, Raveena, Swarna, Ushi, and Vidushi. They are to get sponsorship for the annual cultural fest of
the B-School. For this, they form three teams – A, B, and C - from among them. In each team, there are
at least 3 students and at least one girl. Further, every student is a part of at least one team.
Following is the additional information:
(i) No two students out of Aman, Barun, and Chandan are part of the same team.
(ii) If Aman is part of any team, then Ushi is also part of the same team and vice versa while Princy and
Swarna are never part of the same team.
(iii) Eja is always a part of either Team A or Team B.
(iv) Atleast one and atmost two out of Vidushi, Raveena, and Hardik must be a part of Team C.

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(v) Further, Princy is always a part of Team B only, Barun is never a part of Team C and Swarna is
never a part of Team A.
(vi) Whenever Swarna is part of any team, then Deepak is also part of the same team and vice versa.
(vii) Each team must have at least 2 boys but not more than 2 girls.
16. Which of the following could be a part of only Team C and of no other team?
(1) Deepak (2) Eja (3) Hardik (4) Vidushi
17. What could be the maximum strength (in terms of number of students) of Team A, if no student is
common in any team?
(1) 7 (2) 6 (3) 5 (4) 4
18. If Aman, Ushi, and Raveena are part of Team Aand Princy, Barun, and Fardeen are part of Team B,
then how many different composition of Team C are possible if Vidushi and Hardik are definitely
part of Team C?
(1) 15 (2) 10 (3) 9 (4) 8
19. If Team A comprise of only 4 students – Aman, Ushi, Fardeen, and Gautam, then how many
different composition of Team B are possible?
(1) 9 (2) 12 (3) 16 (4) 8
International Cricket Council (ICC), is organising “Cricket Awards 2019”. For a special category of award
given to the best all-rounder (a player who does batting as well as bowling), ICC has shortlisted five
players- Ben Stokes (BS), Shakib-Ul-Hasan (SH), Mitchell Marsh (MM), Ravindra Jadeja (RJ), and Chris
Morris (CM). They are ranked from 1 to 5 on two parameters – batting and bowling, such that in any
parameter, a numerically lower rank is considered better than a numerically higher rank. For any player,
the sum of the ranks across the two parameters is referred to as the final rank which is distinct for each
player.Additional information is as follows:
(i) SH, who has received 3rd rank in batting, had the numerically highest final rank.
(ii) No player received the same rank across the two parameters.
(iii) BS was ranked better than MM in each of the two parameters.
(iv) The difference in the ranks of MM and RJ in bowling is one.
(v) The player with the numerically lower final rank will be awarded the award for the best all-rounder of
the year.
20. Which player is awarded the best all-rounder award at “Cricket Awards 2019”?
(1) BS (2) RJ (3) MM (4) CM
21. How many players have received rank better than that of BS in the parameter of batting?
(1) 0 (2) 1 (3) 2 (4) 3
22. What is the rank received by RJ in bowling?
23. What is the absolute difference between the ranks received by BS in the parameter of batting and
MM in the parameter of bowling?
(1) 1 (2) 3 (3) 2 (4) 4

LRDI - 1
For questions 1 to 4:
The speed of the athletes in the first lap will determine their
positions at the end of lap 1. Hence, the position at the end of
first lap from first to last in that order is India, Nepal, Bhutan,
Pakistan and Myanmar. In lap 3, Bhutan finished in the third
position and the Bhutan was the fourth fastest in that lap.
From (b), the fourth fastest runner can gain a maximum of
one position. Therefore, in the second lap, Bhutan finished
either in the third or in the fourth position, but from (e), we
can say that Bhutan cannot finish in the third position either in
the second or in the fourth lap. So, Bhutan must have definitely
finished in the fourth position in the second lap. In lap 4,
Bhutan being the fastest runner, can finish the race either at
the first position or at the second position. But from (d), we
can definitely say that Bhutan finished the race in the second
position. In lap 2, Myanmar must have finished in the last
position, from (b). From (a), Nepal finished at the top in the
second lap. From (b), India finished at the second position in
the second lap. Therefore, Pakistan finished at the third position
in the second lap. In the third lap, as Pakistan is the fastest,
so, it finished either at the first or at the second position.
From (b), Nepal either finished at the second position or at
the first position in the third lap respectively. From (e),
Myanmar cannot finish in the fifth position in the third lap.
Therefore, Myanmar finished at the fourth position in the third
lap. Therefore, India finished last in the third lap. The partial
arrangements of the position of the athletes is as follows:
Case(i):
Lap 1 Lap 2 Lap 3 Lap 4
1
st
India Nepal Pakistan
2
nd
Nepal India Nepal Bhutan
3
rd
Bhutan Pakistan Bhutan
4
th
Pakistan Bhutan Myanmar
5th
Myanmar Myanmar India
Case (ii):
1
st
India Nepal Nepal
2nd
Nepal India Pakistan Bhutan
3
rd
Bhutan Pakistan Bhutan
4th
Pakistan Bhutan Myanmar
5
th
Myanmar Myanmar India
In case (ii), we can see that Nepal remained at the first
position in lap 2 and lap 3. Therefore, Nepal definitely cannot
win the race. Hence, this case is eliminated, as Nepal cannot
take any other position from (b). In case (i), Nepal finished
either at the top or at the third position in the race. If Nepal
finished at the top, Myanmar can finish either in the third
position or in the fourth position. Therefore, from (f), India
and Pakistan finished the race according the following sub-
cases:
Case (ia):
1
st
India Nepal Pakistan Nepal
2
nd
3rd
Bhutan Pakistan Bhutan Myanmar
4th
Pakistan Bhutan Myanmar India
5
th
Myanmar Myanmar India Pakistan
Case (ib):
1
st
India Nepal Pakistan Nepal
2
nd
3
rd
Bhutan Pakistan Bhutan India
4
th
Pakistan Bhutan Myanmar Myanmar
5th
Case (ic):
If Nepal finished at the third position, Myanmar definitely
finished at the fourth position. Therefore, India finished at the
top and Pakistan at the last position in the race. The
arrangement is as follows:
1
st
India Nepal Pakistan India
2nd
3
rd
Bhutan Pakistan Bhutan Nepal
4th
Pakistan Bhutan Myanmar Myanmar
5
th
1. 2 Pakistan finished last in the race.
2. 1 India won the race.
LRDI - 1
Answers and Explanations
Workshop
WSP-0016/21
1 2 2 1 3 3 4 4 5 2 6 1 7 4 8 4 9 4 10 1
11 4 12 2 13 2 14 1 15 1 16 1 17 2 18 4 19 3 20 2
21 4 22 3 23 3

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3. 3 Choice (3) is definitely true.
4. 4 Myanmar was at the fourth position in the third lap.
From statement VII: The income of Doctor and Businessman
is Rs. 1,12,500 and Rs. 50,000 respectively.
From statement III & IV: We can conclude that the income
of police and Manager is Rs. 87,500 and Rs. 62,500
respectively and they are from Chennai and Ranchi not
necessarily in that order.
From statement VI: We can conclude that the income of
Engineer and Teacher is Rs. 1,12,500 and Rs. 1,00,000
respectively. The income of Architect and Army man is Rs.
57,500 and Rs. 55,000 in any order.
From statement I: It can be concluded that Emli who is
from Kolkata earns Rs. 1,00,000 and the friend from Varanasi
earns Rs. 50,000.
From statement V: The income of Bimal is Rs. 1,12,500.
From statement II & IV: It can be concluded that the income
of Chandan, Dhruv, Ganesh and Harjeet is Rs. 62,500, Rs.
50,000, Rs. 57,500 and Rs. 55,000 respectively.
Further analysis leads to the following table:
Nam e Profession Place Incom e
Avinash Doctor Mumbai 1,25,000
Bimal Engineer Patna 1,12,500
Emli Teacher Kolkata 1,00,000
Farhan Police Chennai 87,500
Chandan Manager Ranchi 62,500
Ganesh Architect/Army man Delhi/Noida 57,500
Harjeet Army man/Architect Noida/Delhi 55,000
Dhruv Businessman Varanasi 50,000
5. 2 The income of Farhan is Rs. 87,500.
6. 1 Chandan is from Ranchi.
7. 4
8. 4
From the given information, we can see that the total number
of cars sold was 24. From (iii), we can say that, since D sold
eight cars and both of them sold at least four cars each , so,
the only combination possible is (4, 5, 7 and 8). Similarly, the
number of cars of each type is a distinct number and there
are a minimum of four cars of each type. In addition, from (iii),
since, there are seven cars of type S, we can say that this
combination is also (4, 5, 7 and 8). From (iv), B and D sold
equal number of cars of type R and From (v), A and C did not
sell any R, so, there can be either four or eight cars of type
R were sold. From (vi) and the above information, we get the
following cases:
Case (a):
P Q R S
A 0 4
B 2
C 3 0 2
D 2 8
4 7 24
Case (b):
P Q R S
A 0 4
B 1 1 4 1 7
C 0 3 0 2 5
D 4 8
4 5 8 7 24
From (vii), A sold the minimum cars of type P. Hence, case
(ii), can be eliminated. In case (i), C sold seven cars as C
cannot sell zero cars of type P (from (vii)). Hence we get
the following sub-cases:
Case (a1):
P Q R S
A 0 3 0 1 4
B 1 1 2 1 5
C 2 3 0 2 7
D 2 1 2 3 8
5 8 4 7 24
Case (a2):
P Q R S
A 0 1 0 3 4
B 1 1 2 1 5
C 2 3 0 2 7
D 2 3 2 1 8
5 8 4 7 24
Case (a3):
P Q R S
A 0 2 0 2 4
B 1 1 2 1 5
C 2 3 0 2 7
D 2 2 2 2 8
5 8 4 7 24
9. 4 D sold either one or two or three cars of type Q.
10. 1 B sold five cars.
11. 4 If D sold only one car of type S, then A sold three
cars of type S.

LRDI - 1
12. 2 Five cars of type P were sold in total.
From (I) Saptarsh has atleast 3 balls and the number of balls
can be 3, 6, 9 12, 15, 18, 21 ...
From (II) Rushat has atleast 4 balls and the number of balls can
be 4, 8, 12, 16, 20, ...
From (III) Trivendra has atleast 5 balls and the number of balls
can be 5, 7, 9, 11, 13, 15 ....
The total number of balls is atleast 12 and atmost 24.
If total number of balls is even, then Saptarsh must have an
odd number of balls and vice versa.
Make different combinations:
The total number of balls cannot be 13 because then the sum
of the number of balls with them cannot be 13.
Total cannot be 12, 14, 15, 16 and 17 because then the number
of balls with each would be known.
 Contradicting statement (IV)
Total number of balls cannot be 18, 20, 21, 22, 23 or 24 because
then the exact number of balls cannot be known for anybody.
Contradicting statement (IV). So, the total number of balls is
19.
If the total is 19, then Saptarsh must have an even number of
balls which is less than 19 – (4 + 5) = 10.
 Saptarsh must have 6 balls. Rushat and Trivendra together
have 13 balls. Rushat can have either 4 or 8 balls. Trivendra
can have either 9 or 5 balls.
 The number of balls with Rushat and Trivendra cannot be
known. Hence, the speaker is Saptarsh.
13. 2
14. 1
15. 1 As per the information given in the question, the number
of balls with Trivendra would be 9 and therefore
number of balls with Rushat would be 13 – 9 = 4.
16. 1 Using points (ii) and (v), since Princy and Swarna
cannot be in the same team and Princy is always in
Team B and Swarna is never in Team A, therefore,
Swarna can only be a part of Team C. And using
point (vi), it can be concluded that Deepak must be a
part of only Team C.
17. 2 Since no student is common in any of the 2 teams
and we have to maximize the strength of Team A,
therefore, we need to minimize the other two teams
by making them the teams of 3 students each.
One such possible scenario is as follows:
Team C  Chandan, Swarna, Deepak, and Raveena;
(Remember atleast one of Hardik, Vidushi and
Raveena must be in Team C).
Team B Princy, Barun, Eja;
Team A Aman, Fardeen, Gautam, Hardik, Ushi, and
Vidushi.
Note: In Team C, either one of Raveena or Vidhushi
should be given, but not Hardik. As there is a limitation
on the member of girls in any team but there is no
upper limit on the number of boys in the team,
therefore, Team A can accomodate any number of
boys but not more than 2 girls.
18. 4 If Aman, Ushi, and Raveena are part of Team A and
Princy, Barun, and Fardeen are part of Team B,
Team A Team A Team A
Aman
Ushi
Raveena
Princy
Barun
Fardeen
Chandan
Swarna
Deepak
Vidushi
Hardik
In order to find the possible compositions for team C,
observe all those students who can be in team C
other than the 5 mentioned students.
Fardeen, Gautam, and Eja (Eja will be considered
because point (iii) says, he will always be either in
team A or B, but it doesn’t tell if he is a part of team C
or not, therefore he could be a part of team C).
One possible combination is Chandan Swarna,
Deepak, Vidushi, and Hardik. And other will be formed
by taking all possible combinations of Fardeen,
Gautam, and Eja, which are 7.
Total possible combinations are = 1 + 7 = 8.
19. 3 If Aman is in Team A, then Barun must be a part of
Team B. (Refer pts. (i) and (iii)). Since Eja is not in
Team A therefore, he must be in Team B (Refer pt.
(iii)) and Princy is always in Team B (Refer pt. (v)).
Now out of the remaining students, following are the
possibilities:
Deepak  Must be in Team C only (Refer pts. (ii) and
(vi))
Hardik  2 options  may or may not be in Team B
Fardeen  Same as Hardik
Gautam  Same as Hardik
Swarna  Always in Team C
Ushi  Always in team C (Refer pt. (ii))
Now, out of Vidushi and Raveena, at most one can
be a part of Team B (Refer pt. (iv)) and hence 2
options (i.e., only Vidushi, or only Raveena).
Hence, total compositions for Team B
  
 
2 2 2 2
16
Hardik Gautam Fardeen Vidnshi / Raveena
.
As SH has 3rd rank in batting and also has the numerically
highest final rank, so his rank in bowling has to be either 4th
or 5th (as 3rd is not possible and if he gets 2nd rank in bowling
then the player getting 5th rank in batting will have at least 1st
rank in bowling, thus making his overall rank greater or equal
to 6). If we assume SH’s rank in bowling as 4th, then one of
MM, RJ or CM will be ranked 5th in batting or bowling (as BS
can’t get rank 5th in any parameter). The overall rank of SH
becomes 7, so the players getting rank 5th in batting and

LRDI - 1
bowling will have to get 1st rank in vice-versa parameter,
which will make their final rank equal, so SH can’t be ranked
4th in bowling. Therefore, the rank of SH in bowling parameter
is 5th.
Now, BS can’t be ranked 5th in batting and 4th in bowling
(according to statement (iii)). If rank of BS in bowling is 3rd ,
then rank of MM in bowling has to be 4th, but the ranks of MM
and RJ has to be consecutive so BS can’t be ranked 3rd in
bowling.
If BS is ranked 2nd in bowling, then MM and RJ have to be
ranked 3rd or 4th in any order and CM will be ranked 1st in
bowling. Case 1: If we take ranking of MM as 3rd and RJ as
4th in bowling, then CM has to ranked 5th and BS 1st in batting.
Now RJ can’t be 4th in both parameters so he will be ranked
2nd in batting and MM is 4th. But this is not possible as it makes
final rank of CM and RJ equal i.e., 6.
Case 2: If the rank of MM and RJ be 4th and 3rd in bowling,
then in this case also the final rank of MM and CM becomes
equal.
Thus BS is ranked 1st in bowling. Now as RJ and MM have
consecutive ranks in bowling so rank of CM in bowling will
be either 2nd or 4th. So let us make two cases for it-
Case a: CM is ranked 2nd in bowling.
Now MM and RJ will be ranked 3rd or 4th in bowling in any
order. This can further be divided in two cases- Case a(i):
MM is ranked 3rd and RJ is ranked 4th in bowling. Thus, CM will
be ranked 5th in batting, RJ is 1st in batting, BS is 2nd and MM
is 4th. But this will make final rank of CM and MM equal so this
is not possible. Case a(ii): MM is ranked 4th and RJ 3rd in
bowling. Now CM will be ranked 5th in batting and BS can be
only ranked 2nd in batting which leaves only one position of
MM i.e., rank 4th in batting which is not possible. So, Case a is
not possible.
Case b: CM is ranked 4th in bowling.
Now MM and RJ will be ranked 2nd or 3rd in bowling in any
order. This can further be divided in two cases- Case b(i):
MM is ranked 2nd and RJ is ranked 3rd in bowling. Then we
can get two scenarios- 1) In batting CM is 1st, BS is 2nd, RJ is
4th and MM is 5th, but in this final Rank of RJ and MM becomes
equal, hence, not possible. 2) In batting RJ is 1st, CM is 2nd, BS
is 4th and MM is 5th. This case satisfies as the final rank for all
are distinct. Case b(ii): MM is ranked 3rd and RJ is ranked 2nd
in bowling. So in batting, CM will be 1st, BS will be 2nd, MM will
be 4th and RJ will be 5th, but again in this, final rank of MM and
RJ becomes equal.
Thus, only one case is possible on which basis we can form
the final table.
Rank Batting Bowling
1 RJ BS
2 CM MM
3 SH RJ
4 BS CM
5 MM SH
Final ranks-:
BS 5
SH 8
MM 7
RJ 4
CM 6
20. 2 RJ is awarded the best all - rounder award at ‘Cricket
Awards 2019’.
21. 4 3 players - RJ, CM, and SH have received ranks
better than that of BS in the parameter of batting.
22. 3 The rank received by RJ in bowing is 3.
23. 3 The absolute difference between the ranks received
by BS in the parameter of batting and MM in the
parameter of bowling is |4 – 2| = 2.

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