CALL ON ➥8923113531 🔝Call Girls Hazratganj Lucknow best sexual service Online
Presentation.pptx
1. REAL NUMBERS
1.The fundamental theorem of Arithmetic.
2. Revisiting irrational numbers.
3.Revisiting rational numbers and their decimal representation.
2. THE FUNDAMENTAL THEOREM OF
ARITHMETIC
Every composite number can be expressed (factorised) as a product of primes, and this
factorization is unique.
The method of finding the HCF and LCM of two positive numbers by the prime factorization
method.
Example: Find HCF and LCM of 108 and 150 108 =2² X 3³ and 150 =2 X 3 X 5² HCF(108,150) =2 X3
= Product of SMALLEST power of each common prime factor in the numbers.
LCM(108,150)= 2² X 3³ X5² = Product of GREATEST power of each common prime factor in the
numbers. Notice that HCF(108,150) X LCM(108,150)= 108 X150
3. REVISITING IRRATIONAL NUMBERS
In this section, we will prove that numbers of the form √p are irrational where p is a prime.
Example: Prove √2 is irrational. Proof: Assume √2 is rational. Then √2 =a/b ,where a and b are co-
prime and b≠ 0.
Squaring both sides, we get 2b² = a² , i.e. 2 divides a²,implies 2 divides a. Let a=2c.Then ,
substituting for a, we get 2b²=4c² i.e.b² = 2c² This means that 2 divides b²,and so divides b.
Therefore, a and b have at least 2 as a common factor. This contradicts the fact a and b have no
common factors other than 1.
So, we conclude that √2 is irrational. Similarly, we can prove that √3 ,√5 etc are irrational.
4. Proving Irrational Numbers
Example: Show that 3 − √5 is irrational.
Proof: Assume 3 − √5 is rational. Then 3 − √5=a/b, where and b are co-prime,b≠0.
Rearranging the equation, we get √5=3 − (a/b) = (3b − a)/b Since a and b are integers (3b − a)/b is
rational, and so , √5 is rational.
This contradicts the fact that √5 is irrational. Therefore, our assumption is wrong
5. REVISITING RATIONAL NUMBERS AND THEIIR
DECIMAL REPRESENTATION - I
Theorem 1: Let x be a rational number whose decimal expansion terminates. Then ,x can be
expressed in the form p/q, where p and q are coprime ,and the prime-factorisation of q is in the
form 2 n5m where n and m are non-negative integers.
Example : 0.107 = 107/1000= 107/(2³ x 5³ )
Example: 7.28 = 728/100 = 728 / 10²
6. REVISITING RATIONAL NUMBERS AND
THEIR DECIMAL REPRESENTATION - II
Theorem 2 : Let x = p/q be a rational number such that prime factorisation of q is of the form 2
n5m where n and m are non-negative integers. Then x has a decimal representation that
terminates.
Example: 3/8 = 3/2³ = 0.375
Example: 13/250=13/ 2 x 5³ = 0.052
7. REVISITING RATIONAL NUMBERS
AND THEIR DECIMAL REPRESENTATION - III
Theorem 3 :
Let x=p/q ,where p and q are coprimes be a rational number such that prime factorisation of q is
not of the form 2 n5m ,where n and m are non-negative integers.
Then ,x has a decimal expansion which is nonterminating repeating.