Measures of Central Tendency: Ungrouped and Grouped
1.
2. U M O D E A B C V N N M M
M N A S D S F H K H H Y H
I W G R O U P E D D A T A
D K Y R E M E A N Y R O N
D I R T O Y R Y E W S T D
L N Z N B U A L W D B A M
E T Q D A E P T M Z B L O
Q E Y D L M N E E K P O D
A R R Y U I O P D J N B A
Z V V H Y R F A I D D H L
G A W E R T Y U A Y A H B
T L F R E Q U E N C Y T F
F U R E G X A S D G J K A
L O W E R B O U N D E R Y
H U E G B A S F G H J K L
7. An ungrouped data is a set of values that
is not organized or classified as a
group. A measure of central tendency is a
value that represents the whole set of
data. These are mean, median and mode.
8. The mean of ungrouped data is obtained by adding
all the values divided by the frequency of a set of
data. The mean of ungrouped data is also called
average. It is written as:
π₯Μ =
β π±
π
where;
π₯Μ = is the mean
β π = is the sum of all the values in a set
π = is the frequency
9. The number of confirmed COVID 19 cases from
March 21- 27, 2020 are as follows: 77, 73, 82, 90,
84, 71, 96. To get the mean, we have;
π₯Μ =
β π±
π π₯Μ =
77+73+82+90+84+71+96
π
EXAMPLE 1
π₯Μ =
πππ
π
π₯Μ = 81.857142 β¦
π₯Μ = 82
10. Example 2:
Amyβs score in exam are 23, 21, 28, 29, 23. What is
the mean of the given set of data?
π₯Μ =
β π±
π
π₯Μ =
ππ+ππ+ππ+ππ+ππ
π
π₯Μ =
πππ
π
π₯Μ = 24. 8 or 25
11. The median of ungrouped data is the middle value of a set of
data when all values are arranged in either ascending or
descending order.
ο Arrange the data in ascending order.
ο If the frequency of the data is odd , then the middle value will be
median of the set of data. And If the frequency of the data is even, the
median of the data is the mean of the two middle values.
ο To find middle values of the data used this formula.
πΜ =
π§+π
π
where; πΜ β is the median
π β is the frequency
12. The number of confirmed COVID 19 cases from
March 21- 27, 2020 are as follows: 77, 73, 82, 90,
84, 71, 96. Find the median.
ο± Arrange the data in ascending order
71,73,77, 82, 84, 90, 96
π₯Μ =
π±+π
π
π₯Μ =
π+π
π
π₯Μ =
π
π
π₯Μ = 4th score
13. The score in the exam of students are 33, 32,35,
39, 40, 32, 30, 39 what is the median?
EXAMPLE 3
οArrange the set of data in ascending order
30, 32, 32, 33, 35, 39, 39, 40
πΜ =
π+1
2 The π. π ππ score of the data is the mean of
the 4th and 5th score. We have,
33+35
2
=
68
2
=34
πΜ =
8+1
2
πΜ =
9
2
πΜ = 4.5
14. The mode of the ungrouped data is the value that most
frequently appears in a set of data. When the value in a set
of data appears only once, then the data has no mode.
The data can be also classified according to the number of
modes it has.
Unimodal- one mode
Bimodal- two modes
Multimodal- more than 2 modes
15. The number of confirmed COVID 19 cases from March
21- 27, 2020 are as follows: 77, 73, 82, 90, 84, 71, 96.
What is the mode?
- no mode
Find the mode of the given set of data: 8, 4, 7, 9, 5, 5, 5, 7
Mode is 5 Multimodal
16.
17. The data shows the ages of first 55 confirmed Covid-19
Cases Tested in the Philippines. Find the mean, median and
mode of the distribution.
To solve for the mean of
grouped data, use the formula:
where:
πΜ = is the mean
β ππ =is the sum of the
products of the frequency and
its corresponding class mark
N = is the total frequency.
πΏ=
β ππΏ
π΅
18. Class mark is the mid value of the class interval. It can be solved by
adding the lower-class limit and upper-class limit and divided by 2.
Table 1. Frequency Distribution of the Ages of the first 55 confirmed Covid-19
Patient in the Philippines
Ages of
Covid-19
Patient
Frequency Class
Marks (X)
fX
80-89 3 84.5 253.5
70-79 7 74.5 521.5
60-69 11 64.5 709.5
50-59 12 54.5 654
40-49 9 44.5 400.5
30-39 8 34.5 276
20-29 5 24.5 122.5
π = ππ π΅ = ππ ππΏ = π, πππ. π
π=
β ππ
π
π=
2937.5
55
π= 53.41
25. Activity
Part I. Ungrouped Data
Direction: Find the mean, median and mode.
The water consumption (in cubic meter) for the past 6
months is shown below.
January 23
February 24
March 25
April 25
May 26
June 24
26. Part II. Grouped Data
Direction: Complete the table, then solve for the mean, median and mode
of the distribution.
Height of Grade 10 Students
Height in
cm
Frequency Class
Mark
fX Lover
Boundary
<cf
180 β 185 1 182.5 182.5 179.5
174 β 179 2 176.5 49
168 β 173 8 167.5
162 β 167 15 2467.5 39
156 β 161 17 158.5 155.5
150 β 155 7 1067.5 7
π=____ N=___ β ππΏ=__