poweroint presentation

2. 1. Sketch the graph of f(x) = 2x2 – 8x + 8.
Steps Solution
1. Find the axis of symmetry and the
vertex.
a= 2, b = -8, c = 8
axis of symmetry = h or (x) = -
𝑏
2𝑎
= -
(−8)
2(2)
= -
(−8)
4
=
8
4
= 2
k = f(h)
k = 2x2 – 8x + 8
= 2(2)2 – 8(2) + 8
= 2(4) - 16 + 8
= 8 - 16 + 8 = 0
or k or (y) = -
b2 – 4ac
4a
= -
(−8)2 – 4(2)(8)
4(2)
= -
𝟔𝟒 −𝟔𝟒
𝟖
= -
𝟎
𝟖
= 0

3. Steps Solution
2. Write the vertex (h, k) = (2, 0)
3. Prepare a table of values.
Get the value of x which is
higher and less than the axis of
symmetry.
Let x = 0, 1, 2, 3, 4
f(x) = 2x2 – 8x + 8
=2(0)2 – 8(0) + 8 = 8
=2(1)2 – 8(1) + 8 = 2
=2(3)2 – 8(3) + 8 = 2
=2(4)2 – 8(4) + 8 = 8

4. Table of Values
x 0 1 3 4
y 8 2 2 8