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Recalling, a linear function comes in the form f(x) = mx +
b or y = mx + b. This form is referred to as the slope-intercept
form where m is the slope of the line and b represents the y-
intercept of the linear function.
We also have the standard form of linear function, which
is written in the form
ax + by = c
where a, b, and c are integers, and a > 0.
Recall the equation of the line using the following
forms:
1. Point-Slope Form 𝑦 − 𝑦1 = 𝑚 (𝑥 − 𝑥1)
2. Two-Point Slope 𝑦 − 𝑦1 =
𝑦2
−𝑦1
𝑥2
−𝑥1
(𝑥 − 𝑥1)
3. Slope-Intercept Form 𝑦 = 𝑚𝑥 + 𝑏
4. Intercept Form
𝑥
𝑎
+
𝑦
𝑏
= 1
Example1.
Find the general term of the equation of the line which
through P1(-1, 8) and whose slope is m =
𝟐
𝟑
.
Steps Solution
1. Identify the given information
m =
𝟐
𝟑
and P1(-1, 8)
x1 = -1 and y1 = 8
2. Identify the formula to be
used.
𝑦 − 𝑦1 = 𝑚 (𝑥 − 𝑥1)
Steps Solution
3. Substitute the given
information in step 1 to the
formula in step 2.
𝑦 − 𝑦1 = 𝑚 (𝑥 − 𝑥1)
𝑦 − 8 =
𝟐
𝟑
𝑥 − (−1)
4. Find the general equation of
the line
ax + by + c = 0
𝑦 − 8 =
𝟐
𝟑
(𝑥 + 1)
3y – 24 = 2(x + 1)
3y – 24 = 2x + 2
-2x + 3y -24 – 2 = 0
-2x + 3y - 26 = 0
(-2x + 3y - 26 )(-1)= 0(-1)
2x – 3y + 26 = 0
Thus, the general form of the equation of the line is 2x – 3y + 26 = 0.
Example 2.
Determine the general form of the equation of the line
passing through P1(5, -3) and P2(2, 7).
Steps Solution
1. Identify the given information P1(5, -3) and P2(2, 7)
x1= 5, y1 = -3, x2 = 2 and y2 = 7
2. Identify the formula to be
used.
𝑦 − 𝑦1 =
𝑦2
−𝑦1
𝑥2
−𝑥1
(𝑥 − 𝑥1)
Steps Solution
3. Substitute the given
information in step 1 to the
formula in step 2.
𝑦 − 𝑦1 =
𝑦2
−𝑦1
𝑥2
−𝑥1
(𝑥 − 𝑥1)
y – (-3) =
7 −(−3)
2 −5
(x – 5)
4. Find the general equation
the line.
y + 3 =
7+3
−3
(x – 5)
y + 3 =
10
−3
(x – 5)
y + 3 =
10
−3
(x – 5) (-3)
-3y – 9 = 10(x – 5)
-3y – 9 = 10x – 50
-10x – 3y – 9 + 50 = 0
−10x – 3y + 41 (-1)= 0(-1)
10x + 3y – 41 = 0
Therefore the general form of the equation is 10x + 3y – 41 = 0
Example 3.
Determine the slope-intercept form of the equation of the
line whose x – intercept and y-intercept are (-5, 0) and (0, 4),
respectively.
Steps Solution
1. Identify the given.
We have (-5, 0) and (0, 4)
a = -5 and b = 4
2. Identify the formula.
𝑥
𝑎
+
𝑦
𝑏
= 1
3. Find the slope-intercept form
𝑥
−5
+
𝑦
4
= 1 (20)
4x + 5y = 20
5y = - 4x + 20
y = -
𝟒
𝟓
x + 4
Finding Equation of a Line.pptx

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Finding Equation of a Line.pptx

  • 1.
  • 2. Recalling, a linear function comes in the form f(x) = mx + b or y = mx + b. This form is referred to as the slope-intercept form where m is the slope of the line and b represents the y- intercept of the linear function. We also have the standard form of linear function, which is written in the form ax + by = c where a, b, and c are integers, and a > 0.
  • 3. Recall the equation of the line using the following forms: 1. Point-Slope Form 𝑦 − 𝑦1 = 𝑚 (𝑥 − 𝑥1) 2. Two-Point Slope 𝑦 − 𝑦1 = 𝑦2 −𝑦1 𝑥2 −𝑥1 (𝑥 − 𝑥1) 3. Slope-Intercept Form 𝑦 = 𝑚𝑥 + 𝑏 4. Intercept Form 𝑥 𝑎 + 𝑦 𝑏 = 1
  • 4. Example1. Find the general term of the equation of the line which through P1(-1, 8) and whose slope is m = 𝟐 𝟑 . Steps Solution 1. Identify the given information m = 𝟐 𝟑 and P1(-1, 8) x1 = -1 and y1 = 8 2. Identify the formula to be used. 𝑦 − 𝑦1 = 𝑚 (𝑥 − 𝑥1)
  • 5. Steps Solution 3. Substitute the given information in step 1 to the formula in step 2. 𝑦 − 𝑦1 = 𝑚 (𝑥 − 𝑥1) 𝑦 − 8 = 𝟐 𝟑 𝑥 − (−1) 4. Find the general equation of the line ax + by + c = 0 𝑦 − 8 = 𝟐 𝟑 (𝑥 + 1) 3y – 24 = 2(x + 1) 3y – 24 = 2x + 2 -2x + 3y -24 – 2 = 0 -2x + 3y - 26 = 0 (-2x + 3y - 26 )(-1)= 0(-1) 2x – 3y + 26 = 0 Thus, the general form of the equation of the line is 2x – 3y + 26 = 0.
  • 6. Example 2. Determine the general form of the equation of the line passing through P1(5, -3) and P2(2, 7). Steps Solution 1. Identify the given information P1(5, -3) and P2(2, 7) x1= 5, y1 = -3, x2 = 2 and y2 = 7 2. Identify the formula to be used. 𝑦 − 𝑦1 = 𝑦2 −𝑦1 𝑥2 −𝑥1 (𝑥 − 𝑥1)
  • 7. Steps Solution 3. Substitute the given information in step 1 to the formula in step 2. 𝑦 − 𝑦1 = 𝑦2 −𝑦1 𝑥2 −𝑥1 (𝑥 − 𝑥1) y – (-3) = 7 −(−3) 2 −5 (x – 5) 4. Find the general equation the line. y + 3 = 7+3 −3 (x – 5) y + 3 = 10 −3 (x – 5) y + 3 = 10 −3 (x – 5) (-3) -3y – 9 = 10(x – 5) -3y – 9 = 10x – 50 -10x – 3y – 9 + 50 = 0 −10x – 3y + 41 (-1)= 0(-1) 10x + 3y – 41 = 0 Therefore the general form of the equation is 10x + 3y – 41 = 0
  • 8. Example 3. Determine the slope-intercept form of the equation of the line whose x – intercept and y-intercept are (-5, 0) and (0, 4), respectively. Steps Solution 1. Identify the given. We have (-5, 0) and (0, 4) a = -5 and b = 4 2. Identify the formula. 𝑥 𝑎 + 𝑦 𝑏 = 1 3. Find the slope-intercept form 𝑥 −5 + 𝑦 4 = 1 (20) 4x + 5y = 20 5y = - 4x + 20 y = - 𝟒 𝟓 x + 4