4. Introduction
ο§ Solving Trigonometric Equations.
Trigonometric equations are, as the name implies, equations that
involve trigonometric functions. Similar in many ways to solving
polynomial equations or rational equations, only specific values of the
variable will be solutions, if there are solutions at all. Often we will
solve a trigonometric equation over a specified interval. However, just
as often, we will be asked to find all possible solutions, and as
trigonometric functions are periodic, solutions are repeated within
each period. In other words, trigonometric equations may have an
infinite number of solutions. Additionally, like rational equations, the
domain of the function must be considered before we assume that any
solution is valid.
5. Introduction
ο§ Solving trigonometric equations requires the same techniques
as solving algebraic equations. We read the equation from left
to right, horizontally, like a sentence. We look for known
patterns, factor, find common denominators, and substitute
certain expressions with a variable to make solving a more
straightforward process. However, with trigonometric
equations, we also have the advantage of using the identities we
already know.
7. Solve equations for a given interval
Solve sin β cos β β
1
2
cos β = 0. πΌπ 0 β€ β β€ 180Β°.
Solution:
* Factor cos β
πππ β sin β β
1
2
= 0
* Use zero product property:
β’ cos β = 0 or sin β β
1
2
= 0
β’ β = 90Β° sin β =
1
2
β’ β = 30Β° ππ 150Β°
β’ The solutions are 30Β°, 90Β°, 150Β°.
8. Solve equations for
a given interval
Practice
ο§ Find all the solutions of sin 2β = cos β , if 0 β€ β β€ 2π
9. Trigonometric equations are usually solved
for values of variables between 0Β° πππ 360Β°
or between 0 radians and 2π radians.
There are solutions outside that interval,
these other solutions differ by integral
multiples of the period of the function.
10. Infinitely many solutions
Solve cos β + 1 = 0, for all values of β ππ β is measured in radians.
Solution:
cos β + 1 = 0
cos β = β1
Look at the graph of π¦ = cos β to find the solution
of cos β = β1
The solutions are π, 3π, 5π πππ π π ππ, and βπ, β3π, β5π, πππ π π ππ
The only solution in interval 0 radians to 2π radians is π. The period of the cosine function
is 2π radians. So the solution can be written as π + 2ππ, where π is any integer.