![100
120
140
COSTANT LOAD DEVELOPED IN SINE SHAPES
HARMONICS # 1,3,...19
0
20
40
60
80
100
0 2,00 4,00 6,00 8,00 10,00 12,00 14,00 16,00 18,00 20,00 22,00 24,00 26,00 28,00 30,00 32,00 34,00 36,00 38,00 40,00
L= SPAN 40 [m]
q = [100 kN/m]
theoretical load
value 100](https://image.slidesharecdn.com/postslideshare012016ls-160225143253/85/Post-slide-share_01_2016_ls-1-320.jpg)
![What does it happen when one harmonic lacks?
E.g. supposing that harmonic # 5 lacks..
This is the output.
60
80
100
120
140
theoretical
0
20
40
0
2,00
4,00
6,00
8,00
10,00
12,00
14,00
16,00
18,00
20,00
22,00
24,00
26,00
28,00
30,00
32,00
34,00
36,00
38,00
40,00
theoretical
Precision decreases.
It must be pointed out that only odd m-th harmonics contribute to load
development (refinement).
Whatever even m-th contribution vanishes.
Simmetry of load function remains with respect to X=L/2 = 20 [m]](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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Post slide share_01_2016_ls
- 1. 100 120 140 COSTANT LOAD DEVELOPED IN SINE SHAPES HARMONICS # 1,3,...19 0 20 40 60 80 100 0 2,00 4,00 6,00 8,00 10,00 12,00 14,00 16,00 18,00 20,00 22,00 24,00 26,00 28,00 30,00 32,00 34,00 36,00 38,00 40,00 L= SPAN 40 [m] q = [100 kN/m] theoretical load value 100
- 2. What does it happen when one harmonic lacks? E.g. supposing that harmonic # 5 lacks.. This is the output. 60 80 100 120 140 theoretical 0 20 40 0 2,00 4,00 6,00 8,00 10,00 12,00 14,00 16,00 18,00 20,00 22,00 24,00 26,00 28,00 30,00 32,00 34,00 36,00 38,00 40,00 theoretical Precision decreases. It must be pointed out that only odd m-th harmonics contribute to load development (refinement). Whatever even m-th contribution vanishes. Simmetry of load function remains with respect to X=L/2 = 20 [m]
- 3. Take a look to the load shapes.. Harmonic #1, 3, 5 (q=100 [kN/m]) Sum of the first three Harmonics.. And so on for remaining harmonics # 7,9,11,13,15,17,19