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B A S I C D E F I N I T I O N S U N D E R G R O U P
ABSTRACT ALGEBRA
GROUP
A group is a nonempty set tt on which there is defined
a binary operation (a, b)→ ab satisfying the
following properties.
 Closure: If a and b belong to tt, then ab is also in tt;
 Associativity : a(bc) = (ab)c for all a, b, c ∈ tt;
 Identity : There is an element 1 ∈ tt such that a1 =
1a = a for all a in tt;
 Inverse: If a is in tt, then there is an element a−1 in
tt such that aa−1 = a−1a = 1.
ABELIAN GROUP
 A group tt is abelian if the binary operation is
commutative, i.e., ab = ba for all a, b in tt. In this
case the binary operation is often written additively
((a, b) → a + b), with the identity written as 0
rather than 1.
SUBGROUP
A subgroup H of a group tt is a nonempty subset of tt
that forms a group under the binary operation of tt.
Equivalently, H is a nonempty subset of tt such that if
a and b belong to H, so does ab−1.
ISOMORPHIC
The groups tt1 and tt2 are said to be isomorphic if there
is a bijection f : tt1 tt2 that preserves the group
operation, in other words, f (ab) = f (a)f (b).
Isomorphic groups are essentially the same; they differ
only notationally.
ORDER OF AN ELEMENT
If tt is a finite cyclic group of order n, then tt has
exactly one (necessarily cyclic) subgroup of order n/d
for each positive divisor d of n, and tt has no other
subgroups.
PERMUTATION GROUPS
A permutation of a set S is a bijection on S, that is, a
function π : S→ S that is one- to-one and onto. (If S
is finite, then π is one-to-one if and only if it is onto.) If
S is not too large, it is feasible to describe a
permutation by listing the elements x ∈ S and the
corresponding values π(x).
NORMAL SUGROUPS
Let H be a subgroup of tt. If any of the following
equivalent conditions holds, we say that H is a normal
subgroup of tt, or that H is normal in tt:
 cHc−1 ⊆ H for all c ∈ tt (equivalently, c−1Hc ⊆ H for
all c ∈ tt).
 cHc−1 = H for all c ∈ tt (equivalently, c−1Hc = H for all
c ∈ tt).
 cH = Hc for all c ∈ tt.
 Every left coset of H in tt is also a right coset.
 Every right coset of H in tt is also a left coset.
QUOTIENT GROUPS
If H is normal in tt, we may define a group multiplication on cosets, as follows. If aH
and bH are (left) cosets, let
(aH)(bH) = abH;
by (1.3.7), (aH)(bH) is simply the set product. If a1 is another member of aH and b1
another member of bH, then a1H = aH and b1H = bH (Problem 5). Therefore the set
product of a1H and b1H is also abH. The point is that the product of two cosets does
not depend on which representatives we select.
To verify that cosets form a group under the above multiplication, we
consider the four defining requirements.
Closure: The product of two cosets is a coset.
Associativity : This follows because multiplication in tt is associative.
Identity : The coset 1H = H serves as the identity.
Inverse: The inverse of aH is a−1H.
HOMEOMORPHISM
 If f : tt →H, where tt and H are groups, then f is said
to be a homomorphism if for all a, b in tt, we have
f (ab) = f (a)f (b).
THANK YOU

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Abstract algebra ppt

  • 1. B A S I C D E F I N I T I O N S U N D E R G R O U P ABSTRACT ALGEBRA
  • 2. GROUP A group is a nonempty set tt on which there is defined a binary operation (a, b)→ ab satisfying the following properties.  Closure: If a and b belong to tt, then ab is also in tt;  Associativity : a(bc) = (ab)c for all a, b, c ∈ tt;  Identity : There is an element 1 ∈ tt such that a1 = 1a = a for all a in tt;  Inverse: If a is in tt, then there is an element a−1 in tt such that aa−1 = a−1a = 1.
  • 3. ABELIAN GROUP  A group tt is abelian if the binary operation is commutative, i.e., ab = ba for all a, b in tt. In this case the binary operation is often written additively ((a, b) → a + b), with the identity written as 0 rather than 1.
  • 4. SUBGROUP A subgroup H of a group tt is a nonempty subset of tt that forms a group under the binary operation of tt. Equivalently, H is a nonempty subset of tt such that if a and b belong to H, so does ab−1.
  • 5. ISOMORPHIC The groups tt1 and tt2 are said to be isomorphic if there is a bijection f : tt1 tt2 that preserves the group operation, in other words, f (ab) = f (a)f (b). Isomorphic groups are essentially the same; they differ only notationally.
  • 6. ORDER OF AN ELEMENT If tt is a finite cyclic group of order n, then tt has exactly one (necessarily cyclic) subgroup of order n/d for each positive divisor d of n, and tt has no other subgroups.
  • 7. PERMUTATION GROUPS A permutation of a set S is a bijection on S, that is, a function π : S→ S that is one- to-one and onto. (If S is finite, then π is one-to-one if and only if it is onto.) If S is not too large, it is feasible to describe a permutation by listing the elements x ∈ S and the corresponding values π(x).
  • 8. NORMAL SUGROUPS Let H be a subgroup of tt. If any of the following equivalent conditions holds, we say that H is a normal subgroup of tt, or that H is normal in tt:  cHc−1 ⊆ H for all c ∈ tt (equivalently, c−1Hc ⊆ H for all c ∈ tt).  cHc−1 = H for all c ∈ tt (equivalently, c−1Hc = H for all c ∈ tt).  cH = Hc for all c ∈ tt.  Every left coset of H in tt is also a right coset.  Every right coset of H in tt is also a left coset.
  • 9. QUOTIENT GROUPS If H is normal in tt, we may define a group multiplication on cosets, as follows. If aH and bH are (left) cosets, let (aH)(bH) = abH; by (1.3.7), (aH)(bH) is simply the set product. If a1 is another member of aH and b1 another member of bH, then a1H = aH and b1H = bH (Problem 5). Therefore the set product of a1H and b1H is also abH. The point is that the product of two cosets does not depend on which representatives we select. To verify that cosets form a group under the above multiplication, we consider the four defining requirements. Closure: The product of two cosets is a coset. Associativity : This follows because multiplication in tt is associative. Identity : The coset 1H = H serves as the identity. Inverse: The inverse of aH is a−1H.
  • 10. HOMEOMORPHISM  If f : tt →H, where tt and H are groups, then f is said to be a homomorphism if for all a, b in tt, we have f (ab) = f (a)f (b).