7. GUIDE QUESTIONS
1.What was the video all about?
1.What was the video all about?
1.What was the video all about?
2. Describe the motion of the vehicle in the
video.
3. What can be measured in a moving object?
9. OBJECTIVES
Define concepts involving rectilinear motion
(average velocity, instantaneous velocity,
speed and acceleration)
Solve problems involving the concept of
differentiation (rectilinear motion)
10. KINEMATICS
Kinematics is the study of motion of a system of
bodies without directly considering the forces or
potential fields affecting the motion. In other
words, kinematics examines how the momentum
and energy are shared among interacting bodies.
11. RECTILINEAR MOTION
Rectilinear motion is another name for
straight-line motion (vertical or horizontal
orientation). This type of motion describes
the movement of a particle or a body.
12. GUIDE QUESTIONS
1. Does the video showcase a rectilinear motion?
2. What are some examples of rectilinear motion?
16. SCALAR QUANTITIES
Time is the progression of events from the past
to the present into the future.
Units: Seconds ,Minutes, Hours, Day, Week,
Month
17. SCALAR QUANTITIES
Distance is a scalar quantity that refers to
"how much ground an object or a particle has
covered" during its motion.
Units: Meter, Kilometer, Miles, etc.
18. SCALAR QUANTITIES
Speed is a scalar quantity that refers to "how
fast an object is moving." Speed can be thought
of as the rate at which an object covers
distance.
π =
π
π
Units: m/s, km/hr., mi/s, mi./min, etc.
19. VECTOR QUANTITIES
Vector quantity is defined as the physical
quantity that has both magnitude and direction.
Example: Velocity, Acceleration
20. VECTOR QUANTITIES
Velocity is a vector quantity that refers to "the
rate at which an object changes its position."
Average Velocity Instantaneous Velocity
21. VECTOR QUANTITIES
The instantaneous velocity is
the specific rate of change of
position (or displacement) with
respect to time at a single
point.
24. VECTOR QUANTITIES
Acceleration is a vector quantity that is defined as
the rate at which an object changes its velocity. An
object is accelerating if it is changing its velocity.
π =
βπ£
βπ‘
Units: π/π 2
, ππ/βπ.2
, ππ/π 2
, ππ./πππ.2
, ππ‘π.
25. Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
i. The average velocity βπ of P at time π‘1 to π‘2 is βπ =
βπ π
βπ
.
The average velocity of a particle in a rectilinear motion
is the average rate of change of its position function.
RELATIONSHIP OF
POSITION/DISTANCE, SPEED
VELOCITY AND ACCELERATION
OF A PARTICLE IN A
RECTILINEAR MOTION
26. Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
ii. The instantaneous velocity π(π) of P at time t is
π π = πβ² π =
π π
π π
.
β’ The instantaneous velocity of a particle in a rectilinear motion is the
instantaneous rate of change of its position function.
β’ The first derivative of the position function is the instantaneous
velocity of P.
RELATIONSHIP OF
POSITION/DISTANCE, SPEED
VELOCITY AND ACCELERATION
OF A PARTICLE IN A
RECTILINEAR MOTION
27. Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
iii. The speed of P at time t is π π =
π π
π π
.
The speed of P is the absolute value of first
derivative of the position function which is the
velocity of P.
RELATIONSHIP OF
POSITION/DISTANCE, SPEED
VELOCITY AND ACCELERATION
OF A PARTICLE IN A
RECTILINEAR MOTION
28. Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
iv. The acceleration π π of P at time t is
π π = πβ²β² π = πβ² π =
π π
π π
.
The acceleration of P is the second derivative of
the position function. It is also the first derivative
of the velocity function of P.
RELATIONSHIP OF
POSITION/DISTANCE, SPEED
VELOCITY AND ACCELERATION
OF A PARTICLE IN A
RECTILINEAR MOTION
29. Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
i. Average velocity βπ =
βπ π
βπ
ii. Instantaneous velocity π π = πβ² π =
π π
π π
iii. Speed π π =
π π
π π
iv. Acceleration π π = πβ²β² π = πβ² π =
π π
π π
RELATIONSHIP OF
POSITION/DISTANCE, SPEED
VELOCITY AND ACCELERATION OF A
PARTICLE IN A RECTILINEAR
MOTION
30. EXAMPLE
A particle moves along a line so that its position at any time π > π is
given by the function π π = ππ β ππ + π where s is measured in
meters and t is measured in seconds.
a.Find the average velocity during the first 5 seconds.
b.Find the distance traveled by the particle after 7 seconds.
c.Find the instantaneous velocity when π = π.
d.Find the acceleration of the particle when π = π.
31. RELATIONSHIP OF
POSITION/DISTANCE, VELOCITY AND
ACCELERATION OF A PARTICLE IN A
RECTILINEAR MOTION
Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
i. Average velocity βπ =
βπ π
βπ
ii. Instantaneous velocity π π = πβ² π =
π π
π π
.
iii. Speed π π =
π π
π π
iv. Acceleration π π = πβ²β² π = πβ² π =
π π
π π
.
32. SOLUTION
a.To find the average velocity of the particle during first 5 seconds,
we use the formula βπ =
βπ π
βπ
=
π π‘2 βπ π‘1
ππβππ
at π‘1 = 0 and π‘2 = 5.
To find the value of π π‘1 and π π‘2 , substitute π‘1 = 0 and π‘2 = 5 to the
given function
π π = ππ
β ππ + π when ππ = π
π π = π π
β π π + π
π(π) = π β π + π
π(π) = π
π π = ππ
β ππ + π when ππ = π
π π = π π
β π π + π
π (π) = πππ β ππ + π
π(π) = πππ
33. SOLUTION
To find the average velocity, substitute π(π) = π, π(π) = ππ, π‘1 =
0 and π‘2 = 5 to the formula:
βπ =
βπ π
βπ
=
π π‘2 β π π‘1
ππ β ππ
βπ =
612 β 2
π β π
βπ =
610
π
βπ = πππ meters per second
34. RELATIONSHIP OF
POSITION/DISTANCE, VELOCITY AND
ACCELERATION OF A PARTICLE IN A
RECTILINEAR MOTION
Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
i. Average velocity βπ =
βπ π
βπ
ii. Instantaneous velocity π π = πβ² π =
π π
π π
.
iii. Speed π π =
π π
π π
iv. Acceleration π π = πβ²β² π = πβ² π =
π π
π π
.
35. SOLUTION
b. To find the distance traveled by the particle after 7
seconds, substitute π = π to the position function.
π π = ππ
β ππ + π when π = π
π π = π π
β π π + π
π(π) = ππππ β ππ + π
π(π) = ππππ ππ
36. SOLUTION
c. To find the instantaneous velocity of the particle
when π = π, we differentiate π π = ππ
β ππ + π with
respect to time (π).
π π = πβ²(π) =
π π
π π
=
π
π π
ππ
β ππ + π
π π = πβ²(π) =
π π
π π
=
π
π π
ππ
β
π
π π
ππ +
π
π π
π
π π = πππ
β π
37. SOLUTION
Substitute π = π to the velocity function,
π π = πππ
β π
π π = π π π
β π
π π = πππ β π
π π = πππ meters per second
38. RELATIONSHIP OF
POSITION/DISTANCE, VELOCITY AND
ACCELERATION OF A PARTICLE IN A
RECTILINEAR MOTION
Let the position of a particle (P) (or position) on a straight
line at time π be π π . Note that π π is the position function.
i. Average velocity βπ =
βπ π
βπ
ii. Instantaneous velocity π π = πβ² π =
π π
π π
.
iii. Speed π π =
π π
π π
iv. Acceleration π π = πβ²β² π = πβ² π =
π π
π π
.
39. SOLUTION
d. To find the acceleration of the particle when π = π, compute the second
derivative of the position function π π = ππ β ππ + π or compute the first
derivative of the velocity function π π = ππ β π.
π π = πβ²β² π = πβ² π =
π π
π π
π π = πβ²(π) =
π π
π π
=
π
π π
ππ
β ππ + π
π π = πβ²(π) =
π π
π π
=
π
π π
ππ
β
π
π π
ππ +
π
π π
π
π π = πππ β π
42. INSTRUCTION
1.The class will be divided into four groups. Each group will be
given a problem to solve.
2.The group will write their answers in a Manila Paper.
3.After ten minutes, each group will choose a representative to
present their outputs. Additionally, a rubric will be provided
for each group.
43. GROUP 1 & 3
The height s at time t of a one-peso coin dropped from the top of a
building is given by π = β4.9π‘2
+ 45 where s is measured in meters
and t is measured in seconds.
a.Find the average velocity on the interval 1, 2 .
b.Find the instantaneous velocity when t=1 and t=2.
c.How long will it take for one-peso coin hit the ground?
d.Find the velocity of the one-peso coin when it hits the ground.
44. GROUP 2 & 4
A projectile is fired straight upward. Its distance above the ground
after t seconds is given by π π‘ = β4.9π‘2 + 300π‘.
a.Find the time at which the projectile hits the ground.
b.Find the velocity at which the projectile hits the ground.
c.What is the maximum altitude achieved by the projectile?
d.What is the acceleration at any time t?
45. ASSIGNMENT NO. 2
Solve the problem. Then, show the solution.
A projectile is fired directly upward. Its height s(t) in meters
above the ground after t seconds is given by π(π) = πππ β π. ππ.
β’ What are the velocity and acceleration after t
seconds? After 10 seconds?
β’ What is the maximum height?
β’ When does it strike the ground?
46. PERFORMANCE TASK:
VIDEO TUTORIAL
PROJECT
Instruction:
1. This project is a group project. Each group will have a maximum of four
members.
2. The group will collaboratively formulate an original problem involving
rectilinear motion or other application of differentiation (such as rate of change,
related rates, etc.). Also, the group will solve their formulated problem.
3. To present the problem and its solution, the group will create a video tutorial.
The video must be less than seven minutes.
4. The group must submit a mp4 format of their output thru e-mail.
e-mail: john.arlando@deped.gov.ph
Editor's Notes
Guide Questions:
1. Does the video showcase a rectilinear motion?
2. What are some examples of rectilinear motion?