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Tides	
Planetary	sciences	II	
ae4-876	course	year	2017-2018	
Ernst	Schrama	
Del?	University	of	Technology	
Faculty	of	Aerospace	Engineering	
e.j.o.schrama@tudel?.nl
Course	contents	
We	use	the	Lecture	notes	on	Planetary	Sciences	and	Satellite	
Orbit	DeterminaOon,	latest	version	11-Jan-2018:	
	
•  Fourier	frequency	analysis	(Chapter	4)		
•  Measurement	techniques	(Chapter	6)	
•  Tide	generaOng	potenOal	(Chapter	14)		
•  ElasOc	response	of	the	solid	Earth	(Chapter	15)	
•  Ocean	Odes,	modelling	(Chapter	16)	
•  Data	analysis	methods	(Chapter	17)	
•  Tidal	loading	(Chapter	18)	
•  Satellite	AlOmetry	and	Odes	(Chapter	19)	
•  Tidal	energy	dissipaOon	(Chapter	20)	
The	lecture	notes	are	on	brightspace.
OrganisaOon	
•  We	use	a	flipped	classroom	method,	
effecOvely	this	means:	
•  We	rely	on	self-study	rather	than	classical	
lectures	
•  There	will	be	an	assignment	on	Odes	
•  Details	on	how	to	submit	the	assignment	are	
discussed	during	the	contact	hours.	
•  The	forum	on	brightspace	is	your	support	
offline	the	contact	hours.
Contents	of	this	presentaOon	
•  Coastal	observaOons	and	frequency	analysis	of	
the	Odes	at	a	Ode	gauge	
•  Tide	generaOng	force,	relaOon	to	potenOal	
and	Odes	
•  Fluid	dynamics,	how	does	it	work	out?	
•  Load	Odes	and	satellite	alOmetry	
•  Tidal	energy	dissipaOon	and	internal	Odes
Coastal	observaOons	
•  What	do	you	see?	
– Assume	that	you	have	a	record	of	water	heights	
observed	by	a	Ode	gauge	
– Subject	the	data	record	to	a	frequency	analysis,	
see	chapter	4	in	the	lecture	notes		
– We	recover	amplitudes	and	the	phase	of	the	
signal	which	are	water	heights	
– It	is	noOced	that	we	see	daily,	twice	daily	and	
longer	periodic	signals.
Tides	at	Pentrez	Plage	
High Low tide difference of 7
meter (Brittany, France)
Saint	Malo
Cascais, Portugal
England
USA
Phillipines
Vietnam
Sea	level	variaOon	in	1995,	Aukfield	Plaaorm	North	Sea	
1 y
2 w
½ d
Spectra	sea	level	variaOons	Aukfield	plaaorm	
Monthly
Once + Twice Daily
M2
S2/K2
N2
See chapter 4
Frequency	and	Ome	
	
Two	different	domains
Frequency	vs	Ome	domain	(1)	
Normally signals appear in the time domain:
v(t) with t ∈ [0,T]
where T is the length of a record. If we assume that:
v(t +T) = v(t)
then the function is said to be periodic. Furthermore
if v(t) has a finite number of oscillations in [0,T] then
we can develop v(t) in a series:
v(t) = Ai
i=0
N/2
∑ cos(ωit)+ Bi sin(ωit)
which is known as a Fourier series and where Ai and Bi
denote the Euler coefficients.
21/03/18 12
Frequency	versus	Ome	domain	(2)	
•  The	variable	ωi	expresses	an	angular	rate	as	in	the	
formula:	ωi	=i.Δω	where	Δω=2π/T	
•  The	frequency	associated	with	Δω	=	2π/T	is	1/T	Hertz	
(Hz)	when	T	is	specified	in	seconds.		
•  Otherwise	we	rescale	frequencies	to	“cycles	per	
period”	and	period	should	be	defined.	
•  For	a	conOnuous	funcOon	v(t)	there	are	an	infinite	
number	of	frequencies,	in	this	case	N	is	unbounded	
•  Yet	all	those	frequencies	are	mulOples	of	the	base	
frequency	1/T,	except	for	i=0	
•  This	frequency	resoluOon	Δf=1/T	is	determined	by	the	
record	length	T	(and	not	the	sampling)	
21/03/18 13
Frequency	versus	Ome	domain	(3)	
In	order	to	calculate	Ai	and	Bi	from	v(t)	defined	on	[0,T]	we	exploit	
the	orthogonality	properOes	
	
sin(mx)cos(nx)dx = 0
x=0
2π
∫ regardless of m and n
cos(mx)cos(nx)dx =
0
2π
∫
0 : m ≠ n
π : m = n > 0
2π : m = n = 0
#
$
%
&
%
%
sin(mx)sin(nx)dx =
0
2π
∫
π : m = n > 0
0 : m ≠ n, m = n = 0
#
$
%
&%
21/03/18 14
Frequency	versus	Ome	domain	(4)	
v(x)
cos(mx)
sin(mx)
⎧
⎨
⎪
⎩⎪
⎫
⎬
⎪
⎭⎪0
2π
∫ dx ⇒
An cos(nx)+ Bn sin(nx){ }
n=0
N/2
∑
cos(mx)
sin(mx)
⎧
⎨
⎪
⎩⎪
⎫
⎬
⎪
⎭⎪0
2π
∫ dx ⇒
A0 =
1
2π
v(x)dx, B0 = 0
0
2π
∫
Ai =
1
π
v(x)cos(ix)dx, i > 0
0
2π
∫
Bi =
1
π
v(x)sin(ix)dx, i > 0
0
2π
∫
21/03/18 15
Frequency	versus	Ome	domain	(4)	
•  Conversion	from	Ome	domain	v(t)	to	frequency	
domain	(Euler	coefficients)	via	integrals	
•  When	we	speak	about	“the	spectrum”	we	speak	
about	the	existence	of	Euler	coefficients	
•  There	are	efficient	algorithms	that	greatly	speed	
up	the	computaOon	of	the	integrals,	this	is	what	
is	called	the	Fast	Fourier	Transform,	short	FFT	
•  Euler	coefficient	pairs	are	o?en	wrioen	as	
complex	numbers	
•  The	inverse	operator	also	exists,	this	is	the	iFFT	
operator.	Both	FFT	and	iFFT	exist	in	MATLAB.	
21/03/18 16
Frequency	versus	Omeseries	(5)	
•  EssenOally	y=FFT(x)	carries	out	a	Fourier	transform		
•  FFT	algorithm	input	
–  Real	vector	x(0..N-1)	with	N	datasamples	
–  The	record	starts	at	0	and	is	filled	to	N-1	
•  FFT	algorithm	output	
–  Euler	coefficients	are	stored	in	the	form	of	complex	numbers	
–  Stored	in	y(i)	are:		
	y(0)	=	A0	+	I.B0	,	y(1)	=	A1+	I.B1	,	…,	y(N/2)	=	AN/2	+	I.BN/2	
–  I	is	a	complex	number:	
–  Be	careful	with	scaling	factors,	check	this	always	with	a	test	funcOon	of	
which	you	now	the	Euler	coefficients	in	advance	
–  Suitable	test	funcOons	are	for	instance	linear	sin	and	cos	expressions	
•  FFT	algorithms	exploit	symmetries	of	sin	and	cos	funcOons,	please	
use	MATLAB	because	it	is	thoroughly	debugged.	
•  Be	aware	that	indices	in	MATLAB	vectors	start	at	1	(and	not	0)	
I = −1
21/03/18 17
We	use	complex	numbers	
Real
Imaginary
H
G
Z = H exp( j G ) = H [ cos(G) + j sin(G) ] = A + j B
Amplitude	and	Phase:	H	cos(x	–	G)
ProperOes	of	the	FFT	transform	
•  The	FFT	operator	implements	the	discrete	version	of	
the	transformaOon	
•  There	are	no	more	than	N/2	unique	coefficients,	this	
sets	the	highest	frequency	of	a	series	of	N	samples.	
This	is	what	we	call	the	Nyquist	limit	
•  MulOplicaOon	of	coefficients	in	the	frequency	domain	
is	convoluOon	of	two	funcOon	in	the	Ome	domain.		
•  Parseval’s	idenOfy	says	that	the	sum	of	the	squares	in	
the	frequency	domain	is	equal	to	the	sum	of	the	
squares	in	the	Ome	domain.	(proof	via	auto	
convoluOon)	
21/03/18 20
What	is	convoluOon	
•  It	means	that	you	shi?	two	funcOons	along	one	another	while	you	
mulOply	the	result,	input	are	f	and	g,	the	output	is	h	
	
•  With	the	convoluOon	theorem	we	can	build/design/analyze	filters	
•  Most	of	the	filtering	in	digital	radio	is	implemented	by	convoluOon	
21/03/18 21
h(t) = f (τ )g(t −τ )d
−∞
∞
∫ τ
F(ω) = FFT( f (t))
G(ω) = FFT(g(t))
H(ω) = F(ω)×G(ω) fast
slow
f(x)
g(x)
21/03/18 22
h(x) = f (x)⊗ g(x)
This happens when you multiply two block functions
Undersampling,	frequency	resoluOon	
•  Whenever	we	discreOze	a	signal	we	sample	it	
at	a	certain	interval	Δx	(or	Δt)	
•  Undersampling	results	in	aliasing	with	the	
consequence	that	the	spectrum	is	deformed	
•  Oversampling	is	never	a	problem,	the	more	
the	beoer,	oversampling	counteracts	aliasing	
•  Frequency	resoluOon	is	determined	by	the		
record	length,	records	that	are	too	short	
cause	a	poorly	resolved	frequencies	
21/03/18 TU Delft class ae3-535 23
Aliasing	=	Folding	
frequency
power
Watch how a part of the spectrum above the Nyquist frequency folds back
onto the lower part of the spectrum, this is what we call aliasing
Nyquist
frequency
Back	to	Odes
Tide	generaOng	force	(ch	14)	
Topic was already explained in planetary sciences I
Tidal	force	or	potenOal	(ch	3+14)	
•  Force	vectors	are	easy	to	understand	
•  Normally	we	use	a	potenOal	funcOon	U	
•  U	is	scalar,	you	can	add	different	U’s	
•  Gradient	of	U	is	an	acceleraOon	vector	
•  Gradient	of	Odal	potenOal	results	in	the	
Ode	generaOng	force	for	a	unit	mass	
•  Proof	via	work	integral	method	(see	notes)
Tidal	potenOal	(chapter	14)	
€
Ua
=
µm
rem
re
rem
"
#
$
%
&
'
n= 2
3
∑
n
Pn (cosψ)
rem
re
ψ
Laplace	equaOon	and	Legendre	funcOons	(ch	3)	
•  If	you	start	with	ΔU=0	and	if	you	apply	the	
method	of	separaOon	of	variables	then	
•  U(r,λ,θ)	=	R(r)	G(λ,θ)	
•  R(r)	=	c1rn	+	c2r-(n+1)	
•  G(λ,θ)	=	[Anmcos(mλ)	+	Bnmsin(mλ)]	Pnm(cosθ)	
•  See	chapter	3	for	all	properOes	of	Legendre	
funcOons	(it	is	also	part	of	earlier	lectures)
Equilibrium	Ode	(secOon	14.2)	
The	equilibrium	Ode	assumes	that	only	the	Odal	potenOal	dictates		the	
shape	of	the	ocean	surface.	
	
•  In	this	case	the	relaOon	becomes:	
•  Idea	is	equivalent	to	Epot	=	m	.	g	.	h	where:	
–  m:	mass		
–  g:	gravity	(just	the	9.81	m/s2	on	the	Earth’s	surface)	
–  h:	height		
–  Epot	:	potenOal	energy		
–  U	:	potenOal	energy	/	mass		(potenOal	:=	potenOal	energy	for	unit	
mass)	
Ug 1−
=ζ
Tides	deforming	the	Earth	(chapter	15)	
•  The	Earth	resists	forces	that	cause	deformaOon	
–  Solid	earth	Odes	differ	from	equilibrium	Odes	
(geometric	effect)	
–  There	is	an	induced	potenOal	because	of	deformaOon	
and	as	a	result	there	is	an	induced	gravity	effect	
–  Both	effects	can	be	modeled	by	scaling	factors	using	
the	Love	numbers	hn	and	kn	
•  Consequences	
–  One	unified	theory	for:	solid	earth	Odes,	long	periodic	
equilibrium	Odes	in	the	ocean,	acceleraOons	on	
satellites,	gravimeter	Odes,	reference	system		
–  Details	are	discussed	in	chapter	3
Love’s	theory	
€
ζs = g−1
hn
n= 2
∑ Un
UI
= kn
n= 2
∑ Un
ζo = g−1
(1+ kn − hn )
n= 2
∑ Un
Ocean tides (chapter 16)
•  Purpose of this part is to describe motions of fluids
with a system of differential equations.
•  We are only interested in representing currents and
water levels at time and space scales appropriate to
ocean tides. (several km to global, hours to days)
•  Where is the input, what is the response, is it linear?
Topics	in	Fluid	Dynamics	
•  ConOnuity	equaOons	
•  Momentum	equaOons	
•  EquaOons	of	moOon	
•  Depth	averaged	transport	
•  Boundary	condiOon	and	forcing	
•  FricOon	and	advecOon	
•  Turbulence
ConOnuity	equaOon	(1)	
A A’
B B’
River Ocean
Flow in an estuary
ConOnuity	equaOon	(2)	
A
B
A’
B’
D
C C’
D’
Uin
Uout
w
Uin ABCD - Uout A’B’C’D’ + w DCD’C’ = 0
ConOnuity	equaOon	(3)	
•  Surfaces	ABCD	and	A’B’C’D’	are	known	because	
the	bathymetry	is	always	provided	
	
•  Uin	and	Uout	are	measured	at	“secOons”	
	
•  The	verOcal	transport	component	w	automaOcally	
follows	from	the	conOnuity	condiOon,	you	can	not	
easily	observe	it	
	
•  The	verOcal	velocity	component	w	may	be	related	
to	many	different	effects
ConOnuity	equaOon	(4)	
ρ
dx
dy
dz
u u+du
0)(
0)(.....)(.....)(.....
=
∂
∂
+
∂
∂
+
∂
∂
⇔
=+−++−++−
z
w
y
v
x
u
dwwdydxwdydxdvvdzdxvdzdxduudzdyudzdy
ρ
ρρρρρρ
ConOnuity	equaOon	(5)	
If we allow variations along x the u component
becomes:
dydzdx
x
u
udx
x
))((
∂
∂
+
∂
∂
+
ρ
ρ
When this is allowed for all components we get:
0
1
=⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
+
∂
∂
+
∂
∂
+
z
w
y
v
x
u
dt
dρ
ρ
For non-compressible fluids the first term will vanish
Momentum	equaOon	(1)	
Procedure: Decompose accelerations on a fluid parcel
P∇−
ρ
1
Fu +×− ω2
g
FguP
Dt
uD
++×−∇
−
= ω
ρ
2
1
Gravity vector
Pressure
gradient
Coriolis + forcing +
friction + ….
Plane of equal pressure
Momentum	equaOon	(2)	
Why is the pressure gradient like shown? (Pressure = force / area,
Force = pressure times area)
dx
dy
dz
P P+dP
Force effect x direction: zyx
x
P
zydPzydPPzyP δδδδδδδδδ .....).(..
∂
∂
−=−=+−
Momentum	equaOon	(3)	
⎥
⎥
⎥
⎦
⎤
⎢
⎢
⎢
⎣
⎡
∂∂
∂∂
∂∂
−
=∇
−
zP
yP
xP
P
ρρ
11
x
P
∂
∂
−Force per unit volume
Force per unit mass,
(i.e. acceleration) x
P
∂
∂
−
ρ
1
Pressure gradient:
Momentum	equaOon	(4)	
How to get the Coriolis term? Answer: consider an inertial
(i) and a rotating coordinate system (a).
a
a
a
a
a
a
i
i
a
a
a
a
i
i
a
a
i
i
xxxx
xxx
xx
eeeex
eeex
eex
!!!!!!!!!!
!!!!
++==
+==
==
2
Unit vectors coordinate basis: e
Point ordinates on a chosen basis: x
Momentum	equaOon	(6)	
For a rotating basis we have:
aaa
aa
eωωeωe
eωe
××+×=
×=
!!!
!
And the consequence is:
aaaaI xωxωωxωxx ×+××+×+= !!!!!! 2
“frame”“centrifugal”
Momentum	equaOon	(7)	
Du
Dt
=
−1
ρ
∇P − 2ω × u + g + F
The final result is:
Note:
•  pressure and density symbols (watch the symbols)
•  g does contain a centrifugal term!
•  rotation is considered constant
•  this equation holds in an Earth fixed frame
•  contains Friction and ForcingF
Navier	Stokes	equaOons	
€
Du
Dt
=
−1
ρ
∂p
∂x
+ 2Ωsinφv − 2Ωcosφ w + Fx
Dv
Dt
=
−1
ρ
∂p
∂y
− 2Ωsinφ u + Fy
Dw
Dt
=
−1
ρ
∂p
∂z
+ 2Ωcosφ u − g + Fz
Notes:
- w equation: largest terms result in hydrostatic equation
- D./Dt includes local derivative and advection (later)
For a suitable local coordinate frame we find:
HydrostaOc	equaOon	
For the w-equation we get:
€
∂p
∂z
= −gρ
p(z) = − gρdzH
−η
∫ = gρ(H +η)
Example:
• At 1000 m the pressure is approximately 100 bar
• Density changes in the oceans are relatively small (3%)
Velocity	depth	averaged	equaOon	
f = 2Ωsinϕ
€
Du
Dt
= −g
∂η
∂x
+ fv + Fx
Dv
Dt
= −g
∂η
∂y
− fu + Fy
Dη
Dt
= −(H +η)
∂u
∂x
+
∂v
∂y
%
&
'
(
)
*
In these equations u and v are averaged over the entire water
column. The Coriolis term
Laplace	Odal	equaOons	
€
Du
Dt
= −g
∂η
∂x
+ fv + Fx
Dv
Dt
= −g
∂η
∂y
− fu + Fy
Dη
Dt
= −(H +η)
∂u
∂x
+
∂v
∂y
%
&
'
(
)
*
€
Fx
Fy
"
#
$
%
&
' =
∂Γ ∂x
∂Γ ∂y
"
#
$
%
&
' +
rx
ry
"
#
$
%
&
'
Γ = Hω
ω
∑ cos(χω (t) − Gω )
The terms u,v and η represent velocity and water level, f is a
Coriolis term, H is the depth of the ocean, Γ is a forcing
function, r represents dissipative forcing. (Chapter 16)
ProperOes	Laplace	Tidal	EquaOons	
•  Tidal	waves	behave	like	any	other	shallow	water	wave	
•  For	long	gravity	waves	the	propagaOon	speed	is	
approximately	(g.H)1/2	with	H	being	the	local	depth		
•  Surface	speed	astronomic	Ode	is	faster	than	(g.H)1/2	
•  Oceans	and	conOnental	seas	respond	like	a	vibraOng	
membrane,	actually,	the	system	looks	like	a	Helmholtz	
equaOon	
•  Resonances	may	occur	(think	of	bays	and	coastal	seas)	
•  In	principle	there	are	three	Odal	species	(long	periodic,	
diurnal	and	semi-diurnal)	This	property	is	due	to	the	forcing	
mechanism	AND	due	to	the	fact	that	the	problem	is	nearly	
linear
Helmholtz	equaOon	(1)	
€
Df
Dt
≈
df
dt
Approach: insert a test function and avoid non-linearity
u(t) = ˆuexp( jωt)
v(t) = ˆvexp( jωt)
η(t) = ˆηexp( jωt)
€
Du
Dt
= −g
∂η
∂x
+ fv + Fx
Dv
Dt
= −g
∂η
∂y
− fu + Fy
Dη
Dt
= −(H +η)
∂u
∂x
+
∂v
∂y
%
&
'
(
)
*
€
Fx
Fy
"
#
$
%
&
' =
∂Γ ∂x
∂Γ ∂y
"
#
$
%
&
' +
C
H
u
v
"
#
$
%
&
'
Γ = ˆΓexp( jωt)
Question: is this a linear problem?
Helmholtz	equaOon	(2)	
z = a + jb, j = −1, Re(z) = a, Im(z) = b
αz = αa + jαb
z1 + z2 = (a1 + a2 ) + j(b1 + b2 )
z1z2 = (a1a2 − b1b2) + j(a1b2 + a2b1)
z1 /z2 = (a1 + jb1)/(a2 + jb2 )
z = a − jb
exp( jx) = cos(x) + jsin(x)
Helmholtz	equaOon	(3)	
Re
Im
α
R
R.exp( jα) = Rcos(α) + jRsin(α)
αcosR
αsinR
Helmholtz	equaOon	(4)	
If you substitute the characteristic solutions for all dependent
variables in the shallow water equations:
(ω2
− f 2
) ˆη + c2 ∂2
ˆη
∂x2
+
∂2
ˆη
∂y2
⎛
⎝⎜
⎞
⎠⎟ ≈ 0
c = gH
In this relation c is the surface speed of the tide. You can
obtain it by substitution of the test function in the Laplace
tidal equations.
Examples	of	Helmholtz	soluOons	
€
1
r
∂
∂r
r
∂η
∂r
$
%
&
'
(
) +
1
r2
∂2
η
∂ϕ2 + λη = 0 for λ = µ2
⇒
η = AJm (µr) + BYm (µr)[ ]× (Ccosmϕ + Dsinmϕ)
Boundary	condiOons	and	forcing	
•  There	are	always	boundary	condiOons.		
•  No-flux	condiOon,	inner	product	(u.n)	=	0	at	
the	shoreline	
•  IniOal	condiOons	apply	for	Ome	stepping	
models	
•  Forcing	in	F	is	related	to	FricOon	and	
GeneraOon
Example	mixed	boundary	condiOons	
Land
Ocean
η,,vu+
0),( =nv
Closed flux boundary
Open flux boundary
Forcing	
• Question: what are Fx and Fy in the momentum equation?
• Answer: this depends on the type of problem
• Some examples are:
• Gradients tide generating potential
• Friction
• (Advection is not a forcing term)
Linearity	
Ocean tides show a linear behavior when sea bottom friction
is linear and when advection is ignored:
rx =
Cu
H
and ry =
Cv
H
€
Γ(t) = ˆΓexp( jωt)
In reality sea bottom friction is quadratic:
r = Cu u
Linearity	(2)	
)exp(ˆ tjωΓ )exp(ˆ tjh ωΓ= *Zh
Z: admittance function
Non	Linear	Response	
Some Box)exp(ˆ tjωΓ
)exp(ˆ
11 tjh ω
)exp(ˆ
22 tjh ω
AdvecOon	
z
u
w
y
u
v
x
u
u
t
u
Dt
Du
∂
∂
+
∂
∂
+
∂
∂
+
∂
∂
=
Local
effect
Advection part
Total
derivative
Gradient of u
in x direction is large
FricOon	
•  This	is	described	by	
•  Fx	acts	on	a	molecular	level.	
•  The	term	ν	describes	kinemaOc	molecular	viscosity,	ν	is	
about	10-6	m2/s	
•  FricOon	always	introduces	dissipaOon	
•  To	apply	fricOon	in	Ode	models	you	have	to	re-scale	fricOon	
by	means	of	horizontal	and	verOcal	eddy	viscosity	terms	
•  Scale	factor	depends	on	numerical	consideraOons	
Fx =ν
∂2
u
∂x2
+
∂2
u
∂y2
+
∂2
u
∂z2
"
#
$
%
&
'
Scale	consideraOons	
•  To	assess	the	forcing	terms	you	have	to	look	at	the	
scale	of	certain	variables	
•  Assume	that	velociOes	u	and	du	are	scaled	like	U	
•  Assume	for	dx	a	length	scale	L.	
•  Assess	the	raOo	between	fricOon	and	advecOon
The	Reynolds	number	
Re
/
/
)(
)(
2
2
22
==≈
∂∂
∂∂
ννν
UL
LU
LU
xu
xuu
Rule of thumb: if Re<1000 then a flow is not
turbulent, turbulence occurs for large Re numbers
Examples: transport in the gulf stream and water
flow through a tube, smoking match example
Smoking match example
Task: estimate the
Reynolds number
Dispersion	relaOon	
u(t) = ˆuexp( j(ωt − kx − ly))
v(t) = ˆvexp( j(ωt − kx − ly))
η(t) = ˆηexp( j(ωt − kx − ly))
∇F = 0
Unforced or free waves fulfill the following relation:
Show that this results in the following dispersion relation
)()( 2222
lkgHf +=−ω
Do free waves exist for all frequencies at all latitudes?
Simple	Ode	model	
€
h(φ,λ,t) = Hi φ,λ( )
i
∑ cos wi t − t0( )− Gi φ,λ( )( )
Hi φ,λ( ): tidal amplitude
Gi φ,λ( ): Greenwich phase
Deep ocean tides can be predicted by the model:
The tidal frequency is astronomically determined, for a
location at which the tides are predicted it is sufficient to
have a series of H and G values available, t0 is a reference
time, t is the time of observation.
M2 tide with phase lines in hours.
North	Sea	Tides
M2	movie
Tidal	data	analysis	(chapter	17)	
•  We	already	did	it	in	the	introducOon!	
•  Make	use	of	the	property	that	Odal	frequencies	are	
astronomically	determined	
•  Side	lines	(like	255.545)	are	a	problem,	this	is	why	you	
need	nodal	correcOon	terms	(see	secOon	14.3)	
•  Least	squares	esOmators	do	the	rest,	each	Odal	frequency	
introduces	two	other	parameters	to	esOmate.	
•  Response	method	is	a	lot	easier,	but	requires	you	to	
define	an	admioance	funcOon
Response	method	
•  U	is	known	with	astronomical	precision	
•  Z	is	a	smooth	funcOon	
€
H(ω) = Z(ω) × U(ω)
U =
µm
rem
re
rem
$
%
&
'
(
)
n=2,3
∑
n
Pn cos ψ( )( )
Load	Odes	(chapter	18)	
•  Tidal	moOons	cause	loading	on	the	Earth	
•  The	Earth	shows	an	elasOc	response	for	Odal	
frequencies.	
•  The	surface	will	flex	and	this	effect	can	be	
seen	at	a	distance	from	the	Odal	source	
•  Load	Odes	are	obtained	by	convoluOon	of	the	
ocean	Odes	(see	chapter	18)
ElasOc	deformaOons	due	to	
surface	mass	layer	
nl θ,λ,t( )= G(ψ)dM
Ω
∫ θ'
,λ'
,t( )
G(ψ) =
re
Me
hn
'
n=0
∞
∑ Pn cosψ( )
),(:),(: ''
λθλθ qp
+
+
p
q
qp
AlOmetry	and	Odes	(ch.	19)	
Source: JPL
Satellite Altimetry is documented in section 6.3.1
Topex/Poseidon	groundtrack
RepeaOng	ground	tracks	
ze
I
ωo
ωe
xe
ye
(xe,ye,ze) : Earth Fixed
ωo = (ω + f )
ωe = (Ω−θ)
!ωo
!ωe
=
Nr
Nd
Nr and Nd do not share factors (primes)
C20 and Earth rotation control !ω !f !Ω and !θ
Study: 6.3.1
Mesoscale	variability
AlOmetry	and	Aliasing	
•  Tides	occur	mostly	on	a	diurnal	or	semi-diurnal	
frequency	
•  Satellite	ground	tracks	repeat	within	a	few	days.	
•  The	consequence	is	that	the	Ode	signal	is	
undersampled	
•  How	bad	is	this	for	observing	ocean	Odes	with	
satellite	alOmeter?	
•  Study	chapter	4.2.2	on	the	Nyquist	theorem
AlOmetry	and	Odes	
•  AlOmetry:		
–  Topex/Poseidon	(and	both	Jason	satellites),	provide	esOmates	
of	ocean	Odes	at	one	second	intervals	in	the	satellite	flight	
(along	track)	direcOon.	
•  Quality	Models:		
–  The	quality	of	these	models	can	be	verified	by	means	of	an	
independent	comparison	to	in-situ	Ode	gauge	observaOons.	
–  RMS	difference	for	M2:	1.5	cm,	S2:	0.94,	O1:	0.99,	K1:	1.02,		
–  Other	consOtuents	are	well	under	the	0.65	cm	level,	
•  Data	assimilaOon:	
–  There	are	various	numerical	schemes	that	assimilate	alOmeter	
informaOon	in	barotropic	ocean	Ode	models.	(empirical,	
representer	method,	nudging)
M2	ocean	Ode
Tidal	Energy	DissipaOon	(chapter	20)	
•  Tides	are	generated	by	the	Sun	and	the	Moon	
•  ConOnuous	forcing	shouldn’t	result	in	conOnuous	
amplificaOon,	somehow	a	wave	has	to	dissipate	its	energy		
•  Conversion	of	mechanical	energy	into	heat	or	another	form	
of	energy	is	called	dissipaOon	
•  Booom	fricOon	is	such	a	process,	and	for	long	it	was	
assumed	this	is	the	only	way	it	works	
•  Global	energy	dissipaOon	studies:	purpose,	provide	one	
number	like	2.5	TW	for	M2	for	the	enOre	planet	
•  Local	energy	dissipaOon	studies:	purpose,	provide	one	
number	for	e.g.	a	coastal	sea.	
•  Local	dissipaOon	is	related	to	internal	Odes
Tidal	energy	dissipaOon	
3.82 cm/yr
M2 : 2.50 +/- 0.05 TW
Introduced in planetary sciences I, study section 20.1 and 20.2
DissipaOon	calculaOons	
•  We	combine	momentum	and	conOnuity	equaOons	in	the	depth	average	
LTE,	this	results	in	equaOon	(20.9)	
•  In	equaOon	(20.9)	we	mulOply	currents	u	Omes	a	dissipaOve	force	vector	
F,	and	we	average	all	terms	over	a	Odal	cycle		
•  When	you	take	the	average	several	terms	cancel,	next	for	global	
dissipaOon	calculaOons	we	integrate	over	the	oceans,	furthermore	we	
impose	no	flux	boundaries	this	results	in	a	compact	equaOon.	
•  The	obtained	dissipaOon	equaOon	is	global	in	nature,	thus	it	is	valid	for	the	
enOre	system,	it	does	not	pin-point	where	dissipaOon	is	happening	
Section: 20.3
Global	esOmates	Odal	energy	dissipaOon	
Q1 O1 P1 K1 N2 M2 S2 K2
SW80 0.007 0.176 0.033 0.297 0.094 1.896 0.308 0.024
FES99 0.008 0.185 0.033 0.299 0.109 2.438 0.367 0.028
GOT992 0.008 0.181 0.032 0.286 0.110 2.414 0.428 0.029
TPXO51 0.008 0.186 0.032 0.293 0.110 2.409 0.376 0.030
NAO99b 0.007 0.185 0.032 0.294 0.109 2.435 0.414 0.035
Mean 0.008 0.184 0.032 0.294 0.110 2.424 0.396 0.030
Units: TeraWatts
Section 20.3
Global	Odal	energy	dissipaOon	
•  SecOon	20.2	discusses	independent	astronomic	and	
geodeOc	esOmates:	
–  Secular	trend	in	Earth	Moon	distance		
–  Earth	rotaOon	slow	down	
–  Phase	lags	ocean,	body	or	atmospheric	Odes	
•  SecOon	20.3	shows	that	alOmeter	derived	ocean	Ode	
models	have	roughly	the	same	global	dissipaOon	
esOmates	
•  But	there	are	some	noOceable	differences	between	
the	results
Results	Global	DissipaOon	
•  High	coherence	between	models,	SW80	is	an	excepOon	
because	it	is	before	the	alOmeter	era	(TOPEX/Poseidon).	
For	this	reason	global	dissipaOon	esOmates	are	not	a	good	
quality	indicator.	
•  M2:	oceanic	2.42,	astronomic	2.51	TW,	the	difference	is	
dissipated	in	the	solid	Earth	Ode	(Ray,	Eanes	and	Chao,	
1996).	Independent	body	Ode	dissipaOon	measurements	
by	gravimeters	are	not	convincing	at	the	moment	(only	a	
0.1	of	a	degree	lag	is	expected)	
•  S2:	oceanic	0.40,	geodeOc	0.20	TW,	the	difference	is	
mostly	dissipated	in	the	atmosphere	(Platzman,1984)	
•  Challenge:	do	this	for	another	planet	or	moon	(like	Europe	
orbiOng	around	Jupiter)
Europa	surface
Local	DissipaOon	(1)	
∂u
∂t
+ f ×u = −g∇ζ + ∇Γ − F
∂ζ
∂t
= −∇.(uH )
W − P = D
W = ρH < u.∇Γ >
P = gρH∇.< uζ >
D = ρH < u.F >
W: Work
P: Divergence Energy Flux
D: Dissipation
∫
+=
=
=
Ttt
tt
dtFu
T
D
0
0
).(
1
Local	dissipaOon	(2)	
•  In	order	to	compute	local	dissipaOons	you	must	
specify	the	forcings	and	the	velociOes	
•  AlOmetry	only	observes	Odal	heights,	it	does	not	
provide	us	with	Odal	velociOes	(perhaps	acousOc	
sounding	can	independent	values)	
•  The	computaOon	of	barotropic	velociOes	requires	
a	numerical	inversion	scheme	
•  The	forcing	terms	involve	self-aoracOon	and	Odal	
loading	and	the	Ode	generaOng	potenOal.
Internal	Odes	
20 m
5 cm
160 km
ρ1
ρ2
h1
h2
Internal	Odes	seen	at	the	surface	
Mitchum and Ray 1996 GRL
Internal	Odes	(1)	
•  High	frequency	oscillaOon	is	imposed	on	the	along	track	Ode	
signal,	wavelength	typically	160	km	for	M2,	(Mitchum	and	
Ray,	1996).	
•  The	feature	stands	above	the	background	noise	level.	
•  The	phenomenon	is	visible	for	M2	and	S2	(hardly	for	K1).	
•  There	is	some	contaminaOon	in	the	T/P	along	track	Odes	in	
regions	with	increased	meso-scale	variability.	
•  “Clean”	Along	track	Ode	features	are	visible	around	Hawaii,	
French	Polynesia	and	East	of	Mozambique.	
•  Along	track	Odes	appear	near	oceanic	ridge	systems	or	along	
the	conOnental	shelf.
What	is	the	conOnental	shelf?
Internal	Odes	(3)	
)( 21
212
2
1
hh
hh
gc
+⎟⎟
⎠
⎞
⎜⎜
⎝
⎛ Δ
=
Δ
−=
ρ
ρ
ρ
ρ
ζ
ζ
m5000
m300
mkg1025
003.0
2
1
3-
=
=
=
=Δ
h
h
ρ
ρρ
c = 3 ms−1
L =12.42 ×3600 ×3 = 140 km
(Apel, 1987)
Areas	of	interest	
-30 -20 -10 0 10 20 30 mW/m2
R Ray, GSFC
Conclusions	(1)	
•  Global	dissipaOon:		
–  There	are	consistent	values	for	most	models,		
•  The	M2	dissipaOon	converges	at	2.42	TW	to	within	2%	
–  Independent	methods	to	determine	the	rate	of	energy	
dissipaOon	(LLR,	satellite	geodesy).	LLR	arrives	at	2.5	TW	
for	M2	
–  Comparison	to	astronomic/geodeOc	values:	
•  0.2	TW	at	S2	for	dissipaOon	in	the	atmosphere		
•  0.1	TW	at	M2	for	dissipaOon	in	the	solid	earth	
•  gravimetric	confirmaOon	of	the	0.1	TW	is	very	challenging	
–  History	of	Earth	rotaOon	relies	of	dissipaOon	esOmates	from	paleo-
oceanographic	ocean	Ode	models.
Conclusions	(2)	
•  Local	dissipaOon:		
–  it	is	the	same	Odal	energeOcs	equaOon,	the	integraOon	domain	is	
however	local	and	you	need	Odal	transport	esOmates	at	the	boundary	
of	the	local	integraOon	domain	
–  realisOc	esOmates	are	more	difficult	to	obtain	and	require	an	
inversion	of	Odal	elevaOons	into	currents	
•  Along	track	Ode	signal:	
–  so	far	only	results	for	standing	waves	
–  appears	as	high	frequency	Odal	variaOons	in	along	track	alOmetry,	
–  appear	to	be	related	to	internal	wave	features,		
–  coherence	to	local	dissipaOons,	
–  visibility:	Hawaii,	Polynesia,	Mozambique,	Sulu	Celebes	region
Discussion	
•  Why	relate	internal	Odes	to	dissipaOon?	
–  Mixing	in	the	deep	ocean	is	according	to	(Egbert	and	Ray,	
2000)	parOally	caused	by	internal	Odes.	
–  Their	main	conclusion	is	that	the	deep	oceanic	esOmate	
for	M2	is	about	0.7	TW.	
–  Walter	Munk	stated	that	2	TW	is	required	for	maintaining	
the	deep	oceanic	straOficaOon.	
–  Approximately	1	TW	could	come	from	wind	
–  The	remainder	could	be	caused	by	internal	Odes.

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