History and Applications of Finite Element Analysis
Theory of Elasticity
Finite Element Equation of Bar element
Finite Element Equation of Truss element
Finite Element Equation of Beam element
Tutorial related to
Bar element
Beam element
Finite element simulation using ANSYS 15.0
Bar element
Truss element
Beam element
1. Introduction to
Finite Element Analysis
By
Dr. N.Vasiraja, M.Tech., Ph.D
Asst. Prof.(Sr.G)/Mech. Engg.
Mepco Schlenk Engg. College, Sivakasi
2. 17-Jan-23 Introduction to Finite Element Analysis 2
FLOW OF PRESENTATION
1. History and Applications of Finite Element Analysis
2. Theory of Elasticity
3. Finite Element Equation of Bar element
4. Finite Element Equation of Truss element
5. Finite Element Equation of Beam element
6. Tutorial related to
1. Bar element
2. Beam element
7. Finite element simulation using ANSYS 15.0
1. Bar element
2. Truss element
3. Beam element
8. Summary
4. 17-Jan-23 Introduction to Finite Element Analysis 4
Numerical Methods
1. Variational method (Applying Minimum potential energy
Principle)
1. Rayleigh Ritz Method
2. Weighted residual method
1. Point collocation method
2. Subdomain method
3. Least square method
4. Galerkins’ method
3. Finite Difference method
4. Finite element Method
1. By manual
2. By coding using C++, Matlab
3. By FEA packages like ANSYS, NASTRAN, COMSOL, FEAST
etc
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Historical Background
Hrenikoff, 1941 – “frame work method”
Courant, 1943 – “piecewise polynomial interpolation”
Turner, 1956 – derived stiffness matrice for truss, beam, etc
Clough, 1960 – coined the term “finite element”
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Advantages of Finite Element Analysis
Models Bodies of Complex Shape
Can Handle General Loading/Boundary Conditions
Models Bodies Composed of Composite and Multiphase
Materials
Model is Easily Refined for Improved Accuracy by Varying Element
Size and Type (Approximation Scheme)
Time Dependent and Dynamic Effects Can Be Included
Can Handle a Variety Nonlinear Effects Including Material
Behavior, Large Deformations, Boundary Conditions, Etc.
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Steps involved in the finite element analysis
(i) Select suitable field variables and the elements.
(ii) Discritise the domain into small.
(iii) Select interpolation functions.
(iv) Find the element properties.
(v) Assemble element properties to get global properties.
(vi) Impose the boundary conditions.
(vii) Solve the system equations to get the nodal unknowns.
(viii) Make the additional calculations to get the required values.
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Type of Problems
Equilibrium problems
• Time independent problems, BVPs.
Eigen value problems
• Steady state problems whose solution often requires the
determination of natural frequencies and modes of vibration of
solid and fluids.
• These are special class of BVPs where solution exists for only
certain ‘particular’ or ‘characteristic’ value of the parameter.
Propagation problems
• Time dependent problems, IVPs.
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Quiz-1
Who have coined the name Finite Element?
Ans: Clough, 1960
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Applications of Finite Element Methods
Structural & Stress Analysis
Thermal Analysis
Dynamic Analysis
Acoustic Analysis
Electro-Magnetic Analysis
Manufacturing Processes
Fluid Dynamics
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Basic Term related to FEA
(i) The basic unknown and field variables which are encountered
in the engineering problems are displacement in solid
mechanics, velocity in fluid mechanics, electric and magnetic
potential in electrical engineering and temperature in heat
flow.
(ii) Finite number by dividing region in to small parts called
elements.
(iii) The field variables specified at points are called nodes.
(iv) DOF – are field variables
(v) Boundary condition
(i) Essential Boundary conditions ( Displacement and slope)
(ii) Natural boundary conditions ( Force and moment)
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Basic Concept of the Finite Element Method
Exact Analytical Solution
x
T
Approximate Piecewise Linear Solution
x
T
One-Dimensional Temperature Distribution
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Quiz 2
The total number of DOF is six. justify
Ans: Translation along x, y, z direction
Rotation along x, y, z direction
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Common Types of Elements
One-Dimensional Elements
Line
Rods, Beams, Trusses, Frames
Two-Dimensional Elements
Triangular, Quadrilateral
Plates, Shells, 2-D Continua
Three-Dimensional Elements
Tetrahedral, Rectangular Prism (Brick)
3-D Continua
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Discretization Examples
One-Dimensional
Frame Elements
Two-Dimensional
Triangular Elements
Three-Dimensional
Brick Elements
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Hooke’s Law for Different Types of Materials
Anisotropic Material
The most general stress–strain relationship is given as follows for a three-dimensional
body in a 1–2–3 orthogonal Cartesian coordinate system:
• Where 6×6 [D] matrix is called stiffness matrix
• It can be shown that the 36 constants in above equation actually reduce to 21 constants
due to the symmetry of the stiffness matrix [D]. That is called anisotropic materials.
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Orthotropic Material (Orthogonally Anisotropic)/Specially Orthotropic
If a material has three mutually perpendicular planes of material symmetry, it is an
orthotropic materials , then the stiffness matrix is given by
The number of constant is reduced to 9
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Quiz 3
What is Poissons’ ratio?
Ans: Lateral strain/Linear strain
36. 17-Jan-23 Introduction to Finite Element Analysis 36
Development of Finite Element Equation
• The Finite Element Equation Must Incorporate the
Appropriate Physics of the Problem
• The Appropriate Physics Comes from Either Strength of
Materials or Theory of Elasticity
• FEM Equations are Commonly Developed Using
•Direct Method
•Variational-Virtual Work Method
•Virtual work & Principle of minimum potential
energy
•Weighted Residual Method- Galerkin Method
37. 17-Jan-23 Introduction to Finite Element Analysis 37
Finite Element Equation of Bar Element
𝐴𝐸
𝐿
−1 1
−1 1
𝑢1
𝑢2
=
𝜌𝑔𝐴𝐿
2
𝜌𝑔𝐴𝐿
2
+
𝑞0𝐿
2
𝑞0𝐿
2
+
𝑃1
𝑃2
• One dimensional bar element has two variables
• when there is no distributed load q0=0
• When there is no self weight ρg=0
•Size of the global stiffness matrix = number of nodes ×1
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Finite Element Equation of Truss Element
𝐴𝐸
𝐿
𝑙2
𝑙𝑚
𝑙𝑚 𝑚2
−𝑙2
−𝑙𝑚
−𝑙𝑚 −𝑚2
−𝑙2 −𝑙𝑚
−𝑙𝑚 −𝑚2
𝑙2 𝑙𝑚
𝑙𝑚 𝑚2
𝑢1
𝑢2
𝑢3
𝑢4
=
𝑃1
𝑃2
𝑃3
𝑃4
• One dimensional truss element has four variables
• There is no self weight
•Where
•Size of the global stiffness matrix = number of nodes ×2
𝑙 =
𝑥2 − 𝑥1
𝐿
= cosθ m =
𝑦2 − 𝑦1
𝐿
= 𝑠𝑖𝑛θ
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Finite Element Equation of Beam Element
• One dimensional beam element has four variables
• when there is no distributed load p=0
•Size of the global stiffness matrix = number of nodes ×2
40. 17-Jan-23 Introduction to Finite Element Analysis 40
Tutorial 1- Bar element
Consider a bar as shown in figure. An axial load of 200kN is applied at
point P. Take A1=2400 mm2; E1=70×109 N/m2; A2=600 mm2;
E1=200×109 N/m2. Calculate the nodal displacement at point P and
stresses in the each section.
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Tutorial 2- Beam Element
For the beam and loading shown in figure, compute the slope at the
hinged support points. Take E=200 GPa and I=5×10-6 m4.
42. 17-Jan-23 Introduction to Finite Element Analysis 42
Tutorial 3- Truss element
Consider a three bar truss as shown in figure. It is given that Young’s
modulus E= 2x105 N/mm2. Calculate the following:
(i) Nodal displacements.
(ii)Stress in each member.
(iii)Reaction at the support.
Take,
area of element (1) = 2000 mm2
area of element (2) = 2500 mm2
area of element (3) = 2500 mm2