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Circle
A chord of length 6 cm is drawn in a circle of radius 5 cm.
Calculate its distance from the centre of the circle.
A chord of length 8 cm is drawn at a distance of 3 cm from the
centre of the circle. Calculate the radius of the circle.
Let AB be the chord and O be the centre of the circle.
Let OC be the perpendicular drawn from O to AB.
A chord of length 24 cm is at a distance of 5 cm from the centre of the circle. Find the
length of the chord of the same circle which is at a distance of 12 cm from the centre.
=> AP2 = (34)2 - (16)2 = 900
=> AP = 30 cm
AB = AP - BP = 30 - 12 = 18 cm
In a circle of radius 17 cm, two parallel chords of lengths 30 cm and
16 cm are drawn. Find the distance between the chords, if both the
chords are:
(i) on the opposite sides of the centre;
(ii) on the same side of the centre.
Solution 6
Let O be the centre of the circle and AB and CD be the two parallel
chords of length 30 cm and 16 cm respectively.
Drop OE and OF perpendicular on AB and CD from the centre O.
Two parallel chords are drawn in a circle of diameter 30.0 cm. The length of one chord is 24.0 cm and the distance between
the two chords is 21.0 cm; find the length of another chord.
Solution 7
Since the distance between the chords is greater than the radius of the circle (15 cm), so the chords will be on the opposite
sides of the centre.
Let O be the centre of the circle and AB and CD be the two parallel chords such that AB = 24 cm.
Let length of CD be 2x cm.
Drop OE and OF perpendicular on AB and CD from the centre O.
The figure given below shows a circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED
= 8 cm and EB = 4 cm, find the radius of the circle.
M and N are the mid-points of two equal chords AB and CD respectively of a circle with centre O. Prove that:
/BMN= /DNM
/AMN = /CNM
AB=CD
The length of the common chord of two intersecting circles is 30 cm. If the diameters of these two circles be 50 cm and
34 cm, calculate the distance between their centres.
The line joining the midpoints of two chords of a circle passes through its centre. Prove
that the chords are parallel.
AB and CD are two equal chords of a circle with centre O which intersect each other at right angle at point P.
If OM I AB and ON I CD; show that OMPN is a square.
In the given figure, an equilateral triangle ABC is
inscribed in a circle with centre O.
Find: (i) ∠BOC (ii) ∠OBC
We know that equal arcs
subtend equal angles at
the center.
Circle.pptx
Circle.pptx
Circle.pptx
Circle.pptx
Circle.pptx

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Circle.pptx

  • 2.
  • 3.
  • 4.
  • 5.
  • 6. A chord of length 6 cm is drawn in a circle of radius 5 cm. Calculate its distance from the centre of the circle.
  • 7. A chord of length 8 cm is drawn at a distance of 3 cm from the centre of the circle. Calculate the radius of the circle.
  • 8. Let AB be the chord and O be the centre of the circle. Let OC be the perpendicular drawn from O to AB.
  • 9. A chord of length 24 cm is at a distance of 5 cm from the centre of the circle. Find the length of the chord of the same circle which is at a distance of 12 cm from the centre.
  • 10. => AP2 = (34)2 - (16)2 = 900 => AP = 30 cm AB = AP - BP = 30 - 12 = 18 cm
  • 11. In a circle of radius 17 cm, two parallel chords of lengths 30 cm and 16 cm are drawn. Find the distance between the chords, if both the chords are: (i) on the opposite sides of the centre; (ii) on the same side of the centre. Solution 6 Let O be the centre of the circle and AB and CD be the two parallel chords of length 30 cm and 16 cm respectively. Drop OE and OF perpendicular on AB and CD from the centre O.
  • 12. Two parallel chords are drawn in a circle of diameter 30.0 cm. The length of one chord is 24.0 cm and the distance between the two chords is 21.0 cm; find the length of another chord. Solution 7 Since the distance between the chords is greater than the radius of the circle (15 cm), so the chords will be on the opposite sides of the centre. Let O be the centre of the circle and AB and CD be the two parallel chords such that AB = 24 cm. Let length of CD be 2x cm. Drop OE and OF perpendicular on AB and CD from the centre O.
  • 13.
  • 14. The figure given below shows a circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED = 8 cm and EB = 4 cm, find the radius of the circle.
  • 15.
  • 16.
  • 17.
  • 18. M and N are the mid-points of two equal chords AB and CD respectively of a circle with centre O. Prove that: /BMN= /DNM /AMN = /CNM
  • 19. AB=CD
  • 20.
  • 21.
  • 22. The length of the common chord of two intersecting circles is 30 cm. If the diameters of these two circles be 50 cm and 34 cm, calculate the distance between their centres.
  • 23. The line joining the midpoints of two chords of a circle passes through its centre. Prove that the chords are parallel.
  • 24.
  • 25. AB and CD are two equal chords of a circle with centre O which intersect each other at right angle at point P. If OM I AB and ON I CD; show that OMPN is a square.
  • 26. In the given figure, an equilateral triangle ABC is inscribed in a circle with centre O. Find: (i) ∠BOC (ii) ∠OBC
  • 27.
  • 28.
  • 29. We know that equal arcs subtend equal angles at the center.