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ANSYS THERMAL TUTORIAL
Thermal - Mixed Boundary Example
(Conduction/Convection/Insulated)
Introduction
This tutorial was created using ANSYS 7.0 to solve simple thermal examples.
Analysis of a simple conduction as well a mixed conduction/convection/insulation
problem will be demonstrated.
The Mixed Convection/Conduction/Insulated Boundary Conditions Example is
constrained as shown in the following figure (Note that the section is assumed to
be infinitely long):
Preprocessing: Defining the Problem
1. Give example a Title
2. Open preprocessor menu
ANSYS Main Menu > Preprocessor
/PREP7
3. Create geometry
Preprocessor > Modeling > Create > Areas > Rectangle > By 2
Corners > X=0, Y=0, Width=1, Height=1
BLC4,0,0,1,1
4. Define the Type of Element
Preprocessor > Element Type > Add/Edit/Delete... > click 'Add' >
Select Thermal Mass Solid, Quad 4Node 55
ET,1,PLANE55
As in the conduction example, we will use PLANE55 (Thermal Solid, Quad
4node 55). This element has 4 nodes and a single DOF (temperature) at each
node. PLANE55 can only be used for 2 dimensional steady-state or transient
thermal analysis.
5. Element Material Properties
Preprocessor > Material Props > Material Models > Thermal >
Conductivity > Isotropic > KXX = 10
MP,KXX,1,10
This will specify a thermal conductivity of 10 W/m*C.
6. Mesh Size
Preprocessor > Meshing > Size Cntrls > ManualSize > Areas > All
Areas > 0.05
AESIZE,ALL,0.05
7. Mesh
Preprocessor > Meshing > Mesh > Areas > Free > Pick All
AMESH,ALL
Solution Phase: Assigning Loads and Solving
1. Define Analysis Type
Solution > Analysis Type > New Analysis > Steady-State
ANTYPE,0
2. Apply Conduction Constraints
In this example, all 2 sides of the block have fixed temperatures, while
convection occurs on the other 2 sides.
o Solution > Define Loads > Apply > Thermal > Temperature > On
Lines
o Select the top line of the block and constrain it to a constant value of
500 C
o Using the same method, constrain the left side of the block to a
constant value of 100 C
3. Apply Convection Boundary Conditions
o Solution > Define Loads > Apply > Thermal > Convection > On
Lines
o Select the right side of the block.
The following window will appear:
o Fill in the window as shown. This will specify a convection of 10
W/m2
*C and an ambient temperature of 100 degrees Celcius. Note
that VALJ and VAL2J have been left blank. This is because we have
uniform convection across the line.
4. Apply Insulated Boundary Conditions
o Solution > Define Loads > Apply > Thermal > Convection > On
Lines
o Select the bottom of the block.
o Enter a constant Film coefficient (VALI) of 0. This will eliminate
convection through the side, thereby modeling an insulated wall.
Note: you do not need to enter a Bulk (or ambient) temperature
You should obtain the following:
5. Solve the System
Solution > Solve > Current LS
SOLVE
Postprocessing: Viewing the Results
1. Results Using ANSYS
Plot Temperature
General Postproc > Plot Results > Contour Plot > Nodal Solu ... >
DOF solution, Temperature TEMP
Ansys thermal tutorial

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Ansys thermal tutorial

  • 1. ANSYS THERMAL TUTORIAL Thermal - Mixed Boundary Example (Conduction/Convection/Insulated) Introduction This tutorial was created using ANSYS 7.0 to solve simple thermal examples. Analysis of a simple conduction as well a mixed conduction/convection/insulation problem will be demonstrated. The Mixed Convection/Conduction/Insulated Boundary Conditions Example is constrained as shown in the following figure (Note that the section is assumed to be infinitely long): Preprocessing: Defining the Problem 1. Give example a Title 2. Open preprocessor menu ANSYS Main Menu > Preprocessor /PREP7
  • 2. 3. Create geometry Preprocessor > Modeling > Create > Areas > Rectangle > By 2 Corners > X=0, Y=0, Width=1, Height=1 BLC4,0,0,1,1 4. Define the Type of Element Preprocessor > Element Type > Add/Edit/Delete... > click 'Add' > Select Thermal Mass Solid, Quad 4Node 55 ET,1,PLANE55 As in the conduction example, we will use PLANE55 (Thermal Solid, Quad 4node 55). This element has 4 nodes and a single DOF (temperature) at each node. PLANE55 can only be used for 2 dimensional steady-state or transient thermal analysis. 5. Element Material Properties Preprocessor > Material Props > Material Models > Thermal > Conductivity > Isotropic > KXX = 10 MP,KXX,1,10 This will specify a thermal conductivity of 10 W/m*C. 6. Mesh Size Preprocessor > Meshing > Size Cntrls > ManualSize > Areas > All Areas > 0.05 AESIZE,ALL,0.05 7. Mesh Preprocessor > Meshing > Mesh > Areas > Free > Pick All AMESH,ALL Solution Phase: Assigning Loads and Solving 1. Define Analysis Type Solution > Analysis Type > New Analysis > Steady-State ANTYPE,0 2. Apply Conduction Constraints
  • 3. In this example, all 2 sides of the block have fixed temperatures, while convection occurs on the other 2 sides. o Solution > Define Loads > Apply > Thermal > Temperature > On Lines o Select the top line of the block and constrain it to a constant value of 500 C o Using the same method, constrain the left side of the block to a constant value of 100 C 3. Apply Convection Boundary Conditions o Solution > Define Loads > Apply > Thermal > Convection > On Lines o Select the right side of the block. The following window will appear: o Fill in the window as shown. This will specify a convection of 10 W/m2 *C and an ambient temperature of 100 degrees Celcius. Note
  • 4. that VALJ and VAL2J have been left blank. This is because we have uniform convection across the line. 4. Apply Insulated Boundary Conditions o Solution > Define Loads > Apply > Thermal > Convection > On Lines o Select the bottom of the block. o Enter a constant Film coefficient (VALI) of 0. This will eliminate convection through the side, thereby modeling an insulated wall. Note: you do not need to enter a Bulk (or ambient) temperature You should obtain the following: 5. Solve the System Solution > Solve > Current LS SOLVE Postprocessing: Viewing the Results 1. Results Using ANSYS Plot Temperature General Postproc > Plot Results > Contour Plot > Nodal Solu ... > DOF solution, Temperature TEMP