2. Slide 3: What is probability?
Slide 4: Mini Lesson: What Probability Can Be
Slide 5: Demonstrative Situation
Slide 6: Demonstrative Situation: Question 1
Slide 9: Mini Lesson: Finding the # of Possibilities
Slide 11: Demonstrative Situation: Question 2
Slide 13: Demonstrative Situation: Question 3
3. # of favorable outcomes (basically the # of possibilities you want)
Total # of outcomes
4. A probability is always between 1 and 0, which
means that it can be a fraction that is equal to under
100% and has a 0.__ if it is a decimal.
5. Suppose you are playing with a die (singular form of
“dice”) and a coin.
6. Suppose you are playing with a die (singular form of
“dice”) and a coin.
What are the possible outcomes?
7. To find the possible outcomes we have to first think
about how many sides there on a dice, since there
are 6 sides there are 6 possible outcomes.
1
side
2
sides
3
sides
4
sides
5
sides
6
sides
8. Since there are 2 sides on a coin there are 2 possible outcomes if we
are only using a coin alone, since we have 6 possible outcomes
already, we will add those outcomes to the chart keeping in mind the
fact that there a 6 outcomes, now they have 2 versions of those
original 6 outcomes. Since there are 12 coins at the bottom, there
are 12 possible possible mixes of how the coin and die will fall.
1
side
2
sides
3
sides
4
sides
5
sides
6
sides
H T H T H T H T H T H T
H = Heads
T = Tails
9. In doing our last problem we could have used
multiplication due to the fact that what were were
really doing on part two was finding six twos (6(2)).
Those two numbers multiply to our our total number
of possibilities, 12.
10. Written out the possibilities are;
1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T
1
side
2
sides
3
sides
4
sides
5
sides
6
sides
H T H T H T H T H T H T
11. Suppose you are playing with a die (singular form of
“dice”) and a coin.
What is the possibility that you get an even number
12. To find this out we need to look at the possibilities
again.
1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T
Since there a 6 chances, we will put that above the
total number of possibilities as stated in slide 3.
6/12 = ½ which is the final answer.
13. Suppose you are playing with a die (singular form of
“dice”) and a coin.
What is the possibility of you getting an even number
and* heads.
*when “and” shows up in problems such as these it is an omen for multiplication.
14. What is the possibility of you getting an even number
and heads.
The first thing to do is to check the possibilities of
getting them separately.
1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T
Each one of them has a 6/12 or ½ chance of occuring so
I will follow the omen of the “and” and I will multiply them.
½ x ½ = ¼
