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‹#›
Eeng224
Chapter 10
Sinusoidal Steady State Analysis
Huseyin Bilgekul
Eeng224 Circuit Theory II
Department of Electrical and Electronic Engineering
Eastern Mediterranean University
Chapter Objectives:
 Apply previously learn circuit techniques to sinusoidal steady-state
analysis.
 Learn how to apply nodal and mesh analysis in the frequency domain.
 Learn how to apply superposition, Thevenin’s and Norton’s theorems
in the frequency domain.
 Learn how to analyze AC Op Amp circuits.
 Be able to use PSpice to analyze AC circuits.
 Apply what is learnt to capacitance multiplier and oscillators.
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Eeng224
 Transform a voltage source in series with an impedance to a current source in
parallel with an impedance for simplification or vice versa.
Source Transformation
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Eeng224
Source Transformation
If we transform the current source to a voltage source, we obtain the circuit shown in Fig. (a).
 Practice Problem 10.4: Calculate the current Io
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Eeng224
Source Transformation
 Practice Problem 10.4: Calculate the current Io
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Eeng224
Thevenin Equivalent Circuit
 Thévenin’s theorem, as stated for sinusoidal AC circuits, is changed only to
include the term impedance instead of resistance.
 Any two-terminal linear ac network can be replaced with an equivalent
circuit consisting of a voltage source and an impedance in series.
 VTh is the Open circuit voltage between the terminals a-b.
 ZTh is the impedance seen from the terminals when the independent sources are
set to zero.
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Eeng224
Norton Equivalent Circuit
 The linear circuit is replaced by a current source in parallel with an impedance.
IN is the Short circuit current flowing between the terminals a-b when the
terminals are short circuited.
 Thevenin and Norton equivalents are related by:
Th N N Th N
V Z I Z Z
 
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Eeng224
Thevenin Equivalent Circuit
P.P.10.8 Thevenin Equivalent At terminals a-b
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Eeng224
Thevenin Equivalent Circuit
P.P.10.9 Thevenin and Norton Equivalent
for Circuits with Dependent Sources
To find Vth , consider the circuit in Fig. (a).
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Eeng224
Thevenin Equivalent Circuit
P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources
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Eeng224
Thevenin Equivalent Circuit
P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources
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Eeng224
Thevenin Equivalent Circuit
P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources
Since there is a dependent source, we can find the impedance by inserting a voltage source
and calculating the current supplied by the source from the terminals a-b.
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Eeng224
OP Amp AC Circuits
 Practice Problem 10.11: Calculate vo and current io
The frequency domain equivalent circuit.
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Eeng224
OP Amp AC Circuits
 Practice Problem 10.11: Calculate vo and current io
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Eeng224
OP Amp AC Circuits
 Practice Problem 10.11: Calculate vo and current io
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Eeng224
 Capacitance multiplier: The circuit acts as an equivalent capacitance Ceq
2
1
1
1
i
i eq
i eq
V R
Z C C
I j C R

 
   
 
 
OP Amp Capacitance Multiplier Circuit
( )
1
i o
i i o
V V
I j C V V
j C



   0 2
0
1 2 1
0 0
i
i
V V R
V V
R R R
 
   
2 2
1 1
Substituting, (1 ) or (1 )
i
i i
i
I
R R
I j C V j C
R V R
 
   
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Eeng224
Oscillators
 An oscillator is a circuit that produces an AC waveform as output when
powered by a DC input (The OP AMP circuit needs DC to operate).
 A circuit will oscillate if the following criteria (BARKHAUSEN) is satisfied.
 The overall gain of the oscillator must be unity or greater.
 The overall phase shift from the input to ouput and back to input must be
zero.
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Eeng224
Oscillators
 An oscillator is a circuit that produces an AC waveform as output when powered by a
DC input (The OP AMP circuit needs DC to operate).
OUTPUT
+ INPUT
- INPUT
Phase shift circuit to
produce 180 degree
shift
Produce overall gain
greater than 1
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Eeng224
Assignment to be Submitted
Construct the PSpice schemmatic of the oscillator shown Prob. 10.91 from the
textbook which is also shown above.
 Display the oscilloscope AC waveforms of V2 and Vo to show the phase
relationship.
 Submit the printout of your circuit schemmatic and the oscilloscope waveforms
of V2 and Vo as shown in the next page for a similar circuit.
 Do you obtain the required phase shift and the oscillation frequency? If not it will
not oscillate to produce a pure sine wave.
 Submission date 21 March 2007.
 The analytic solution is given in the next page to help your simulation.
Vo
V2
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Eeng224
Assignment (Analytic Solution)
Chapter 10, Solution 91.
voltage at the noninverting terminal of the op amp

2
V

o
V output voltage of the op amp
1
10
p o s
k R R j L
j C


     
Z Z
2 2
2
) )
( ( 1
p o o
o s p o o
o
R CR
j C R R
R R j L
C
j LC





  
  
 
 
Z
V V
V Z Z V
For this to be purely real,
2
-3 -9
1 1 1
1 0
2 2 (0.4 10 )(2 10
180kHz Osc. Fr
)
eq.
o o o
LC f
LC LC
 
 
  
    
 
o
o
o
o
o
o
o
2
R
R
R
)
R
R
(
C
CR






V
V
At oscillation,
This must be compensated for by
2
80
40
1
1 5 4
20
k
5
o o
v o
o
R
R R
R R
     
   

V
A
V
‹#›
Eeng224
Similar Oscillator as the Assignment

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chpt10_2.ppt

  • 1. ‹#› Eeng224 Chapter 10 Sinusoidal Steady State Analysis Huseyin Bilgekul Eeng224 Circuit Theory II Department of Electrical and Electronic Engineering Eastern Mediterranean University Chapter Objectives:  Apply previously learn circuit techniques to sinusoidal steady-state analysis.  Learn how to apply nodal and mesh analysis in the frequency domain.  Learn how to apply superposition, Thevenin’s and Norton’s theorems in the frequency domain.  Learn how to analyze AC Op Amp circuits.  Be able to use PSpice to analyze AC circuits.  Apply what is learnt to capacitance multiplier and oscillators.
  • 2. ‹#› Eeng224  Transform a voltage source in series with an impedance to a current source in parallel with an impedance for simplification or vice versa. Source Transformation
  • 3. ‹#› Eeng224 Source Transformation If we transform the current source to a voltage source, we obtain the circuit shown in Fig. (a).  Practice Problem 10.4: Calculate the current Io
  • 4. ‹#› Eeng224 Source Transformation  Practice Problem 10.4: Calculate the current Io
  • 5. ‹#› Eeng224 Thevenin Equivalent Circuit  Thévenin’s theorem, as stated for sinusoidal AC circuits, is changed only to include the term impedance instead of resistance.  Any two-terminal linear ac network can be replaced with an equivalent circuit consisting of a voltage source and an impedance in series.  VTh is the Open circuit voltage between the terminals a-b.  ZTh is the impedance seen from the terminals when the independent sources are set to zero.
  • 6. ‹#› Eeng224 Norton Equivalent Circuit  The linear circuit is replaced by a current source in parallel with an impedance. IN is the Short circuit current flowing between the terminals a-b when the terminals are short circuited.  Thevenin and Norton equivalents are related by: Th N N Th N V Z I Z Z  
  • 7. ‹#› Eeng224 Thevenin Equivalent Circuit P.P.10.8 Thevenin Equivalent At terminals a-b
  • 8. ‹#› Eeng224 Thevenin Equivalent Circuit P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources To find Vth , consider the circuit in Fig. (a).
  • 9. ‹#› Eeng224 Thevenin Equivalent Circuit P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources
  • 10. ‹#› Eeng224 Thevenin Equivalent Circuit P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources
  • 11. ‹#› Eeng224 Thevenin Equivalent Circuit P.P.10.9 Thevenin and Norton Equivalent for Circuits with Dependent Sources Since there is a dependent source, we can find the impedance by inserting a voltage source and calculating the current supplied by the source from the terminals a-b.
  • 12. ‹#› Eeng224 OP Amp AC Circuits  Practice Problem 10.11: Calculate vo and current io The frequency domain equivalent circuit.
  • 13. ‹#› Eeng224 OP Amp AC Circuits  Practice Problem 10.11: Calculate vo and current io
  • 14. ‹#› Eeng224 OP Amp AC Circuits  Practice Problem 10.11: Calculate vo and current io
  • 15. ‹#› Eeng224  Capacitance multiplier: The circuit acts as an equivalent capacitance Ceq 2 1 1 1 i i eq i eq V R Z C C I j C R            OP Amp Capacitance Multiplier Circuit ( ) 1 i o i i o V V I j C V V j C       0 2 0 1 2 1 0 0 i i V V R V V R R R       2 2 1 1 Substituting, (1 ) or (1 ) i i i i I R R I j C V j C R V R      
  • 16. ‹#› Eeng224 Oscillators  An oscillator is a circuit that produces an AC waveform as output when powered by a DC input (The OP AMP circuit needs DC to operate).  A circuit will oscillate if the following criteria (BARKHAUSEN) is satisfied.  The overall gain of the oscillator must be unity or greater.  The overall phase shift from the input to ouput and back to input must be zero.
  • 17. ‹#› Eeng224 Oscillators  An oscillator is a circuit that produces an AC waveform as output when powered by a DC input (The OP AMP circuit needs DC to operate). OUTPUT + INPUT - INPUT Phase shift circuit to produce 180 degree shift Produce overall gain greater than 1
  • 18. ‹#› Eeng224 Assignment to be Submitted Construct the PSpice schemmatic of the oscillator shown Prob. 10.91 from the textbook which is also shown above.  Display the oscilloscope AC waveforms of V2 and Vo to show the phase relationship.  Submit the printout of your circuit schemmatic and the oscilloscope waveforms of V2 and Vo as shown in the next page for a similar circuit.  Do you obtain the required phase shift and the oscillation frequency? If not it will not oscillate to produce a pure sine wave.  Submission date 21 March 2007.  The analytic solution is given in the next page to help your simulation. Vo V2
  • 19. ‹#› Eeng224 Assignment (Analytic Solution) Chapter 10, Solution 91. voltage at the noninverting terminal of the op amp  2 V  o V output voltage of the op amp 1 10 p o s k R R j L j C         Z Z 2 2 2 ) ) ( ( 1 p o o o s p o o o R CR j C R R R R j L C j LC                Z V V V Z Z V For this to be purely real, 2 -3 -9 1 1 1 1 0 2 2 (0.4 10 )(2 10 180kHz Osc. Fr ) eq. o o o LC f LC LC               o o o o o o o 2 R R R ) R R ( C CR       V V At oscillation, This must be compensated for by 2 80 40 1 1 5 4 20 k 5 o o v o o R R R R R            V A V