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Question 1.
Find the squares of the following numbers using column method. Verify the
result by finding the square using the usual multiplication :
(i) 25
(ii) 37
(iii) 54
(iv) 71
(v) 96
Solution:
(i) (25)2
Question 2.
Find the squares of the following numbers using diagonal method :
(i) 98
(ii) 273
(iii) 348
(iv) 295
(v) 171
Solution:
Question 3.
Find the squares of the following numbers :
(i) 127
(ii) 503
(iii) 451
(iv) 862
(v) 265
Solution:
(i) (127)2
= (120 + 7)2
{(a + b)2
= a2
+ lab + b2
}
= (120)2
+ 2 x 120 x 7 + (7)2
= 14400+ 1680 + 49 = 16129
(ii) (503)2
= (500 + 3)2
{(a + b)2
= a2
+ lab + b1
}
= (500)2
+ 2 x 500 x 3 + (3)2
= 250000 + 3000 + 9 = 353009
(iii) (451)2
= (400 + 51)2
{(a + b)2
= a2
+ lab + b2
}
= (400)2
+ 2 x 400 x 51 + (5l)2
= 160000 + 40800 + 2601 = 203401
(iv) (451)2
= (800 + 62)2
{(a + b)2
= a2
+ lab + b2
}
= (800)2
+ 2 x 800 x 62 + (62)2
= 640000 + 99200 + 3844 = 743044
(v) (265)2
{(a + b)2
= a2
+ 2ab + b2
}
(200 + 65)2
= (200)2
+ 2 x 200 x 65 + (65)2
= 40000 + 26000 + 4225 = 70225
Question 4.
Find the squares of the following numbers
(i) 425
(ii) 575
(iii) 405
(iv) 205
(v) 95
(vi) 745
(vii) 512
(viii) 995
Solution:
(i) (425)2
Here n = 42
∴ n (n + 1) = 42 (42 + 1) = 42 x 43 = 1806
∴ (425)2
= 180625
(ii) (575)2
Here n = 57
∴ n (n + 1) = 57 (57 + 1) = 57 x 58 = 3306
∴ (575)2
= 330625
(iii) (405)2
Here n = 40
∴ n (n + 1) = 40 (40 + 1) -40 x 41 = 1640
∴ (405)2
= 164025
(iv) (205)2
Here n = 20
∴ n (n + 1) = 20 (20 + 1) = 20 x 21 = 420
∴ (205)2
= 42025
(v) (95)2
Here n = 9
∴ n (n + 1) = 9 (9 + 1) = 9 x 10 = 90
∴ (95)2
= 9025
(vi) (745)2
Here n = 74
∴ n (n + 1) = 74 (74 + 1) = 74 x 75 = 5550
∴ (745)2
= 555025
(vii) (512)2
Here a = 1, b = 2
∴ (5ab)2
= (250 + ab) x 1000 + (ab)2
∴ (512)2
= (250 + 12) x 1000 + (12)2
= 262 x 1000 + 144
= 262000 + 144 = 262144
(viii) (995)2
Here n = 99
∴ n (n + 1) = 99 (99 + 1) = 99 x 100 = 9900
∴ (995)2
= 990025
Question 5.
Find the squares of the following numbers using the identity (a + b)1 = a2 + lab
+ b1
(i) 405
(ii) 510
(iii) 1001
(iv) 209
(v) 605
Solution:
a + b)2
= a2
+ lab + b2
(i) (405)2
= (400 + 5)2
= (400)2
+ 2 x 400 x 5 + (5)2
= 160000 + 4000 + 25 = 164025
(ii) (510)2
= (500 + 10)2
= (500)2
+ 2 x 500 x 10 x (10)2
= 250000 + 10000 + 100
= 260100
(iii) (1001)2
= (1000+1)2
= (1000)2
+ 2 X 1000 x 1 + (1)
= 1000000 + 2000 + 1
=1002001
(iv) (209)2
= (200 + 9)2
= (200)2
+ 2 x 200 x 9 x (9)2
= 40000 + 3600 +81
= 43681
(v) (605)2
= (600 + 5)2
= (600)2
+ 2 x 600 x 5 +(5)2
= 360000 + 6000 25
=366025
Question 6.
Find the squares of the following numbers using the identity (a – b)2
= a2
– 2ab
+ b2
:
(i) 395
(ii) 995
(iii) 495
(iv) 498
(v) 99
(vi) 999
(vii) 599
Solution:
a – b)2
= a2
– lab + b2
(i) (395)2
= (400 – 5)2
= (400)2
– 2 x 400 x 5 + (5)2
= 160000-4000 + 25
= 160025-4000
= 156025
(ii) (995)2
= (1000 – 5)2
= (1000)2
– 2 x 1000 x 5 + (5)2
= 1000000- 10000 + 25
= 1000025- 10000
= 990025
(iii) (495)2
= (500 – 5)2
= (500)2
– 2 x 500 x 5 + (5)2
= 250000 – 5000 + 25
= 250025 – 5000
= 245025
(iv) (498)2
= (500 – 2)2
= (500)2
– 2 x 500 x 2 + (2)2
= 250000 – 2000 + 4
= 250004 – 2000
= 248004
(v) (99)2
= (100 – l)2
= (100)2
– 2 x 100 x 1 + (1)2
= 10000 – 200 + 1
= 10001 – 200
= 9801
(vi) (999)2
= (1000- l)2
= (1000)2
– 2 x 1000 x 1+ (1)2
= 1000000-2000+1
= 10000001-2000=998001
(vii) (599)2
= (600 – 1)2
= (600)2
-2 x 600 X 1+ (1)2
= 360000 -1200+1
= 360001 – 1200 = 358801
Question 7.
Find the squares of the following numbers by visual method :
(i) 52
(ii) 95
(iii) 505
(iv) 702
(v) 99
Solution:
(a + b)2
= a2
– ab + ab + b2
(i) (52)2
= (50 + 2)2
= 2500 + 100 + 100 + 4
= 2704
(ii) (95)2
= (90 + 5)2
= 8100 + 450 + 450 + 25
= 9025
(iii) (505)2
= (500 + 5)2
= 250000 + 2500 + 2500 + 25
= 255025
(iv) (702)2
= (700 + 2)2
= 490000 + 1400+ 1400 + 4
= 492804
(v) (99)2
= (90 + 9)2
= 8100 + 810 + 810 + 81
= 9801
C3 3.1
C3 3.1

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Solving Puzzles Benefits Everyone (English).pptx
 

C3 3.1

  • 1. Question 1. Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication : (i) 25 (ii) 37 (iii) 54 (iv) 71 (v) 96 Solution: (i) (25)2
  • 2.
  • 3. Question 2. Find the squares of the following numbers using diagonal method :
  • 4. (i) 98 (ii) 273 (iii) 348 (iv) 295 (v) 171 Solution:
  • 5. Question 3. Find the squares of the following numbers : (i) 127 (ii) 503 (iii) 451 (iv) 862 (v) 265 Solution: (i) (127)2 = (120 + 7)2 {(a + b)2 = a2 + lab + b2 }
  • 6. = (120)2 + 2 x 120 x 7 + (7)2 = 14400+ 1680 + 49 = 16129 (ii) (503)2 = (500 + 3)2 {(a + b)2 = a2 + lab + b1 } = (500)2 + 2 x 500 x 3 + (3)2 = 250000 + 3000 + 9 = 353009 (iii) (451)2 = (400 + 51)2 {(a + b)2 = a2 + lab + b2 } = (400)2 + 2 x 400 x 51 + (5l)2 = 160000 + 40800 + 2601 = 203401 (iv) (451)2 = (800 + 62)2 {(a + b)2 = a2 + lab + b2 } = (800)2 + 2 x 800 x 62 + (62)2 = 640000 + 99200 + 3844 = 743044 (v) (265)2 {(a + b)2 = a2 + 2ab + b2 } (200 + 65)2 = (200)2 + 2 x 200 x 65 + (65)2 = 40000 + 26000 + 4225 = 70225 Question 4. Find the squares of the following numbers (i) 425 (ii) 575 (iii) 405 (iv) 205 (v) 95 (vi) 745 (vii) 512 (viii) 995 Solution: (i) (425)2 Here n = 42 ∴ n (n + 1) = 42 (42 + 1) = 42 x 43 = 1806 ∴ (425)2 = 180625 (ii) (575)2 Here n = 57 ∴ n (n + 1) = 57 (57 + 1) = 57 x 58 = 3306 ∴ (575)2 = 330625 (iii) (405)2 Here n = 40
  • 7. ∴ n (n + 1) = 40 (40 + 1) -40 x 41 = 1640 ∴ (405)2 = 164025 (iv) (205)2 Here n = 20 ∴ n (n + 1) = 20 (20 + 1) = 20 x 21 = 420 ∴ (205)2 = 42025 (v) (95)2 Here n = 9 ∴ n (n + 1) = 9 (9 + 1) = 9 x 10 = 90 ∴ (95)2 = 9025 (vi) (745)2 Here n = 74 ∴ n (n + 1) = 74 (74 + 1) = 74 x 75 = 5550 ∴ (745)2 = 555025 (vii) (512)2 Here a = 1, b = 2 ∴ (5ab)2 = (250 + ab) x 1000 + (ab)2 ∴ (512)2 = (250 + 12) x 1000 + (12)2 = 262 x 1000 + 144 = 262000 + 144 = 262144 (viii) (995)2 Here n = 99 ∴ n (n + 1) = 99 (99 + 1) = 99 x 100 = 9900 ∴ (995)2 = 990025 Question 5. Find the squares of the following numbers using the identity (a + b)1 = a2 + lab + b1 (i) 405 (ii) 510 (iii) 1001 (iv) 209 (v) 605 Solution: a + b)2 = a2 + lab + b2 (i) (405)2 = (400 + 5)2 = (400)2 + 2 x 400 x 5 + (5)2 = 160000 + 4000 + 25 = 164025 (ii) (510)2 = (500 + 10)2 = (500)2 + 2 x 500 x 10 x (10)2
  • 8. = 250000 + 10000 + 100 = 260100 (iii) (1001)2 = (1000+1)2 = (1000)2 + 2 X 1000 x 1 + (1) = 1000000 + 2000 + 1 =1002001 (iv) (209)2 = (200 + 9)2 = (200)2 + 2 x 200 x 9 x (9)2 = 40000 + 3600 +81 = 43681 (v) (605)2 = (600 + 5)2 = (600)2 + 2 x 600 x 5 +(5)2 = 360000 + 6000 25 =366025 Question 6. Find the squares of the following numbers using the identity (a – b)2 = a2 – 2ab + b2 : (i) 395 (ii) 995 (iii) 495 (iv) 498 (v) 99 (vi) 999 (vii) 599 Solution: a – b)2 = a2 – lab + b2 (i) (395)2 = (400 – 5)2 = (400)2 – 2 x 400 x 5 + (5)2 = 160000-4000 + 25 = 160025-4000 = 156025 (ii) (995)2 = (1000 – 5)2 = (1000)2 – 2 x 1000 x 5 + (5)2 = 1000000- 10000 + 25 = 1000025- 10000 = 990025 (iii) (495)2 = (500 – 5)2 = (500)2 – 2 x 500 x 5 + (5)2 = 250000 – 5000 + 25
  • 9. = 250025 – 5000 = 245025 (iv) (498)2 = (500 – 2)2 = (500)2 – 2 x 500 x 2 + (2)2 = 250000 – 2000 + 4 = 250004 – 2000 = 248004 (v) (99)2 = (100 – l)2 = (100)2 – 2 x 100 x 1 + (1)2 = 10000 – 200 + 1 = 10001 – 200 = 9801 (vi) (999)2 = (1000- l)2 = (1000)2 – 2 x 1000 x 1+ (1)2 = 1000000-2000+1 = 10000001-2000=998001 (vii) (599)2 = (600 – 1)2 = (600)2 -2 x 600 X 1+ (1)2 = 360000 -1200+1 = 360001 – 1200 = 358801 Question 7. Find the squares of the following numbers by visual method : (i) 52 (ii) 95 (iii) 505 (iv) 702 (v) 99 Solution: (a + b)2 = a2 – ab + ab + b2 (i) (52)2 = (50 + 2)2 = 2500 + 100 + 100 + 4 = 2704 (ii) (95)2 = (90 + 5)2 = 8100 + 450 + 450 + 25 = 9025
  • 10. (iii) (505)2 = (500 + 5)2 = 250000 + 2500 + 2500 + 25 = 255025 (iv) (702)2 = (700 + 2)2 = 490000 + 1400+ 1400 + 4 = 492804 (v) (99)2 = (90 + 9)2 = 8100 + 810 + 810 + 81 = 9801