2. Pin / Hinge Roller Fixed
Fx
Fy Fy
Fx
Fy
Mz
Supports
Reactions
3. Determinacy and Indeterminacy
P
L/2 L/2
A B
Ra
Hx
Rb
Ra = ?
Rb = ?
Hx = ?
Ra = P/2
Rb = P/2
Hx = 0
Equilibrium
equations
⅀ Fx = 0
⅀ Fy = 0
⅀ Mz = 0
P
4. P
L/2 L/2
A B
Ra
Hx
Rb
⅀Fx = 0 → Hx = 0
⅀Fy = 0 → Ra + Rb = P
⅀Ma = 0 → P(L/2) - Rb(L) = 0
P(L/2) = Rb(L)
Rb = P/2
Ra = P - Rb
P – P/2
Ra = P/2
3 equations, 3 unknowns → Statically Determinate beam
Unknowns can be solved using available equations
P
5. P
A B C
P
Ra
Hx
Rb Rc
3 Equations, 4
Unknowns
Statically
Indeterminate Beam
Cannot solve for the
unknowns
Reactions – Equations = 0 → Determinate
Reactions – Equations ˃ 0 → Indeterminate
Reactions – Equations < 0 → Unstable
6. Indeterminacy
Static Indeterminacy
(associated with force)
Kinematic Indeterminacy
(associated with displacement)
Degree of freedom (DOF)
Externally
Indeterminate
Internally
Indeterminate
Degree of Static Indeterminacy (DSI) = External + Internal
13. Frames
Open Cut Concept
1. Supports should be fixed
2. No. of supports = no. of open
structures
DSI = 3C-R (2D)
6C-R (3D)
C = no. of cuts
R = no. of reactions introduced
R=2 DSI= (3x2) – 2 = 4
7.
20. Trusses
Trusses – all the joints are pin (hinge) joints
all members are tie members (take axial load only)
m members will have m loads
r support reaction
Each joint (j) will have 2
equilibrium equations
DSI = (m+r) -2j
m
21. 14.
c
Find DSI ? Method 1→ c as joint
m = 8
r = 3
j = 5
DSI = m+r – 2j
8+3 – (2x5) = 1
Method 2→ c not as joint
m = 6
r = 3
j = 4
DSI = 6+3 – (2x4) = 1
27. Find Internal and External indeterminacy ?20.
Ext Indeterminacy = Rns – Eqns
(2+2) – 3 = 1
Total DSI = m+r – 2j
15+4 – (2x8) = 3
Int Indeterminacy = Total – Ext
3-1 = 2
28. Kinematic Indeterminacy
Degrees of freedom or independent coordinated required
to locate the structure in displaced configuration,
relative to the original configuration
DOF = 0 DOF = 3
DOF = 1 DOF = 2
DKI = 3j-r + additional DOF due to hinge
c
c
DOF = 4 linear
DOF = m-1 angular
Δx
Δy
θ1
θ2
31. 23. Find DKI ?
All members are inextensible
Inextensible members : Rigid members with
no axial deformation
DK’ = DKI – no. of members
DK’ = 3j-r- m
(3x4)-6 – 3 = 3