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Solving simultaneous
equations graphically
The Question:


                y = 2x + 1
                 y=4-x

Solve the simultaneous equations graphically.
y = 2x + 1       y=4-x

Begin by constructing a table of values:

 y = 2x + 1
              x    -2       0      2      4
              y    -3       1      5      9



        Use the equation to fill in the y value when x = -2

         Now fill in the rest of the table
y = 2x + 1                y=4-x
                                                                 Use the
y = 2x + 1                                                       table to draw
         x            -2                 0       2       4       the graph of
         y            -3                 1       5       9       the equation.
                            10       y
                            8

                            6

                            4

                            2

                            0
        -3       -2    -1        0           1   2   3       4    5
                                                                   x
                            -2

             y = 2x + 1     -4
y = 2x + 1         y=4-x
Now construct a second table of values:
Y=4-x
        x      -2      0      2      4
        y       6      4      2      0



Plot this line on the axes you used earlier...
10       y
                      8
    y=4-x             6

                      4

                      2

                      0                            x
   -3   -2       -1        0       1   2   3   4   5
                      -2
    y = 2x + 1        -4




The solution is where the 2 lines cross:
   Read the x-value from the x-axis... 1
   Now read off the y-value... 3
So the solution of y = 2x + 1 and
y = 4 - x is...

     x=1     and    y=3

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Lecture 2.2 graphs ii - solving simult.eqns graphically

  • 2. The Question: y = 2x + 1 y=4-x Solve the simultaneous equations graphically.
  • 3. y = 2x + 1 y=4-x Begin by constructing a table of values: y = 2x + 1 x -2 0 2 4 y -3 1 5 9 Use the equation to fill in the y value when x = -2 Now fill in the rest of the table
  • 4. y = 2x + 1 y=4-x Use the y = 2x + 1 table to draw x -2 0 2 4 the graph of y -3 1 5 9 the equation. 10 y 8 6 4 2 0 -3 -2 -1 0 1 2 3 4 5 x -2 y = 2x + 1 -4
  • 5. y = 2x + 1 y=4-x Now construct a second table of values: Y=4-x x -2 0 2 4 y 6 4 2 0 Plot this line on the axes you used earlier...
  • 6. 10 y 8 y=4-x 6 4 2 0 x -3 -2 -1 0 1 2 3 4 5 -2 y = 2x + 1 -4 The solution is where the 2 lines cross: Read the x-value from the x-axis... 1 Now read off the y-value... 3
  • 7. So the solution of y = 2x + 1 and y = 4 - x is... x=1 and y=3