1. Faculty of Engineering
Computer Science and Engineering (CSE)
Course Name: Networking
Submitted to:
Mr. Afzal Hossain
Lecturer
Computer Science & Engineering
World University of Bangladesh
ARIFUL ISLAM
Program: Computer Science & Engineering (CSE)
Batch: 31(E)
Roll: 1217
Semester: 6th
ID: WUB 03/15/31/1217
Date of Submission: 19,9,2016
Prepared by:
WORLD UNIVERSITY
OF BANGLADESH
2. Content:
Listed IP Address:
10.12.5.2
172.125.2.5
192.168.4.2
192.256.212.5
Finding:
1. How to identify an IP address
2. How to identify class of an IP address
3. Specify Network and Host portion
4. Find subnet mask
5. Find Broadcast Address
6. Find Network Address
7. Find Network bits and Host bits
8. And also find Total Host and Usable Host
>> 10.12.5.2
1. How to identify an IP address
10.12.5.2 is valid IP address, because we know that an IP address every portion bits
number is 8 and every bit portion decimal range 0-255
2. How to identify class of an IP address
This IP address’s class A [Class A: 0-127]. We find first 8 bit portion that decimal
range Between 0 to 127, this first number is 10.
A Class IP Address
10 12 5 2
Network and Host portion N H H H
8 8 8 8
Total Network and Host portion bits Total Network
=Network*8
=1*8
=8
Total Host portion
=Host*8
=3*8
=24
3. Subnet Mask 255 0 0 0
Network Address 10 0 0 0
Broadcast address 10 255 255 255
Total Host 2 Host bits
= 2 24
= 16777216
Usable Host 2 Host bits
-2 = 2 24
-2 = 16777214
>>172.125.2.5
How to identify an IP address
172.125.2.5 is valid IP address, because we know that an IP address every portion bits number is 8 and
every bit portion decimal range 0-255
How to identify class of an IP address
This IP address’s class B[Class B: 128-191]. We find first 8 bit portion that decimal range between 128 to
191, this first number is 172.
B Class IP Address
172 125 2 5
Network and Host portion N N H H
8 8 8 8
Total Network and Host portion bits Total Network
=Network*8
=2*8
=16
Total Host portion
=Host*8
=2*8
=16
Subnet Mask 255 255 0 0
Network Address
172 125 0 0
Broadcast address
172 125 255 255
Total Host 2 Host bits
= 2 16
= 65536
Usable Host 2 Host bits
-2 = 2 16
-2 = 65534
4. >> 192.168.4.2
How to identify an IP address
192.168.4.2 is valid IP address, because we know that an IP address every portion bits number is 8 and
every bit portion decimal range 0-255
How to identify class of an IP address
This IP address’s class C[Class C: 192-223]. We find first 8 bit portion that decimal range between 192 to
223, this first number is 192.
C Class IP Address 192 168
4 2
Network and Host portion N N N H
8 8 8 8
Total Network and Host portion bits Total Network
=Network*8
=3*8
=24
Total Host portion
=Host*8
=1*8
=8
Subnet Mask 255 255 255 0
Network Address 192 168
4 0
Broadcast address 192 168
4 255
Total Host 2 Host bits
= 2 16
= 65536
Usable Host 2 Host bits
-2 = 2 16
-2 = 65534