An introduction to ideal gas equations and examples of how to use them to solve problems.

1. Gases
Gas equations

2. BOYLE’S LAW

3. P
1
V

4. have
Temperature
Volume
Pressure
Amount

5. Volume
Pressure
(dm3)
1
5
2
2,5
3
1,67
4
1,25
5
1
6
0,833
k
(units)
x
x
x
x
x
x
1
2
3
4
5
6
(proportionality
constant: PV)
5
=
=
=
=
=
=
5
5
5
5
5

6. Volume
k
Pressure
1 V1 = 5
P1 = 1
(proportionality
constant: PV)
5
2 2,5
2
5
3 1,67
3
5
4 1,25
4
5
5 1
5
5
6 0,833
6
5
(dm3)
(units)

7. V1 x P 1 = k

8. Volume
k
Pressure
1 V1 = 5
P1 = 1
(proportionality
constant: PV)
5
2 V2 = 2,5
P2 = 2
5
3 1,67
3
5
4 1,25
4
5
5 1
5
5
6 0,833
6
5
(dm3)
(units)

9. V1 x P 1 = k
V2 x P2 = k

10. V1 x P 1 = k
V2 x P2 = k
V1 x P1 = V2 x P2

11. V1 x P 1 = k
V2 x P2 = k
V1 x P1 = V2 x P2
P1V1 = P2V2

12. V1 x P 1 = k
V2 x P2 = k
V1 x P1 = V2 x P2
P1V1 = P2V2

13. P1V1 = P2V2

14. PRESSURE AND TEMPERATURE

15. P
T

16. have
Temperature
Volume
Pressure
Amount

17. Temperature
Pressure
(kPa)
( C)
(K)
1 20
293
1,00
0,0034
2 40
313
1,07
0,0034
3 60
333
1,14
0,0034
4 80
353
1,21
0,0034
5 100
373
1,28
0,0034
6 313
586
2,01
0,0034

18. Temperature
Pressure
(kPa)
( C)
(K)
1 20
T1=293
P1=1,00
0,0034
2 40
313
1,07
0,0034
3 60
333
1,14
0,0034
4 80
353
1,21
0,0034
5 100
373
1,28
0,0034
6 313
586
2,01
0,0034

20. Temperature
Pressure
(kPa)
( C)
(K)
1 20
T1=293
P1=1,00
0,0034
2 40
T2=313
P2=1,07
0,0034
3 60
333
1,14
0,0034
4 80
353
1,21
0,0034
5 100
373
1,28
0,0034
6 313
586
2,01
0,0034

24. CHARLES’ LAW

25. V
T

26. have
Temperature
Volume
Pressure
Amount

27. Temperature
Volume
(cm3)
( C)
(K)
1 1
274
34
0,12
2 14
287
36
0,13
3 53
326
37
0,11
4 76
349
41
0,12

31. GENERAL GAS EQUATION

32. have
Temperature
Volume
Pressure
Amount

33. have
Temperature
Volume
Pressure
Amount

36. QUESTION 1

37. Question
A gas bubble at the bottom of a lake has a
volume of 200cm3 at a temperature of 8 C.
This bubble rises and when it reaches the
surface where the temperature is 15 C and
the pressure is 100kPa, its volume
increases to 550cm3. Calculate the
pressure on the bubble when it was at the
bottom of the lake.

38. 8 C = 281 K
15 C = 288 K

42. have
Temperature
Volume
Pressure
Amount

43. have
Temperature
Volume
Pressure
Amount

44. Amount
(n)

45. Amount
(n)
measured in
moles
(mol)

46. movie

47. n
n
n
n

48. n
P
n
P
n
P
nP

49. P
n

51. QUESTION

52. Question
1 mole of gas at 101,3 kPa and 273
K has a volume of 22,4 dm3. What
is the volume of 5 moles of gas at
120 kPa and 280 K?

57. Standard Temperature: 273 K
Standard Pressure: 101,3 kPa

58. STP
Standard Temperature: 273 K
Standard Pressure: 101,3 kPa

59. STP
Standard Temperature: 273 K
Standard Pressure: 101,3 kPa
Volume of 1 mole of any gas at STP: 22,4 dm3

65. PV = nRT
GENERAL GAS EQUATION

66. Universal Gas Constant
R = 8,3 J • mol-1 • K-1

67. Universal Gas Equation
PV = nRT

71. 1 000 Pa = 1 kPa

72. 1 m3 = 1 000 dm3

73. 1 000 Pa = 1 kPa
1 m3 = 1 000 dm3

79. Universal Gas Constant

80. Universal Gas Constant

81. QUESTION

82. Question
What is the volume of 5 moles of
gas at 120 kPa and 280 K?

87. SI units
P : Pa
T:K
V : m3
n : mol

88. Question
What is the volume of 5 moles of
gas at 120 kPa and 280 K?

89. 120 kPa = 120 000 Pa

96. QUESTION

97. Question
A sample of nitrogen gas has a mass of
7 g and a volume of 5,6 dm3 at a
temperature of 27 °C. Calculate the
pressure of the gas.

98. PV = nRT

100. N2 (g)

101. N2
M = 2(14)g•mol-1
-1
M = 28 g•mol

104. T = 27 + 273 = 300 K