Implement Bellford Man algorithm in Javascript where the use.pdf

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Implement Bellford Man algorithm in Javascript where the user would be able to change the nodes (add/remove vertex, add/remove edges) and you must be able to visualize on interface. You can use the basic HTML/CSS/Javascript to build a simple a interface and execute bellford man algorithm. Please attach screenshots below for the answers as well..

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In 2010 the Pew Research Center reported that teenagers send on average 50 text messages every day. A researcher suspects this number is out of date, and wishes to determine if teens are sending fewer texts than they used to. A random sample of 25 teens were found to be sending an average of 47.75 texts per day, with a standard deviation of 15. Testing at 10% significance and stating the null and alternative hypothesis, what can the researcher conclude?.

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Implement special cases here: (define (delete t v) (let ((path (find t v))) (cond (( empty? t ) ) ((empty? (bst-root t)) ) ((not ( = v (node-value (car path))) ) (( > (node-count (car path)) 1) decrement count) ((equal? (car path) (bst-root t)) ;node were trying to delete (cond ; nest conditiona; ( (let-AND right (car path) empty) ; case 0.1 root <- null ((let-root empty, right empty) ; case 1 root <- left car path ; case 1.1 ((left-empty, right not empty) ; case 1.2 root <- right car path (else (delete-node path)) (else (delete-node path)) ) ) ) ) ) ) ) ) ) Special cases Top-Level Function: Delete Value from BST: (delete t v) The first parameter t is a reference to a bst, and the second parameter v is a value to find and delete. Like the insert function, delete will directly resolve a few special cases. For the general cases, it will call (find t v) to obtain a list of nodes that represent a path from the root to the node to be deleted, and will then call a helper function (delete-node path) to handle the rest of the work. In the case of delete the helper function will further rely on secondary helper functions to resolve cases and subcases. Deletion logically breaks down into cases based on how many child nodes the node to delete has. Each of those cases has subcases. The large number of cases implies the need for a correspondingly larger set of test cases: a test case to trigger each deletion case. Delete Cases Before we look at the detailed code for delete in Racket, lets look at the general approach. As for some of the other functions, it will be convenient to create a top-level function (delete t v) and several helper functions that manage specific detailed cases. There will be some initial special cases that should be managed separately, before launching any lower level helper function. Special cases for (delete t v): Tree t is empty: end the function because there is nothing to do. At this point, call (find t v) to create the path from root to node to delete if it is present. Assume the list returned is bound to a symbol named path. The node of interest will be the first node in the list: (car path) By examining node (car path), you can determine if the value to delete is present or not. Value v is not in the tree: end the function because there is nothing to do. Value v is in the tree: o Is the count field > 1? Dont delete the node, simply decrement its count field. o Is the count field = 1? In this case, we must move forward to actually delete the node. Is the node to delete the root of the tree? Does the node have 0 or 1 child nodes? This corresponds to delete cases 0.1, 1.1, and 1.2. Delete the node and update the root of the tree. o If we reach this pointvalue v is in the tree, count field is 1, node is not the root if it has 0 or 1 child nodes then the general delete case applies, call (delete-node path) The remaining delete cases will be covered by the (delete-node path) helper function. Some general considerations for node n (.

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