Find the domain of the function. (Enter your answer using interval no.pdf

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Find an equation of the line through (-6, 10), parallel to the line with equation 3x - 7y = 14. Write the new equation in point-slope form. Convert the equation of the new line found in problem #14 to standard form, Ax + By = C, where A, B, and C are integers. Solution 14) Given line is 3x-7y =14 7y = 3x-14 y = (3/7)x - 2 It is of the form, y = mx + c Hence, slope = 3/7 We know that two parallel lines have same slope. Hence, The equation parallel to 3x-7y =14 has slope equal to 3/7. Hence, the required line passing through (-6,10) and parallel to 3x-7y=14 in slope-point form is slope point formula is y-y1= m (x-x1) y-10 = (3/7) (x+6) 15) From 14) , y-10 = (3/7) (x+6) 7y-70 = 3x+18 3x-7y = -88 It is of the form Ax + By = C.

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Find the domain of the function. (Enter your answer using interval notation.) f(x) = 1/4x - 20
Solution
Dear Student
Thank you for using Chegg !!
given
f(x) = 1/ (4x -20)
The funcyttion shall have definite values for all values of x except when 4x -20 =0
i.e. when x = 5
Therefore the domain of the given function is
= (-Inf, 5) U (5 , Inf) ..................................

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Why is it helpful to approach the marketing research process from a \"backward” approach? How can this backward approach lead to more useful research findings? Solution Backward approach in marketing design helps to analyse each stage properly and determines what comes after it. This will also give more control over realistic market picture rather than just historical data analysis. This gives more sensitive information from the end users and can work backward to integrate the necessary things more precisely.The backward approach will help the researchers to design the outcome more better so that they can define the problem statement more precisely. The backward approach avoids the usual glitches in research as it has more control over the end outcomes and can guide the researcher with more rational support. This will also reduce the overall time taken for data interpretation and give better control over classification of relevenat information and creating value added insights.Thys backward approach will help to guide the research forward and it is all about what it is required and what they need from the study so that routemap will be clear for all data collection sampling and processing..

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What process causes plant ion-uptake to acidify soil? What soil pH range generally promotes the greatest availability of cations? Solution The process that causes plant ion-uptake to acidify soil is known as soil acidification. It is a process by which the soil pH decreases over time without producing any visible signs. Slow soil acidification occurs under natural conditions over thousands of years, with high rainfall areas most affected, whereas, rapid acidification occurs over a few years under intensive agricultural practices. Soil acidification affects the surface and the subsoil simultaneously. However, areas that remain unaffected by industrial pollution, there soil acidification is mainly caused by the release of protons (H+) during the oxidation of carbon (C), sulphur (S) and nitrogen (N) compounds in soils. During nitrogen cycling, the major processes leading to acidification consists of the cation imbalance over anion during uptake in the rhizosphere of plants, during nitrification from fixation or from the fertilizers, and during the removal of plant and animal products by leaching. The uptake of excess cations over anions by plants results in the acidification of the rhizosphere which is a “localized” effect and can be balanced by the release of hydroxyl (OH-) ions during subsequent plant decomposition. Soils are considered acidic below a pH of 5, and alkaline above a pH of 7.5 and very alkaline above a pH of 8. It has been observed that the “ideal” soil pH is close to neutral, which fall within a range from a slightly acidic pH of 6.5 to slightly alkaline pH of 7.5. It has been determined that most plant nutrients are optimally available to plants within this range helpful for plant root growth. However, Nitrogen (N), Potassium (K), and Sulfur (S) are major plant nutrients that enhance plant growth and development. Most of the plant nutrients (cations) tend to be less available when soil pH is above 7.5, and are optimally available at a slightly acidic pH in the range of 6.5 to 6.8..

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We learned the various design reviews during the application life cycle. What is the role of DBA in each review stage? Who, other than DBA, should be involved at each stage and why? Do you think some of the design reviews may need to be reviewed again as a result of application development? Why or why not? Solution Design reviews are an important factor of the system development lifecycle for database applications. It is during the design review that all aspects of the database and application code are reviewed for efficiency, effectiveness, and accuracy. It is imperative that all database applications, regardless of their size, are reviewed to assure that the application was design properly, efficient coding techniques were used, and the database is accessed and modified correctly and efficiently. The design review is an important process for checking the validity of design decisions and correcting errors before applications and databases are promoted to production status. Multiple design reviews should be conducted throughout the application’s life. There are seven basic design review phases for a database application: There are many aspects of the development process and its resulting application that are addressed by design reviews. Some of the areas that can be addressed by a design review include: The DBA usually must act as the center point for organizing and conducting design reviews. If the DBA does not organize design reviews it is unlikely that any design review will be conducted. And if design reviews are not conducted, the application is more apt to suffer performance and availability problems in a production environment. A group consisting of subject matter experts and the developer’s peers and co-workers should conduct each design review. Formal design review roles should include the leader, the scribe, the mediator, and the participants. The leader can change from one design review to the next, but within the scope of a single design review a single leader must be assigned. The primary role of the leader is to act as a master of ceremonies to keep the review process moving along. Other duties include creating an agenda and ensuring that the agenda is followed, engaging all participants of the design review to solicit everyone’s input, ensuring that all participants maintain proper decorum, working with the proper participants before the meeting to ensure that all required documentation will be made available for the design review, and any other tasks necessary to ensure a successful design review. Though it is not mandatory, the DBA typically acts as the leader of design reviews for applications using a database. Thank you..

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Investment Advisors, Inc., is a brokerage firm that manages stock portfolios for a number of clients. A particular portfolio consists of U shares of U.S. Oil and H shares of Huber Steel. The annual return for U.S. Oil is $3 per share and the annual return for Huber Steel is $5 per share. U.S. Oil sells for $25 per share and Huber Steel sells for $50 per share. The portfolio has $80,000 to be invested. The portfolio risk index (0.50 per share of U.S. Oil and 0.25 per share for Huber Steel) has a maximum of 700. In addition, the portfolio is limited to a maximum of 1000 shares of U.S. Oil. The linear Optimal Objective Value = 8400.00000 Solution a. U for U.S. Oil (decision variable) = 800H for Huber Steel (decisions variable) = 1200so then $25 per share x 800U = $20,000+ $50 per share x 1200H = $60,000Total $ 80,000Constraint 1is binding in this problem because the sensitivity report shows no slack AND,therefore, we know that the optimal solution requires us to use all $80,000 of the available funds.Constraint 2is also binding because the report shows no slack and that in turn tells us that wereached the risk maximum of 700 shares.Constraint 3is non-binding because of the slack (or 200 units) but also and more directly,because we won\'t ever need to use all 1000 shares allowed.Estimated Annual Return= $8400 in profit by purchasing 800 shares of U and 1200 sharesof H. In order to max out our objective function to $8,400 in profit, we need only purchase 800(not 1000) of these shares. b. Constraints 1 and 2.All funds available are being utilized and the maximum permissiblerisk is being incurred.Constraint 1is binding in this problem because the sensitivity report shows no slack AND,therefore, we know that the optimal solution requires us to use all $80,000 of the available funds.Constraint 2is also binding because the report shows no slack and that in turn tells us that wereached the risk maximum of 700 shares.

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