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Lesson 51
Operations & Composition Functions
                              Text: Chapter 3, section 9


 A function is a relationship between x and y in which each x-value has
  exactly one y-value.

 X-values are the input or the domain of the function and the y-values are
  outputs or range of the function.

 Functions are written this way:

                                  f ( x)  x 2  1
          If f ( x)  x 2  1 ,            then f (2)  (2) 2  1
                                                      5

This is the point (2, 5). Any x-value from the domain will result in another
point.

 REMEMBER – the vertical line test to check if a graph is a function.

 Operations of Functions:

          ( f  g )( x)  f ( x)  g ( x)

          ( f  g )( x)  f ( x)  g ( x)

          ( f  g )( x)  f ( x) g ( x)

           f       f ( x)
             x         , g ( x)  0
          g        g ( x)

 The domains of these functions are restricted to the intersection of the
  domains of f ( x) and g ( x) .
Example:
If        f ( x)  x 2  5 x  2
          g ( x)  3x  4

Find:
A) ( f  g )( x)
B) ( f  g )( x)
C) ( f  g )( x)

Solution:
A)     ( f  g )( x)  f ( x)  g ( x)
                         ( x 2  5 x  2)  (3x  4)
                         x2  8x  6

B)        ( f  g )( x)  f ( x)  g ( x)
                         ( x 2  5 x  2)  (3x  4)
                         x2  2 x  2

C)        ( f  g )( x)  f ( x) g ( x)
                         ( x 2  5 x  2)(3x  4)
                          3x 3  19 x 2  26 x  8

Composition of a function:
      The composition of a function f and g, is written as ( f  g )( x) and is defined
       as f ( g ( x)) .

      The function g is substituted into the function f.

Example:

If f ( x)  x  1 and g ( x)  x  2 find f ( g (2))

g (2)  (2)  2                f (4)  (4)  1
      =4                              =3

 f ( g ( x))  f ( x  2)
              ( x  2)  1
              x 1
( g  f )( x)  g ( f ( x))
               g ( x  1)
               ( x  1)  2
               x 1

Usually ( f  g )( x)  ( g  f )( x)




                  Assignment: Exercise 51 Q 1 to 17

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Lesson 51

  • 1. Lesson 51 Operations & Composition Functions Text: Chapter 3, section 9  A function is a relationship between x and y in which each x-value has exactly one y-value.  X-values are the input or the domain of the function and the y-values are outputs or range of the function.  Functions are written this way: f ( x)  x 2  1 If f ( x)  x 2  1 , then f (2)  (2) 2  1 5 This is the point (2, 5). Any x-value from the domain will result in another point.  REMEMBER – the vertical line test to check if a graph is a function.  Operations of Functions: ( f  g )( x)  f ( x)  g ( x) ( f  g )( x)  f ( x)  g ( x) ( f  g )( x)  f ( x) g ( x)  f  f ( x)    x  , g ( x)  0 g g ( x)  The domains of these functions are restricted to the intersection of the domains of f ( x) and g ( x) .
  • 2. Example: If f ( x)  x 2  5 x  2 g ( x)  3x  4 Find: A) ( f  g )( x) B) ( f  g )( x) C) ( f  g )( x) Solution: A) ( f  g )( x)  f ( x)  g ( x)  ( x 2  5 x  2)  (3x  4)  x2  8x  6 B) ( f  g )( x)  f ( x)  g ( x)  ( x 2  5 x  2)  (3x  4)  x2  2 x  2 C) ( f  g )( x)  f ( x) g ( x)  ( x 2  5 x  2)(3x  4)  3x 3  19 x 2  26 x  8 Composition of a function:  The composition of a function f and g, is written as ( f  g )( x) and is defined as f ( g ( x)) .  The function g is substituted into the function f. Example: If f ( x)  x  1 and g ( x)  x  2 find f ( g (2)) g (2)  (2)  2  f (4)  (4)  1 =4 =3 f ( g ( x))  f ( x  2)  ( x  2)  1  x 1
  • 3. ( g  f )( x)  g ( f ( x))  g ( x  1)  ( x  1)  2  x 1 Usually ( f  g )( x)  ( g  f )( x) Assignment: Exercise 51 Q 1 to 17