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# Dividing Polynomials Slide Share

## by Kristen T, Instructional Technologist at University on Dec 05, 2007

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I have added to the original presentation in response to one of the comments.... the result of 'x' is correct on slide 7, take a look at the new version of this ppt to clear up any confusion about ...

I have added to the original presentation in response to one of the comments.... the result of 'x' is correct on slide 7, take a look at the new version of this ppt to clear up any confusion about why...

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## Dividing Polynomials Slide SharePresentation Transcript

• Dividing polynomials This PowerPoint presentation demonstrates two different methods of polynomial division. © Kristen A. Treglia 2007
• Algebraic long division Divide 2 x ³ + 3 x ² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend
• Algebraic long division First divide the first term of the dividend, 2 x ³, by x (the first term of the divisor). This gives 2x². This will be the first term of the quotient.
• Algebraic long division Now multiply 2x² by x + 2 and subtract
• Algebraic long division Bring down the next term, - x .
• Algebraic long division Now divide – x ², the first term of – x ² - x , by x , the first term of the divisor which gives – x .
• Algebraic long division Multiply –x by x + 2 To get a result of:
• Algebraic long division Now subtract ** remember, you must subtract both the –x 2 term and the -2x term
• Algebraic long division Now combine like terms (since we subtracted two negative terms they both turned into positive terms) {
• Algebraic long division Bring down the next term, 1
• Algebraic long division Divide x , the first term of x + 1, by x , the first term of the divisor which gives 1
• Algebraic long division Multiply x + 2 by 1 and subtract
• Algebraic long division The remainder is –1. The quotient is 2x² - x + 1