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Pada saat atlet angkat besi mengangkat beban, sebetulnya ia sedang 
melakukan kerja pada beban yang disimpan sebagai energi potensial. 
67 
Bab 
3 
Usaha, Energi, dan Daya 
A. Gaya Dapat 
Melakukan Usaha 
B. Energi dan Usaha 
C. Gaya Konservatif dan 
Hukum Kekekalan 
Energi Mekanik 
D. Daya 
Hasil yang harus Anda capai: 
menganalisis gejala alam dan keteraturan dalam cakupan mekanika benda titik. 
Setelah mempelajari bab ini, Anda harus mampu: 
5A79 B171C 492DCD8;1 =1DB91 411= =51;D;1 1;C9E9C1BH1 
B581A9	81A9
 1H1; 1;C9E9C1B	1;C9E9C1B @A9=5A =1DB91 H17 =5=2DCD8	 
;1 55A79 B5@5AC9 =5=1B1; =53D39 @1;191 41 B521719 BD=25A 
@55A171 @141 =11= 81A9
 ,519 1;C9E9C1B @A9=5A 21H1; 1;C9E9C1B 
19H1H17=5=2DCD8;155A79491C1A1H1?18A171
*141 71=21A 49 
1C1B B5?A17 1C5C B5417 =5717;1C 2521 H17 B171C 25A1C
 C5C 
C5AB52DC 81ADB 41@1C =57D;DA 1@1;18 91 =1=@D 1C1D C941; =5717;1C 
2521 C5AB52DC
 ,51=1 @A?B5B 1C981 1C5C C5AB52DC 81ADB =5789CD7 
25A1@121H1;;1?A9H1781ADB91;?BD=B9BD@1H1 411=@5A?=21191 
41@1C =5717;1C 2521 H17 49979;1
 
11= 212 99 1;1 492181B C5C17 DB181 55A79 41H1 41 
8D2D71 1C1A1 ;5C971H1
 %?B5@  9B9;1 C5C17 DB181 55A79 41 
41H1 99 21H1; B5;19 1@9;1B9H1 411= ;5894D@1 B581A9	81A9
 
Sumber: Fundamentals of Physics, 2001 
• menganalisis hubungan antara usaha, perubahan energi dan hukum 
kekekalan energi mekanik; 
• menerapkan hukum kekekalan energi mekanik untuk menganalisis gerak 
dalam kehidupan sehari-hari.
(%(.6//(/2(.$,$3+-104(24$*$0(3)+'$0$:$-(3,$-$0.$*41$.41$.%(3+-65'$.$/%6-6.$5+*$0 
A. Gaya Dapat Melakukan Usaha 
71A 41 5298 =5=181=9 @575AC91 DB181 411= ;5894D@1 
B581A9	81A9 @51:1A9 =1C5A9 25A9;DC 99
 
1. Pengertian Usaha 
*141B11C49;51B4125ADB181251:1A=1;B9=1DCD;=5=@5A?58 
919C9779
%5C9;1251:1A41=577D1;1C517141@9;9A1
11= 
;5894D@1 B581A9	81A9 DB181 4945699B9;1 B521719 @5;5A:11 H17 
491;D;1 DCD; =5=@5A?58 CD:D1 H17 49979;1
 '5DADC 41 
1@1;18@575AC91DB181411=69B9;1B1=14571@575AC91DB181411= 
;5894D@1 B581A9	81A9 C5AB52DC .B181 411= 69B9;1 B51D 25A8D2D71 
4571 CA1B65A 55A79 41 71H1
 ,9=1;18 3?C?8 25A9;DC
 ,52D18 =?29 
=?7?;494?A?7?58-?71A457171H1B589771=?2925A@9418C5=@1C 
B5:1D8 4 41A9 @?B9B9 1F1H1
 %5C9;1 -?71A =54?A?7 =?29 C5AB52DC 
B589771=?2925A75A1;-?71A=51;D;1DB181H19CD=5CA1B65A55A79 
=51D9 71H1 4?A?7 @141 =?29 B589771 =?29 25A75A1; 41 25A@9418 
B5:1D8 4
 5B1A DB181  H17 491;D;1 -?71A DCD; =54?A?7 =?29 
?58 71H1 B1=1 4571 81B9 ;19 71H1  4571 @5A@94181 4
 
F 
68 Mudah dan Aktif Belajar Fisika untuk Kelas XI 

4 K
 
%5C5A171 
 
 DB181 :?D5 
  71H1 ( 
4  @5A@94181 = 
.B181 14118 25B1A1 B;11A F11D@D 71H1  41 @5A@94181 4 
=5AD@1;1 E5;C?A
 '5DADC @5A;191 E5;C?A 
 81B9H1 81ADB 25AD@1 
B;11A
.B181H17491;D;1?5871H1;?BC1H17=5=25CD;BD4DC 
  C5A8141@ 1A18 @5A@94181 2541 B5@5AC9 C5A981C @141 $/%$3 
	 
25B1A DB181H1 14118 

,3?B K 
/5;C?A  41@1C 49DA19;1 =5:149 4D1 ;?=@?5 71H1 H17 B197 
C571;DADBH19CD;?=@?53?B H17B51A1845711A18@5A@94181 
2541 41  B9  H17 C571; DADB 4571 1A18 @5A@94181
 -5AH1C1 
81H1;?=@?571H1H17B51A184571@5A@94181H17=5781B9;1 
DB181 H19CD B525B1A  , 3?B 
 5A9;DC 99 2525A1@1 ;51411 9BC9=5F1 
H17 4981B9;1 (34$/$$0 
;	
 
1
J 
.CD;
J 1A18 71H1 B51A18 4571 1A18 @5A@94181 B589771 
49@5A?58 

,3?B
J 

, K 

 $51B;145712181B141B549A9@575AC91DB181 
4155A79
 

 @1;18 @141 B52D18 2?1 H17 1;1 49C5417 
C5A41@1C55A79@?C5B91 
Gambar 3.1 
Togar melakukan usaha(W) dengan 
mentransfer energi melalui gaya 
dorong F sehingga mobil berpindah 
sejauh s. 
F 
s 

 ,52DC;1 3?C?8	3?C?8 @55A1@1 D;D= 
%5;5;115A79H1714149B5;9C1A41
 

 @1@5A2541141H14155A79 
Tes Kompetensi Awal 
Gambar 3.2 
(a) Usaha oleh gaya F yang 
membentuk sudut  terhadap 
perpindahan benda s. 
(b) Penguraian vektor F menjadi 
komponen-komponennya. 
F sin 
F cos 
2 
 
arah perpindahan 
F 
s 
 
1
w 
F 
Usaha, Energi, dan Daya 69 
,52D1871H1C5C1@B525B1A(25;5A:1@141B52D182541H1725A=1BB1;7
$9;1 
BD4DCH174925CD;1C1A171H1412941741C1A14118J25A1@1DB181H17 
491;D;171H19CDC5A8141@2541B51=145C9; 
$8$% 
9;5C18D9 (';7 J
 
), ' 
 
  3?B 
' 
  
(3?B  
;7 
 
=B 
2
J 
.CD;
J 1A18 71H1  C571; DADB 4571 1A18 @5A@94181 
B589771 49@5A?58 

,3?B
J
K 
$9;1
25A1AC9 71H1 C5AB52DC C941; =51;D;1 DB181
 571 
;1C1 19 71H1 H17 C571; DADB 4571 1A18 @5A@94181 2541 
1AC9H1 71H1 C5AB52DC C941; =51;D;1 DB181
 
3
J 
%51411 99 =5H1C1;1 218F1 1A18 71H1 25A1F11 4571 1A18 
@5A@94181 B589771 49@5A?58 

,3?B
J 

,K
 

4, K 
?C?8 DB181 571C96 H19CD B5?A17 @57541A1 B5@541 H17 B5417 
=5=13D B5@541H1 C921	C921 =575A5= B5@541H1
 .B181 H17 
491;D;1 ?58 71H1 75B5; H17 C5A:149 1C1A1 ;54D1 21 B5@541 
4571 :11 25A919 571C96 ;1A51 71H1 75B5; 25A1F11 1A18 
4571 1A18 @5A@94181 B5@541
 5B1AH1 DB181 571C96 C5AB52DC 
B521497457171H175B5;41@5A@94181H1749C5=@D8B5@541 
B51=171H175B5;25;5A:1
57145=9;91B5@541=5711=975A1; 
49@5A1=21C
 
4
 *5A@94181 2541,
*141 $/%$3 

  149 B5417 25A49A9 B1=29 =57754?7 C1B
 -1B 
C5AB52DC =5=99;9 71H1 25A1C B525B1A 0 4571 1A18 ;5 21F18
 5B1A 
71H1 C1A9; C19 C1B ?58 @D77D7  149  B1=1 4571 25B1A 71H1 
25A1C C1B 8 B589771 C1B 411= ;51411 B5C9=217
 !1H1 A51;B9 ;5 
1C1B?58@D77D7 149@141C19C1BC5AB52DCC941;4989CD7B521719 
DB181;1A51C941;141@5A@94181@141C1B1;921C71H1A51;B9
1A9 
(34$/$$0 
;	 4941@1C;1 218F1 
 
,3?B
3?B
?C?81914118B5?A1711;H1725AB141A@14149497$/%$3 


 9497 C941; 25A75B5A ;1A51 71H1 H17 491;D;1H1 C941; 
3D;D@ ;D1C DCD; =5775B5A 49497
 571 45=9;91 DB181 H17 
491;D;1 ?58 71H1 4?A?7H1 B1=1 4571 ?
 
*5AD 41 ;5C18D9 B1CD1 DB181 14118 :?D5 49B97;1C $ -. 
$). # #(#,#%( ,!# ,+ ., 2(! #%.%( ) !2 ,,+ ,-. 
(0-)( .(-.% ''#(%( ( ,$. ,-. '-+
 
F 
Gambar 3.3 
Fadli sedang menggendong tas. 
Gambar 3.4 
Seorang anak sedang bersandar 
pada dinding. 
Contoh 3.1 
F 
F cos 
 
s
Contoh 3.2 
,52D18254125A=1BB1;7C5A5C1;491C1B2941741C1A;1B1A4571;?569B95 
75B5;;95C9;
541C5AB52DC49C1A9;B5:1D8=5C5A45711:DC5C1@
5A1@1;18 
DB181H174981B9;1?5871H1C1A9;C5AB52DC:9;1C1A9;1H1B5:1:1A45711C19 
49;5C18D9!
=B 
$8$% 
9;5C18D9 ';7 , = 
 ;
=B 
5B1AH1DB181?5871H1C1A9;14118 
 4
3?B , 
)58;1A51
3=1;125B1ADB18114118 
 , 
5B1A71H1=1B9825D=49;5C18D9
 
)58;1A511:D2541C5C1@=1;125B1AA5BDC171H1
14 %
@141BD=2D-1 
41 240
@141BD=2D-2 
B589771 
3?B

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Bahare Shariat Jild 2 By SadurshSharia Mufti Amjad Ali Azmi
 

Bab 3 kls xi

  • 1. Pada saat atlet angkat besi mengangkat beban, sebetulnya ia sedang melakukan kerja pada beban yang disimpan sebagai energi potensial. 67 Bab 3 Usaha, Energi, dan Daya A. Gaya Dapat Melakukan Usaha B. Energi dan Usaha C. Gaya Konservatif dan Hukum Kekekalan Energi Mekanik D. Daya Hasil yang harus Anda capai: menganalisis gejala alam dan keteraturan dalam cakupan mekanika benda titik. Setelah mempelajari bab ini, Anda harus mampu: 5A79 B171C 492DCD8;1 =1DB91 411= =51;D;1 1;C9E9C1BH1 B581A9 81A9 1H1; 1;C9E9C1B 1;C9E9C1B @A9=5A =1DB91 H17 =5=2DCD8 ;1 55A79 B5@5AC9 =5=1B1; =53D39 @1;191 41 B521719 BD=25A @55A171 @141 =11= 81A9 ,519 1;C9E9C1B @A9=5A 21H1; 1;C9E9C1B 19H1H17=5=2DCD8;155A79491C1A1H1?18A171 *141 71=21A 49 1C1B B5?A17 1C5C B5417 =5717;1C 2521 H17 B171C 25A1C C5C C5AB52DC 81ADB 41@1C =57D;DA 1@1;18 91 =1=@D 1C1D C941; =5717;1C 2521 C5AB52DC ,51=1 @A?B5B 1C981 1C5C C5AB52DC 81ADB =5789CD7 25A1@121H1;;1?A9H1781ADB91;?BD=B9BD@1H1 411=@5A?=21191 41@1C =5717;1C 2521 H17 49979;1 11= 212 99 1;1 492181B C5C17 DB181 55A79 41H1 41 8D2D71 1C1A1 ;5C971H1 %?B5@ 9B9;1 C5C17 DB181 55A79 41 41H1 99 21H1; B5;19 1@9;1B9H1 411= ;5894D@1 B581A9 81A9 Sumber: Fundamentals of Physics, 2001 • menganalisis hubungan antara usaha, perubahan energi dan hukum kekekalan energi mekanik; • menerapkan hukum kekekalan energi mekanik untuk menganalisis gerak dalam kehidupan sehari-hari.
  • 2. (%(.6//(/2(.$,$3+-104(24$*$0(3)+'$0$:$-(3,$-$0.$*41$.41$.%(3+-65'$.$/%6-6.$5+*$0 A. Gaya Dapat Melakukan Usaha 71A 41 5298 =5=181=9 @575AC91 DB181 411= ;5894D@1 B581A9 81A9 @51:1A9 =1C5A9 25A9;DC 99 1. Pengertian Usaha *141B11C49;51B4125ADB181251:1A=1;B9=1DCD;=5=@5A?58 919C9779 %5C9;1251:1A41=577D1;1C517141@9;9A1 11= ;5894D@1 B581A9 81A9 DB181 4945699B9;1 B521719 @5;5A:11 H17 491;D;1 DCD; =5=@5A?58 CD:D1 H17 49979;1 '5DADC 41 1@1;18@575AC91DB181411=69B9;1B1=14571@575AC91DB181411= ;5894D@1 B581A9 81A9 C5AB52DC .B181 411= 69B9;1 B51D 25A8D2D71 4571 CA1B65A 55A79 41 71H1 ,9=1;18 3?C?8 25A9;DC ,52D18 =?29 =?7?;494?A?7?58-?71A457171H1B589771=?2925A@9418C5=@1C B5:1D8 4 41A9 @?B9B9 1F1H1 %5C9;1 -?71A =54?A?7 =?29 C5AB52DC B589771=?2925A75A1;-?71A=51;D;1DB181H19CD=5CA1B65A55A79 =51D9 71H1 4?A?7 @141 =?29 B589771 =?29 25A75A1; 41 25A@9418 B5:1D8 4 5B1A DB181 H17 491;D;1 -?71A DCD; =54?A?7 =?29 ?58 71H1 B1=1 4571 81B9 ;19 71H1 4571 @5A@94181 4 F 68 Mudah dan Aktif Belajar Fisika untuk Kelas XI 4 K %5C5A171 DB181 :?D5 71H1 ( 4 @5A@94181 = .B181 14118 25B1A1 B;11A F11D@D 71H1 41 @5A@94181 4 =5AD@1;1 E5;C?A '5DADC @5A;191 E5;C?A 81B9H1 81ADB 25AD@1 B;11A .B181H17491;D;1?5871H1;?BC1H17=5=25CD;BD4DC C5A8141@ 1A18 @5A@94181 2541 B5@5AC9 C5A981C @141 $/%$3 25B1A DB181H1 14118 ,3?B K /5;C?A 41@1C 49DA19;1 =5:149 4D1 ;?=@?5 71H1 H17 B197 C571;DADBH19CD;?=@?53?B H17B51A1845711A18@5A@94181 2541 41 B9 H17 C571; DADB 4571 1A18 @5A@94181 -5AH1C1 81H1;?=@?571H1H17B51A184571@5A@94181H17=5781B9;1 DB181 H19CD B525B1A , 3?B 5A9;DC 99 2525A1@1 ;51411 9BC9=5F1 H17 4981B9;1 (34$/$$0 ; 1
  • 4. J 1A18 71H1 B51A18 4571 1A18 @5A@94181 B589771 49@5A?58 ,3?B
  • 5. J , K $51B;145712181B141B549A9@575AC91DB181 4155A79 @1;18 @141 B52D18 2?1 H17 1;1 49C5417 C5A41@1C55A79@?C5B91 Gambar 3.1 Togar melakukan usaha(W) dengan mentransfer energi melalui gaya dorong F sehingga mobil berpindah sejauh s. F s ,52DC;1 3?C?8 3?C?8 @55A1@1 D;D= %5;5;115A79H1714149B5;9C1A41 @1@5A2541141H14155A79 Tes Kompetensi Awal Gambar 3.2 (a) Usaha oleh gaya F yang membentuk sudut terhadap perpindahan benda s. (b) Penguraian vektor F menjadi komponen-komponennya. F sin F cos 2 arah perpindahan F s 1
  • 6. w F Usaha, Energi, dan Daya 69 ,52D1871H1C5C1@B525B1A(25;5A:1@141B52D182541H1725A=1BB1;7 $9;1 BD4DCH174925CD;1C1A171H1412941741C1A14118J25A1@1DB181H17 491;D;171H19CDC5A8141@2541B51=145C9; $8$% 9;5C18D9 (';7 J ), ' 3?B ' (3?B ;7 =B 2
  • 8. J 1A18 71H1 C571; DADB 4571 1A18 @5A@94181 B589771 49@5A?58 ,3?B
  • 9. J
  • 11. 25A1AC9 71H1 C5AB52DC C941; =51;D;1 DB181 571 ;1C1 19 71H1 H17 C571; DADB 4571 1A18 @5A@94181 2541 1AC9H1 71H1 C5AB52DC C941; =51;D;1 DB181 3
  • 12. J %51411 99 =5H1C1;1 218F1 1A18 71H1 25A1F11 4571 1A18 @5A@94181 B589771 49@5A?58 ,3?B
  • 13. J ,K 4, K ?C?8 DB181 571C96 H19CD B5?A17 @57541A1 B5@541 H17 B5417 =5=13D B5@541H1 C921 C921 =575A5= B5@541H1 .B181 H17 491;D;1 ?58 71H1 75B5; H17 C5A:149 1C1A1 ;54D1 21 B5@541 4571 :11 25A919 571C96 ;1A51 71H1 75B5; 25A1F11 1A18 4571 1A18 @5A@94181 B5@541 5B1AH1 DB181 571C96 C5AB52DC B521497457171H175B5;41@5A@94181H1749C5=@D8B5@541 B51=171H175B5;25;5A:1 57145=9;91B5@541=5711=975A1; 49@5A1=21C 4 *5A@94181 2541,
  • 14. *141 $/%$3 149 B5417 25A49A9 B1=29 =57754?7 C1B -1B C5AB52DC =5=99;9 71H1 25A1C B525B1A 0 4571 1A18 ;5 21F18 5B1A 71H1 C1A9; C19 C1B ?58 @D77D7 149 B1=1 4571 25B1A 71H1 25A1C C1B 8 B589771 C1B 411= ;51411 B5C9=217 !1H1 A51;B9 ;5 1C1B?58@D77D7 149@141C19C1BC5AB52DCC941;4989CD7B521719 DB181;1A51C941;141@5A@94181@141C1B1;921C71H1A51;B9 1A9 (34$/$$0 ; 4941@1C;1 218F1 ,3?B
  • 15. 3?B
  • 16. ?C?81914118B5?A1711;H1725AB141A@14149497$/%$3 9497 C941; 25A75B5A ;1A51 71H1 H17 491;D;1H1 C941; 3D;D@ ;D1C DCD; =5775B5A 49497 571 45=9;91 DB181 H17 491;D;1 ?58 71H1 4?A?7H1 B1=1 4571 ? *5AD 41 ;5C18D9 B1CD1 DB181 14118 :?D5 49B97;1C $ -. $). # #(#,#%( ,!# ,+ ., 2(! #%.%( ) !2 ,,+ ,-. (0-)( .(-.% ''#(%( ( ,$. ,-. '-+ F Gambar 3.3 Fadli sedang menggendong tas. Gambar 3.4 Seorang anak sedang bersandar pada dinding. Contoh 3.1 F F cos s
  • 19. =B $8$% 9;5C18D9 ';7 , = ;
  • 21. 3=1;125B1ADB18114118 , 5B1A71H1=1B9825D=49;5C18D9 )58;1A511:D2541C5C1@=1;125B1AA5BDC171H1
  • 22. 14 %
  • 25. J4 % B9
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  • 28. =B ( =1;1 , (=$ $149DB181H17491;D;171H1C5AB52DC14118$ Tokoh James Prescott Joule (1824–1907) Sumber: Jendela Iptek, 1997 James Prescott Joule lahir di Salford, Inggris. Ia adalah fisikawan kenamaan Inggris yang berperan dalam perumusan Hukum Kekekalan Energi. Pada 1840, Joule mendeklarasikan sebuah hukum, yang dikenal sebagai Hukum Joule, yaitu tentang panas yang diproduksi dalam konduktor listrik. Untuk menghormati jasa-jasanya, nama Joule digunakan sebagai satuan energi dan usaha. Contoh 3.3 70 Mudah dan Aktif Belajar Fisika untuk Kelas XI F N fk s w , 1 2 - 12 =BB
  • 29. = ,3?B (
  • 30. =
  • 31.
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  • 38.
  • 39. ;7/
  • 43. =BB K=B , - -
  • 44. =BB K=BB
  • 45. =K
  • 46. =
  • 47. = , ;1A511A1871H1B5:1:1A4571@5A@941812541 ',
  • 48.
  • 49. ;7K=B
  • 50. BK
  • 51.
  • 52.
  • 53.
  • 55. ;$
  • 56. F = s F(t) s1 s s2 F Gambar 3.5 Pada besar F konstan, W = luas daerah di bawah kurva F(t). s1 s2 s s s F d s Usaha, Energi, dan Daya 71 , , K 9= , K , 9= 9= , ,5@?C?7 21?; ;1HD H17 =1BB1H1 ;7 C5A5C1;491C1B2941741C1A %5=D491 21?;;1HDC5AB52DC=5711=975A1;DADB H1749B5212;1?5871H1H1725B1AH1 25AD218 D218C5A8141@;54D4D;121?; B5@5AC9C1=@1;@14171=21A -5CD;1C?C1 DB181 H17 491;D;1 71H1 @141 21?; 8977125A@9418B5:1D8= $8$% D1BCA1@5B9D=
  • 57. 40
  • 58. :?D5 D1B
  • 59. ! D1BB579C971 ! !N! NK
  • 60. K
  • 63. K
  • 64. $
  • 65. $ Gambar 3.6 Grafik gaya (F) terhadap perpindahan (s) dengan gaya (F) tidak konstan atau berubah-ubah. F (N) B C D E G A 2 4 5 7 s –40 F Gambar 3.7 Usaha merupakan luas daerah arsir di antara s1 dan s2 pada kurva antara gaya F dan perpindahan s. 2. Menentukan Usaha dari Grafik Gaya Terhadap Perpindahan *141DA191B525D=H171H1H17497D1;125A919;?BC1DCD; =5781B9;1 DB181 @141 2541 H17 25A@9418 B5:1D8 , $9;1 41 =5=2D1C 7A169; C C5A8141@ , @5A@94181 @141 71H1 ;?BC1 41 1;1 =5=@5A?58 7A169; B5@5AC9 @141 $/%$3
  • 66. 5A41B1A;17A169;C5AB52DC25B1ADB181H174981B9;1?5871H1;?BC1 B589771254125A@9418B5:1D84B1=14571D1B415A184921F18 ;DAE1 C .CD; DB181 H17 4981B9;1 71H1 H17 25B1AH1 25AD218 D218 1;1 4941@1C;1 B52D18 7A169; B5@5AC9 @141 $/%$3 D1B 415A18 H17 491AB9A 25A141 49 1C1A1 71A9B BD=2D , 41 71A9B BD=2D .B181C?C1H17C5A:149@141$/%$3 =5AD@1;1@5:D=181 B5C91@ DB181 41A9 , B1=@19 4571 , $149 41@1C 49CD9B;1 -)- , *545;1C1 C5A219; 14118 4571 31A1=5=@5A;539 , B1=@19 =545;1C9?1C1D
  • 68. , -)- , , 1C1D
  • 69. , , , , , , K AC99C57A1@141(34$/$$0 ;14118D1B415A18H17491AB9A 49 1C1A1 ;DAE1 25B1A 71H1 41 25B1A @5A@94181 , Contoh 3.4 s F Kata Kunci • usaha negatif • usaha nol • usaha positif s s1 s2 s F 2 1
  • 70. Tes Kompetensi Subbab A (3,$-$0.$*'$.$/%6-6.$5+*$0 4 –4 B. Energi dan Usaha 89CD718DB181 F (N) 2 4 7 6 8 x (cm) *5A18;18 41 =5981C B55;?A ;D41 H17 B5417 =51A9; 75A?21; H17@5D84571=D1C1%5C9;1;D41B5417=51A9;75A?21;411= F1;CD H17 3D;D@ 1=1 291B1H1 1@1B ;D41 C5A981C C5AB571 B571 '571@1 45=9;91 %D41 C5AB52DC C518 =575D1A;1 55A79 H17 49 7D1;1 DCD; =51;D;1 DB181 571 45=9;91 (+!# ,.-. %''*.( .(-.% '%.%( ., 1. Energi Kinetik dan Teori Usaha-Energi -51841@51:1A9@141BD2212B525D=H1218F1DB18141@1CC5A:149 @14171H1;?BC11C1D71H1H1725AD218 D218%54D1:59BDB181C5AB52DC =5=99;9 ;5B1=11 H19CD 141H1 71H1 H17 25;5A:1 @141 2541 B589771 2541 25A75A1; 1:DH1 ;?BC1 1C1D =5=99;9 @5A35@1C1 ,5;1A17 1;1 492181B ;51411 4571 A5BDC1 71H1 ;?BC1 !1H1 C5AB52DC 25;5A:1 @141 2541 25A=1BB1 ' 41 1;1 =5781B9;1 @5A35@1C1 '5DADC D;D= ## (5FC? 25B1A @5A35@1C1 C5AB52DC 41@D @5AB1=11 25B1A @5A@94181H1 14118 14118 ' - , / / .B181 H17 491;D;1 ?58 71H1 C5AB52DC 14118
  • 71. 72 Mudah dan Aktif Belajar Fisika untuk Kelas XI ,',
  • 72. - ' / / '/ '/ -
  • 74. ( 5A1@1;18 DB181 H17 491;D;1 ?58 71H1 4?A?7171A=5:125A@9418B5:1D8= 5A1@1;18DB181H17491;D;1DCD;=5717;1C B52D18=5B9C9;H17=1BB1H1;789771;5C97791 =!=B ,52D182541H17=1BB1H1;7=5D3DA4571 ;535@1C1
  • 75. =B )58;1A51141@571AD871H1 75B5;1C1A11C19412541254125A85C9B5C518 25A75A1;45C9; -5CD;1DB181H17491;D;1?58 71H175B5;@1412541C5AB52DC ,52D18 2541 25A=1BB1 ;7 49C1A9; ;5 1C1B @141 29417=9A97;1B1A?5871H1
  • 76. (B51A184571 29417 ,D4DC;5=9A97129417C5A8141@8?A9I?C1 14118 C1 B589771 2541 25A@9418 B5:1D8 = $9;1 ;?569B95 75B5;1 1C1A1 2541 457129417
  • 77. 41 C1 H17491;D;1?5871H125A1C4171H175B5;;95C9; ,52D18 71H1 H17 25AD218 D218 25;5A:1 @141 B52D182541B5897712541=5711=9@5AD2181 B5@5AC97A169;@14171=21A25A9;DC 9CD7 DB181 H17 491;D;1 ?58 71H1 @141 2541DCD;:1A1;B5:1D8=
  • 78. Vt V0 F A s B Gambar 3.8 Besar usaha yang dilakukan oleh pengemudi becak sama dengan besar gaya yang bekerja pada becak dikalikan dengan besar perpindahannya. Usaha, Energi, dan Daya 73 41 C518 =575C18D9 218F1 DB181 14118 @A?B5B CA1B65A 55A79 =51D9 71H1 B589771 2541 25A75A1; %5C9;1 2541 25A75A1; 2541 =5=99;9 ;535@1C1 41 =5781B9;1 55A79 ;95C9; 5A41B1A;1 (34$/$$0 ; 55A79 ;95C9; 2541 49H1C1;1 4571 % '/ K
  • 79. %5C5A171 % 55A79 ;95C9; $ ' =1BB1 2541 ;7 / ;51:D1 2541 =B 571 45=9;91 ;4; K $149DB181H174981B9;171H1A5BDC1@141@1AC9;5C5AB52DCB1=1 4571 @5AD2181 55A79 ;95C9; @1AC9;5 ; K (34$/$$0 ; 49;51 4571 C5?A5=1 DB181 55A79 DCD; @1AC9;5 Tugas Anda 3.1 Amatilah perubahan energi yang terjadi di sekitar Anda. Diskusikanlah hal tersebut bersama teman Anda, apakah perubahan energi yang terjadi akan memengaruhi usaha yang dilakukan? Contoh 3.5 ,52D18;55A5725A=1BB1
  • 82. K;7 /
  • 83. 3=B
  • 84. =B % '/ N
  • 85. K;7
  • 86. =B N
  • 88. K$ Contoh 3.6 *1;D25A=1BB17C5A5@1B41A9C171B5?A17CD;17;1HD %5C9;1@1;D=5H5CD8 C118 ;51:D1H1
  • 89. =B $9;1 71H1 75B5; @1;D C5A8141@ C118 B525B1A ( 89CD718;5411=1@1;DH17=5131@411=C118 $8$% 9;5C18D9 ' 7 /
  • 90. =B ( 2 2 2 1 m / / , K N
  • 91. K;7
  • 92. K
  • 93. =B F s , ,
  • 95. =
  • 96. 2. Energi Potensial (+!# *)-(,# (+!# 2(! -+,#'*( * ,.-. ( %#- (-.%(2-%(2-.%((2($#%%(''.(!%#(%((+!# -+,.-*-#'.(.%( ?C?8H1C192DBDAH17B541749C5717;1 *141 ;51411 99 C19 2DBDA =5=99;9 55A79 @?C5B91 $9;1 C19 2DBDA 495@1B;1 11; @118 41@1C C5A5=@1A 4571 :1A1; C5AC5CD 579CD :D71 @141 ;1C1@5 5A79 @?C5B91=D3D ;5C9;1 ;1A5C ;1C1@5 49C5717 ;1 ;5=D491 8917 ;5C9;1 ;1A5C ;1C1@5 495@1B;1 5CD; 55A79 @?C5B91 19 H17 C5A41@1C 49 11= 14118 55A79 @?C5B91 7A1E9C1B9 41 55A79 @?C5B91 @571B a. Energi Potensial Gravitasi 5A79 C941; 41@1C 4939@C1;1 41 C941; 41@1C 49=DB18;1 C5C1@9 41@1C 25AD218 41A9 BD1CD 25CD; =5:149 25CD; H17 19 5=9;91 :D71 55A79 @?C5B91 7A1E9C1B9 H17 B5A97 49C5=D;1 411= ;5894D@1 B581A9 81A9 *5A81C9;1 3?C?8 25A9;DC ,52D18 21CD ;5A9;9 495=@1A;1 B531A1 E5AC9;1 5A79 @?C5B91 C5A25B1A H17 49=99;9 21CD 14118 ;5C9;1 21CD =531@19 ;5C97791 =1;B9=D= ?C?8 19 B52D18 @5B9 H17 C5A5C1; 49 1C1B =5:1 =5=99;9 55A79 @?C5B91 7A1E9C1B9 H17 25B1AH1 B521497 4571 =1BB1 41 C5=@1C ;54D4D;1 @5B9 C5A8141@ 1C19 %5C9;1 @5B9 41B5CD84141291A;1:1CD8;51C1971H125A1C@5B9=51;D;1 DB181 B589771 @5B9 25A@9418 @?B9B9H1 41A9 1C1B =5:1 ;5 1C19 5B1A 55A79 @?C5B91 7A1E9C1B9 H17 49=99;9 2541 2541 @141 3?C?8 49 1C1B 25A71CD7 @141 ;54D4D;1 2541 C5AB52DC C5A8141@ 13D1 C5AC5CD *141 $/%$3 DCD; =5717;1C B55;?A 9;1 H17 25A1CH10B5C9779DB181H17491;D;1*1;,9=2??14118 1A18 71H1 B51A18 @5A@94181 2541 1C1D 49CD9B F h mg y2 74 Mudah dan Aktif Belajar Fisika untuk Kelas XI '! K %5C5A171 ' =1BB1 2541 ;7 ! 25B1A @5A35@1C1 7A1E9C1B9 =B C9779 2541 = 541H1725A141@141;5C9779141A9C9C9;13D1=5=99;955A79 @?C5B91 DCD; =51;D;1 DB181 B525B1A '! $149 2541 =5=99;9 @?C5B91 7A1E9C1B9 H17 25B1AH1 *'! K 6%60)$0 $05$3$ (0(3)+ 215(04+$. )3$7+5$4+ '$0 64$*$ *5A81C9;1$/%$3 A18E5AC9;1;51C1BBD=2D-249C5C1@;1 B521719 1A18 @?B9C96 B5417;1 71H1 7A1E9C1B9 25A1A18 ;5 BD=2D-2 571C96 ;5 21F18 %5C9;1 ;5 1C1B C171 C1714 '! '!2 4 2 Gambar 3.9 Menegangkan tali panah dan katapel memunculkan energi potensial. Gambar 3.10 Usaha yang dibutuhkan Pak Simbolon untuk mengangkat ikan setinggi h adalah W = mgh. Gambar 3.11 Sebuah benda yang diangkat oleh gaya dorong Ftangan = mg dari posisi y1 ke y2. h y1 s ' Ftangan= mg Fgravitasi=mg
  • 97. N mg s mg 2 h F =mg sin Usaha, Energi, dan Daya 75 .B181 C5AB52DC 4945699B9;1 B521719 @5AD2181 55A79 5;BC5A1 C171 * 5;B *5;B * 4 * 5;B ' !2 4 2 K ,11C ;5 21F18 7A1E9C1B9 7A1E9C1B9 '!2 4 2 4' ! .B181C5AB52DC4945699B9;1B521719@5AD218155A79@?C5B917A1E9C1B9 * 7A1E * 7A1E *4 * 47A1E ' !24 2 K 5A79 @?C5B91 7A1E9C1B9 @141 C9C9; 2 41A9 C9C9; 13D1 C5AC5CD 2
  • 98. 49H1C1;1 4571 @5AB1=11 * ' ! 2 1C1D * ' ! K 4571 =5AD@1;1 C9779 2541 C5A8141@ 1C19 4$*$:$0)'+.$-6-$01.(*)$:$2$'$%(0'$2$'$-(5+0))+$0 *5A81C9;1$/%$3 $41$/%$3 % 1A9441,1=D5 B5417 =5=9418;1 21?; H17 25A=1BB1 B1=1 ;5 ;5C97791 1A94 =5=9418;1 21?; =577D1;1 29417 =9A97 B5417;1 ,1=D5 =5=9418;1 21?; =577D1;1 ;1CA? '5DADC 41 B1=1;18 DB181 H17 491;D;1 1A94 41 ,1=D5 C5A8141@ 21?; C5AB52DC *141 $/%$3 $ @1:17 9C1B1 H17 49C5=@D8 , =5=25CD;BD4DC C5A8141@294178?A9I?C1 57145=9;91DB181 @141 9C1B1 =9A97 H17 491;D;1 1A94 14118 O4 '!,B9
  • 99. '! B9 B9 '! K 41@D DB181 H17 491;D;1 ,1=D5 DCD; =5=9418;1 21?; ;5 ;5C97791 =5781B9;1 9C1B1 E5AC9;1 B5@1:17 571 45=9;91 DB181 H17 491;D;1 ,1=D5 14118 '! K 5A41B1A;1;54D13?C?8C5AB52DC41@1C49B9=@D;1218F1DB181 H17 491;D;1 2541 25A71CD7 @141 ;5C97791 H17 4931@19 C941; 25A71CD7 @141 31A1 @5717;1C1 2541 C5AB52DC 1C1D 9C1B1 H17 49C5=@D8 B51=1 @5717;1C1 Contoh 3.7 1CD25A=1BB1;7:1CD82521B41A9;5C97791
  • 101. == Gambar 3.12 (a) Farid memindahkan balok ke ketinggian h menggunakan bidang miring, sedangkan (b) Samuel menggunakan katrol dengan lintasan vertikal. Samakah usaha yang dilakukan keduanya? h 1 A B
  • 102. Tantangan untuk Anda Gambar 3.13 (a) Keadaan awal benda dalam posisi seimbang. (b) Pegas ditarik sejauh simpangan y2. (c) Posisi benda kembali ke titik setimbang karena gaya pegas F = –ky2. 1 *5AD218155A79@?C5B91 p E '!K;7
  • 103. =B=K
  • 104. =K
  • 105.
  • 107.
  • 109. =B=K
  • 110. =
  • 111.
  • 113.
  • 114. :?D5 5A1@1;18 55A79 @?C5B91 H17 49=99;9 ?58
  • 115.
  • 116. = 19A H17 25A141 @141 ;5C97791
  • 118.
  • 119.
  • 122.
  • 123.
  • 124. ;7=
  • 125.
  • 126. =N
  • 128. ;7
  • 129. =B
  • 130. =N
  • 132. :?D5 b. Energi Potensial Elastis Pegas 5A79 @?C5B91 51BC9B @571B 25A2541 4571 55A79 @?C5B91 @141 D=D=H1 5A79@?C5B91@571B1411855A79H1749=99;9@571B1;921C 141H1@5AD2181@1:171C1DA57171@571B !1H1H1725;5A:1@141 @571B =5=D7;9;1 @571B DCD; =5A5717 *5A81C9;1$/%$3 *141$/%$3 $=D1 =D1@571B411= ;51411 B5C9=217 5A79 @?C5B91 @571B 41 55A79 ;95C9;H1 ? *141 $/%$3 %41$/%$3 @571B=5=99;9B9=@171B5:1D82 41 2 @1:17 2 2 )58 ;1A51 141 C1A9;1 B525B1A %2 41 @571B =51A9; ;5=219 2541 B5BD19 D;D= ### (5FC? @571B K% 5B1AH1DB181H17491;D;1@571B41A9;514112
  • 134. 4122 @571B 4 ,25B1A@5A@94181@?B9B92541 76 Mudah dan Aktif Belajar Fisika untuk Kelas XI 2 2
  • 135. 2 2 2
  • 136. %2 2 %2 571 45=9;91 25B1AH1 DB181 H17 491;D;1 ?58 71H1 @571B 49H1C1;1 4571 @5AB1=11 @571B @ @571B 4571 @@571B %2 K
  • 137. %5C9;1 @571B 495@1B;1 @571B 1;1 =51;D;1 75A1; 81A=?9; ,51=1 @5A75A1;1H1 @571B =5711=9 @5AD2181 55A79 ;95C9; =5:149 55A79 @?C5B91 @571B 1C1D B5219;H1 -941; B51=1H1 @571B =51;D;1 75A1; 81A=?9; @571AD8 71H1 D1A 1;1 =5=2D1C @571B 25A85C9 @141 @?B9B9 ;5B5C9=2171 1 2 3 y2' y2 y1=0 Contoh 3.8 Sumber: Fisika untuk Sains dan Teknik, 1998 Perhatikan gambar di atas. Jika seorang ahli gizi menyatakan bahwa pada pizza isi daging dan keju tersebut mengandung energi 16 megajoule, bagaimana pendapat Anda jika dikaitkan dengan konsep Fisika? Bagaimana cara mendapatkan angka tersebut?
  • 138. Kata Kunci • energi kinetik • energi potensial x m v m v m k 1 2 3 licin x1 x2 x = x2 – x1 licin licin Usaha, Energi, dan Daya 77 Contoh 3.9 *571B25AC1=218@1:17
  • 141. (1
  • 142. 3=
  • 143. = F F Tes Kompetensi Subbab B (3,$-$0.$*'$.$/%6-6.$5+*$0 ,52D1821CD;53925A=1BB17495@1B;141A9;1C1@5 B58977125B1A55A79;95C9;H1749=99;9H114118
  • 145. ;7 B5417 25A75A1; 4571 ;535@1C1;=:1=C921 C92149A5=4125A85C9 B5C518=55=@D8:1A1;
  • 146. = -5CD;118 1 71H1A5=@141=?2941 2 DB181H1749@5A?5841A9@575A5=1 %5A5C1 =191 H17 =1BB1H1 ;7 495@1B;1 41A9 @D31;29417=9A979394571BD4DC;5=9A971
  • 151.
  • 152. 3= 1 9CD718DB181H17491;D;171H17A1E9C1B9 @1412541C5AB52DC 2 9CD71825A;DA17H155A79@?C5B917A1E9C1B9 2541C5AB52DC 541'25A=1BB1 ;7:1CD8=5775939A41A91C1B 29417=9A974571BD4DC;5=9A971J 541 C5AB52DC=5D=2D;B52D18@571BH17C5A5C1; = 41A9 5C1;' B5=D1 $9;1 %
  • 153.
  • 154. (= 41 @571B C5AC5;1=1;B9=D=B5:1D8
  • 156. (
  • 157. =
  • 158.
  • 160. ( ( 1 % (
  • 161.
  • 162. (=
  • 163.
  • 164. (=
  • 165. = * %1
  • 166.
  • 167. (=
  • 168. = $ $14925B1A55A79@?C5B9151BC9B@571B14118 $ C. Gaya Konservatif dan Hukum Kekekalan Energi Mekanik *5A81C9;1 $/%$3 $ ,52D18 @571B 495C1;;1 49 1C1B 1C19 41 B118 B1CD D:D7H1 499;1C;1 @141 49497 %5=D491 B52D18 21?; 25A=1BB1'=5D3DA4571;535@1C1 C5@1C;51A18@571B $9;11C19 41C1A41939B5AC1@571BH19451B9BC5=1;1=5=5D89D;D=??;5 K% 9 4571 14118 71H1 @141 @571B B11C D:D7 2521BH1 25A75B5A B5:1D8 %51411 H17 49979;1 @141 B9BC5= C5AB52DC 14118 55A79 ;95C9;C5A@DB1C@141=1BB121?;B58977155A79;95C9;@571B491219;1 ;921CH1 =1BB1 @571B 491771@ B171C ;539 41A9@141 =1BB1 21?; %5C9;121?;=5H5CD8@571B1:D21?;25A;DA17B1=@191;89AH1 25A85C9 ;1A51 71H1 @571B H17 =51F1 71H1 4?A?71 41A9 21?; *5A81C9;1$/%$3 % %5=D4911A1821?;25A219;1;921C71H1 @571B 25;5A:1 ;921CH1 21?; =5=@5A?58 55A79 ;95C9;H1 ;5=219 B5@5AC9 B11C 21?; =5H5CD8 @571B F11D@D 1A18H1 25A2541 1?; Gambar 3.14 Gaya pada pegas merupakan gaya konservatif.
  • 169. Gambar 3.15 Seseorang sedang melakukan usaha memindahkan peti. Tugas Anda 3.2 Sebutkan contoh-contoh gaya konservatif yang ada di sekitar Anda. ;589171 55A79 ;95C9;H1 @141 B118 B1CD 1A18 75A1;H1 C5C1@9 =5=@5A?58 55A79 ;95C9;H1 ;5=219 @141 1A18 75A1; H17 19 H19CD ;5C9;1 21?; 25A219; ;5 @?B9B9 B5=D1 $/%$3 *141 @5A9BC9F1 C5AB52DC DB181 H17 491;D;1 71H1 @571B % 9 C941;=57D21855A79=5;19;B9BC5=@571B !1H1H17491;D;1?58 @571BC5AB52DC25AB961C;?B5AE1C96 !1H17A1E9C1B9:D7125AB961C;?B5AE1C96 41@1C;1841=5:51B;1=571@171H17A1E9C1B925AB961C;?B5AE1C96 1A9BD4DC@1417H171971H1;?B5AE1C96:D71=5=99;939A9218F1 :D=18DB181H17491;D;171H1@141@1AC9;52541491771@B521719 @1AC9;5 14118 ? *141 ;51411 B5C9=217 @?B9B9 1
  • 170. 71H1 @571B @ @141 3?C?8 C5AB52DC 49H1C1;1 4571 @5AB1=11 78 Mudah dan Aktif Belajar Fisika untuk Kelas XI @ % 9 K -18D;18 41 DB181 H17 491;D;1 ?58 71H1 @571B C5AB52DC *5A81C9;1 ;5=219 $/%$3 ;5C9;1 2541 25A@9418 41A9 @?B9B9 H17=5=99;9B9=@1711 ;5@?B9B94571B9=@171125B1ADB181 H17491;D;171H1@571BC5A8141@254149H1C1;14571@5AB1=11 K* 1 K%1 1 -141 571C96 =5H1C1;1 218F1 1A18 71H1 @571B * 25A1F11 4571 1A18 @5A@94181 1 *.( ,#'*(!( G *- #*+) +# (##+-+-+#,#'*(!(1 411 571 45=9;91 @5AB1=11 41@1C 49H1C1;1 4571 K%1 1 1 1 K% 1 1 % 1 1 1 1 % 1 1 5A41B1A;1 @5AB1=11 :51B18 218F1 DB181 H17 491;D;1 ?58@571BC941;=57D21855A79=5;19;B9BC5=41C941;25A71CD7 @141@?B9B91F141@?B9B91;89A2541H1749;51971H1@571BC5AB52DC *5A81C9;1$/%$3
  • 171. ,52D18@5C949@9418;1;5C5=@1C19 B5C9779 .B181 H17 49@5AD;1 DCD; =5=9418;1 @5C9 14118 K'!-141571C96C9=2D;1A511A1871H125A1C25A1F11 4571 1A18 75A1; @5C9 .B181 ;5C9;1 =5=9418;1 @5C9 C941; 25A71CD7 @141 @1:17 9C1B1H17491D9@5C9C5C1@925A71CD7@14125B1A@5AD2181C9779 @5C941A9;54D4D;11;89A;5;54D4D;11F1H1 $9;1@5C949@9418;1 179;5@?B9B91F1H1DB181H17491;D;1H114118'! ,531A1 =1C5=1C9B DB181 C?C1 H17 491;D;1 DCD; =5=9418;1 @5C9 41A9 21F18 ;5 1C1B 1D 49@9418;1 179 ;5 21F18 14118 C?C K'! '!
  • 172. 5B1A DB181 @5=94181 B52D18 @5C9 41A9 ;54D4D;1 1F1 89771 ;5=219 ;5 ;54D4D;1 1;89AH1 25A919 ? $149 41@1C 49B9=@D;1 218F1 DB181 H17 491;D;1 ?58 71H1 ;?B5AE1C96 1;1 25A919 ? :9;1 ;54D4D;1 1;89A 2541 ;5=219 ;5 ;54D4D;1 1F1H1
  • 173. v 1 1 v2 2 h mg 2 h1 Usaha, Energi, dan Daya 79 1. Perumusan Hukum Kekekalan Energi Mekanik 11= =541 7A1E9C1B9 :D=18 55A79 @?C5B91 41 55A79 ;95C9; BD1CD2541C5C1@:9;181H114171H17A1E9C1B9 *5AH1C11C5AB52DC49;51 B521719 D;D= %5;5;11 5A79 '5;19; *5A81C9;1 $/%$3 ,52D18 2541 25A=1BB1 ' :1CD8 2521B *141 @?B9B9 ;5C97791H1 C5A8141@ 13D1 1C19 ,5B11C ;5=D491 2541 25A141 @141 @?B9B9 4571 ;5C97791 C5A8141@ 13D1 9;1C1;1 218F1 @141 2541 C5A:149 @57DA171 55A79 @?C5B91 H17 25B1AH1 B1=1 4571 DB181 H17 491;D;1 71H1 25A1C K@4@ K *141 @?B9B9 ;535@1C1 2541 / ;5=D491 2541 CDAD 89771 @141 @?B9B9 4571 ;535@1C1 / *141 ;51411 C5AB52DC ;535@1C1 2541 25AC1=218 ;1A51 @571AD8 @5A35@1C1 7A1E9C1B9 B589771 DB181 H17 491;D;1 2541 B1=1 4571 @5AD2181 55A79 ;95C9; H19CD ;4; K 5A41B1A;1 (34$/$$0 ; 41 (34$/$$0 ; 49@5A?58 @ K@;K; 1C1D @ ; @; K Gambar 3.16 Balok dijatuhkan dari ketinggian tertentu. Contoh 3.10 ,52D182?125A=1BB1'495=@1A;1E5AC9;1;51C1B4571;535@1C11F1B525B1A
  • 174. -5CD;1 1 C9779=1;B9=D=H174931@1941 2 ;535@1C1;5C9;12?1=531@19C9779B5C5718=1;B9=D= $8$% 1 * % *% '! '/ '! '/
  • 175. '/ '!
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  • 183. '/ '
  • 184. / '/
  • 185. '/ '/ /
  • 186. / /
  • 188. / h m v2 = 0 h2 = h h1 = 0 v1 = v0 Ek2 ; Ep2 Ek1 ; Ep1
  • 189. ,52D1821CD25A=1BB1'C5A71CD7@141B5DC1BC19H17@1:17H1 4925A971H1 =541C1A 1CD=D1925A75A1;4571;51:D11F1/
  • 190. B5@5AC9@14171=21A;5C9;1 21CD=5H9=@174571BD4DC C9779H174931@192?141A9C9C9;B5C9=217H1 14118 -5CD;1 1 C9779=1;B9=D=H174931@1921CD41 2 25B1A;535@1C11F121CD/
  • 191. $8$% 1 *%*% '! /2 A m '! 80 Mudah dan Aktif Belajar Fisika untuk Kelas XI '/
  • 192. /2 0 m '!
  • 193. /
  • 194. !
  • 196. / ! 2 3?B K
  • 197. 3?B / ! K
  • 198. 3?B / ! /
  • 199. ! 3?B h v0 1?;H1725A=1BB1;7=5775939A41A91C1BB52D1829417=9A97H17BD4DC =9A97H1
  • 202.
  • 203. (= $8$% .B181H17491;D;171H1@571B14118571C96;1A51@571B=51F171H1C5;1 21?; AC9H1;5C9;1@571BC5AC5;1@571B=51F171H1C5;1B58977171H1 @571B411A18@5A@9418125A1F111A18 *5A81C9;171=21A25A9;DC @571B %1K % 7A1E 4 * 4'!3K1 '!,B9
  • 204. J
  • 205. '!, .B181?5875B5;125A919571C96 ;1A511A1821?;25A1F11 45711A1871H175B5; !,% 4 ;, k'!3?B
  • 206. J, '!, ; ha hb hc A B b C s 30° Contoh 3.11 Contoh 3.12 Tugas Anda 3.3 Apakah Anda tahu olahraga bungee jumping? Selidikilah Hukum Kekekalan Energi yang bekerja saat orang melakukan bungee jumping.
  • 207. Pembahasan Soal 32 Dua buah benda A dan B yang bermassa masing-masing m, jatuh bebas dari ketinggian h meter dan 2h meter. Jika A menyentuh tanah dengan kecepatan v m/s, benda B akan menyentuh tanah dengan energi kinetik sebesar .... a. mv2 d. 1 2 mv2 b. mv2 e. 1 4 mv2 c. 3 4 mv2 Soal UMPTN Tahun 1989 Pembahasan: hB = 2hA Berarti, EpB = 2 EpA Sesuai dengan Hukum Kekekalan Energi Mekanik maka EpB – EpA = EkA – EkB EkB = 2 EkA = 2 1 2 mv2 = mv2 Jawaban: b Usaha, Energi, dan Daya 81 '5AD:D;@A9B9@55A7949;5C18D9218F1 -)- % B58977149@5A?58 *!,!+/!,% '/ 4/ K % '!,K 3'!, k '
  • 208. K
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  • 210. k 4
  • 211. , 3 k ,
  • 213.
  • 215. 41!
  • 217.
  • 218. ;7
  • 219. =B
  • 220. 4
  • 221. = 3
  • 222. =
  • 223. =4
  • 224. =K=
  • 225. K
  • 229.
  • 230. 3=B 5A1@11:D49C9C9;41 A $8$% *141B9BC5=25A1;D%5;5;115A79'5;19;B589771 1 '! '/ '! '/
  • 231. =B
  • 232. = =B
  • 233. / /
  • 235. =B
  • 236. = =B
  • 237. =B
  • 238. = / /
  • 239. =B =B $149;51:D12?149C9C9;14118 =B C B 80 cm 50 cm Contoh 3.13
  • 240. B A lintasan loop Gambar 3.17 Lintasan roller coaster. 2. Analisis Gerak pada Roller Coaster 1=@9A B5=D1 C5;??79 49 C1=1 892DA1 B5@5AC9 #,(2 ( #,(2 )+1C1DD91 1C1B9B171C;1H11;1;?B5@69B9;1 91C1A1B5:D=18 @5A=191 H17 141 +)+ ),-+ 1C1D H17 291B1 49B52DC 8199C1A 41@1C =54?A?741DCD;=5=181=95298411=;?B5@69B9;1C5C1775A1; *5A81C9;1 $/%$3 %541A11 C1@1 =5B9 =577D1;1 21 25A:11)(/2)+-DCD;19;;5@D31;2D;9C=51D99C1B1H17 C941; C5A1D 3DA1= *D31; 2D;9C B571:1 49A1317 5298 C9779 41A9@141 @D31; ??@ 81 C5AB52DC =5=D7;9;1 55A79 @?C5B91 ;541A11 49 H17 5298 25B1A B589771 =1=@D 25A:11 =51D9 9C1B1 =5D:D @D31; 4571 219; 9C1B1 ??@ B571:1 492D1C B5@5AC9 C5C5B1 19A C5A219; $9;1??@25AD@197;1A1@5D81;149@5A?582?2?C@5D= @1751=;192?2?C?A=1H1B11C;541A1149@?B9B9C5A5418;?49B9 99 41@1C =5H5212;1 @DB97 1D @97B1 9C1B1 ??@ H17 B5@5AC9 C5C5B1 19A 81H1 =5=25A9;1 2?2?C =1;B9=D= ;19 2?2?C ?A=1 H1 @141 2?2?C C5AB52DC @5D=@17 =1B98 =5A1B1;1 ;5H1=11 %5C9;1 +)+ ),-+ 25A141 49 C9C9; C5AC9779 41A9 9C1B1 ??@ H19CD 49C9C9;B5@5AC9H1741981C@141$/%$3 71H1B5CA9@5C1H1 14118 A5BDC1 41A9 71H1 C5;1 41 25B1A 71H1 25A1C @5D=@17 '! B589771 B C 82 Mudah dan Aktif Belajar Fisika untuk Kelas XI B3'! / ' ,H1A1C ;51:D1 =99=1 49 C9C9; 14118
  • 242. '! / ' / Cmin !+ %5C9;1 +)+ ),-+ 25A141 49 C9C9; C5A5418 H19CD C9C9; *
  • 243. %* %3*3 '/ '! '! '/ %19;1 ;54D1 AD1B @5AB1=11 C5AB52DC 4571 ' B589771 49@5A?58 !/ !/ )58;1A51
  • 244. 41/ !=1;1 @5AB1=11 =5:149 !!
  • 245. / =9 / ! K %5C97791 1F1 =99=1 D3DA1 49 C9C9; 41@1C 41 89CD7 =51D9 @55A1@1 D;D= %5;5;11 5A79 '5;19; 49 C9C9; 41 171A +)+ ),-+ =1=@D =55F1C9 ??@ 4571 1=1 Gambar 3.18 Lintasan roller coaster dengan loop berbentuk lingkaran. A Sumber: Dokumentasi Penerbit Nc mg
  • 246. Usaha, Energi, dan Daya 83 Contoh 3.14 ,5@?C?721?;25A=1BB1'=5D3DA@141BD1CDC11797;1A1411=B5@5AC9 C5A981C@14171=21A $9;171H175B5;1C1A121?;41C117491219;1 1 25A1@1;18;5C97791=99=D=21?;H1781ADB495@1B171A75A1;1H141@1C =531@19@D31;97;1A1C9C9;41 2 C5CD;11825B1A@5A35@1C121?;49C9C9; $8$% 1 !D1;1AD=DB;51:D1=99=D=@141C9C9;C5A5418(34$/$$0 ;
  • 247. $149;51:D1=99=D=49C9C9;25B1AH1/=9 ! B5897711C1A1C9C9; 414571=577D1;18D;D=;5;5;1155A79=5;19; *%*% ' ! ' / ' ! ' / ' !
  • 248. '! $149;5C97791=99=D=171A21?;=531@19C9C9;14118 2 5B1A@5A35@1C149C9C9;14118@5A35@1C1B5CA9@5C1 5A41B1A;171=21A 49C9C9; B'! ', '!49=11
  • 249. ,! $149@5A35@1C121?;49C9C9;14118,! Kata Kunci • energi mekanik • gaya konservatif • gaya sentripetal • kelajuan minimal • konstanta pegas Tes Kompetensi Subbab C (3,$-$0.$*'$.$/%6-6.$5+*$0 @1;18H1741;5C18D9C5C1771H1;?B5AE1C96 4171H1C941;;?B5AE1C96 @1;188D;D=;5;5;1155A79=5;19;25A1;D @141B52D182541:9;171H1;?B5AE1C9625;5A:1@141 2541C5AB52DC D12D18254141H1725A=1BB1=1B97 =1B97 ':1CD82521B41A9;5C97791=5C5A41=5C5A $9;1=5H5CD8 C118 4571 ;535@1C1 /=B C5CD;118 55A79 ;95C9; 2541 B11C 1;1 =5H5CD8C118 ,52D1821?;25A=1BB1;7=D1 =D1491= 1?; C5AB52DC;5=D49149:1CD8;141A9BD1CD;5C97791 3=@141B52D18@571BH17;?BC1C171H1H1
  • 250.
  • 251. (= $9;1!=B25A1@1=5C5A@571BC5AC5;1 -?5 =5=9418;1 2D;D 41A9 1C19 ;5 1C1B =5:1 5A1@1DB181C?C1H1749C5A9=1?582D;DC5AB52DC -97121CD21C1H17C521H13=495C1;;1491C1B B52D18 =5:1 9CD718 DB181 DCD; =5D=@D; ;5C97121CD21C1C5AB52DC411=B1CDCD=@D;1:9;1 =1BB1B5C91@21CD21C1 ;7 A v B NB mg R hA C
  • 253. =B C5CD;118;535@1C12D18;51@1B11C=531@19 ;5C97791=5C5A41A9C1184155A79;95C9;2D18 ;51@1B5B11CB525D==531@19C118 ,52D18;5A5C1=55F1C99C1B1+)+),-+4571 491=5C5A
  • 254. = 71A;5A5C141@1C=59C1B4571 1=1 C5CD;118 ;535@1C1 =99=D= ;5A5C1 C5AB52DC 84 Mudah dan Aktif Belajar Fisika untuk Kelas XI ,52D18 2541 25A=1BB1
  • 255. ;7 :1CD8 2521B 41A9 ;5C97791 =5C5A 49 1C1B C118 $9;1!
  • 256. =B C5CD;118 1 ;535@1C12541B11CC92149C11841 2 DB181?5871H125A1CB51=1@5A@94181
  • 259. =BC5CD;11855A79;95C9;4155A79 @?C5B912541@141B11C=531@19C9C9;C5AC9779 D. Daya 41 C518 251:1A C5C17 31A1 =5789CD7 DB181 41A9 71H1 H17 491;D;1 921497;1 =575C18D9 25B1A DB181 5298 =51A9; =575 C18D9 B525A1@1 1:D DB181 C5AB52DC 49;5A:1;1 -5CDH1 25B1A1 F1;CD 49 411= 2181B1 99 =5:149 B171C 25A@5A1 ,11C DB181 @5A B1CD1 F1;CD 4945699B9;1 =D3D18 9BC918 41H1 *5AD41971C218F141H1C941;49C5CD;1?5825B1A55A79H17 49=99;9 BD1CD 2541 .CD; 5298 =5=181=9H1 @5A81C9;1 3?C?8 25A9;DC .3?; 41 DC5C 25A=1BB1 B1=1 H19CD
  • 260. ;7 =519;9 1C19 4D1 B5;?18H1 B5C9779 =5C5A %54D1H1 =5=99;9 55A79 B1=1 25B1A DCD; =51;D;1DB181
  • 261.
  • 262. :?D5 5A79@?C5B91H1749=99;9=5A5;1B1=1 F11D@D;5H1C11H1.3?;B1=@19491C194D1529835@1C 1A9DA191 3?C?8 C5AB52DC 49;5C18D9 218F1 1AC9H1 DB181 25D= 41@1C =5=25A9;1 96?A=1B9529857;1@C5C17@5A@941811;921C@571AD871H1 11= @5A9BC9F1 99 41@1C 49;1C1;1 218F1 .3?; =5=99;9 41H1 5298 25B1A 41A9@141 DC5C F11D@D ;54D1H1 =5=99;9 ;5=1=@D1 DCD; =57 81B9;1 55A79 H17 B1=1 $149 41H1 14118 25B1A1 69B9;1 H17 =5H1C1;1 DB181 H17 491;D;1 ?58 2541 B5C91@ B5;?H1 1C1D 1:D 55A79 H17 492DCD8;1 2541 B5C91@ B5;?H1 1H1 A1C1 A1C1 DB181 B517F1;CD - 1C1D , / - K %5C5A171 DB181 H17 491;D;1 :?D5 - F1;CD H17 49@5AD;1 B5;? / ;51:D1 A1C1 A1C1 =B 11=B9BC5=,#B1CD141H149CDAD;141A9B1CD1DB181H19CD$B ,1CD1 C5AB52DC B5A97 49B52DC F1CC 49C5C1@;1 B521719 @5781A711 C5A8141@ 9=DF1 ,;?C1491 H19CD $/(4#$55 K ,1CD1 41H1 411= ;5=1=@D1 B52D18 =5B9 291B1 =577D1;1 B1CD1 )+, *)0+ * 1C1D 41H1 ;D41 8@F1CC
  • 264. $ Tugas Anda 3.4 Sebutkan contoh alat-alat yang mencantumkan besaran daya yang ada di sekitar Anda.
  • 265. Usaha, Energi, dan Daya 85 ;08 14118 B1CD1 DB181 1C1D 55A79 2D;1 B1CD1 41H1 ,1CD1 C5AB52DC 21H1; 497D1;1 DCD;=5H1C1;1 55A79 9BCA9; $9;1 B5CA9;1 9BCA9; =5=99;9 41H1
  • 266.
  • 267. F1CC 55=5 B5CA9;1 C5AB52DC 55A79 9BCA9; =51;D;1 ;5A:1 1C1D DB181
  • 268.
  • 269. :?D5 B5C91@ B5;?H1 Contoh 3.15 +9C?H1725A=1BB1
  • 272. ;7 = -
  • 273. =59C '! - -
  • 274. ;7
  • 275. =B =
  • 276.
  • 277. F1CC
  • 279.
  • 280. F1CC Contoh 3.16 ,52D18=5B9@?=@1B5CA96D7141@1C=5=9418;1
  • 281.
  • 284.
  • 285. ;7 = - =59C
  • 287.
  • 288. ;7
  • 289. =B =
  • 290. F1CC
  • 293. 14118
  • 294. F1CC
  • 295. F1CC
  • 296.
  • 299.
  • 300. F1CC
  • 301. Tes Kompetensi Subbab D (3,$-$0.$*'$.$/%6-6.$5+*$0 +9?=519;9C1771H17C9779H1=411=F1;CD 45C9; 9CD71841H1A1C1 A1C1+9?411=B1CD1 *:9;1=1BB1H1
  • 302. ;7 !=B ,52D18@?=@1=5B94975A1;;1?58=?C?A9BCA9;H17 =5=99;941H1* '5B9C5AB52DC1;1=519;;1 2521;7;5C5=@1CH17C9779H1 = 9CD718 F1;CD H17 492DCD8;1 DCD; =519;;1 2521 C5AB52DC ,52D18=?29=577D1;1=5B9
  • 304. ;=:1= ,52D1821?;25A=1BB1;725A141411=;51411 491=491C1B29417=9A97 1?;C5AB52DC=541@1C 71H1B525B1A (B51A1829417=9A97;51C1B 1 -5CD;1;535@1C121?;B5C518=55=@D8 :1A1;,
  • 306. =!
  • 308. J W1 F 86 Mudah dan Aktif Belajar Fisika untuk Kelas XI ,52D18=5B9@?=@141@1C=5=9418;1
  • 309.
  • 311. 25A1@1;1841H1 9BCA9;H1749@5AD;1 $?125A=19@1@1D3DA49;5C97791=5C5A41A9 1C19 $9;1;535@1C1$?1@1411F1@5D3DA1=B 25A1@1;18;535@1C1H1;5C9;1=5H5CD81C19 1A9;5C97791
  • 313. ;7 :1CD8 41A9 @?8? 5A1@1;18 55A79 ;95C9; H17 49=99;9 ;51@1 @141 B11C =531@19 ;5C97791
  • 315. =B ,52D182541H17=1BB1H1;725A75A1;4571 ;535@1C1C5C1@=B %5=D4912541C5AB52DC4925A9 71H1 B589771 2541 =5711=9 @5A1=21C1 ;5=D491 25A85C9 B5C518 =55=@D8 :1A1; = -5CD;1 1 25B1A71H1@575A5=1H1725;5A:1@1412541 2 DB181H17491;D;125418977125A85C9 F m = 2 kg 30° Rangkuman .B181 14118 25B1AH1 71H1 B51A18 @5A @94181B49;19457125B1AH1@5A@94181 3?B ,1C1D,3?B 4571 14118 BD4DC 1C1A1 71H1 41 @5A@94181 .B18125A81A71571C96=5D:D;;1218F171H1 H1725;5A:125A1F1145711A18@5A@94181 *1417A169;71H1C5A8141@@5A@9418125B1ADB181 =5AD@1;1D1B415A18H17491AB9A 5A79 14118 ;5=1=@D1 DCD; =51;D;1 DB181 5A79;95C9;1411855A79H1749=99;9 ?58B5C91@2541H1725A75A1; % '/ 5A79@?C5B911411855A79H1749=99;9?58 B5C91@2541;1A51;54D4D;1H1 $9;1;51411 =5=D7;9;155A79C5AB52DC41@1C49=D3D;1 *'!DCD;55A79@?C5B917A1E9C1B9 *51BC9B %1DCD;55A79@?C5B91@571B .B181 =5AD@1;1 @5AD2181 55A79 41A9 BD1CD 2541 %4% DCD;55A79;95C9; *4* DCD;55A79@?C5B91 D;D= %5;5;11 5A79 '5;19; L$9;1 @141 BD1CD B9BC5= H17 25;5A:1 81H1 71H1 71H1 ;?B5AE1C9655A79=5;19;B9BC5=B51DC5C1@ M *4% ;?BC1 * % *% Wtotal = W1+W2 s W2
  • 316. .B181 5A79 1H1 Usaha, Energi, dan Daya 87
  • 317. .B181C?C1H17491;D;1?5871H1;?B5AE1C96 81H1=5=@5A81C9;1;514111F141;51411 1;89A@?B9B925419C1B1C941;=5=571AD89 1H1 14118 DB181 H17 491;D;1 ?58 2541 B5C91@B5;?1C1D1:D55A79H1725AD218=5:149 55A7925CD;19 Refleksi 4$*$0(3)+'$0$:$ .B181*5AD21815A79 Setelah mempelajari bab ini, tentu Anda dapat memahami konsep usaha, energi, dan daya. Anda juga tentu dapat mengetahui hubungan antara usaha, energi, dan daya. Nah, dari materi-materi bab ini, bagian manakah yang Anda anggap sulit? Coba diskusikan dengan teman atau guru Fisika Anda. Dengan mempelajari konsep usaha, Anda dapat menentukan usaha dengan menentukan lintasan yang lebih efisien untuk dilakukan. Hal tersebut adalah salah satu manfaat mempelajari bab ini. Coba Anda sebutkan manfaat lain setelah mempelajari bab ini. Peta Konsep 5A79%95C9; 5A79*?C5B91 D;D=%5;5;11 5A79'5;19; 5A79*?C5B91 !A1E9C1B9 5A79*?C5B91 *571B =5=2181B 8D2D71H1 =5=2181B =5=2181B
  • 318. Tes Kompetensi Bab 3 A. Pilihlah salah satu jawaban yang paling tepat dan kerjakanlah pada buku latihan. ,1CD1 B1CD125A9;DC99H17-#%C5A=1BD;B1CD1 DB18114118 1 5FC?=5C5A 2 :?D5 3 ;7=BK 4 ;7=B 5 ;7=B 5B1A1 25B1A125A9;DC99-#%=5=99;9B1CD1B1=1 14118 1 DB181 55A79 2 DB181 55A79;95C9; 3 55A79@?C5B91 55A79;95C9; 4 C5171 DB181 5 71H1 DB181 ,52D182541=1BB1H1;7411=;51411491= %5=D4912541C5AB52DC4925A971H1C5C1@B525B1A
  • 319. ( B51=1 45C9; .B181 H17 491;D;1 71H1 C5AB52DC14118 1
  • 320.
  • 321. $ 2
  • 322.
  • 323. $ 3
  • 324.
  • 325.
  • 326. $ 4
  • 327.
  • 328. $ 5
  • 329.
  • 330. $ D'91 =5=21F1 ;5A1:17 25A=1BB1
  • 334.
  • 335.
  • 336. $ 2
  • 337.
  • 338.
  • 339. $ 3
  • 340.
  • 341. $ 4
  • 342.
  • 343. $ 5 ? '?29 H17 =1BB1H1
  • 344.
  • 345.
  • 346. ;7 49A5= 4571 71H1
  • 347.
  • 348.
  • 349.
  • 351. $ 2 N
  • 352. $ 3 N
  • 353. $ 4 N
  • 354. $ 5 N
  • 356.
  • 359. $ 2
  • 360.
  • 361. $ 3 $ 4
  • 362. $ 5 $ 88 Mudah dan Aktif Belajar Fisika untuk Kelas XI *14129417=9A9741939495@1B;12541 C1@1 ;535@1C1 1F189771 2541 25A141 49;1;9 29417=9A97B5:1D8= $9;1B9
  • 363. ;535@1C1 254114118 1 =B 2 =B 3 =B 4 =B 5 =B ,52D1871H1+,(=51;D;1DB1814571 C9C9;C17;1@H125A@9418=5DADC3+,= 41E5;C?A+41,25ACDADC CDADC14118E5;C?AB1CD1 H17 B51A18 4571 BD=2D 1 41 BD=2D 2 @141 ;??A491C1AC5B9DB $9;1DB181C5AB52DC25A919$ 919B1=14571 1 2 3 4 5 ! !5A?21;4571=1BB1
  • 364. ;7C5A5C1;@14129417 =9A97 H17 BD4DC ;5=9A971H1
  • 366. =B4175A?21;25A75B5AB5:1D8=;51A18 21F18 DB181 H17 491;D;1 ?58 71H1 25A1C 14118 1
  • 367. $ 2
  • 368. $ 3
  • 369. $ 4
  • 370.
  • 371. $ 5
  • 372.
  • 373. $
  • 374. ,52D18 2541 25A=1BB1 ;7 :1CD8 2521B 41A9 ;5C97791
  • 376. =B ;535@1C1 2541 B11C 25A141 49 ;5C97791=41A9C11814118 1 =B 2 =B 3
  • 377. =B 4
  • 378. =B 5 =B 9AC5A:DB5C9779==5719A;1
  • 380.
  • 381.
  • 384. 55A79@?C5B91 19A H17 41@1C 49D218 =5:149 55A79 9BCA9; 25B1A 55A799BCA9;H1741@1C4981B9;1B5C91@B5;?H1 14118
  • 385. Usaha, Energi, dan Daya 89 1
  • 386. ;$ 2 ;$ 3
  • 387. ;$ 4
  • 388. ;$ 5 ;$ ,52D18@?C:1CD82521B41A9C5=@1CH17C9779H1
  • 390.
  • 391.
  • 394. =B 2
  • 395. =B 3 =B 4 =B 5
  • 398.
  • 399. ( 2
  • 400.
  • 401. ( 3
  • 402.
  • 403.
  • 404. ( 4
  • 405.
  • 406.
  • 407. ( 5
  • 408.
  • 409.
  • 410.
  • 411. ( 9AC5A:DB5C9779
  • 413. =B 49=1611C;1 DCD; =5=DC1A CDA29 H17 =57 75A1;1755A1C?A9BCA9; $9;155A7919AC5A:D41@1C 49D218=5:1499BCA9;41H1;5;D1C1755A1C?AB5C91@ B5;?H1B1=14571 1
  • 414. =0 2
  • 415. =0 3 =0 4
  • 416. =0 5
  • 417. =0 $9;14125AB5@541=5DAD92D;9CC1@1=571HD8 4125B1A;535@1C1H1C5C1@C5A:149@5AD218155A79 41A9 1 ;95C9;=5:149@?C5B91 2 @?C5B91=5:149;95C9; 3 @?C5B91=5:149;1?A 4 ;1?A=5:149@?C5B91 5 ;95C9;=5:149;1?A !(4!
  • 418. ,52D18 2?1 4971CD7;1 @141 D:D7 C19 H17 @1:17H1 = ?149C1A9;;5B1=@97B589771 C19=5=25CD;BD4DC
  • 420. =B 3 =B 4 =B 5
  • 421. =B ,52D18 2541 H17 25A=1BB1 ;7 =D1 =D1 491= ;5=D49125A75A1;DADB4571@5A35@1C1=B .B181 H17=5:14955A79;95C9;B5C51845C9;14118 1 :?D5 2 :?D5 3 :?D5 4 :?D5 5 :?D5 ,52D18@571B=5=99;9C5C1@1%
  • 422.
  • 423. (= $9;1@141 D:D7 @571B C5AB52DC 4971CD7;1 2521 H17 25A1CH1
  • 425. $ 2
  • 426. $ 3
  • 427. $ 4
  • 428. $ 5
  • 429. $ D1254141=1B97 =1B9725A=1BB1':1CD8 2521B 41A9 ;5C97791 =5C5A 41 =5C5A $9;1 =5H5CD8C1184571;535@1C1/=B25411;1 =5H5CD8C118457155A79;95C9;B525B1A 1 '/ 2 '/ 3 '/ 4 '/ 5 '/
  • 430. ,52D18 @571B 49C1A9; 4571 71H1
  • 431.
  • 433. $ 2
  • 434. $ 3 $ 4
  • 435. $ 5 $
  • 436. 90 Mudah dan Aktif Belajar Fisika untuk Kelas XI ,52D18254125A=1BB1;74971CD74571B5DC1B C19H17@1:17H1= .:D7C19H1719499;1C @141179C 179C 54149@D;DB58977125A75A1; 4571;535@1C1C5C1@ =B 5A1@1;1825B1A BD4DC=1;B9=D=H174925CD;C19C5A8141@1A18 E5AC9;1 ?1H17=1BB1H1
  • 439. = 9CD718 1 55A79;95C9;1F1 2 55A79@?C5B911F1 3 55A79;95C9;2?1;5C9;1=5D=2D;C118 4 ;51:D12?1;5C9;1=5D=2D;C118 *141B52D18@571BC5A71CD72521H17=1BB1H1 ;7 *571BC5AB52DC25AC1=218@1:173= 9CD718 55A79 @?C5B91 @571B 41 25A1@1;18 25B1A 55A79 @?C5B91@571B:9;12521H149C1=218;7 !
  • 440. =B ,52D1821?;25A=1BB1;7=D1 =D1491= 1?; C5AB52DC;5=D49149:1CD8;141A9;5C97791 =@141 B52D18 @571B -5AH1C1 @571B C5AC5;1=1;B9=D= B525B1A
  • 442. =B
  • 446. 55A79 19A H17 25AD218 =5:149 55A79 9BCA9; 25A1@1 F1CC 41H1 H17 4981B9;1 755A1C?AC5AB52DC 55A79 @5CD:D; 41H1 =5=99;9B1CD1F1CC B5;? $8$%.$*2(35$0:$$0%(3+-65+0+'(0)$05(2$5 ,52D182541H17=1BB1H1;741A9;51411491= 25A75A1;89771;535@1C1H1=5:149
  • 447. =BB51=1 B5;? ;1A51 @571AD8 71H1 5A1@1;18 25B1A DB181H17491;D;1?5871H1C5AB52DC ,52D182541=5=99;9=1BB1;7411=;51411491= %5=D491 25A75A1; DADB 4571 ;535@1C1 =B B51=145C9; ,1=1;1825B1ADB18141@5AD2181 55A79;95C9;H17C5A:149$51B;1 ,52D18@5DAD25A=1BB1;749C5=21;;1E5AC9;1;5 1C1B 4571 ;535@1C1 1F1
  • 448. =B -9779 H17 4931@19 @5DAD 14118
  • 449.
  • 450. = 5A1@1;18 25B1AH1 @5AD218155A79=5;19;=5:14955A79@11B@141 @5A9BC9F1C5AB52DC!
  • 452. -9779 =1;B9=D= H17 4931@19 14118 (H1C1;1;5C977912541411=@141 B11C 55A79 @?C5B91 2541 B1=1 4571 55A79 ;95C9;H1 ,52D18+)+),-+49D91 1C1B93?49B52DC 8199C1A=541;9;5;5C97791=1;B9=D=H1
  • 454. =B %5=D491 +)+ ),-+ =5D3DA ;5 21F18 ;5 ;5C97791=99=D=H1=B525D==541;9 ;5=219=5D:D;5C97791
  • 455. = A B C hA hB hC lintasan roller coaster $9;171H175B5;+)+),-+419C1B1H1491219;1 C5CD;1 ;51:D1 +)+ ),-+ @141 ;54D1 C9C9; C5AB52DC v0 vx vy v 0 120 m gedung B A vx vy v lantai gedung