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Do problems on HW worksheet. 5.1 #2, 14 5.2 #2, 6, 8 5.1  2. x=8 14. DE = 17 5. 2 2. AB = 26 6. yes 8. DE = 44 Bellwork
5.3 Angle Bisectors Angle Bisector Theorem:  If a point is on the < bisector,    then it is equidistant from the 2 sides of the angle. Conv erse of Angle Bisector Theorem:  If a point is in the interior of an <    and is equidistant from the sides of the <,  then it lies on the < bisector. C B DB = DC AD bisects <BAC
5.4 Medians & Altitudes Median:  segment from a vertex to the midpoint of opposite side Centr oid:  point of concurrency (intersection of medians) Co ncurrency of Medians of a Triangle Theorem:  The medians  intersect at a point that is 2/3 of the distance from  each vertex to the midpoint of the opposite side. A C B P E F D AP = 2/3 AE BP = 2/3 BF CP = 2/3 CD
 
Altitude:  perpendicular segment form a vertex to the opposite side  Concu rrency of Altitudes Theorem:   The lines containing the altitudes are concurrent.
HW 5 .3-5.4 Worksheet Evens

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5.3 5.4 notes

  • 1. Do problems on HW worksheet. 5.1 #2, 14 5.2 #2, 6, 8 5.1 2. x=8 14. DE = 17 5. 2 2. AB = 26 6. yes 8. DE = 44 Bellwork
  • 2. 5.3 Angle Bisectors Angle Bisector Theorem: If a point is on the < bisector, then it is equidistant from the 2 sides of the angle. Conv erse of Angle Bisector Theorem: If a point is in the interior of an < and is equidistant from the sides of the <, then it lies on the < bisector. C B DB = DC AD bisects <BAC
  • 3. 5.4 Medians & Altitudes Median: segment from a vertex to the midpoint of opposite side Centr oid: point of concurrency (intersection of medians) Co ncurrency of Medians of a Triangle Theorem: The medians intersect at a point that is 2/3 of the distance from each vertex to the midpoint of the opposite side. A C B P E F D AP = 2/3 AE BP = 2/3 BF CP = 2/3 CD
  • 4.  
  • 5. Altitude: perpendicular segment form a vertex to the opposite side Concu rrency of Altitudes Theorem: The lines containing the altitudes are concurrent.
  • 6. HW 5 .3-5.4 Worksheet Evens