Where should seaweeds and kelps be classified Give characteristics .pdf
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Where should seaweeds and kelps be classified? Give characteristics of these organisms which you used to place them in a taxonomic unit and the source you used to find their characteristics. Solution Seaweeds are classified into three phylum\'s based on the colour of the thallus, biochemical compositions, cell wall structures, photosynthetic pigments and chloroplasts. The three kingdoms of seaweeds are, Kingdom bacteria, Kindom Plantae and Kingdom Chromista. The three phylum\'s are, Phylum Rhodophyta (red alage), Phylum Chlorophyta (green algae) and Phylum Ochrophyta (brown algae). Kelps are the brown algae that belong to the order Laminariales, genus Laminaria..
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Given a newly created Binary Search Tree with the following numerica.pdf
Given a newly created Binary Search Tree with the following numerical key input sequence
(from left to right): 9, 4, 12, 7, 5, 2, 20, 14, 11, 13, 19, 16, 17, 42, 24
a.) We are asked to add a function Position lowestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position lowestKey(const Position& v);
input argument: position of the starting node in the binary search tree to calculate from. For the
whole tree this would be the position for the root of the tree.
return value: position of the node having the lowest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
b) We are also asked to add a function Position highestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position highestKey(const Position& v) const;
input argument: position of the node in the binary search tree to calculate from. For the whole
tree this would be the position for the root of the tree.
return value: position of the node having the highest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
Solution
#include
#include
/* A binary tree node has data, pointer to left child
and a pointer to right child */
struct node
{
int data;
struct node* left;
struct node* right;
};
/* Helper function that allocates a new node
with the given data and NULL left and right
pointers. */
struct node* newNode(int data)
{
struct node* node = (struct node*)
malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
/* Give a binary search tree and a number,
inserts a new node with the given number in
the correct place in the tree. Returns the new
root pointer which the caller should then use
(the standard trick to avoid using reference
parameters). */
struct node* insert(struct node* node, int data)
{
/* 1. If the tree is empty, return a new,
single node */
if (node == NULL)
return(newNode(data));
else
{
/* 2. Otherwise, recur down the tree */
if (data <= node->data)
node->left = insert(node->left, data);
else
node->right = insert(node->right, data);
/* return the (unchanged) node pointer */
return node;
}
}
/* Given a non-empty binary search tree,
return the minimum data value found in that
tree. Note that the entire tree does not need
to be searched. */
int minValue(struct node* node) {
struct node* current = node;
/* loop down to find the leftmost leaf */
while (current->left != NULL) {
current = current->left;
}
return(current->data);
}
/* Driver program to test sameTree function*/
int main()
{
struct node* root = NULL;
root = insert(root, 4);
insert(root, 2);
insert(root, 1);
insert(root, 3);
insert(root, 6);
insert(root, 5);
printf(\"\ Minimum value in BST is %d\", minValue(root));
getchar();
return 0;
}
#include
#include
/* A binary tree node has data, pointer to left child
.
Gather information on the following two disasters Space shuttle Ch.pdf
Gather information on the following two disasters: Space shuttle \"Challenger\", Jan 1986.
Space shuttle \"Columbia\", Jan 2003. Describe (may still be speculative for Columbia) what
(materials & design as well as political/management factors) caused the disasters.
Solution
Cause of Space shuttle Challenger disaster, Jan 1986:
It was determined that the two rubber O-rings, which had been designed to separate the sections
of the rocket booster, had failed due to cold temperatures on the morning of the launch. This seal,
called an O-ring, on the shuttle\'s right solid rocket booster had failed at liftoff, allowing
pressurized hot gas to escape from inside the booster. This vaporized material impinged on the
strut connecting the solid rocket booster to the shuttle\'s huge orange external tank, causing both
pieces of hardware to break down.
About 72 seconds into Challenger\'s flight, there was a massive, almost explosive, burning of the
hydrogen that was streaming from the failed tank bottom, combined with liquid oxygen leaking
from a part of the fuel tank known as the intertank which eventually lead to the biggest disaster
in the history.
Cause of Space shuttle Columbia disaster, Jan 2003:
This space shuttle Columbia broke apart returning to earth killing all the seven crew members on
the board. An investigation determined that the disaster was caused by a problem that took place
shortly while a large piece of foam fell from the shuttle’s propellant tank and fatally damaged the
edge of the shuttle’s left wing.They lost temperature readings from sensors located on the left
wing. Then, tire pressure readings from the left side also vanished. It was later found that a hole
on the left wing allowed atmospheric gases to bleed into the shuttle as it went through its fiery
re-entry, leading to the loss of the sensors and eventually, Columbia itself.This Columbia disaster
was the second major tragedy in the history of the space shuttle program after the space shuttle
Challenger broke apart shortly after launch on January 28, 1986..
Determine the Laplace transform, F(s), of the following time signal..pdf
Determine the Laplace transform, F(s), of the following time signal.
Solution
we\'ll be interested in signals de¯ned for t ¸ 0
the Laplace transform of a signal (function) f is the function F = L(f)
de¯ned by
F(s) =
Z 1
0
f(t)e¡st dt
for those s 2 C for which the integral makes sense
² F is a complex-valued function of complex numbers
² s is called the (complex) frequency variable, with units sec¡1; t is called
the time variable (in sec); st is unitless
² for now, we assume f contains no impulses at t = 0
common notation convention: lower case letter denotes signal; capital
letter denotes its Laplace transform, e.g., U denotes L(u), Vin denotes
L(vin), etc..
Describe the difference between a monitor and a semaphoreSolutio.pdf
Describe the difference between a monitor and a semaphore
Solution
Monitor: Monitor is a highly structured programming language construct.It consists of Private
variables and private procedures that can only be used within a monitor. Constructors that
initialize the monitor.A number of public monitor procedures that can be invoked by users.
These monitors have no public data.A monitor is a mini OS with monitor procedures as system
calls.
Semaphore: Semaphore is a data structure that is used to provide mutual exclusion to critical
sections. Semaphores mainly support two operations called wait and Signal . The wait operation
blocks a process until the semaphore is open and the signal operation allows another process to
enter.MonitorSemaphoreCondition variables only uses these MonitorsThese can be used in
anywhere but not in Monitorswait() always blocks it\'s callerwait() does not always blocks it\'s
callersignal() either releases a process or the signal is lost as if it never occurssignal() either
releases a process or increases Semaphore counterif signal() releases a process,either the caller
or the released continues,but not bothif signal() releases a process,the caller and the released
both continued.
Create a link list. Add some nodes to it, search and delete nodes fro.pdf
Create a link list. Add some nodes to it, search and delete nodes from it.
Solution
#include
#include
using std::cout;
using std::endl;
/*
A linked list is a list constructed using pointers. It is not fixed in
size and could grow and shrink while the program is running.
A typical defination of list nodes contains at least two parts, both the
content or date of each element and the pointer to the next element,
which is shown in the figure below.
+---------+
| Data | -----> holds the data of this element in the list.
+---------+
| pointer | -----> is a pointer to the next element in the list.
+---------+
***Attention***:
The pointer holds the address of the next element, not the address of the
data in the next element, even though they are the same in value sometimes.
And It should be set to NULL while acting as the last node of the list.
Implementation of the single linked list:
+---------+ --->+---------+ --->+---------+
| Data | | | Data | | | Data |
+---------+ | +---------+ | +---------+
| pointer |----- | pointer |----- | pointer |
+---------+ +---------+ +---------+
*/
/* definition of the list node class */
class Node
{
friend class LinkedList;
private:
int _value; /* data, can be any data type, but use integer for easiness */
Node *_pNext; /* pointer to the next node */
public:
/* Constructors with No Arguments */
Node(void)
: _pNext(NULL)
{ }
/* Constructors with a given value */
Node(int val)
: _value(val), _pNext(NULL)
{ }
/* Constructors with a given value and a link of the next node */
Node(int val, Node* next)
: _value(val), _pNext(next)
{}
/* Getters */
int getValue(void)
{ return _value; }
Node* getNext(void)
{ return _pNext; }
};
/* definition of the linked list class */
class LinkedList
{
private:
/* pointer of head node */
Node *_pHead;
/* pointer of tail node */
Node *_pTail;
public:
/* Constructors with No Arguments */
LinkedList(void);
/* Constructors with a given value of a list node */
LinkedList(int val);
/* Destructor */
~LinkedList(void);
/* Function to add a node at the head of a linked list */
void headInsert(int val);
/* Function to add a node in the middle of a linked list */
void insertAfter(Node* afterMe, int val);
/* Function to append a node to the end of a linked list */
void tailAppend(int val);
/* Function to get the node in the specific position */
Node* getNode(int pos);
/* Traversing the list and printing the value of each node */
void traverse_and_print();
};
LinkedList::LinkedList()
{
/* Initialize the head and tail node */
_pHead = _pTail = NULL;
}
LinkedList::LinkedList(int val)
{
/* Create a new node, acting as both the head and tail node */
_pHead = new Node(val);
_pTail = _pHead;
}
LinkedList::~LinkedList()
{
/*
* Leave it empty temporarily.
* It will be described in detail in the example \"How to delete a linkedlist\".
*/
}
void LinkedList::headInsert(int val)
{
/* The list is empty? */
if (_pHead == NULL) {
/* the same to create a new list with a given value */
_pTail = _pHead = new Node(val);
.
A speedometer is a measuring instrument. What are the independent and.pdf
A speedometer is a measuring instrument. What are the independent and dependent variables
when it is used? Give an example of an extraneous variable for this measurement.
Solution
Input time is the independent variable where as out put mileage is the dependent variable.
Mileage is a function which takes something as input that cant be controlled by us. Example for
this is robotic speedometer. It is clear that the dependent variables are derived from independent
variables. Here time is independent variable, the dependent variables can be extended to
derivatives such as velocity,acceleration,etc..
A recent study by the EPA has determined that the amount of contamin.pdf
A recent study by the EPA has determined that the amount of contaminants in Minnesota Lakes
in parts per million averages 64 ppm with a variance of 17.6 Suppose 35 lakes are randomly
seelected and sampled. What is the probability that the sample average amount of contaminants
is between 64 and 72 ppm?
Solution.
choice one correct answerRocks containing iron, calcium, magnesium.pdf
choice one correct answer
Rocks containing iron, calcium, magnesium, or sodium break down into
a) sands and gravels, b) clays
Solution
Answer:- (b) Clays
One types of clay montmorillonite which is hydrated sodium calcium aluminium
Magnesium silicate hydroxide. (Na,Ca)0.33(Al,Mg)2Si4O10(OH)2 . nH2O
Some other type of clay are
Halloysite
Illite
Vermuculite
Talc
Palygorskite.
Recommended
Given a newly created Binary Search Tree with the following numerica.pdf
Given a newly created Binary Search Tree with the following numerical key input sequence
(from left to right): 9, 4, 12, 7, 5, 2, 20, 14, 11, 13, 19, 16, 17, 42, 24
a.) We are asked to add a function Position lowestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position lowestKey(const Position& v);
input argument: position of the starting node in the binary search tree to calculate from. For the
whole tree this would be the position for the root of the tree.
return value: position of the node having the lowest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
b) We are also asked to add a function Position highestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position highestKey(const Position& v) const;
input argument: position of the node in the binary search tree to calculate from. For the whole
tree this would be the position for the root of the tree.
return value: position of the node having the highest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
Solution
#include
#include
/* A binary tree node has data, pointer to left child
and a pointer to right child */
struct node
{
int data;
struct node* left;
struct node* right;
};
/* Helper function that allocates a new node
with the given data and NULL left and right
pointers. */
struct node* newNode(int data)
{
struct node* node = (struct node*)
malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
/* Give a binary search tree and a number,
inserts a new node with the given number in
the correct place in the tree. Returns the new
root pointer which the caller should then use
(the standard trick to avoid using reference
parameters). */
struct node* insert(struct node* node, int data)
{
/* 1. If the tree is empty, return a new,
single node */
if (node == NULL)
return(newNode(data));
else
{
/* 2. Otherwise, recur down the tree */
if (data <= node->data)
node->left = insert(node->left, data);
else
node->right = insert(node->right, data);
/* return the (unchanged) node pointer */
return node;
}
}
/* Given a non-empty binary search tree,
return the minimum data value found in that
tree. Note that the entire tree does not need
to be searched. */
int minValue(struct node* node) {
struct node* current = node;
/* loop down to find the leftmost leaf */
while (current->left != NULL) {
current = current->left;
}
return(current->data);
}
/* Driver program to test sameTree function*/
int main()
{
struct node* root = NULL;
root = insert(root, 4);
insert(root, 2);
insert(root, 1);
insert(root, 3);
insert(root, 6);
insert(root, 5);
printf(\"\ Minimum value in BST is %d\", minValue(root));
getchar();
return 0;
}
#include
#include
/* A binary tree node has data, pointer to left child
.
Gather information on the following two disasters Space shuttle Ch.pdf
Gather information on the following two disasters: Space shuttle \"Challenger\", Jan 1986.
Space shuttle \"Columbia\", Jan 2003. Describe (may still be speculative for Columbia) what
(materials & design as well as political/management factors) caused the disasters.
Solution
Cause of Space shuttle Challenger disaster, Jan 1986:
It was determined that the two rubber O-rings, which had been designed to separate the sections
of the rocket booster, had failed due to cold temperatures on the morning of the launch. This seal,
called an O-ring, on the shuttle\'s right solid rocket booster had failed at liftoff, allowing
pressurized hot gas to escape from inside the booster. This vaporized material impinged on the
strut connecting the solid rocket booster to the shuttle\'s huge orange external tank, causing both
pieces of hardware to break down.
About 72 seconds into Challenger\'s flight, there was a massive, almost explosive, burning of the
hydrogen that was streaming from the failed tank bottom, combined with liquid oxygen leaking
from a part of the fuel tank known as the intertank which eventually lead to the biggest disaster
in the history.
Cause of Space shuttle Columbia disaster, Jan 2003:
This space shuttle Columbia broke apart returning to earth killing all the seven crew members on
the board. An investigation determined that the disaster was caused by a problem that took place
shortly while a large piece of foam fell from the shuttle’s propellant tank and fatally damaged the
edge of the shuttle’s left wing.They lost temperature readings from sensors located on the left
wing. Then, tire pressure readings from the left side also vanished. It was later found that a hole
on the left wing allowed atmospheric gases to bleed into the shuttle as it went through its fiery
re-entry, leading to the loss of the sensors and eventually, Columbia itself.This Columbia disaster
was the second major tragedy in the history of the space shuttle program after the space shuttle
Challenger broke apart shortly after launch on January 28, 1986..
Determine the Laplace transform, F(s), of the following time signal..pdf
Determine the Laplace transform, F(s), of the following time signal.
Solution
we\'ll be interested in signals de¯ned for t ¸ 0
the Laplace transform of a signal (function) f is the function F = L(f)
de¯ned by
F(s) =
Z 1
0
f(t)e¡st dt
for those s 2 C for which the integral makes sense
² F is a complex-valued function of complex numbers
² s is called the (complex) frequency variable, with units sec¡1; t is called
the time variable (in sec); st is unitless
² for now, we assume f contains no impulses at t = 0
common notation convention: lower case letter denotes signal; capital
letter denotes its Laplace transform, e.g., U denotes L(u), Vin denotes
L(vin), etc..
Describe the difference between a monitor and a semaphoreSolutio.pdf
Describe the difference between a monitor and a semaphore
Solution
Monitor: Monitor is a highly structured programming language construct.It consists of Private
variables and private procedures that can only be used within a monitor. Constructors that
initialize the monitor.A number of public monitor procedures that can be invoked by users.
These monitors have no public data.A monitor is a mini OS with monitor procedures as system
calls.
Semaphore: Semaphore is a data structure that is used to provide mutual exclusion to critical
sections. Semaphores mainly support two operations called wait and Signal . The wait operation
blocks a process until the semaphore is open and the signal operation allows another process to
enter.MonitorSemaphoreCondition variables only uses these MonitorsThese can be used in
anywhere but not in Monitorswait() always blocks it\'s callerwait() does not always blocks it\'s
callersignal() either releases a process or the signal is lost as if it never occurssignal() either
releases a process or increases Semaphore counterif signal() releases a process,either the caller
or the released continues,but not bothif signal() releases a process,the caller and the released
both continued.
Create a link list. Add some nodes to it, search and delete nodes fro.pdf
Create a link list. Add some nodes to it, search and delete nodes from it.
Solution
#include
#include
using std::cout;
using std::endl;
/*
A linked list is a list constructed using pointers. It is not fixed in
size and could grow and shrink while the program is running.
A typical defination of list nodes contains at least two parts, both the
content or date of each element and the pointer to the next element,
which is shown in the figure below.
+---------+
| Data | -----> holds the data of this element in the list.
+---------+
| pointer | -----> is a pointer to the next element in the list.
+---------+
***Attention***:
The pointer holds the address of the next element, not the address of the
data in the next element, even though they are the same in value sometimes.
And It should be set to NULL while acting as the last node of the list.
Implementation of the single linked list:
+---------+ --->+---------+ --->+---------+
| Data | | | Data | | | Data |
+---------+ | +---------+ | +---------+
| pointer |----- | pointer |----- | pointer |
+---------+ +---------+ +---------+
*/
/* definition of the list node class */
class Node
{
friend class LinkedList;
private:
int _value; /* data, can be any data type, but use integer for easiness */
Node *_pNext; /* pointer to the next node */
public:
/* Constructors with No Arguments */
Node(void)
: _pNext(NULL)
{ }
/* Constructors with a given value */
Node(int val)
: _value(val), _pNext(NULL)
{ }
/* Constructors with a given value and a link of the next node */
Node(int val, Node* next)
: _value(val), _pNext(next)
{}
/* Getters */
int getValue(void)
{ return _value; }
Node* getNext(void)
{ return _pNext; }
};
/* definition of the linked list class */
class LinkedList
{
private:
/* pointer of head node */
Node *_pHead;
/* pointer of tail node */
Node *_pTail;
public:
/* Constructors with No Arguments */
LinkedList(void);
/* Constructors with a given value of a list node */
LinkedList(int val);
/* Destructor */
~LinkedList(void);
/* Function to add a node at the head of a linked list */
void headInsert(int val);
/* Function to add a node in the middle of a linked list */
void insertAfter(Node* afterMe, int val);
/* Function to append a node to the end of a linked list */
void tailAppend(int val);
/* Function to get the node in the specific position */
Node* getNode(int pos);
/* Traversing the list and printing the value of each node */
void traverse_and_print();
};
LinkedList::LinkedList()
{
/* Initialize the head and tail node */
_pHead = _pTail = NULL;
}
LinkedList::LinkedList(int val)
{
/* Create a new node, acting as both the head and tail node */
_pHead = new Node(val);
_pTail = _pHead;
}
LinkedList::~LinkedList()
{
/*
* Leave it empty temporarily.
* It will be described in detail in the example \"How to delete a linkedlist\".
*/
}
void LinkedList::headInsert(int val)
{
/* The list is empty? */
if (_pHead == NULL) {
/* the same to create a new list with a given value */
_pTail = _pHead = new Node(val);
.
A speedometer is a measuring instrument. What are the independent and.pdf
A speedometer is a measuring instrument. What are the independent and dependent variables
when it is used? Give an example of an extraneous variable for this measurement.
Solution
Input time is the independent variable where as out put mileage is the dependent variable.
Mileage is a function which takes something as input that cant be controlled by us. Example for
this is robotic speedometer. It is clear that the dependent variables are derived from independent
variables. Here time is independent variable, the dependent variables can be extended to
derivatives such as velocity,acceleration,etc..
A recent study by the EPA has determined that the amount of contamin.pdf
A recent study by the EPA has determined that the amount of contaminants in Minnesota Lakes
in parts per million averages 64 ppm with a variance of 17.6 Suppose 35 lakes are randomly
seelected and sampled. What is the probability that the sample average amount of contaminants
is between 64 and 72 ppm?
Solution.
choice one correct answerRocks containing iron, calcium, magnesium.pdf
choice one correct answer
Rocks containing iron, calcium, magnesium, or sodium break down into
a) sands and gravels, b) clays
Solution
Answer:- (b) Clays
One types of clay montmorillonite which is hydrated sodium calcium aluminium
Magnesium silicate hydroxide. (Na,Ca)0.33(Al,Mg)2Si4O10(OH)2 . nH2O
Some other type of clay are
Halloysite
Illite
Vermuculite
Talc
Palygorskite.
1.write down the RTL for the SUBT instructions. 2.Draw a flowchart.pdf
1.write down the RTL for the SUBT instructions.
2.Draw a flowchart to indicate SUBT instructions is processed.
Solution
1)
RTL is a easy human understandable language to specify or to perform the operations
SUBT is instruction which is used to perform or subtracts the Source operand from destination
operand and the subtracted result is stored into destination operand
Conditions
Source operand should be a register or a memory location or may be a immediate address
Destination operand should be a Register or memory location but not be a Immediate address
At a single time its not possible if both source and destinations to be a memory locations
General format of a SUB RTL(Register Transfer Language) format
SUB DESTINATION OPERAND,SOURCE OPERAND;
eg
SUB AX,18H;
SUB AX,BX;
SUB AX,[2000H];
2)
FLOW CHART to indicate SUBT instruction process
Instruction Cycle Implementation
1) Fetching of instructions will be performed at first
2) Updation of PC(Program counter will takes place) in second stage
3) Decoding of fetched instructions will be takes place in next stage
4) Execution of given eithr arthemetic or logic or conditional or unconditional or anyother
operations will takes place in the later stage
If Incase of SUB instruction Both Source and destinations datas are retrieved then it will check
Sign of both datas,If.
Write a Java application that asks for an integer and returns its fac.pdf
Write a Java application that asks for an integer and returns its factorization into prime factors
including their powers. The prime factors must appear in increasing order. For example if 120 (=
2*2*2*3*5) in the input number, then your program should output 120 = 2^3 * 3^1 * 5^1 The
factors should appear in increasing order and should be separated from each other by asterisks
(*).
Solution
import java.util.Scanner;
public class factorialFactorization {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.print(\"Enter a number:\");
int n = scan.nextInt();
int fact=1;
for(int i=2;i<=n;i++)
{
fact = fact*i;
}
int count=0,hat=0;
System.out.print(fact);
System.out.print(\" = \");
for(int i=2;fact>1;i++)
{
count = 0;
while(true)
{
if(fact%i==0)
{
count++;
fact = fact/i;
}
else
{
break;
}
}
if(count>0)
{
if(hat>0)
{
System.out.print(\" * \");
}
System.out.print(i);
System.out.print(\"^\");
System.out.print(count);
hat ++;
}
}
}
}.
What is the name of the connective tissue that divides the se.pdf
What is the name of the connective tissue that \"divides\" the segments of the rectus abdominis
muscles?
What is the name of the connective tissue that \"divides\" the segments of the rectus abdominis
muscles?
Solution
Linea alba is a band of connective tissue which is present either sides of the rectus abdominal
muscle and divides the muscle in two halves..
What is the current ratio of Chester Use the results of the Balance.pdf
What is the current ratio of Chester? Use the results of the Balance Sheet Survey Below.Balance
Sheet
SurveyAndrewsBaldwinChesterDigbyErieFerrisCash$3,434$0$15,756$3,605$52,632$5,613Acc
ounts
Receivable$8,307$14,914$12,076$9,550$16,903$4,576Inventory$8,617$25,931$5,044$3,491$3
,473$10,616Total Current Assets$20,358$40,845$32,876$16,646$73,008$20,804Plant and
equipment$113,800$177,400$124,100$122,200$193,600$78,300Accumulated
Depreciation($37,933)($76,903)($33,454)($40,920)($71,416)($42,600)Total Fixed
Assets$75,867$100,497$90,646$81,280$122,184$35,700Total
Assets$96,225$141,342$123,523$97,926$195,192$56,504Accounts
Payable$6,583$8,687$11,450$4,443$10,571$3,463Current
Debt$0$12,555$7,550$10,000$21,830$9,975Long Term
Debt$41,700$69,850$56,850$59,850$59,643$16,308Total
Liabilities$48,283$91,092$75,850$74,293$92,044$29,747Common
Stock$18,360$22,860$22,775$18,360$24,310$19,119Retained
Earnings$29,582$27,391$24,898$5,273$78,839$7,638Total
Equity$47,942$50,251$47,673$23,633$103,148$26,757Total Liabilities & Owner\'s
Equity$96,225$141,342$123,523$97,926$195,192$56,504
Solution
Current ratio = Total Current Assets /Current Liabilities = 32876/(11450+7550)= 1.73.
What is glass-transition temperature Give a material example. How ma.pdf
What is glass-transition temperature? Give a material example. How many types of polymer
structures do you know? Briefly explain each type of polymer structures. b) What is creep and
what is stress relaxation? c) What are the two structure components in reinforced plastics and
what are the functions of each of them? What are the advantages and disadvantages of reinforced
plastics comparing with the regular plastics?
Solution
a) The glass–liquid transition or glass transition for short is the reversible transition in
amorphous materials (or in amorphous regions within semicrystalline materials) from a hard and
relatively brittle \"glassy\" state into a molten or rubber-like state, as the temperature is
increased. An amorphous solid that exhibits a glass transition is called a glass.
The glass-transition temperatureTg of a material characterizes the range of temperatures over
which this glass transition occurs. It is always lower than the melting temperature, Tm, of the
crystalline state of the material, if one exists.
Examples Rubber elastomers like polyisoprene and polyisobutylene are used above their Tg\'s,
that is, in the rubbery state, where they are soft and flexible.
Typical polymer structures are
b) creep is the tendency of a solid material to move slowly or deform permanently under the
influence of mechanical stresses. It can occur as a result of long-term exposure to high levels of
stress that are still below the yield strength of the material. Creep is more severe in materials that
are subjected to heatfor long periods, and generally increases as they near their melting point.
Stress relaxation is defined as a gradual decrease in stress with time under a constant
deformation or strain.
c) Fibre-reinforced plastic is a composite material made of a polymer matrix reinforced with
fibres. The fibres are usually glass, carbon,aramid, or basalt. Rarely, other fibres such as paper or
wood or asbestos have been used. The polymer is usually an epoxy, vinylester or polyester
thermosetting plastic, andphenol formaldehyde resins are still in use.
Advantages
Disadvantages.
What are some contributions to the development of industrializat.pdf
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
Solution
Answer:
The steam engine was one of the most important technologies of the Industrial Revolution,
although steam did not replace water power in importance in Britain until after the Industrial
Revolution. From Englishman Thomas Newcomen\'s atmospheric engine, of 1712, through
major developments by Scottish inventor and mechanical engineer James Watt, the steam engine
began to be used in many industrial settings, not just in mining, where the first engines had been
used to pump water from deep workings. Early mills had run successfully with water power, but
by using a steam engine a factory could be located anywhere, not just close to water. Water
power varied with the seasons and was not available at times due to freezing, floods and dry
spells
The technological advances of the Industrial Revolution happened more quickly because firms
often shared information, which they then could use to create new techniques or products. From
mines to mills, steam engines found many uses in a variety of industries. The introduction of
steam engines improved productivity and technology, and allowed the creation of smaller and
better engines.
The development of the stationary steam engine was an essential early element of the Industrial
Revolution, however it should be remembered that for most of the period of the Industrial
Revolution the majority of industries still relied on wind and water power as well as horse and
man-power for driving small machines. Transportation was one of those important beneficiaries.
By the early 1800s, high-pressure steam engines had become compact enough to move beyond
the factory, prompting the first steam-powered locomotive to hit the rails in Britain in 1804. For
the first time in history, goods were transported over land by something other than the muscle of
man or animal. The railroad rapidly spread and sped transportation. This created new jobs,
forcing people to move into cities. Cities like London, for example, the steam engine and
locomotive propelled countless other industries such as driving bellows and rollers, spinning
machines, and weaving machines. And, for the first time in history, people had the ability to
quickly and cheaply move to big cities to find work, as opposed to working on a farm.
Subsequently, it had a major impact on businesses, as it boosted production of natural resources,
which were vital to society, and created numerou.
The “creative revolution” that handed more authority to agency art d.pdf
The “creative revolution” that handed more authority to agency art directors and copywriters in
the 1960s led to key shifts in the appearance and message of mainstream advertising. Describe
these changes and how they continue to influence advertising today.
Solution
The key shift in terms of appearance and message of mainstream advertising was that the
commercials started using irony and irreverence to reach out to the young customers.
The situation was that the young customers were indifferent to advertisements by companies at
that time. Advertisements were designed, both in terms of its message and appearance, to
connect with the youth.
Secondly, the creative revolution also saw social messages and issues being used in commercials
and advertisements.
These changes continue to influence advertising today. Advertisements, be it print or any other
media, increasingly are targeting the youths. Marketers are not afraid of using self deprecating
humor or using social messages in today\'s advertisements and commercials..
The three main coefficients (not properties or dimensionless numbers).pdf
The three main coefficients (not properties or dimensionless numbers) interphase transport are
For momentum transport For heat transport For mass transport Write two assumptions of
Navier Stoke equation. What is the assumption of Euler\'s equation?
Solution
Assumption for navier stroke:
1. Continuous media
2. Viscous constant
3. Incompressible
4. Steady state
5. Fully developed
Assumption of euler equation:
The fluid is non-viscous (i,e., the frictional losses are zero).
The fluid is homogeneous and incompressible (i.e., mass density of the fluid is constant).
The flow is continuous, steady and along the streamline..
The project will study the coordination of multiple threads using se.pdf
The project will study the coordination of multiple threads using semaphores.
The design should consist of two things:
(1) a list of every semaphore, its purpose, and its initial value, and
(2) pseudocode for each function. Code Your code should be nicely formatted with plenty of
comments. The code should be easy to read, properly indented, employ good naming standards,
good structure, and should correctly implement the design. Your code should match your
pseudocode.
Project Language/Platform
This project must target a Unix platform and execute properly on our cs1 or csgrads1 Linux
server.
The project must be written in Java. Elevator Simulation In this project threads are used to
simulate people using an elevator to reach their floor.
The threads to be used are as follows: Person:
1) 49 people are in line at the elevator at the beginning of the simulation (1 thread per person).
2) Each person begins at floor 1.
3) Each person randomly picks a floor from 2 to 10.
4) A person will wait for an elevator to arrive at floor 1.
5) A person will board the elevator only if there is room.
6) Once at the destination floor, the person exits the elevator.
Elevator:
1) There is 1 elevator (1 thread for the elevator).
2) The elevator can only hold 7 people.
3) The elevator begins on floor 1.
4) The elevator leaves after the 7th person enters.
Main
1) Creates all threads and joins all person threads.
2) When last person reaches their floor, the simulation ends.
Other rules:
1) Each activity of each thread should be printed with identification (e.g., person 1).
2) A thread may not use sleeping as a means of coordinating with other threads.
3) Busy waiting (polling) is not allowed.
4) Mutual exclusion should be kept to a minimum to allow the most concurrency.
5) The semaphore value may not obtained and used as a basis for program logic.
6) All activities of a thread should only be output by that thread. Sample output:
Your project’s output should match the wording of the sample output:
Elevator door opens at floor 1
Person 0 enters elevator to go to floor 5
Person 1 enters elevator to go to floor 2
Person 2 enters elevator to go to floor 8
Person 3 enters elevator to go to floor 4
Person 4 enters elevator to go to floor 6
Person 5 enters elevator to go to floor 7
Person 6 enters elevator to go to floor 2
Elevator door closes
Elevator door opens at floor 2
Person 1 leaves elevator
Person 6 leaves elevator
Elevator door closes
Elevator door opens at floor 4
Person 3 leaves elevator
Elevator door closes
Elevator door opens at floor 5
Person 0 leaves elevator
Elevator door closes
Elevator door opens at floor 6
Person 4 leaves elevator
Elevator door closes
Elevator door opens at floor 7
Person 5 leaves elevator
Elevator door closes
Elevator door opens at floor 8
Person 2 leaves elevator
Elevator door closes
Elevator door opens at floor 1
…
Simulation done
Solution
public class Person implements Runnable{
//possible actions
public static final int WAITING = 1;
publ.
The positive selection process for T lymphocytes that occurs In the t.pdf
The positive selection process for T lymphocytes that occurs In the thymus Involves selection of
T lymphocytes that have a high affinity for MHC have a high affinity for MHC and self peptide
have a low affinity for MHC and self peptide have a low affinity for MHC
Solution
Answer c: Positive selection select cells with a T cell receptor able to bind MHC class I and II
molecules with at least a weak affinity.hence answer c is correct..
The local public health agency has received reports of an outbreak o.pdf
The local health agency received reports of a Salmonella outbreak among attendees at a chili cook-off. To investigate, the agency would use molecular identification techniques like FISH or ERIC-PCR to establish that gastroenteritis was caused by Salmonella. They would also use molecular phylogenetic techniques like 16S rRNA sequencing or MLST to determine if attendees were infected by the same Salmonella strain.
how are musical sounds produced Explain your reasoning.Solution.pdf
how are musical sounds produced? Explain your reasoning.
Solution
Almost all musical programs are produced
basically in two stages:
(1) Sound from each individual intrument is recorded in an acoustically inert studio on a single
track of a multitrack tape recorder
(2) Signals from each track are manipulated by the sound engineer by adding special audio
effects and then combined in a mix-down system to generate the final stereo recording on a two-
track tape recorder
The special audio effects are either generated using time-domain operations or frequency-domain
operations.
Commonly used time-domain operations are echo generation,reverberation,flanging,chorus
generation, and
phasing.
Commonly used frequency-domain operations are filters and equalizers.
Please fill in the blanks with the correct information organs Tissue.pdf
Please fill in the blanks with the correct information organs Tissues Locations Characteristics
Functions cell Types shoots Dermal Dermal roots Leaves Parenchyma stems Ground
Collenchyma and Scleren roots Xylem vessel elements and tracheids Vascular Phloem sieve tube
cells and companion Cells Parenchyma Meristematic
Solution
Characteristic functions: Photosynthesis, respiration, storage, structural support.
3. Vascular Tissues:
Location: in tubes, throughout the plant
Characteristic functions: Support, Transport
4. Meristematic Tissues:
Location: Apical- tips of stems and roots; Intercalary- between tip and base of stems and leaves;
Lateral- sides of stems and roots.
Characteristic functions: Growth, increase in length at tips, between nodes and diameter..
5. What is the role of the SRY gene in determining sexSolution.pdf
5. What is the role of the SRY gene in determining sex?
Solution
ANS:
SRY (Sex Determining Region of Y chromosome) Gene:
In the early stage of embryonic development, immature gonads of male and female are
indistinguishable.
Male: During the 7th week of embryonic development, SRY gene present on the Y chromosome
is activated. So due to these later gonads develops into testes.
Female: In females SRY gene is absent, so gonads later develops into ovaries by default.
The Y chromosome in humans contains SRY gene. This gene can capable to produce TDF (testis
determining factor).
On Y chromosome approximately 150 genes are present. SRY region only determines male
characteristics.
In mice spontaneous deletion or insertion of SRY gene can results, in mice with XX have testes
and XY mice present with ovaries..
Outliers We know many types of data fall into a normal distribution.pdf
Outliers: We know many types of data fall into a normal distribution with most of the
observations falling toward the middle. However, sometimes data are outliers or data that are
very different -larger or smaller- from the rest of the members of the sample. Think of an
example in the real world of an outlier and discuss its effect.
Solution
Outliers may be appears in the parent population is non-normal or for small samples. in real
world many of the examples can be seen..
Explain why the cultural differences argument is not soundSolut.pdf
Explain why the cultural differences argument is not sound?
Solution
Because of Cultural Relativism.
=================================================
To numerous scholars, this observation.
\"Different societies have distinctive good codes,
has appeared to be the way to comprehension profound quality. The possibility of generally
accepted fact in morals, they say, is a myth. The traditions of various social orders are all that
exist. These traditions can\'t be said to be \"right\" or \"inaccurate,\" for that infers we have an
autonomous standard of good and bad by which they might be judged. Yet, there is no such free
standard; each standard is culture-bound. The colossal spearheading humanist William Graham
Sumner, writing in 1906, put the point this way:
The \"right\" way is the way which the precursors utilized and which has been passed on. The
custom is its own warrant. It is not held subject to check by involvement. The idea of right is in
the folkways. It is not outside of them, of autonomous root, and conveyed to test them. In the
folkways, whatever is, is correct. This is on the grounds that they are conventional, and
accordingly contain in themselves the specialist of the tribal apparitions. When we go to the
folkways we are toward the finish of our investigation.
This line of thought has most likely induced a bigger number of individuals to be suspicious
about morals than some other single thing. Social Relativism, as it has been called, challenges
our conventional faith in the objectivity and all inclusiveness of good truth. It says, as a result,
that there is not such thing as generally accepted fact in morals; there are just the different social
codes, and nothing more. Besides, our own code has no uncommon status; it is only one among
numerous..
In the diagram of a villus shown here, atructure A belong to the sys.pdf
In the diagram of a villus shown here, atructure A belong to the system of the body known as the
a. Circulatory system
b. Lymphatic system
c. Digestive system
d. Respiratory system
e. Excretory system emmmmmmmmmmmmmmmmmmmmmns
Solution
Ans . B Lymphatic system
Option A shown in the diagram is Lymphatic system. lacteal is a lymphatic capillary that absorbs
dietary fats in the villi of the small intestine.
Earths atmosphere has not always contained enough oxygen to support.pdf
Earth\'s atmosphere has not always contained enough oxygen to support life. What was
responsible for enriching Earth\'s atmosphere with oxygen\'? photosynthesis by cyanobacteria an
asteroid colliding with Earth the evolution of land animals photosynthesis by early land plants
Solution
Photosynthesis by cyanobacteria is responsible for enriching Earth\'s atmosphere with oxygen..
PCOS corelations and management through Ayurveda.
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
it describes the bony anatomy including the femoral head , acetabulum, labrum . also discusses the capsule , ligaments . muscle that act on the hip joint and the range of motion are outlined. factors affecting hip joint stability and weight transmission through the joint are summarized.
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...National Information Standards Organization (NISO)
This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.How to Create a More Engaging and Human Online Learning Experience
How to Create a More Engaging and Human Online Learning Experience Wahiba Chair Training & Consulting
Wahiba Chair's Talk at the 2024 Learning Ideas Conference. More Related Content
More from hadpadrrajeshh
1.write down the RTL for the SUBT instructions. 2.Draw a flowchart.pdf
1.write down the RTL for the SUBT instructions.
2.Draw a flowchart to indicate SUBT instructions is processed.
Solution
1)
RTL is a easy human understandable language to specify or to perform the operations
SUBT is instruction which is used to perform or subtracts the Source operand from destination
operand and the subtracted result is stored into destination operand
Conditions
Source operand should be a register or a memory location or may be a immediate address
Destination operand should be a Register or memory location but not be a Immediate address
At a single time its not possible if both source and destinations to be a memory locations
General format of a SUB RTL(Register Transfer Language) format
SUB DESTINATION OPERAND,SOURCE OPERAND;
eg
SUB AX,18H;
SUB AX,BX;
SUB AX,[2000H];
2)
FLOW CHART to indicate SUBT instruction process
Instruction Cycle Implementation
1) Fetching of instructions will be performed at first
2) Updation of PC(Program counter will takes place) in second stage
3) Decoding of fetched instructions will be takes place in next stage
4) Execution of given eithr arthemetic or logic or conditional or unconditional or anyother
operations will takes place in the later stage
If Incase of SUB instruction Both Source and destinations datas are retrieved then it will check
Sign of both datas,If.
Write a Java application that asks for an integer and returns its fac.pdf
Write a Java application that asks for an integer and returns its factorization into prime factors
including their powers. The prime factors must appear in increasing order. For example if 120 (=
2*2*2*3*5) in the input number, then your program should output 120 = 2^3 * 3^1 * 5^1 The
factors should appear in increasing order and should be separated from each other by asterisks
(*).
Solution
import java.util.Scanner;
public class factorialFactorization {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.print(\"Enter a number:\");
int n = scan.nextInt();
int fact=1;
for(int i=2;i<=n;i++)
{
fact = fact*i;
}
int count=0,hat=0;
System.out.print(fact);
System.out.print(\" = \");
for(int i=2;fact>1;i++)
{
count = 0;
while(true)
{
if(fact%i==0)
{
count++;
fact = fact/i;
}
else
{
break;
}
}
if(count>0)
{
if(hat>0)
{
System.out.print(\" * \");
}
System.out.print(i);
System.out.print(\"^\");
System.out.print(count);
hat ++;
}
}
}
}.
What is the name of the connective tissue that divides the se.pdf
What is the name of the connective tissue that \"divides\" the segments of the rectus abdominis
muscles?
What is the name of the connective tissue that \"divides\" the segments of the rectus abdominis
muscles?
Solution
Linea alba is a band of connective tissue which is present either sides of the rectus abdominal
muscle and divides the muscle in two halves..
What is the current ratio of Chester Use the results of the Balance.pdf
What is the current ratio of Chester? Use the results of the Balance Sheet Survey Below.Balance
Sheet
SurveyAndrewsBaldwinChesterDigbyErieFerrisCash$3,434$0$15,756$3,605$52,632$5,613Acc
ounts
Receivable$8,307$14,914$12,076$9,550$16,903$4,576Inventory$8,617$25,931$5,044$3,491$3
,473$10,616Total Current Assets$20,358$40,845$32,876$16,646$73,008$20,804Plant and
equipment$113,800$177,400$124,100$122,200$193,600$78,300Accumulated
Depreciation($37,933)($76,903)($33,454)($40,920)($71,416)($42,600)Total Fixed
Assets$75,867$100,497$90,646$81,280$122,184$35,700Total
Assets$96,225$141,342$123,523$97,926$195,192$56,504Accounts
Payable$6,583$8,687$11,450$4,443$10,571$3,463Current
Debt$0$12,555$7,550$10,000$21,830$9,975Long Term
Debt$41,700$69,850$56,850$59,850$59,643$16,308Total
Liabilities$48,283$91,092$75,850$74,293$92,044$29,747Common
Stock$18,360$22,860$22,775$18,360$24,310$19,119Retained
Earnings$29,582$27,391$24,898$5,273$78,839$7,638Total
Equity$47,942$50,251$47,673$23,633$103,148$26,757Total Liabilities & Owner\'s
Equity$96,225$141,342$123,523$97,926$195,192$56,504
Solution
Current ratio = Total Current Assets /Current Liabilities = 32876/(11450+7550)= 1.73.
What is glass-transition temperature Give a material example. How ma.pdf
What is glass-transition temperature? Give a material example. How many types of polymer
structures do you know? Briefly explain each type of polymer structures. b) What is creep and
what is stress relaxation? c) What are the two structure components in reinforced plastics and
what are the functions of each of them? What are the advantages and disadvantages of reinforced
plastics comparing with the regular plastics?
Solution
a) The glass–liquid transition or glass transition for short is the reversible transition in
amorphous materials (or in amorphous regions within semicrystalline materials) from a hard and
relatively brittle \"glassy\" state into a molten or rubber-like state, as the temperature is
increased. An amorphous solid that exhibits a glass transition is called a glass.
The glass-transition temperatureTg of a material characterizes the range of temperatures over
which this glass transition occurs. It is always lower than the melting temperature, Tm, of the
crystalline state of the material, if one exists.
Examples Rubber elastomers like polyisoprene and polyisobutylene are used above their Tg\'s,
that is, in the rubbery state, where they are soft and flexible.
Typical polymer structures are
b) creep is the tendency of a solid material to move slowly or deform permanently under the
influence of mechanical stresses. It can occur as a result of long-term exposure to high levels of
stress that are still below the yield strength of the material. Creep is more severe in materials that
are subjected to heatfor long periods, and generally increases as they near their melting point.
Stress relaxation is defined as a gradual decrease in stress with time under a constant
deformation or strain.
c) Fibre-reinforced plastic is a composite material made of a polymer matrix reinforced with
fibres. The fibres are usually glass, carbon,aramid, or basalt. Rarely, other fibres such as paper or
wood or asbestos have been used. The polymer is usually an epoxy, vinylester or polyester
thermosetting plastic, andphenol formaldehyde resins are still in use.
Advantages
Disadvantages.
What are some contributions to the development of industrializat.pdf
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
Solution
Answer:
The steam engine was one of the most important technologies of the Industrial Revolution,
although steam did not replace water power in importance in Britain until after the Industrial
Revolution. From Englishman Thomas Newcomen\'s atmospheric engine, of 1712, through
major developments by Scottish inventor and mechanical engineer James Watt, the steam engine
began to be used in many industrial settings, not just in mining, where the first engines had been
used to pump water from deep workings. Early mills had run successfully with water power, but
by using a steam engine a factory could be located anywhere, not just close to water. Water
power varied with the seasons and was not available at times due to freezing, floods and dry
spells
The technological advances of the Industrial Revolution happened more quickly because firms
often shared information, which they then could use to create new techniques or products. From
mines to mills, steam engines found many uses in a variety of industries. The introduction of
steam engines improved productivity and technology, and allowed the creation of smaller and
better engines.
The development of the stationary steam engine was an essential early element of the Industrial
Revolution, however it should be remembered that for most of the period of the Industrial
Revolution the majority of industries still relied on wind and water power as well as horse and
man-power for driving small machines. Transportation was one of those important beneficiaries.
By the early 1800s, high-pressure steam engines had become compact enough to move beyond
the factory, prompting the first steam-powered locomotive to hit the rails in Britain in 1804. For
the first time in history, goods were transported over land by something other than the muscle of
man or animal. The railroad rapidly spread and sped transportation. This created new jobs,
forcing people to move into cities. Cities like London, for example, the steam engine and
locomotive propelled countless other industries such as driving bellows and rollers, spinning
machines, and weaving machines. And, for the first time in history, people had the ability to
quickly and cheaply move to big cities to find work, as opposed to working on a farm.
Subsequently, it had a major impact on businesses, as it boosted production of natural resources,
which were vital to society, and created numerou.
The “creative revolution” that handed more authority to agency art d.pdf
The “creative revolution” that handed more authority to agency art directors and copywriters in
the 1960s led to key shifts in the appearance and message of mainstream advertising. Describe
these changes and how they continue to influence advertising today.
Solution
The key shift in terms of appearance and message of mainstream advertising was that the
commercials started using irony and irreverence to reach out to the young customers.
The situation was that the young customers were indifferent to advertisements by companies at
that time. Advertisements were designed, both in terms of its message and appearance, to
connect with the youth.
Secondly, the creative revolution also saw social messages and issues being used in commercials
and advertisements.
These changes continue to influence advertising today. Advertisements, be it print or any other
media, increasingly are targeting the youths. Marketers are not afraid of using self deprecating
humor or using social messages in today\'s advertisements and commercials..
The three main coefficients (not properties or dimensionless numbers).pdf
The three main coefficients (not properties or dimensionless numbers) interphase transport are
For momentum transport For heat transport For mass transport Write two assumptions of
Navier Stoke equation. What is the assumption of Euler\'s equation?
Solution
Assumption for navier stroke:
1. Continuous media
2. Viscous constant
3. Incompressible
4. Steady state
5. Fully developed
Assumption of euler equation:
The fluid is non-viscous (i,e., the frictional losses are zero).
The fluid is homogeneous and incompressible (i.e., mass density of the fluid is constant).
The flow is continuous, steady and along the streamline..
The project will study the coordination of multiple threads using se.pdf
The project will study the coordination of multiple threads using semaphores.
The design should consist of two things:
(1) a list of every semaphore, its purpose, and its initial value, and
(2) pseudocode for each function. Code Your code should be nicely formatted with plenty of
comments. The code should be easy to read, properly indented, employ good naming standards,
good structure, and should correctly implement the design. Your code should match your
pseudocode.
Project Language/Platform
This project must target a Unix platform and execute properly on our cs1 or csgrads1 Linux
server.
The project must be written in Java. Elevator Simulation In this project threads are used to
simulate people using an elevator to reach their floor.
The threads to be used are as follows: Person:
1) 49 people are in line at the elevator at the beginning of the simulation (1 thread per person).
2) Each person begins at floor 1.
3) Each person randomly picks a floor from 2 to 10.
4) A person will wait for an elevator to arrive at floor 1.
5) A person will board the elevator only if there is room.
6) Once at the destination floor, the person exits the elevator.
Elevator:
1) There is 1 elevator (1 thread for the elevator).
2) The elevator can only hold 7 people.
3) The elevator begins on floor 1.
4) The elevator leaves after the 7th person enters.
Main
1) Creates all threads and joins all person threads.
2) When last person reaches their floor, the simulation ends.
Other rules:
1) Each activity of each thread should be printed with identification (e.g., person 1).
2) A thread may not use sleeping as a means of coordinating with other threads.
3) Busy waiting (polling) is not allowed.
4) Mutual exclusion should be kept to a minimum to allow the most concurrency.
5) The semaphore value may not obtained and used as a basis for program logic.
6) All activities of a thread should only be output by that thread. Sample output:
Your project’s output should match the wording of the sample output:
Elevator door opens at floor 1
Person 0 enters elevator to go to floor 5
Person 1 enters elevator to go to floor 2
Person 2 enters elevator to go to floor 8
Person 3 enters elevator to go to floor 4
Person 4 enters elevator to go to floor 6
Person 5 enters elevator to go to floor 7
Person 6 enters elevator to go to floor 2
Elevator door closes
Elevator door opens at floor 2
Person 1 leaves elevator
Person 6 leaves elevator
Elevator door closes
Elevator door opens at floor 4
Person 3 leaves elevator
Elevator door closes
Elevator door opens at floor 5
Person 0 leaves elevator
Elevator door closes
Elevator door opens at floor 6
Person 4 leaves elevator
Elevator door closes
Elevator door opens at floor 7
Person 5 leaves elevator
Elevator door closes
Elevator door opens at floor 8
Person 2 leaves elevator
Elevator door closes
Elevator door opens at floor 1
…
Simulation done
Solution
public class Person implements Runnable{
//possible actions
public static final int WAITING = 1;
publ.
The positive selection process for T lymphocytes that occurs In the t.pdf
The positive selection process for T lymphocytes that occurs In the thymus Involves selection of
T lymphocytes that have a high affinity for MHC have a high affinity for MHC and self peptide
have a low affinity for MHC and self peptide have a low affinity for MHC
Solution
Answer c: Positive selection select cells with a T cell receptor able to bind MHC class I and II
molecules with at least a weak affinity.hence answer c is correct..
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The local health agency received reports of a Salmonella outbreak among attendees at a chili cook-off. To investigate, the agency would use molecular identification techniques like FISH or ERIC-PCR to establish that gastroenteritis was caused by Salmonella. They would also use molecular phylogenetic techniques like 16S rRNA sequencing or MLST to determine if attendees were infected by the same Salmonella strain.
how are musical sounds produced Explain your reasoning.Solution.pdf
how are musical sounds produced? Explain your reasoning.
Solution
Almost all musical programs are produced
basically in two stages:
(1) Sound from each individual intrument is recorded in an acoustically inert studio on a single
track of a multitrack tape recorder
(2) Signals from each track are manipulated by the sound engineer by adding special audio
effects and then combined in a mix-down system to generate the final stereo recording on a two-
track tape recorder
The special audio effects are either generated using time-domain operations or frequency-domain
operations.
Commonly used time-domain operations are echo generation,reverberation,flanging,chorus
generation, and
phasing.
Commonly used frequency-domain operations are filters and equalizers.
Please fill in the blanks with the correct information organs Tissue.pdf
Please fill in the blanks with the correct information organs Tissues Locations Characteristics
Functions cell Types shoots Dermal Dermal roots Leaves Parenchyma stems Ground
Collenchyma and Scleren roots Xylem vessel elements and tracheids Vascular Phloem sieve tube
cells and companion Cells Parenchyma Meristematic
Solution
Characteristic functions: Photosynthesis, respiration, storage, structural support.
3. Vascular Tissues:
Location: in tubes, throughout the plant
Characteristic functions: Support, Transport
4. Meristematic Tissues:
Location: Apical- tips of stems and roots; Intercalary- between tip and base of stems and leaves;
Lateral- sides of stems and roots.
Characteristic functions: Growth, increase in length at tips, between nodes and diameter..
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5. What is the role of the SRY gene in determining sex?
Solution
ANS:
SRY (Sex Determining Region of Y chromosome) Gene:
In the early stage of embryonic development, immature gonads of male and female are
indistinguishable.
Male: During the 7th week of embryonic development, SRY gene present on the Y chromosome
is activated. So due to these later gonads develops into testes.
Female: In females SRY gene is absent, so gonads later develops into ovaries by default.
The Y chromosome in humans contains SRY gene. This gene can capable to produce TDF (testis
determining factor).
On Y chromosome approximately 150 genes are present. SRY region only determines male
characteristics.
In mice spontaneous deletion or insertion of SRY gene can results, in mice with XX have testes
and XY mice present with ovaries..
Outliers We know many types of data fall into a normal distribution.pdf
Outliers: We know many types of data fall into a normal distribution with most of the
observations falling toward the middle. However, sometimes data are outliers or data that are
very different -larger or smaller- from the rest of the members of the sample. Think of an
example in the real world of an outlier and discuss its effect.
Solution
Outliers may be appears in the parent population is non-normal or for small samples. in real
world many of the examples can be seen..
Explain why the cultural differences argument is not soundSolut.pdf
Explain why the cultural differences argument is not sound?
Solution
Because of Cultural Relativism.
=================================================
To numerous scholars, this observation.
\"Different societies have distinctive good codes,
has appeared to be the way to comprehension profound quality. The possibility of generally
accepted fact in morals, they say, is a myth. The traditions of various social orders are all that
exist. These traditions can\'t be said to be \"right\" or \"inaccurate,\" for that infers we have an
autonomous standard of good and bad by which they might be judged. Yet, there is no such free
standard; each standard is culture-bound. The colossal spearheading humanist William Graham
Sumner, writing in 1906, put the point this way:
The \"right\" way is the way which the precursors utilized and which has been passed on. The
custom is its own warrant. It is not held subject to check by involvement. The idea of right is in
the folkways. It is not outside of them, of autonomous root, and conveyed to test them. In the
folkways, whatever is, is correct. This is on the grounds that they are conventional, and
accordingly contain in themselves the specialist of the tribal apparitions. When we go to the
folkways we are toward the finish of our investigation.
This line of thought has most likely induced a bigger number of individuals to be suspicious
about morals than some other single thing. Social Relativism, as it has been called, challenges
our conventional faith in the objectivity and all inclusiveness of good truth. It says, as a result,
that there is not such thing as generally accepted fact in morals; there are just the different social
codes, and nothing more. Besides, our own code has no uncommon status; it is only one among
numerous..
In the diagram of a villus shown here, atructure A belong to the sys.pdf
In the diagram of a villus shown here, atructure A belong to the system of the body known as the
a. Circulatory system
b. Lymphatic system
c. Digestive system
d. Respiratory system
e. Excretory system emmmmmmmmmmmmmmmmmmmmmns
Solution
Ans . B Lymphatic system
Option A shown in the diagram is Lymphatic system. lacteal is a lymphatic capillary that absorbs
dietary fats in the villi of the small intestine.
Earths atmosphere has not always contained enough oxygen to support.pdf
Earth\'s atmosphere has not always contained enough oxygen to support life. What was
responsible for enriching Earth\'s atmosphere with oxygen\'? photosynthesis by cyanobacteria an
asteroid colliding with Earth the evolution of land animals photosynthesis by early land plants
Solution
Photosynthesis by cyanobacteria is responsible for enriching Earth\'s atmosphere with oxygen..
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Chapter 2
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