Write a Java application that asks for an integer and returns its fac.pdf
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Write a Java application that asks for an integer and returns its factorization into prime factors including their powers. The prime factors must appear in increasing order. For example if 120 (= 2*2*2*3*5) in the input number, then your program should output 120 = 2^3 * 3^1 * 5^1 The factors should appear in increasing order and should be separated from each other by asterisks (*). Solution import java.util.Scanner; public class factorialFactorization { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); System.out.print(\"Enter a number:\"); int n = scan.nextInt(); int fact=1; for(int i=2;i<=n;i++) { fact = fact*i; } int count=0,hat=0; System.out.print(fact); System.out.print(\" = \"); for(int i=2;fact>1;i++) { count = 0; while(true) { if(fact%i==0) { count++; fact = fact/i; } else { break; } } if(count>0) { if(hat>0) { System.out.print(\" * \"); } System.out.print(i); System.out.print(\"^\"); System.out.print(count); hat ++; } } } }.
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![Write a Java application that asks for an integer and returns its factorization into prime factors
including their powers. The prime factors must appear in increasing order. For example if 120 (=
2*2*2*3*5) in the input number, then your program should output 120 = 2^3 * 3^1 * 5^1 The
factors should appear in increasing order and should be separated from each other by asterisks
(*).
Solution
import java.util.Scanner;
public class factorialFactorization {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.print("Enter a number:");
int n = scan.nextInt();
int fact=1;
for(int i=2;i<=n;i++)
{
fact = fact*i;
}
int count=0,hat=0;
System.out.print(fact);
System.out.print(" = ");
for(int i=2;fact>1;i++)
{
count = 0;
while(true)
{
if(fact%i==0)
{
count++;
fact = fact/i;](https://image.slidesharecdn.com/writeajavaapplicationthatasksforanintegerandreturnsitsfac-230706230249-e50e4fb1/85/Write-a-Java-application-that-asks-for-an-integer-and-returns-its-fac-pdf-1-320.jpg)
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fixed. The final element of the array should have the value of 0xF, which is not used in
calculations, and should be used to calculate the size of the array. The program can prompt the
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array if found. If the number does not match any element in the array, insert the number in the
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Enter a number to search: 20
Number not found. Added to array.
Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 20, 23, 67
Enter a number to search: 5
Number at index 2
Solution
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a.
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Write the program in MIPS that declares an array of positive integers. The size of the array is not
fixed. The final element of the array should have the value of 0xF, which is not used in
calculations, and should be used to calculate the size of the array. The program can prompt the
user for an integer input. Compare the input with the array. Display the index of the input in the
array if found. If the number does not match any element in the array, insert the number in the
array in sorted order. The program is terminated when input a negative integer. Print the new
array with appropriate message on the screen. For example assume an array as follows:
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Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 23, 67
Enter a number to search: 20
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Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 20, 23, 67
Enter a number to search: 5
Number at index 2
Solution
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a.
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the code below is a recommendation system application to suggest a suitable degree program (or
department) based on student interest and industry demand.
-main class code:
package project;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.net.InetAddress;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Scanner;
public class project {
private static final int MAX_INVALID_INPUTS = 3;
private static final String LOG_FILE_PATH = "failed_attempts.txt";
public static void main(String[] args) {
SE_dep SE_obj = new SE_dep();
CSAIDepartment csaiDepartment = new CSAIDepartment();
CYDepartment cyDepartment = new CYDepartment();
DS_Dep dsDep = new DS_Dep();
double SE_minIndustSalary;
double SE_prevGPA;
String SE_interestOfStudent;
Scanner input = new Scanner(System.in);
System.out.println("Please enter the Minimum acceptable industry salary: ");
SE_minIndustSalary = validateInput(input, 10); // Maximum of 10 digits
System.out.println("Please Enter Your previous GPA: ");
SE_prevGPA = validateInput(input, 2); // Maximum of 2 digits
SE_interestOfStudent = validateInterestInput(input);
System.out.println("Student inputs: Minimum acceptable industry salary[" +
SE_minIndustSalary + "] Previous GPA[" + SE_prevGPA + "] Computer Programming
interest[" + SE_interestOfStudent + "]");
System.out.println("Suggested programs:\n\n");
SE_obj.ifIncluded_SE(SE_minIndustSalary, SE_prevGPA, SE_interestOfStudent);
cyDepartment.recommendPrograms(SE_minIndustSalary, SE_prevGPA,
SE_interestOfStudent);
csaiDepartment.recommendPrograms(SE_minIndustSalary, SE_prevGPA,
SE_interestOfStudent);
dsDep.DS_Program(SE_minIndustSalary, SE_prevGPA, SE_interestOfStudent);
double studyHours = SE_prevGPA * 1.0; // Each GPA point corresponds to 1 hour of study
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int minutes = (int) ((studyHours - hours) * 60); // Calculate the minutes
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" + minutes + " minutes");
input.close();
}
private static double validateInput(Scanner input, int maxDigits) {
int invalidInputs = 0;
while (invalidInputs < MAX_INVALID_INPUTS) {
String userInput = input.next();
try {
double value = Double.parseDouble(userInput);
if (userInput.length() <= maxDigits) {
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maxDigits + " digits: ");
invalidInputs++;
}
} catch (NumberFormatException e) {
invalidInputs++;
System.out.println("Invalid input! Please enter a valid number: ");
}
}
System.out.println("Maximum number of invalid inputs reached. Exiting...");
logFailedAttempt("Invalid input: " + input);
System.exit(0); // Terminate the program gracefully
return 0; // This line won't be executed, added to satisfy the method return type
}
private static String validateInterestInput(Scanner input) {
.
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
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if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}
Solution
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}.
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}
Solution
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}.
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import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Java Programs
The document contains 3 Java programs that check various properties of numbers:
1) A program that checks if a number is even or odd.
2) A program that checks if a number is prime by testing for factors.
3) A program that checks if a number is a palindrome by reversing it and comparing it to the original.
Java final lab
The document contains a list of 16 experiments to be performed in Java programming. It includes programs to check Armstrong numbers, sort strings, multiply matrices, calculate volume and surface area of a box, use copy constructors, create abstract classes for shapes and inherit subclasses, handle exceptions, create custom exceptions, create and run threads, use network classes, handle mouse events using applets, implement remote methods using RMI, create servlets, perform student mark list processing using JDBC, and create a basic text editor. It also provides sample code for 10 programs related to number swapping, multiplication tables, checking Armstrong numbers, calculating sum, checking palindromes, reversing numbers, finding largest of 3 numbers, printing prime numbers, Floyd
5 Rmi Print
This document describes the implementation of a remote method invocation (RMI) based arithmetic calculator application. It defines an interface for arithmetic operations (add, subtract, multiply, divide) and classes to implement the interface, start an RMI server, and run a client. The client allows selecting an operation, entering numbers, and displays the result, demonstrating the use of RMI to remotely execute arithmetic functions.
Java programI made this Account.java below. Using the attached cod.pdf
Java program
I made this Account.java below. Using the attached code I need help with 10.7 (Game: ATM
machine)
Use the Account class created in Programming Exercise 9.7 to simulate an ATM machine.
Create ten accounts in an array with id 0, 1, . . . , 9, and initial balance $100.
The system prompts the user to enter an id. If the id is entered incorrectly, ask the user to enter a
correct id.
Once an id is accepted, the main menu is displayed as shown in the sample run.
You can enter a choice 1 for viewing the current balance, 2 for withdrawing money, 3 for
depositing money, and 4 for exiting the main menu.
Once you exit, the system will prompt for an id again. Thus, once the system starts, it will not
stop.
*/
import java.util.Date;
public class Account {
/**
* @param args
*/
private int id=0;
private double balance=0;
private double annualIntrestRate=0;
private Date dateCreated;
public Account() {
super();
}
public Account(int id, double balance) {
super();
this.id = id;
this.balance = balance;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public double getBalance() {
return balance;
}
public void setBalance(double balance) {
this.balance = balance;
}
public double getAnnualIntrestRate() {
return annualIntrestRate;
}
public void setAnnualIntrestRate(double annualIntrestRate) {
this.annualIntrestRate = annualIntrestRate;
}
public Date getDateCreated() {
return dateCreated;
}
public void setDateCreated(Date dateCreated) {
this.dateCreated = dateCreated;
}
public double getMonthlyInterestRate()
{
return (this.getAnnualIntrestRate()/12);
}
public double getMonthlyInterest()
{
return (getBalance() *getMonthlyInterestRate()/100);
}
public double withDraw(double balance)
{
this.setBalance(this.getBalance()-balance);
return this.getBalance();
}
public double diposite(double balance)
{
this.setBalance(this.getBalance()+balance);
return this.getBalance();
}
public double totalBalance()
{
balance =balance + getMonthlyInterest();
return balance;
}
}
//AccountTest.java
import java.util.Calendar;
import java.util.Date;
import java.util.Scanner;
public class AccountTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc=new Scanner(System.in);
Account ac=new Account(1,5000.00);
System.out.println(\"Enter the annual intrest rate\");
double intrestRate=sc.nextDouble();
ac.setAnnualIntrestRate(intrestRate);
Date d=new Date();
Calendar currentDate = Calendar.getInstance();
ac.setDateCreated(currentDate.getTime());
System.out.println(\"Date id \"+ac.getDateCreated());
System.out.println(\"Monthly intrest rate is :\"+ac.getMonthlyInterestRate());
System.out.println(\"Monthly intrest is :\"+ac.getMonthlyInterest());
System.out.println(\"Enter Amount for diposite \");
double dipositeAmount=sc.nextDouble();
System.out.println(\"The amount after diposite is :\"+ac.diposite(dipositeAmount));
System.out.println(\"Enter Amount to withdraw :\");
double withdramount= sc.nextDouble.
Problemas secuenciales.
The document contains 16 code examples that demonstrate sequential program structure in Java. Each example solves a different problem by prompting the user for input, performing calculations or logical operations, and displaying output. The examples cover topics like addition, division, interest calculation, area calculation, character classification, and parity checking.
Problemas secuenciales.
The document contains 21 code examples that demonstrate sequential program structure in Java. Each example solves a different numerical or logical problem by prompting the user for input, performing calculations or comparisons, and outputting the results. The examples cover basic math operations, conditional logic, string manipulation and other programming fundamentals.
Given a newly created Binary Search Tree with the following numerica.pdf
Given a newly created Binary Search Tree with the following numerical key input sequence
(from left to right): 9, 4, 12, 7, 5, 2, 20, 14, 11, 13, 19, 16, 17, 42, 24
a.) We are asked to add a function Position lowestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position lowestKey(const Position& v);
input argument: position of the starting node in the binary search tree to calculate from. For the
whole tree this would be the position for the root of the tree.
return value: position of the node having the lowest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
b) We are also asked to add a function Position highestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position highestKey(const Position& v) const;
input argument: position of the node in the binary search tree to calculate from. For the whole
tree this would be the position for the root of the tree.
return value: position of the node having the highest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
Solution
#include
#include
/* A binary tree node has data, pointer to left child
and a pointer to right child */
struct node
{
int data;
struct node* left;
struct node* right;
};
/* Helper function that allocates a new node
with the given data and NULL left and right
pointers. */
struct node* newNode(int data)
{
struct node* node = (struct node*)
malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
/* Give a binary search tree and a number,
inserts a new node with the given number in
the correct place in the tree. Returns the new
root pointer which the caller should then use
(the standard trick to avoid using reference
parameters). */
struct node* insert(struct node* node, int data)
{
/* 1. If the tree is empty, return a new,
single node */
if (node == NULL)
return(newNode(data));
else
{
/* 2. Otherwise, recur down the tree */
if (data <= node->data)
node->left = insert(node->left, data);
else
node->right = insert(node->right, data);
/* return the (unchanged) node pointer */
return node;
}
}
/* Given a non-empty binary search tree,
return the minimum data value found in that
tree. Note that the entire tree does not need
to be searched. */
int minValue(struct node* node) {
struct node* current = node;
/* loop down to find the leftmost leaf */
while (current->left != NULL) {
current = current->left;
}
return(current->data);
}
/* Driver program to test sameTree function*/
int main()
{
struct node* root = NULL;
root = insert(root, 4);
insert(root, 2);
insert(root, 1);
insert(root, 3);
insert(root, 6);
insert(root, 5);
printf(\"\ Minimum value in BST is %d\", minValue(root));
getchar();
return 0;
}
#include
#include
/* A binary tree node has data, pointer to left child
.
Gather information on the following two disasters Space shuttle Ch.pdf
Gather information on the following two disasters: Space shuttle \"Challenger\", Jan 1986.
Space shuttle \"Columbia\", Jan 2003. Describe (may still be speculative for Columbia) what
(materials & design as well as political/management factors) caused the disasters.
Solution
Cause of Space shuttle Challenger disaster, Jan 1986:
It was determined that the two rubber O-rings, which had been designed to separate the sections
of the rocket booster, had failed due to cold temperatures on the morning of the launch. This seal,
called an O-ring, on the shuttle\'s right solid rocket booster had failed at liftoff, allowing
pressurized hot gas to escape from inside the booster. This vaporized material impinged on the
strut connecting the solid rocket booster to the shuttle\'s huge orange external tank, causing both
pieces of hardware to break down.
About 72 seconds into Challenger\'s flight, there was a massive, almost explosive, burning of the
hydrogen that was streaming from the failed tank bottom, combined with liquid oxygen leaking
from a part of the fuel tank known as the intertank which eventually lead to the biggest disaster
in the history.
Cause of Space shuttle Columbia disaster, Jan 2003:
This space shuttle Columbia broke apart returning to earth killing all the seven crew members on
the board. An investigation determined that the disaster was caused by a problem that took place
shortly while a large piece of foam fell from the shuttle’s propellant tank and fatally damaged the
edge of the shuttle’s left wing.They lost temperature readings from sensors located on the left
wing. Then, tire pressure readings from the left side also vanished. It was later found that a hole
on the left wing allowed atmospheric gases to bleed into the shuttle as it went through its fiery
re-entry, leading to the loss of the sensors and eventually, Columbia itself.This Columbia disaster
was the second major tragedy in the history of the space shuttle program after the space shuttle
Challenger broke apart shortly after launch on January 28, 1986..
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Oot practical
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the code below is a recommendation system application to suggest a s.pdf
the code below is a recommendation system application to suggest a suitable degree program (or
department) based on student interest and industry demand.
-main class code:
package project;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.net.InetAddress;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Scanner;
public class project {
private static final int MAX_INVALID_INPUTS = 3;
private static final String LOG_FILE_PATH = "failed_attempts.txt";
public static void main(String[] args) {
SE_dep SE_obj = new SE_dep();
CSAIDepartment csaiDepartment = new CSAIDepartment();
CYDepartment cyDepartment = new CYDepartment();
DS_Dep dsDep = new DS_Dep();
double SE_minIndustSalary;
double SE_prevGPA;
String SE_interestOfStudent;
Scanner input = new Scanner(System.in);
System.out.println("Please enter the Minimum acceptable industry salary: ");
SE_minIndustSalary = validateInput(input, 10); // Maximum of 10 digits
System.out.println("Please Enter Your previous GPA: ");
SE_prevGPA = validateInput(input, 2); // Maximum of 2 digits
SE_interestOfStudent = validateInterestInput(input);
System.out.println("Student inputs: Minimum acceptable industry salary[" +
SE_minIndustSalary + "] Previous GPA[" + SE_prevGPA + "] Computer Programming
interest[" + SE_interestOfStudent + "]");
System.out.println("Suggested programs:\n\n");
SE_obj.ifIncluded_SE(SE_minIndustSalary, SE_prevGPA, SE_interestOfStudent);
cyDepartment.recommendPrograms(SE_minIndustSalary, SE_prevGPA,
SE_interestOfStudent);
csaiDepartment.recommendPrograms(SE_minIndustSalary, SE_prevGPA,
SE_interestOfStudent);
dsDep.DS_Program(SE_minIndustSalary, SE_prevGPA, SE_interestOfStudent);
double studyHours = SE_prevGPA * 1.0; // Each GPA point corresponds to 1 hour of study
int hours = (int) studyHours; // Extract the integer part (hours)
int minutes = (int) ((studyHours - hours) * 60); // Calculate the minutes
System.out.println("Required study hours (at home beside lectures): " + hours + " hours and
" + minutes + " minutes");
input.close();
}
private static double validateInput(Scanner input, int maxDigits) {
int invalidInputs = 0;
while (invalidInputs < MAX_INVALID_INPUTS) {
String userInput = input.next();
try {
double value = Double.parseDouble(userInput);
if (userInput.length() <= maxDigits) {
return value; // Input has the desired number of digits, return the value
} else {
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maxDigits + " digits: ");
invalidInputs++;
}
} catch (NumberFormatException e) {
invalidInputs++;
System.out.println("Invalid input! Please enter a valid number: ");
}
}
System.out.println("Maximum number of invalid inputs reached. Exiting...");
logFailedAttempt("Invalid input: " + input);
System.exit(0); // Terminate the program gracefully
return 0; // This line won't be executed, added to satisfy the method return type
}
private static String validateInterestInput(Scanner input) {
.
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}
Solution
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}.
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}
Solution
The sample program for above series in JAVA will be like below
import java.util.Scan;
public class PIVALUE {
public static void main(String[] args) {
// Scan object creation
Scan input = new Scan (System.in);
// ask user for input
System.out.println(\"Enter num.\");
double j = input.nextDouble(); // user entered value of j
double Tot = 0;
for(j=0; j<10000; j++){
if(j%2 == 0) // check remainder of `j/2` is 0
Tot += -1 / ( 2 * j - 1);
else
Tot += 1 / (2 * j - 1);
}
System.out.println(Tot);
}
}.
Base de-datos
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2. A dice simulation program that rolls a dice multiple times and counts the frequency of each result.
3. Code for classes in an inheritance hierarchy including Person, Employee, Customer, PartTime, and FullTime with methods to input and display object details.
4. Methods to compare Employee and FullTime objects and a test program to demonstrate.
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import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Java Programs
The document contains 3 Java programs that check various properties of numbers:
1) A program that checks if a number is even or odd.
2) A program that checks if a number is prime by testing for factors.
3) A program that checks if a number is a palindrome by reversing it and comparing it to the original.
Java final lab
The document contains a list of 16 experiments to be performed in Java programming. It includes programs to check Armstrong numbers, sort strings, multiply matrices, calculate volume and surface area of a box, use copy constructors, create abstract classes for shapes and inherit subclasses, handle exceptions, create custom exceptions, create and run threads, use network classes, handle mouse events using applets, implement remote methods using RMI, create servlets, perform student mark list processing using JDBC, and create a basic text editor. It also provides sample code for 10 programs related to number swapping, multiplication tables, checking Armstrong numbers, calculating sum, checking palindromes, reversing numbers, finding largest of 3 numbers, printing prime numbers, Floyd
5 Rmi Print
This document describes the implementation of a remote method invocation (RMI) based arithmetic calculator application. It defines an interface for arithmetic operations (add, subtract, multiply, divide) and classes to implement the interface, start an RMI server, and run a client. The client allows selecting an operation, entering numbers, and displays the result, demonstrating the use of RMI to remotely execute arithmetic functions.
Java programI made this Account.java below. Using the attached cod.pdf
Java program
I made this Account.java below. Using the attached code I need help with 10.7 (Game: ATM
machine)
Use the Account class created in Programming Exercise 9.7 to simulate an ATM machine.
Create ten accounts in an array with id 0, 1, . . . , 9, and initial balance $100.
The system prompts the user to enter an id. If the id is entered incorrectly, ask the user to enter a
correct id.
Once an id is accepted, the main menu is displayed as shown in the sample run.
You can enter a choice 1 for viewing the current balance, 2 for withdrawing money, 3 for
depositing money, and 4 for exiting the main menu.
Once you exit, the system will prompt for an id again. Thus, once the system starts, it will not
stop.
*/
import java.util.Date;
public class Account {
/**
* @param args
*/
private int id=0;
private double balance=0;
private double annualIntrestRate=0;
private Date dateCreated;
public Account() {
super();
}
public Account(int id, double balance) {
super();
this.id = id;
this.balance = balance;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public double getBalance() {
return balance;
}
public void setBalance(double balance) {
this.balance = balance;
}
public double getAnnualIntrestRate() {
return annualIntrestRate;
}
public void setAnnualIntrestRate(double annualIntrestRate) {
this.annualIntrestRate = annualIntrestRate;
}
public Date getDateCreated() {
return dateCreated;
}
public void setDateCreated(Date dateCreated) {
this.dateCreated = dateCreated;
}
public double getMonthlyInterestRate()
{
return (this.getAnnualIntrestRate()/12);
}
public double getMonthlyInterest()
{
return (getBalance() *getMonthlyInterestRate()/100);
}
public double withDraw(double balance)
{
this.setBalance(this.getBalance()-balance);
return this.getBalance();
}
public double diposite(double balance)
{
this.setBalance(this.getBalance()+balance);
return this.getBalance();
}
public double totalBalance()
{
balance =balance + getMonthlyInterest();
return balance;
}
}
//AccountTest.java
import java.util.Calendar;
import java.util.Date;
import java.util.Scanner;
public class AccountTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc=new Scanner(System.in);
Account ac=new Account(1,5000.00);
System.out.println(\"Enter the annual intrest rate\");
double intrestRate=sc.nextDouble();
ac.setAnnualIntrestRate(intrestRate);
Date d=new Date();
Calendar currentDate = Calendar.getInstance();
ac.setDateCreated(currentDate.getTime());
System.out.println(\"Date id \"+ac.getDateCreated());
System.out.println(\"Monthly intrest rate is :\"+ac.getMonthlyInterestRate());
System.out.println(\"Monthly intrest is :\"+ac.getMonthlyInterest());
System.out.println(\"Enter Amount for diposite \");
double dipositeAmount=sc.nextDouble();
System.out.println(\"The amount after diposite is :\"+ac.diposite(dipositeAmount));
System.out.println(\"Enter Amount to withdraw :\");
double withdramount= sc.nextDouble.
Problemas secuenciales.
The document contains 16 code examples that demonstrate sequential program structure in Java. Each example solves a different problem by prompting the user for input, performing calculations or logical operations, and displaying output. The examples cover topics like addition, division, interest calculation, area calculation, character classification, and parity checking.
Problemas secuenciales.
The document contains 21 code examples that demonstrate sequential program structure in Java. Each example solves a different numerical or logical problem by prompting the user for input, performing calculations or comparisons, and outputting the results. The examples cover basic math operations, conditional logic, string manipulation and other programming fundamentals.
Similar to Write a Java application that asks for an integer and returns its fac.pdf (20)
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the code below is a recommendation system application to suggest a s.pdf
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like belowimpo.pdf
The sample program for above series in JAVA will be like belowimpo.pdf
import java.util.;public class Program{public static void.pdf
import java.util.;public class Program{public static void.pdf
Java programI made this Account.java below. Using the attached cod.pdf
Java programI made this Account.java below. Using the attached cod.pdf
More from hadpadrrajeshh
Given a newly created Binary Search Tree with the following numerica.pdf
Given a newly created Binary Search Tree with the following numerical key input sequence
(from left to right): 9, 4, 12, 7, 5, 2, 20, 14, 11, 13, 19, 16, 17, 42, 24
a.) We are asked to add a function Position lowestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position lowestKey(const Position& v);
input argument: position of the starting node in the binary search tree to calculate from. For the
whole tree this would be the position for the root of the tree.
return value: position of the node having the lowest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
b) We are also asked to add a function Position highestKey(const Position& v) const to the class
SearchTree.
Function prototype: Position highestKey(const Position& v) const;
input argument: position of the node in the binary search tree to calculate from. For the whole
tree this would be the position for the root of the tree.
return value: position of the node having the highest key value.
i. Describe strategy with reasonings and examples to convince that it will work.
ii. Implement the function using C++ and show the source code listing.
Solution
#include
#include
/* A binary tree node has data, pointer to left child
and a pointer to right child */
struct node
{
int data;
struct node* left;
struct node* right;
};
/* Helper function that allocates a new node
with the given data and NULL left and right
pointers. */
struct node* newNode(int data)
{
struct node* node = (struct node*)
malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
/* Give a binary search tree and a number,
inserts a new node with the given number in
the correct place in the tree. Returns the new
root pointer which the caller should then use
(the standard trick to avoid using reference
parameters). */
struct node* insert(struct node* node, int data)
{
/* 1. If the tree is empty, return a new,
single node */
if (node == NULL)
return(newNode(data));
else
{
/* 2. Otherwise, recur down the tree */
if (data <= node->data)
node->left = insert(node->left, data);
else
node->right = insert(node->right, data);
/* return the (unchanged) node pointer */
return node;
}
}
/* Given a non-empty binary search tree,
return the minimum data value found in that
tree. Note that the entire tree does not need
to be searched. */
int minValue(struct node* node) {
struct node* current = node;
/* loop down to find the leftmost leaf */
while (current->left != NULL) {
current = current->left;
}
return(current->data);
}
/* Driver program to test sameTree function*/
int main()
{
struct node* root = NULL;
root = insert(root, 4);
insert(root, 2);
insert(root, 1);
insert(root, 3);
insert(root, 6);
insert(root, 5);
printf(\"\ Minimum value in BST is %d\", minValue(root));
getchar();
return 0;
}
#include
#include
/* A binary tree node has data, pointer to left child
.
Gather information on the following two disasters Space shuttle Ch.pdf
Gather information on the following two disasters: Space shuttle \"Challenger\", Jan 1986.
Space shuttle \"Columbia\", Jan 2003. Describe (may still be speculative for Columbia) what
(materials & design as well as political/management factors) caused the disasters.
Solution
Cause of Space shuttle Challenger disaster, Jan 1986:
It was determined that the two rubber O-rings, which had been designed to separate the sections
of the rocket booster, had failed due to cold temperatures on the morning of the launch. This seal,
called an O-ring, on the shuttle\'s right solid rocket booster had failed at liftoff, allowing
pressurized hot gas to escape from inside the booster. This vaporized material impinged on the
strut connecting the solid rocket booster to the shuttle\'s huge orange external tank, causing both
pieces of hardware to break down.
About 72 seconds into Challenger\'s flight, there was a massive, almost explosive, burning of the
hydrogen that was streaming from the failed tank bottom, combined with liquid oxygen leaking
from a part of the fuel tank known as the intertank which eventually lead to the biggest disaster
in the history.
Cause of Space shuttle Columbia disaster, Jan 2003:
This space shuttle Columbia broke apart returning to earth killing all the seven crew members on
the board. An investigation determined that the disaster was caused by a problem that took place
shortly while a large piece of foam fell from the shuttle’s propellant tank and fatally damaged the
edge of the shuttle’s left wing.They lost temperature readings from sensors located on the left
wing. Then, tire pressure readings from the left side also vanished. It was later found that a hole
on the left wing allowed atmospheric gases to bleed into the shuttle as it went through its fiery
re-entry, leading to the loss of the sensors and eventually, Columbia itself.This Columbia disaster
was the second major tragedy in the history of the space shuttle program after the space shuttle
Challenger broke apart shortly after launch on January 28, 1986..
Determine the Laplace transform, F(s), of the following time signal..pdf
Determine the Laplace transform, F(s), of the following time signal.
Solution
we\'ll be interested in signals de¯ned for t ¸ 0
the Laplace transform of a signal (function) f is the function F = L(f)
de¯ned by
F(s) =
Z 1
0
f(t)e¡st dt
for those s 2 C for which the integral makes sense
² F is a complex-valued function of complex numbers
² s is called the (complex) frequency variable, with units sec¡1; t is called
the time variable (in sec); st is unitless
² for now, we assume f contains no impulses at t = 0
common notation convention: lower case letter denotes signal; capital
letter denotes its Laplace transform, e.g., U denotes L(u), Vin denotes
L(vin), etc..
Describe the difference between a monitor and a semaphoreSolutio.pdf
Describe the difference between a monitor and a semaphore
Solution
Monitor: Monitor is a highly structured programming language construct.It consists of Private
variables and private procedures that can only be used within a monitor. Constructors that
initialize the monitor.A number of public monitor procedures that can be invoked by users.
These monitors have no public data.A monitor is a mini OS with monitor procedures as system
calls.
Semaphore: Semaphore is a data structure that is used to provide mutual exclusion to critical
sections. Semaphores mainly support two operations called wait and Signal . The wait operation
blocks a process until the semaphore is open and the signal operation allows another process to
enter.MonitorSemaphoreCondition variables only uses these MonitorsThese can be used in
anywhere but not in Monitorswait() always blocks it\'s callerwait() does not always blocks it\'s
callersignal() either releases a process or the signal is lost as if it never occurssignal() either
releases a process or increases Semaphore counterif signal() releases a process,either the caller
or the released continues,but not bothif signal() releases a process,the caller and the released
both continued.
Create a link list. Add some nodes to it, search and delete nodes fro.pdf
Create a link list. Add some nodes to it, search and delete nodes from it.
Solution
#include
#include
using std::cout;
using std::endl;
/*
A linked list is a list constructed using pointers. It is not fixed in
size and could grow and shrink while the program is running.
A typical defination of list nodes contains at least two parts, both the
content or date of each element and the pointer to the next element,
which is shown in the figure below.
+---------+
| Data | -----> holds the data of this element in the list.
+---------+
| pointer | -----> is a pointer to the next element in the list.
+---------+
***Attention***:
The pointer holds the address of the next element, not the address of the
data in the next element, even though they are the same in value sometimes.
And It should be set to NULL while acting as the last node of the list.
Implementation of the single linked list:
+---------+ --->+---------+ --->+---------+
| Data | | | Data | | | Data |
+---------+ | +---------+ | +---------+
| pointer |----- | pointer |----- | pointer |
+---------+ +---------+ +---------+
*/
/* definition of the list node class */
class Node
{
friend class LinkedList;
private:
int _value; /* data, can be any data type, but use integer for easiness */
Node *_pNext; /* pointer to the next node */
public:
/* Constructors with No Arguments */
Node(void)
: _pNext(NULL)
{ }
/* Constructors with a given value */
Node(int val)
: _value(val), _pNext(NULL)
{ }
/* Constructors with a given value and a link of the next node */
Node(int val, Node* next)
: _value(val), _pNext(next)
{}
/* Getters */
int getValue(void)
{ return _value; }
Node* getNext(void)
{ return _pNext; }
};
/* definition of the linked list class */
class LinkedList
{
private:
/* pointer of head node */
Node *_pHead;
/* pointer of tail node */
Node *_pTail;
public:
/* Constructors with No Arguments */
LinkedList(void);
/* Constructors with a given value of a list node */
LinkedList(int val);
/* Destructor */
~LinkedList(void);
/* Function to add a node at the head of a linked list */
void headInsert(int val);
/* Function to add a node in the middle of a linked list */
void insertAfter(Node* afterMe, int val);
/* Function to append a node to the end of a linked list */
void tailAppend(int val);
/* Function to get the node in the specific position */
Node* getNode(int pos);
/* Traversing the list and printing the value of each node */
void traverse_and_print();
};
LinkedList::LinkedList()
{
/* Initialize the head and tail node */
_pHead = _pTail = NULL;
}
LinkedList::LinkedList(int val)
{
/* Create a new node, acting as both the head and tail node */
_pHead = new Node(val);
_pTail = _pHead;
}
LinkedList::~LinkedList()
{
/*
* Leave it empty temporarily.
* It will be described in detail in the example \"How to delete a linkedlist\".
*/
}
void LinkedList::headInsert(int val)
{
/* The list is empty? */
if (_pHead == NULL) {
/* the same to create a new list with a given value */
_pTail = _pHead = new Node(val);
.
A speedometer is a measuring instrument. What are the independent and.pdf
A speedometer is a measuring instrument. What are the independent and dependent variables
when it is used? Give an example of an extraneous variable for this measurement.
Solution
Input time is the independent variable where as out put mileage is the dependent variable.
Mileage is a function which takes something as input that cant be controlled by us. Example for
this is robotic speedometer. It is clear that the dependent variables are derived from independent
variables. Here time is independent variable, the dependent variables can be extended to
derivatives such as velocity,acceleration,etc..
A recent study by the EPA has determined that the amount of contamin.pdf
A recent study by the EPA has determined that the amount of contaminants in Minnesota Lakes
in parts per million averages 64 ppm with a variance of 17.6 Suppose 35 lakes are randomly
seelected and sampled. What is the probability that the sample average amount of contaminants
is between 64 and 72 ppm?
Solution.
choice one correct answerRocks containing iron, calcium, magnesium.pdf
choice one correct answer
Rocks containing iron, calcium, magnesium, or sodium break down into
a) sands and gravels, b) clays
Solution
Answer:- (b) Clays
One types of clay montmorillonite which is hydrated sodium calcium aluminium
Magnesium silicate hydroxide. (Na,Ca)0.33(Al,Mg)2Si4O10(OH)2 . nH2O
Some other type of clay are
Halloysite
Illite
Vermuculite
Talc
Palygorskite.
1.write down the RTL for the SUBT instructions. 2.Draw a flowchart.pdf
1.write down the RTL for the SUBT instructions.
2.Draw a flowchart to indicate SUBT instructions is processed.
Solution
1)
RTL is a easy human understandable language to specify or to perform the operations
SUBT is instruction which is used to perform or subtracts the Source operand from destination
operand and the subtracted result is stored into destination operand
Conditions
Source operand should be a register or a memory location or may be a immediate address
Destination operand should be a Register or memory location but not be a Immediate address
At a single time its not possible if both source and destinations to be a memory locations
General format of a SUB RTL(Register Transfer Language) format
SUB DESTINATION OPERAND,SOURCE OPERAND;
eg
SUB AX,18H;
SUB AX,BX;
SUB AX,[2000H];
2)
FLOW CHART to indicate SUBT instruction process
Instruction Cycle Implementation
1) Fetching of instructions will be performed at first
2) Updation of PC(Program counter will takes place) in second stage
3) Decoding of fetched instructions will be takes place in next stage
4) Execution of given eithr arthemetic or logic or conditional or unconditional or anyother
operations will takes place in the later stage
If Incase of SUB instruction Both Source and destinations datas are retrieved then it will check
Sign of both datas,If.
Where should seaweeds and kelps be classified Give characteristics .pdf
Where should seaweeds and kelps be classified? Give characteristics of these organisms which
you used to place them in a taxonomic unit and the source you used to find their characteristics.
Solution
Seaweeds are classified into three phylum\'s based on the colour of the thallus, biochemical
compositions, cell wall structures, photosynthetic pigments and chloroplasts. The three kingdoms
of seaweeds are, Kingdom bacteria, Kindom Plantae and Kingdom Chromista. The three
phylum\'s are, Phylum Rhodophyta (red alage), Phylum Chlorophyta (green algae) and Phylum
Ochrophyta (brown algae).
Kelps are the brown algae that belong to the order Laminariales, genus Laminaria..
What is the name of the connective tissue that divides the se.pdf
What is the name of the connective tissue that \"divides\" the segments of the rectus abdominis
muscles?
What is the name of the connective tissue that \"divides\" the segments of the rectus abdominis
muscles?
Solution
Linea alba is a band of connective tissue which is present either sides of the rectus abdominal
muscle and divides the muscle in two halves..
What is the current ratio of Chester Use the results of the Balance.pdf
What is the current ratio of Chester? Use the results of the Balance Sheet Survey Below.Balance
Sheet
SurveyAndrewsBaldwinChesterDigbyErieFerrisCash$3,434$0$15,756$3,605$52,632$5,613Acc
ounts
Receivable$8,307$14,914$12,076$9,550$16,903$4,576Inventory$8,617$25,931$5,044$3,491$3
,473$10,616Total Current Assets$20,358$40,845$32,876$16,646$73,008$20,804Plant and
equipment$113,800$177,400$124,100$122,200$193,600$78,300Accumulated
Depreciation($37,933)($76,903)($33,454)($40,920)($71,416)($42,600)Total Fixed
Assets$75,867$100,497$90,646$81,280$122,184$35,700Total
Assets$96,225$141,342$123,523$97,926$195,192$56,504Accounts
Payable$6,583$8,687$11,450$4,443$10,571$3,463Current
Debt$0$12,555$7,550$10,000$21,830$9,975Long Term
Debt$41,700$69,850$56,850$59,850$59,643$16,308Total
Liabilities$48,283$91,092$75,850$74,293$92,044$29,747Common
Stock$18,360$22,860$22,775$18,360$24,310$19,119Retained
Earnings$29,582$27,391$24,898$5,273$78,839$7,638Total
Equity$47,942$50,251$47,673$23,633$103,148$26,757Total Liabilities & Owner\'s
Equity$96,225$141,342$123,523$97,926$195,192$56,504
Solution
Current ratio = Total Current Assets /Current Liabilities = 32876/(11450+7550)= 1.73.
What is glass-transition temperature Give a material example. How ma.pdf
What is glass-transition temperature? Give a material example. How many types of polymer
structures do you know? Briefly explain each type of polymer structures. b) What is creep and
what is stress relaxation? c) What are the two structure components in reinforced plastics and
what are the functions of each of them? What are the advantages and disadvantages of reinforced
plastics comparing with the regular plastics?
Solution
a) The glass–liquid transition or glass transition for short is the reversible transition in
amorphous materials (or in amorphous regions within semicrystalline materials) from a hard and
relatively brittle \"glassy\" state into a molten or rubber-like state, as the temperature is
increased. An amorphous solid that exhibits a glass transition is called a glass.
The glass-transition temperatureTg of a material characterizes the range of temperatures over
which this glass transition occurs. It is always lower than the melting temperature, Tm, of the
crystalline state of the material, if one exists.
Examples Rubber elastomers like polyisoprene and polyisobutylene are used above their Tg\'s,
that is, in the rubbery state, where they are soft and flexible.
Typical polymer structures are
b) creep is the tendency of a solid material to move slowly or deform permanently under the
influence of mechanical stresses. It can occur as a result of long-term exposure to high levels of
stress that are still below the yield strength of the material. Creep is more severe in materials that
are subjected to heatfor long periods, and generally increases as they near their melting point.
Stress relaxation is defined as a gradual decrease in stress with time under a constant
deformation or strain.
c) Fibre-reinforced plastic is a composite material made of a polymer matrix reinforced with
fibres. The fibres are usually glass, carbon,aramid, or basalt. Rarely, other fibres such as paper or
wood or asbestos have been used. The polymer is usually an epoxy, vinylester or polyester
thermosetting plastic, andphenol formaldehyde resins are still in use.
Advantages
Disadvantages.
What are some contributions to the development of industrializat.pdf
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
What are some contributions to the development of industrialization made by the steam engine.
In other words what role did the steam engine play in the development of the industrial
revolution
Solution
Answer:
The steam engine was one of the most important technologies of the Industrial Revolution,
although steam did not replace water power in importance in Britain until after the Industrial
Revolution. From Englishman Thomas Newcomen\'s atmospheric engine, of 1712, through
major developments by Scottish inventor and mechanical engineer James Watt, the steam engine
began to be used in many industrial settings, not just in mining, where the first engines had been
used to pump water from deep workings. Early mills had run successfully with water power, but
by using a steam engine a factory could be located anywhere, not just close to water. Water
power varied with the seasons and was not available at times due to freezing, floods and dry
spells
The technological advances of the Industrial Revolution happened more quickly because firms
often shared information, which they then could use to create new techniques or products. From
mines to mills, steam engines found many uses in a variety of industries. The introduction of
steam engines improved productivity and technology, and allowed the creation of smaller and
better engines.
The development of the stationary steam engine was an essential early element of the Industrial
Revolution, however it should be remembered that for most of the period of the Industrial
Revolution the majority of industries still relied on wind and water power as well as horse and
man-power for driving small machines. Transportation was one of those important beneficiaries.
By the early 1800s, high-pressure steam engines had become compact enough to move beyond
the factory, prompting the first steam-powered locomotive to hit the rails in Britain in 1804. For
the first time in history, goods were transported over land by something other than the muscle of
man or animal. The railroad rapidly spread and sped transportation. This created new jobs,
forcing people to move into cities. Cities like London, for example, the steam engine and
locomotive propelled countless other industries such as driving bellows and rollers, spinning
machines, and weaving machines. And, for the first time in history, people had the ability to
quickly and cheaply move to big cities to find work, as opposed to working on a farm.
Subsequently, it had a major impact on businesses, as it boosted production of natural resources,
which were vital to society, and created numerou.
The “creative revolution” that handed more authority to agency art d.pdf
The “creative revolution” that handed more authority to agency art directors and copywriters in
the 1960s led to key shifts in the appearance and message of mainstream advertising. Describe
these changes and how they continue to influence advertising today.
Solution
The key shift in terms of appearance and message of mainstream advertising was that the
commercials started using irony and irreverence to reach out to the young customers.
The situation was that the young customers were indifferent to advertisements by companies at
that time. Advertisements were designed, both in terms of its message and appearance, to
connect with the youth.
Secondly, the creative revolution also saw social messages and issues being used in commercials
and advertisements.
These changes continue to influence advertising today. Advertisements, be it print or any other
media, increasingly are targeting the youths. Marketers are not afraid of using self deprecating
humor or using social messages in today\'s advertisements and commercials..
The three main coefficients (not properties or dimensionless numbers).pdf
The three main coefficients (not properties or dimensionless numbers) interphase transport are
For momentum transport For heat transport For mass transport Write two assumptions of
Navier Stoke equation. What is the assumption of Euler\'s equation?
Solution
Assumption for navier stroke:
1. Continuous media
2. Viscous constant
3. Incompressible
4. Steady state
5. Fully developed
Assumption of euler equation:
The fluid is non-viscous (i,e., the frictional losses are zero).
The fluid is homogeneous and incompressible (i.e., mass density of the fluid is constant).
The flow is continuous, steady and along the streamline..
The project will study the coordination of multiple threads using se.pdf
The project will study the coordination of multiple threads using semaphores.
The design should consist of two things:
(1) a list of every semaphore, its purpose, and its initial value, and
(2) pseudocode for each function. Code Your code should be nicely formatted with plenty of
comments. The code should be easy to read, properly indented, employ good naming standards,
good structure, and should correctly implement the design. Your code should match your
pseudocode.
Project Language/Platform
This project must target a Unix platform and execute properly on our cs1 or csgrads1 Linux
server.
The project must be written in Java. Elevator Simulation In this project threads are used to
simulate people using an elevator to reach their floor.
The threads to be used are as follows: Person:
1) 49 people are in line at the elevator at the beginning of the simulation (1 thread per person).
2) Each person begins at floor 1.
3) Each person randomly picks a floor from 2 to 10.
4) A person will wait for an elevator to arrive at floor 1.
5) A person will board the elevator only if there is room.
6) Once at the destination floor, the person exits the elevator.
Elevator:
1) There is 1 elevator (1 thread for the elevator).
2) The elevator can only hold 7 people.
3) The elevator begins on floor 1.
4) The elevator leaves after the 7th person enters.
Main
1) Creates all threads and joins all person threads.
2) When last person reaches their floor, the simulation ends.
Other rules:
1) Each activity of each thread should be printed with identification (e.g., person 1).
2) A thread may not use sleeping as a means of coordinating with other threads.
3) Busy waiting (polling) is not allowed.
4) Mutual exclusion should be kept to a minimum to allow the most concurrency.
5) The semaphore value may not obtained and used as a basis for program logic.
6) All activities of a thread should only be output by that thread. Sample output:
Your project’s output should match the wording of the sample output:
Elevator door opens at floor 1
Person 0 enters elevator to go to floor 5
Person 1 enters elevator to go to floor 2
Person 2 enters elevator to go to floor 8
Person 3 enters elevator to go to floor 4
Person 4 enters elevator to go to floor 6
Person 5 enters elevator to go to floor 7
Person 6 enters elevator to go to floor 2
Elevator door closes
Elevator door opens at floor 2
Person 1 leaves elevator
Person 6 leaves elevator
Elevator door closes
Elevator door opens at floor 4
Person 3 leaves elevator
Elevator door closes
Elevator door opens at floor 5
Person 0 leaves elevator
Elevator door closes
Elevator door opens at floor 6
Person 4 leaves elevator
Elevator door closes
Elevator door opens at floor 7
Person 5 leaves elevator
Elevator door closes
Elevator door opens at floor 8
Person 2 leaves elevator
Elevator door closes
Elevator door opens at floor 1
…
Simulation done
Solution
public class Person implements Runnable{
//possible actions
public static final int WAITING = 1;
publ.
The positive selection process for T lymphocytes that occurs In the t.pdf
The positive selection process for T lymphocytes that occurs In the thymus Involves selection of
T lymphocytes that have a high affinity for MHC have a high affinity for MHC and self peptide
have a low affinity for MHC and self peptide have a low affinity for MHC
Solution
Answer c: Positive selection select cells with a T cell receptor able to bind MHC class I and II
molecules with at least a weak affinity.hence answer c is correct..
The local public health agency has received reports of an outbreak o.pdf
The local health agency received reports of a Salmonella outbreak among attendees at a chili cook-off. To investigate, the agency would use molecular identification techniques like FISH or ERIC-PCR to establish that gastroenteritis was caused by Salmonella. They would also use molecular phylogenetic techniques like 16S rRNA sequencing or MLST to determine if attendees were infected by the same Salmonella strain.
how are musical sounds produced Explain your reasoning.Solution.pdf
how are musical sounds produced? Explain your reasoning.
Solution
Almost all musical programs are produced
basically in two stages:
(1) Sound from each individual intrument is recorded in an acoustically inert studio on a single
track of a multitrack tape recorder
(2) Signals from each track are manipulated by the sound engineer by adding special audio
effects and then combined in a mix-down system to generate the final stereo recording on a two-
track tape recorder
The special audio effects are either generated using time-domain operations or frequency-domain
operations.
Commonly used time-domain operations are echo generation,reverberation,flanging,chorus
generation, and
phasing.
Commonly used frequency-domain operations are filters and equalizers.
More from hadpadrrajeshh (20)
Given a newly created Binary Search Tree with the following numerica.pdf
Given a newly created Binary Search Tree with the following numerica.pdf
Gather information on the following two disasters Space shuttle Ch.pdf
Gather information on the following two disasters Space shuttle Ch.pdf
Determine the Laplace transform, F(s), of the following time signal..pdf
Determine the Laplace transform, F(s), of the following time signal..pdf
Describe the difference between a monitor and a semaphoreSolutio.pdf
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