When is there a risk of a Type II errorSolutionWhenever a res.pdf
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A Type II error occurs whenever a researcher fails to reject the null hypothesis, which means accepting the null hypothesis even though the alternative hypothesis is true. This type of error confirms an idea that should have been rejected by claiming two observances are the same when they are actually different. A Type II error happens whenever the decision is to fail to reject the null hypothesis.
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Please I need help with this....Please also provide comments in each.pdf
Please I need help with this....Please also provide comments in each line and a successful output
screenshot.
Lanuage: C++
*****************************************************************************
*************
Create an array of strings: Names.
Initialize forwardOrderNames with: “Fred”, “Tuyet”, “Annie”, “Moe”, “Ria”, “Luke”, “Jim”,
“May”, ”Rex”, ”Omar”.
Add this Bubble sort code, AND run the code and print the array again. Explain how it works.
string tmp;
for( i=1; i
for( j=4; j>=i; --j)
if (strcmp(forwardOrderNames [j-1], forwardOrderNames [j])>0) {
tmp = forwardOrderNames [j-1]; forwardOrderNames [j-1] = forwardOrderNames [j];
forwardOrderNames [j] = tmp;
} }
Solution
#include
#include
using namespace std;
int main()
{
int i,j;
string forwardOrderNames[]= {\"Fred\", \"Tuyet\", \"Annie\", \"Moe\", \"Ria\", \"Luke\",
\"Jim\", \"May\", \"Rex\", \"Omar\"};
string tmp;
for( i=0; i<10; i++)
{
for( j=1; j<10; j++)
if (forwardOrderNames [j-1]> forwardOrderNames [j])
{
tmp = forwardOrderNames [j-1];
forwardOrderNames [j-1] = forwardOrderNames [j];
forwardOrderNames [j] = tmp;
}
}
for( i=1; i<10; i++)
cout << \" \" <.
Please give me the origin and history on Hassall’s corpusclesSol.pdf
Please give me the origin and history on Hassall’s corpuscles
Solution
Hassall\'s corpuscles:
1) Introduction : Also known as thymic corpuscles are specialized bodies found in medulla of the
thymus. Thymus is primary primary lymphoid organ responsible for production of hormones like
thymosin, thymopoetin etc.
2) Origin: Hassall\'s corpuscles origin can be described by two proposed hypothesis. One is its
vascular origin ( originated from blood vessels i.e capillary occlusion). Other suggeted that they
originated from ductules of thymus also known as thymopharyngeal ducts
3) History: hassall\'s corpuscles were described about 150 years ago and their sturucture differ
within mammalian species. These are characteristic of thymic medulla. They appear as onions
arranged concentrically in their structure..
OBJ. 2 PE 12-2A Dividing partnership net income Han Lee and Monica An.pdf
OBJ. 2 PE 12-2A Dividing partnership net income Han Lee and Monica Andrews formed a
partnership, dividing income as follows: 1. Annual salary allowance to Lee of $32,000 2. Interest
of 4% on each partner\'s capital balance on January 1. g net income divided to Lee and Andrews,
2:1. Lee and Andrews had $80,000 and $150,000, respectively, in their January 1 capital ances.
Net income for the year was $64,000. How much net income should be distributed to Lee and
Andrews?
Solution
PE 12-4A
The partner bonus here is the over and above amount received for partnership
Amount paid for share. : 340,000
Share in adjusted share capital : 120,000
Total amount of bonus : 220,000Particularshan
leeandrewsSalary32,000Interest3,2006,000Income distrubuted15,2007,600Total50,40013,600.
O’Connor says that Aristotelian justice “overcomes misorientation to.pdf
O’Connor says that Aristotelian justice “overcomes misorientation to inappropriate ends rather
than egoistic insensitivity to fair claims [and] emphasizes collegial excellence in shared pursuit
of a common vision of the good, rather than the respect appropriate between human beings who
confront each other as independent sources of value and valuation” (C 269). What does this
mean?
Solution
\"Overcomes misorientation to inappropriate ends\" meaning that Aristotellian Justice isn\'t
trivial about if it\'s a good end or a bad one. \"rather than egoistic insensitivity to fair claim\" and
by showing natuarally the appropiate end, it doedn\'t show insensitivity to claims that maybe
wasn\'t in the convinience of all, even if they were fair, \"emphasizes collegial excellence in
shared pursuit os a common vision of the good\" since Aristoteles beloved in equiality, he
believed in balance for their rights and his, at the same time, therefor this way of thinking was
always up for the greater good, rather then fighting each one for their own good..
Let T R^5 rightarrow R^3 be a linear transformation whose null space.pdf
Let T: R^5 rightarrow R^3 be a linear transformation whose null space is a three dimensional
subspace of R^5. What is the dimension of the image of T? Describe the image geometrically Is
the image of T a subset of R^5 or R^3?
Solution
Theorem:
If T::V->W is a linear transformation , then
dim V = dim Null space T + dim Image T
In the present case, dim V=5, dim Nullspace is 3 (given)
So dim (Image T) (using the theorem ) is 2.
Geometrically , Image of T is a two dimensional subspace (a plane) of R3
Image of T is a subspace (hence a subset of R3).
Make drawings of both organisms stained in each staining procedure. L.pdf
Make drawings of both organisms stained in each staining procedure. Label each drawing with
the organism name, the total magnification and the name of the staining procedure. For each
drawing, record your observations, including the staining result (acid-fast or non-acid-fast;
spores present or spores absent), cell shape, cell arrangement and cell size. Explain the
mechanism by which the acid-fast stain differentiates between acid-fast and non-acid-fast
organisms. Explain why endospores stain one color and vegetative cells stain a different color in
the endospore stain. Be thoughtful and complete in your explanation. Would you expect to see
endospores in a fresh (24 hour) culture of a Bacillus species? Explain your answer. Suppose you
prepare a Gram stain using a 7-day old culture of a Bacillus species. You suspect endospores
might be present. What would you expect the spores to look like in a Gram stain and why?
Explain when, why and/or how the acid-fast and spore stains are important or useful. In other
words, how do we use that information? (Go farther than just stating that these procedures
identify acid-fast and spore-forming organisms, respectively.)
Solution
1) It is totally dependent on your lab observations.
2) Acid fast staining involves, primary staining with Carbolfuchsin followed by
decolourisation with Acid-alcohol and at last counter staining with Methylene blue. In primary
staining both acid fast and non-acid fast bacteria stained red. But in second decolourisation step
non-acid fast bacteria loses red colour whereas acid fast bacteria remain red. In third counter
staining step non-acid fast bacteria who initially lost red colour in decolourisation step will be
counter stained blue with methylene blue whereas acid fast bacteria retain its red colour
(Carbolfuchsin).
Acid fast bacteria: Mycobacterium and many Nocardia species
3) When vegetative cell of certain bacteria is exposed to harsh conditions, to protect cell forms
an endosperm to survive and as the favourable conditions come again cell behaves like
vegetative cell.
Endospore staining has following major steps:
1. Making bacterial cell smear on slide
2. Heating slide gently for fixing it
3. malachite green staining along with heating gently
4. Rinsing slide with tap water
5. Counterstain with safranin
Spores resist staining. Therefore heating is done to allow stain to penetrate in endospore.
Malachite green is a water soluble dye which is removed easily in washing step from cell wall of
vegetative cells but not from the spores. And that’s why spores appear blue (due to primary dye
malachite green) and vegetative cell retain the secondary stain safranin and appear pin/red.
4) A 24 hour culture will not show any endospore. Endospores forms when cell exposed to
harsh conditions like harsh temperature, lack of nutrients etc. But as it faces favourable
conditions of temperature and nutrition, it again gains its vegetative characteristics. As bacteria
are in culture from 24 ho.
Link to TextThese selected condensed data are taken from a recent ba.pdf
Link to TextThese selected condensed data are taken from a recent balance sheet of Sanson
Company (in millions of dollars).
Cash$7.2Accounts receivable14.4Inventory18.0Other current assets11.1Total current
liabilities$24.8
Additional information: Current liabilities at the beginning of the year were $35.6 million.
Solution
Total current assets=Cash+AR+Inventory+AR
=(7.2+14.4+18+11.1)=$50.7
1.WC=Total current assets-Total current liabilities
=(50.7-24.8)=$25.9 million
2.Current ratio=Total current assets/Total current liabilities
=(50.7/24.8)=2.04:1(Approx)..
Java Database Connect Write a program that views, inserts, and u.pdf
Java Database Connect
Write a program that views, inserts, and updates staff information stored in a database, as shown
below. The view button displays a record with a specified ID. The Insert button inserts a new
record. The Update button updates the record for the specified ID. The Staff table is created as
follows:
Create table Staff(id char(9) not null, lastName varchar(15), firstName varchar(15), mi char(1),
address varchar(20), city varchar(20), state char(2), telephone char(10), email varchar(40),
primary key(id));
Solution
import java.awt.*;
import java.awt.event.*;
import java.sql.*;
import javax.swing.JOptionPane;
class Assignment6DB extends Frame implements ActionListener
{
Button b1,b2,b3,b4;
Panel top,bottom;
TextField tf1,tf2,tf3,tf4,tf5,tf6,tf7,tf8;
TextArea ta1;
Label l1,l2,l3,l4,l5,l6,l7,l8,l9;
Connection con;
Statement st;
PreparedStatement pst;
ResultSet rs;
Assignment6DB(){
setVisible(true);setSize(750,700);
setTitle(\"Assignment6DB\");
setFont(new Font(\"Arial\",Font.BOLD,25));
bottom=new Panel();
b1=new Button(\"view\");bottom.add(b1);
b2=new Button(\"insert\");bottom.add(b2);
b3=new Button(\"delete\");bottom.add(b3);
b4=new Button(\"clear\");bottom.add(b4);
add(bottom,\"South\");
top=new Panel();
top.setBackground(Color.cyan);
l1=new Label(\"ID\");top.add(l1);
tf1=new TextField(10);top.add(tf1);
l2=new Label(\"LastName\");top.add(l2);
tf2=new TextField(20);top.add(tf2);
l3=new Label(\"FirstName\");top.add(l3);
tf3=new TextField(20);top.add(tf3);
l4=new Label(\"MI\");top.add(l4);
tf4=new TextField(10);top.add(tf4);
l5=new Label(\"Address\");top.add(l5);
ta1=new TextArea(5,10);top.add(ta1);
l6=new Label(\"City\");top.add(l6);
tf5=new TextField(20);top.add(tf5);
l7=new Label(\"State\");top.add(l7);
tf6=new TextField(20);top.add(tf6);
l8=new Label(\"Telephone\");top.add(l8);
tf7=new TextField(10);top.add(tf7);
l9=new Label(\"EmailID\");top.add(l9);
tf8=new TextField(30);top.add(tf8);
add(top,\"Center\");
validate();
b1.addActionListener(this);
b2.addActionListener(this);
b3.addActionListener(this);
b4.addActionListener(this);
}
public void actionPerformed(ActionEvent ae)
{
try{
Class.forName(\"oracle.jdbc.OracleDriver\");//type-4 driver for oracle
con=DriverManager.getConnection(\"jdbc:oracle:thin:1521:@xe\",\"system\",\"system\");//URL,
USerName,Password
String str=ae.getActionCommand();
if(str.equals(\"clear\"))//clear operation
{
tf1.setText(\"\");
tf2.setText(\"\");
tf3.setText(\"\");
tf4.setText(\"\");
tf5.setText(\"\");
tf6.setText(\"\");
tf7.setText(\"\");
ta1.setText(\"\");
}
else if(str.equals(\"insert\"))//insert operation
{
String id=tf1.getText();
String lname=tf2.getText();
String fname=tf3.getText();
String mi=tf4.getText();
String address=ta1.getText();
String city=tf5.getText();
String state=tf6.getText();
String phone=tf7.getText();
String email=tf8.getText();
PreparedStatement pst=con.prepareStatement(\"insert into staff values(?,?,?,?,?,?,?,?,?)\");
pst.setString(1,id);
pst.setString(2,lname);
pst.setStri.
Recommended
Please I need help with this....Please also provide comments in each.pdf
Please I need help with this....Please also provide comments in each line and a successful output
screenshot.
Lanuage: C++
*****************************************************************************
*************
Create an array of strings: Names.
Initialize forwardOrderNames with: “Fred”, “Tuyet”, “Annie”, “Moe”, “Ria”, “Luke”, “Jim”,
“May”, ”Rex”, ”Omar”.
Add this Bubble sort code, AND run the code and print the array again. Explain how it works.
string tmp;
for( i=1; i
for( j=4; j>=i; --j)
if (strcmp(forwardOrderNames [j-1], forwardOrderNames [j])>0) {
tmp = forwardOrderNames [j-1]; forwardOrderNames [j-1] = forwardOrderNames [j];
forwardOrderNames [j] = tmp;
} }
Solution
#include
#include
using namespace std;
int main()
{
int i,j;
string forwardOrderNames[]= {\"Fred\", \"Tuyet\", \"Annie\", \"Moe\", \"Ria\", \"Luke\",
\"Jim\", \"May\", \"Rex\", \"Omar\"};
string tmp;
for( i=0; i<10; i++)
{
for( j=1; j<10; j++)
if (forwardOrderNames [j-1]> forwardOrderNames [j])
{
tmp = forwardOrderNames [j-1];
forwardOrderNames [j-1] = forwardOrderNames [j];
forwardOrderNames [j] = tmp;
}
}
for( i=1; i<10; i++)
cout << \" \" <.
Please give me the origin and history on Hassall’s corpusclesSol.pdf
Please give me the origin and history on Hassall’s corpuscles
Solution
Hassall\'s corpuscles:
1) Introduction : Also known as thymic corpuscles are specialized bodies found in medulla of the
thymus. Thymus is primary primary lymphoid organ responsible for production of hormones like
thymosin, thymopoetin etc.
2) Origin: Hassall\'s corpuscles origin can be described by two proposed hypothesis. One is its
vascular origin ( originated from blood vessels i.e capillary occlusion). Other suggeted that they
originated from ductules of thymus also known as thymopharyngeal ducts
3) History: hassall\'s corpuscles were described about 150 years ago and their sturucture differ
within mammalian species. These are characteristic of thymic medulla. They appear as onions
arranged concentrically in their structure..
OBJ. 2 PE 12-2A Dividing partnership net income Han Lee and Monica An.pdf
OBJ. 2 PE 12-2A Dividing partnership net income Han Lee and Monica Andrews formed a
partnership, dividing income as follows: 1. Annual salary allowance to Lee of $32,000 2. Interest
of 4% on each partner\'s capital balance on January 1. g net income divided to Lee and Andrews,
2:1. Lee and Andrews had $80,000 and $150,000, respectively, in their January 1 capital ances.
Net income for the year was $64,000. How much net income should be distributed to Lee and
Andrews?
Solution
PE 12-4A
The partner bonus here is the over and above amount received for partnership
Amount paid for share. : 340,000
Share in adjusted share capital : 120,000
Total amount of bonus : 220,000Particularshan
leeandrewsSalary32,000Interest3,2006,000Income distrubuted15,2007,600Total50,40013,600.
O’Connor says that Aristotelian justice “overcomes misorientation to.pdf
O’Connor says that Aristotelian justice “overcomes misorientation to inappropriate ends rather
than egoistic insensitivity to fair claims [and] emphasizes collegial excellence in shared pursuit
of a common vision of the good, rather than the respect appropriate between human beings who
confront each other as independent sources of value and valuation” (C 269). What does this
mean?
Solution
\"Overcomes misorientation to inappropriate ends\" meaning that Aristotellian Justice isn\'t
trivial about if it\'s a good end or a bad one. \"rather than egoistic insensitivity to fair claim\" and
by showing natuarally the appropiate end, it doedn\'t show insensitivity to claims that maybe
wasn\'t in the convinience of all, even if they were fair, \"emphasizes collegial excellence in
shared pursuit os a common vision of the good\" since Aristoteles beloved in equiality, he
believed in balance for their rights and his, at the same time, therefor this way of thinking was
always up for the greater good, rather then fighting each one for their own good..
Let T R^5 rightarrow R^3 be a linear transformation whose null space.pdf
Let T: R^5 rightarrow R^3 be a linear transformation whose null space is a three dimensional
subspace of R^5. What is the dimension of the image of T? Describe the image geometrically Is
the image of T a subset of R^5 or R^3?
Solution
Theorem:
If T::V->W is a linear transformation , then
dim V = dim Null space T + dim Image T
In the present case, dim V=5, dim Nullspace is 3 (given)
So dim (Image T) (using the theorem ) is 2.
Geometrically , Image of T is a two dimensional subspace (a plane) of R3
Image of T is a subspace (hence a subset of R3).
Make drawings of both organisms stained in each staining procedure. L.pdf
Make drawings of both organisms stained in each staining procedure. Label each drawing with
the organism name, the total magnification and the name of the staining procedure. For each
drawing, record your observations, including the staining result (acid-fast or non-acid-fast;
spores present or spores absent), cell shape, cell arrangement and cell size. Explain the
mechanism by which the acid-fast stain differentiates between acid-fast and non-acid-fast
organisms. Explain why endospores stain one color and vegetative cells stain a different color in
the endospore stain. Be thoughtful and complete in your explanation. Would you expect to see
endospores in a fresh (24 hour) culture of a Bacillus species? Explain your answer. Suppose you
prepare a Gram stain using a 7-day old culture of a Bacillus species. You suspect endospores
might be present. What would you expect the spores to look like in a Gram stain and why?
Explain when, why and/or how the acid-fast and spore stains are important or useful. In other
words, how do we use that information? (Go farther than just stating that these procedures
identify acid-fast and spore-forming organisms, respectively.)
Solution
1) It is totally dependent on your lab observations.
2) Acid fast staining involves, primary staining with Carbolfuchsin followed by
decolourisation with Acid-alcohol and at last counter staining with Methylene blue. In primary
staining both acid fast and non-acid fast bacteria stained red. But in second decolourisation step
non-acid fast bacteria loses red colour whereas acid fast bacteria remain red. In third counter
staining step non-acid fast bacteria who initially lost red colour in decolourisation step will be
counter stained blue with methylene blue whereas acid fast bacteria retain its red colour
(Carbolfuchsin).
Acid fast bacteria: Mycobacterium and many Nocardia species
3) When vegetative cell of certain bacteria is exposed to harsh conditions, to protect cell forms
an endosperm to survive and as the favourable conditions come again cell behaves like
vegetative cell.
Endospore staining has following major steps:
1. Making bacterial cell smear on slide
2. Heating slide gently for fixing it
3. malachite green staining along with heating gently
4. Rinsing slide with tap water
5. Counterstain with safranin
Spores resist staining. Therefore heating is done to allow stain to penetrate in endospore.
Malachite green is a water soluble dye which is removed easily in washing step from cell wall of
vegetative cells but not from the spores. And that’s why spores appear blue (due to primary dye
malachite green) and vegetative cell retain the secondary stain safranin and appear pin/red.
4) A 24 hour culture will not show any endospore. Endospores forms when cell exposed to
harsh conditions like harsh temperature, lack of nutrients etc. But as it faces favourable
conditions of temperature and nutrition, it again gains its vegetative characteristics. As bacteria
are in culture from 24 ho.
Link to TextThese selected condensed data are taken from a recent ba.pdf
Link to TextThese selected condensed data are taken from a recent balance sheet of Sanson
Company (in millions of dollars).
Cash$7.2Accounts receivable14.4Inventory18.0Other current assets11.1Total current
liabilities$24.8
Additional information: Current liabilities at the beginning of the year were $35.6 million.
Solution
Total current assets=Cash+AR+Inventory+AR
=(7.2+14.4+18+11.1)=$50.7
1.WC=Total current assets-Total current liabilities
=(50.7-24.8)=$25.9 million
2.Current ratio=Total current assets/Total current liabilities
=(50.7/24.8)=2.04:1(Approx)..
Java Database Connect Write a program that views, inserts, and u.pdf
Java Database Connect
Write a program that views, inserts, and updates staff information stored in a database, as shown
below. The view button displays a record with a specified ID. The Insert button inserts a new
record. The Update button updates the record for the specified ID. The Staff table is created as
follows:
Create table Staff(id char(9) not null, lastName varchar(15), firstName varchar(15), mi char(1),
address varchar(20), city varchar(20), state char(2), telephone char(10), email varchar(40),
primary key(id));
Solution
import java.awt.*;
import java.awt.event.*;
import java.sql.*;
import javax.swing.JOptionPane;
class Assignment6DB extends Frame implements ActionListener
{
Button b1,b2,b3,b4;
Panel top,bottom;
TextField tf1,tf2,tf3,tf4,tf5,tf6,tf7,tf8;
TextArea ta1;
Label l1,l2,l3,l4,l5,l6,l7,l8,l9;
Connection con;
Statement st;
PreparedStatement pst;
ResultSet rs;
Assignment6DB(){
setVisible(true);setSize(750,700);
setTitle(\"Assignment6DB\");
setFont(new Font(\"Arial\",Font.BOLD,25));
bottom=new Panel();
b1=new Button(\"view\");bottom.add(b1);
b2=new Button(\"insert\");bottom.add(b2);
b3=new Button(\"delete\");bottom.add(b3);
b4=new Button(\"clear\");bottom.add(b4);
add(bottom,\"South\");
top=new Panel();
top.setBackground(Color.cyan);
l1=new Label(\"ID\");top.add(l1);
tf1=new TextField(10);top.add(tf1);
l2=new Label(\"LastName\");top.add(l2);
tf2=new TextField(20);top.add(tf2);
l3=new Label(\"FirstName\");top.add(l3);
tf3=new TextField(20);top.add(tf3);
l4=new Label(\"MI\");top.add(l4);
tf4=new TextField(10);top.add(tf4);
l5=new Label(\"Address\");top.add(l5);
ta1=new TextArea(5,10);top.add(ta1);
l6=new Label(\"City\");top.add(l6);
tf5=new TextField(20);top.add(tf5);
l7=new Label(\"State\");top.add(l7);
tf6=new TextField(20);top.add(tf6);
l8=new Label(\"Telephone\");top.add(l8);
tf7=new TextField(10);top.add(tf7);
l9=new Label(\"EmailID\");top.add(l9);
tf8=new TextField(30);top.add(tf8);
add(top,\"Center\");
validate();
b1.addActionListener(this);
b2.addActionListener(this);
b3.addActionListener(this);
b4.addActionListener(this);
}
public void actionPerformed(ActionEvent ae)
{
try{
Class.forName(\"oracle.jdbc.OracleDriver\");//type-4 driver for oracle
con=DriverManager.getConnection(\"jdbc:oracle:thin:1521:@xe\",\"system\",\"system\");//URL,
USerName,Password
String str=ae.getActionCommand();
if(str.equals(\"clear\"))//clear operation
{
tf1.setText(\"\");
tf2.setText(\"\");
tf3.setText(\"\");
tf4.setText(\"\");
tf5.setText(\"\");
tf6.setText(\"\");
tf7.setText(\"\");
ta1.setText(\"\");
}
else if(str.equals(\"insert\"))//insert operation
{
String id=tf1.getText();
String lname=tf2.getText();
String fname=tf3.getText();
String mi=tf4.getText();
String address=ta1.getText();
String city=tf5.getText();
String state=tf6.getText();
String phone=tf7.getText();
String email=tf8.getText();
PreparedStatement pst=con.prepareStatement(\"insert into staff values(?,?,?,?,?,?,?,?,?)\");
pst.setString(1,id);
pst.setString(2,lname);
pst.setStri.
JUST DO QUESTION 32) You have discussed with the human resource ma.pdf
JUST DO QUESTION 3
2) You have discussed with the human resource manager the new budget. Why is it now
important that you incorporate their suggestions and make the modifications to the budget
promptly?
3) i: What types of resources could be allocated in a budget?
ii: To ensure effective monitoring and reporting of budgets what do you need to do?
Solution
resource allocation aims to ensure that each department has sufficient resources to meet the costs
of all its activities taken together. In isolation individual activities attract more or less budget
than they require. However, when these are looked at together they result in a sufficient level of
resource for all the activities to take place and there will proper record of the resources consumed
.
resource allocation is type of materials , equipment ,services which are required. for all type of
budgets key components are material,labour , machines, suppliers.
ii)steps to be taken are.
Ins struction Use the information that is associated with your name .pdf
Ins struction: Use the information that is associated with your name in the table below to
analyze and journalize the transactions 1 (b) (0 121 (a) . 10,000-1-1,000-1 11,000 1,50012,500
100 115 110 125 1,100 1521,200 11,500 I. Verde Company uses the following accounts from its
chart of accounts: Cash (III), Accounts Receivable (112), Equipment (121) Jake Verde, Capital
(311), Jake Verde, Withdrawal G12), Professional Fees, (411), Utilities Expenses (51 1), and
Wages Expense (512) Record the following transactions Accounts Payable 211) cash and
equipment worth $ a. Jake Verde invested in the business S b. Billed clients for services rendered
S c. Utilities bill due but unpaid, $ kusoo d. Withdrew cash for personal use, S5 e. Paid salaries
expense, S 500 fr his personal assets. -,soo 125 Analysis Accounting a. Investment of Cash and
Equipment [12.5 Points] ACCT Descriptiorn Debit Credit Categorn [Asset, Liabilaies Capital,
Reveaue, Cash Rules Accounts Affee ver hAsst Debit Egwipment t12L llysoo.co
Solution
Date Particulars A.C. No Debit Credit On purchase of equipment Equipment 121
11500 To Cash 111 11500 This is the entry on purchase of equipment..
I how does double fertilization aid in the survival of land plants o.pdf
I how does double fertilization aid in the survival of land plants on land?
Solution
Double fertilization is a process, in which two male. plant Each pollen grain produces two nuclei,
one fuses with an egg and the other fuses with the one or more polar nuclei to form the
megagametophyte or the embryosac to form an endosperm..
how does malpractice affect quality of healthcare service What are .pdf
how does malpractice affect quality of healthcare service? What are two options of malpractice
reform?
Solution
Any sort of unskilled or negligent treatment on the part of healthcare providers, be it a doctor,
dentist, nurse, even the hospital or any other professional of the domain, towards the patients can
be treated as \'malpractice\'. And it can have several adverse effects on the patients as well as
doctors. Following lists a few of them:
The most obvious effect is the reluctance among patients to seek medical help at the hour of
need. This is as a result of the lack of trust in the patients for the whole system of treatment,
which ultimately affects the basis of doctor and patient relationship.
Malpractice claims can also affect the cost of treatment, ultimately making them exorbitantly
high for the patients to be able to afford it. Easy access to helathcare by patients can also become
difficult due to a rise in the insurance premiums.
Claims of negligence by the patients can also lead to a potential threat amongst the doctors. This
results in the latter becoming more conscious or defensive in choosing their line of treatment,
where they end up prescribing all sorts of additional diagnostic tests. The ultimately results in
excess cost incurred in the part of the patients, who then find it increasinly difficult to afford it.
As for the doctors, they could be involved in lawsuits and that can jeopardise their career, induce
stress, and in extreme scenarios, when the cost of malpractice insurance becomes too high, they
can even look for alternative careers.
The most common type of malpractice reform is the traditional tort reform, that can be both
direct as well as indirect. The direct reform puts a cap of the costs incurred in the hospital but it
generally doesnot impact the quality of healthcare that is provided to the potential patient.
Indirect reforms, on the other hand, puts a cap on the liability cost, such as attorney\'s fees in
case of a lawsuit. This as well has no effect on the quality of treatment. The traditional tort
reform can however reduce the occurance of defensive medication. According to Daniel Kessler,
there is a need for a more aggressive reform system that can address issues such as errors on the
part of healthcare provides, transactional costs incurred in the system, and the slow
compensation rate for the injured patients. And in turn he proposed the \"administrative
compensation system\". According to this system, there are two models to be followed for
reforms, the health court and the no fault models..
How can critical researchers claim to represent groups to which they.pdf
How can critical researchers claim to represent groups to which they do not belong?
Solution
A generic term usually applied to any research that challenges those conventional knowledge
bases and methodologies whether quantitative or qualitative – that make claims of scientific
objectivity. Rather, critical social research attempts to reveal the socio-historical specificity of
knowledge and to shed light on how particular knowledges reproduce structural relations of
inequality and oppression. Critical social research, in the sense of offering critiques of social
order, has a long history encompassing the likes of Aristotle, Socrates, Hobbes and Marx. It is
currently evident in the work of a wide variety of social critics, including Marxists, feminists and
poststructuralists and is often ‘hailed’ through attaching the adjective of ‘critical’ to any number
of existing disciplines or methodologies, as in ‘critical sociology’, ‘critical discourse analysis’,
‘critical anthropology’, ‘critical psychiatry’, ‘critical criminology’, ‘critical ethnography’ and so
on. and after than critical researchers claim to repersent group decribe below by critical case
researches study.
I was sitting in a park near my house one day half reading a novel and half watching the people
move around the area. As someone who studies people, I spend a lot of time watching them and
attempting to both make sense of what they do and use these observations to make sense of my
own research and theory development. On this particular day in the park, I saw two children
playing on opposite sides of a typical swing set, and around the time I was getting bored with my
novel one of the little kids asked the other, “are you a boy,” and the other little kid said “no.”
Smiling, the first child said, “oh, then you’re a girl,” but again the second child said “no.” After
staring for a moment, the first child said, “but I thought you had to pick one or the other.”
Climbing into a swing, the second child responded, “My parents don’t make me choose – they
say I can be anything I want.” Smiling, the first child asked, “I wonder why I can’t be anything I
want,” and without missing a beat, the second child responded, “Ask your parents.”
This experience (along with many other observations of children when they don’t think adults
are paying attention) reminds me of an exercise I do in my classes where I ask students to answer
the question “who am I” twenty times. Every time, students (like most humans) respond with
group identities (i.e., \"I’m a son,\" \"I’m white,\" \"I’m gay,\" \"I’m a football player,\" \"I’m an
atheist,\" \"I’m genderqueer,\" \"I’m a boy,\" \"I’m black,\" \"I’m a soccer player,\" \"I’m a
mother,\" \"I’m a Muslim,\" etc.) that they have been taught to use to define themselves. I then
ask my students “Is there anything about you that makes you an individual instead of part of a
bunch of different groups.” While one or two might try to use their names (which come from
languages, .
Discuss Allport’s concept of psychological healthy personality.Des.pdf
Discuss Allport’s concept of psychological healthy personality.
Describe how Freud’s three levels of mental life relate to his concept of the provinces of the
mind.
Solution
According to Allport psychologically healthy humans tend to be motivated by present conscious
drives. Such individuals seek to establish new tensions. It was his belief that individuals are
capable of proactive behavior. This suggests that a person can consciously behave in new as well
as creative ways that help in promotion of their growth and change. As per Allport,
psychologically healthy individuals tend to engage in proactive behaviors. The 6 criteria he gave
for psychological health are given as follows:
1. There is an extension of the sense of self
2. Have warm relationships with other individuals
3. Self acceptance
4. Have a realistic view of world
5. Insight
6. Have a unifying philosophy of life
Allport also believed that people of intrinsic religious orientation are psychologically healthy
whereas those who have an extrinsic religious orientation tend to have poor psychological health.
Several years before Freud developed the notion of the id, ego, and superego, he formulated the
concept of the unconscious, preconscious, and conscious.
The unconscious is that dynamic aspect of mental life which is responsible for a large number of
our behaviors. It not only consists of repressed experiences but also experiences that were never
conscious. The preconscious categorizes those experiences that were less threatening as
compared to those of the unconscious. Such ideas have the tendency of becoming conscious with
different degrees of difficulty and are mainly dependent on their potential threat to ego. The
conscious mind has a minor role comparatively in Freudian psychology. Those ideas that are in
our awareness comprise of the conscious mind.
The id is the completely unconscious amoral side of our nature that serves the pleasure
principle. Ego which is the sense of I, can be unconscious, preconscious, or conscious and serves
the reality principle. The superego is also completely unconscious and serves idealistic as well as
moral principles..
Earning revenue journal entry is recorded asA Increases assets.pdf
Earning revenue journal entry is recorded as:
A: Increases assets, decreases stockholders’ liabilities
B: Decreases assets, increases liabilities
C: Increases assets, increases stockholders’ equity
D: Increases one asset, decrease another asset
Solution
Answer:
C: Increases assets, increases stockholders’ equity is correct.Journal Entry for earning
revenueNatureEffectDateAccountsDebit $Credit $Debtors/CashAmountAssetsIncrease(as it has
been debited)Sales/RevenueAmountStockholders’ equityIncrease(as it has been credited).
Discuss why is it important to use logical and physical data flow di.pdf
Discuss why is it important to use logical and physical data flow diagram (DFDs) to graphically
depict data movement for humans and systems in an organization. Is it worthwhile to share them
with users? Why or why not?
Solution
It is important to use logical and physical data flow diagram (DFDs) to graphically depict data
movement for humans and systems in an organization due to following reason.
Did HBGary’s Aaron Barr have the legal and ethical right to pursue A.pdf
Did HBGary’s Aaron Barr have the legal and ethical right to pursue Anonymous? Did
Anonymous act ethically and legally toward HBGary?
Solution
HBGary’s Aaron Barr have the legal and ethical right to pursue Anonymous and Anonymous did
not
act ethically and legally toward HBGary::-
A little over a year ago, small security firm HBGary Federal made the news for all the wrong
reasons:
it had been hacked, its CEO had been made a laughing stock, and its private e-mails were
splashed across
the Internet. The perpetrators, a group of hackers sympathetic to the Anonymous group, trashed
HBGary Federal\'s
servers and name with impunity, confident that tor and private VPNs would keep their identities
secret
For months, they seemed invincible; most went on to form LulzSec during the summer of 2011,
which infiltrated a
huge number of corporations and police servers, releasing e-mails, taking credit card numbers,
and taunting their
pursuers. But the pursuers kept coming, and this week brought down their quarry with a string
of indictments and
the possibility of lengthy jail terms. With the arrests, the HBGary Federal hack saga is largely
concluded
The HBGary Federal attack
HBGary sells security software for detecting, categorizing, and analyzing malware. Its HBGary
Federal subsidiary
was created to cater to the security and classification needs of federal agencies, and hoped to sell
HBGary\'s
software to the Department of Defense and the numerous three-letter agencies. Federal was
struggling, however,
failing to bring in the lucrative government contracts that HBGary had hoped for
After years of minor trolling and harassment of Scientologists, the Anonymous group had
performed a series of
high-profile denial-of-service attacks on PayPal, MasterCard, and Visa, after the credit card
companies and
payment processor halted all donations in support of WikiLeaks.
Though presenting itself as a faceless collective, Anonymous undoubtedly had ring-leaders,
people within the
group setting the agenda and co-ordinating the attacks. Law enforcement agencies around the
world wanted to
know who was behind the pro-WikiLeaks attacks—and Aaron Barr thought he knew
It was the perfect opportunity to get HBGary Federal\'s name some high profile press and
reinvigorate the business,
and on February 5th, 2011, Barr announced his plans to unmask Anonymous\' main players
The reaction from Anonymous was immediate and brutal. HBGary\'s servers were hacked, and
its e-mail system pillaged.
A server belonging to its CEO, Greg Hoglund, was also compromised and wiped
The hacks revealed basic errors in the configuration and administration of HBGary\'s
systems—embarrassing enough for
a company working in the security sphere. Worse still was the leaking of the e-mails, which laid
bare the company\'s
efforts to solicit government contracts to discredit WikiLeaks and develop undetectable rootkits
for the government..
Define each of the following terms. Be clear whether it is at develop.pdf
Define each of the following terms. Be clear whether it is at developmental STAGE, PROCESS,
or STRUCTURE. Then, place a check to indicate in which of the organisms the term can be
found
Solution
CLEAVAGE:The process by which zygote rapidly divides without growing to become
multicellular. the cleavage is a process,it occurs in birds,reptiles, it occurs in human zygote etc.
MORULA:morula is an early stage of embryo contain cells of blastomeres in a solid ball with in
the zonna pellucida it is a developmental stage,it forms in.human zygote after cleavage.
BLASTULA:blastula is a hollow sphere of cells surrounding by an inner fluid filled cavity called
blastocoele.,it is an embryonic development stage.it occurs in embryonic development in
animals.
GASTRULA:During gastrula single layered blastula is reorganised in to trilamminar structure
known as gastrula.it occurs in early phase in embryonic development stage.it occurs in most of
animals.
NEURALA: It is relating to the Nervous system.it is a folding process in vertebrate
embryos.it gives rise to both the spinal cord and the brain.
Archenteron: It is the rudimentary alimentary cavity of an embryo at the gastrula stage.The
primary gut that forms during gastrulation in the developing zygote is known as the archenteron
or the digestive tube.
Blastocoel: Blastocoel is termed as blastocyst cavity.It is a fluid filled cavity that forms in the
animal hemisphere of early amphibian and echinoderm embryos.It have two major functions in
frog embryos: (1) it permits cell migration during gastrulation, and (2) it prevents the cells
beneath it from interacting prematurely with the cells above it.
Blastomere: It is a cell formed by cleavage of a fertilized ovum.Cells in cleavage stage embryo
are known as blastomeres. Embryo divides without growth ,It undergoes cleavage divisions that
produce separate cells called Blastomeres.
Blastopore: opening of the archenteron in the gastrula that develops into the mouth in
protostomes and the anus in deuterostomes.It is the opening into the archenteron during the
embryonic stages of an organism.
Brain: Human brain is the organ of central nervous system.Located in the head protected by the
skull.The brain is the most complex organ in a vertebrate\'s body.
Ectoderm: The outermost layer of cells or tissue of an embryo in early development, or the parts
derived from this, which include the epidermis, nerve tissue, and nephridia.
Endoderm: The innermost layer of the germ layer which includes the linings of the digestive and
respiratory tracts, parts of the urinary system, the liver, the pancreas, the gallbladder, the thyroid
gland, the parathyroid glands, and the thymus..
Could anyone please explain how CPS1 and CPS2 are used for reliabili.pdf
Could anyone please explain how CPS1 and CPS2 are used for reliability standard. Thanks
Solution
In simple terms, CPS1 assigns each Control Area a “slice” of the responsibility for control of
Interconnection frequency. The amount of responsibility is directly related to Control Area size.
ACE is to a Control Area what frequency is to the Interconnection. Over-generation makes ACE
go positive and frequency increase. A large negative ACE causes frequency to drop. “Noisy”
ACE causes “noisy” frequency. CPS1 captures these relationships.
The CPS1 equation can be simplified as follows:
CPS1 (in percent) = 100* (2 – (a Constant[1])* (frequency error)*(ACE))
Frequency error is deviation from scheduled frequency. Normally this is deviation from 60Hz.
Scheduled frequency is different during a time correction, but for the purposes of this discussion,
assume scheduled frequency is always 60 Hz.
Refer to the equation above. Any minute where the average frequency is exactly on schedule or
Control Area ACE is zero, the quantity ((frequency error)*(ACE)) is zero. Therefore CPS1 =
100* (2-0). CPS1 is exactly 200% whenever frequency is on schedule or ACE is zero.
For any one-minute average where ACE and frequency error are “out of phase”, CPS1 is greater
than 200%. For example, if frequency is low, but ACE is positive (tending to correct frequency
error), the Control Area gets extra CPS1 points.
Conversely, if ACE is aggravating the frequency error, CPS1 will be less than 200%. CPS1 can
even go negative.
The CONSTANT in the equation above is sized such that if a Control Area’s ACE is
proportionally as “noisy” as a benchmark frequency noise, the Control Area will get a CPS1 of
100%. The minimum acceptable long-term score for CPS1 is 100%.
When CPS was established, each Interconnection was given a target or benchmark “frequency
noise”. This target noise is called “Epsilon 1” or 1. Epsilon 1 is nothing more than a statistician’s
variable that means the RMS value of the one-minute averages of frequency.
The target values (in millihz of frequency noise) for each Interconnection are shown in Table 1
below. The NERC Resources Subcommittee monitors each Interconnection’s frequency
performance and can tighten (or loosen) the 1 values should an Interconnection’s frequency
performance decline (improve).
Interconnection
Epsilon 1
Eastern
18.0
Hydro Quebec
21.0
Western
22.8
ERCOT
20.0
Table 1 Target Values of \"One Minute Frequency Noise\"
The Epsilon 1 target initially set for each Interconnection was on the order of 1.6 times historic
frequency noise. This is why “average” Control Areas have been scoring around 160% for CPS1.
Let’s review how CPS1 data can be applied to measure the adequacy of control performance and
the deployment of resources to meet load. NERC refers to these resources as Interconnected
Operating Services (IOS). Although there are some differences in definitions, the FERC calls
these resources Ancillary Services.
Figure 1 shows ACE charts for one hour.
Complete the following code by deallocating the memory. Int ptr1; .pdf
Complete the following code by deallocating the memory. Int *ptr1; int *ptr2; ptr1 = new Int;
ptr2 = new intl[10]; *ptr1 = 10;
Solution
Dear Student,
The memory in c++ is created by a operator call new.
And the memory is deallocated by a operator called delete.
Below is the complete program...
#include
using namespace std;
int main()
{
int *ptr1;
int *ptr2;
ptr1 = new int; //allocate memory for the variable
ptr2= new int[10]; // allocate memory for integer variable which size is 10.
*ptr1=10; // assignment of value to pointer
cout << *ptr1 << endl;
delete ptr1; //Deallocate memory allocated for ptr1
delete ptr2; //Deallocate memory allocated for ptr2
return 0;
}
Output : 10
Note- The above program is tested on g++ compiler under ubuntu 14.04 system.
***** Dear Student if you are satisfied with the answer kindly provide your valubale
feedback******.
Briefly discuss why you are proud to be a mammal and give examples of.pdf
Briefly discuss why you are proud to be a mammal and give examples of mammals that habitat
various water kingdoms?
Solution
Mammals are vertibrate, endothermic amneotes possessing neocortex, hair, three middle year
bones and mammary glands. As mammals are endothermic they can live almost all type of
environments. Produce milk, to feed babies. There are 4000 different species of Mammals. The
smallest mammal is Hog nosed bat and largest one is Blue whale.
Some mammales habit to the water bodies. Eg. Blue whale, Dolphins, polar bears, pinnipeds,
dugongs etc..
AVR data memory consists of (Flash ROM, internal SRAM). True or false.pdf
AVR data memory consists of (Flash ROM, internal SRAM). True or false. The special function
register in AVR is called the I/O register. True or false. The I/O registers are part of the data
memory space. True or false. The general-purpose registers are not part of the data memory
space. True or false. The data memory is the same size in all members of AVR. If we add the I/O
registers, internal RAM, and general purpose register sizes together we should get the total space
for the .
Solution
11> SRAM (Flash has seperate address space)
12> FALSE ( It is called Accumulator)
13> TRUE (SRAM , I/O Register, Register file are part of data memory space)
14> FALSE (It is part of Data memory space. The DMS makes 32 General purpose registers)
15> FALSE
16> RAM but except it cannot be overwritten..
Below is a table of probabilities representing a sample survey of 100.pdf
Below is a table of probabilities representing a sample survey of 1000 adults and their opinions
on whether college education was too expensive or not. They were also ether they had a child in
college or not. What is the probability that a respondent has a child in college or thinks that
college educations is too expensive?
Solution
My choose E.
Based on the Spectroscopy data below, identify the material and it.pdf
Based on the Spectroscopy data below, identify the material and it\'s exact grade. Mn Mo 0.329
0.214 0.300 0.696 0.0791 0.0431 Al Co Cu Nb Pb 0.0070 0.0038 0.329 0.0047 0.0514 0.0277 Sn
Ca Sb Se 0.0135 0.0023 0.00014 0.0074 0.227 0.00037 0.0280 Fe 97.6
Solution
The material is a low carbon steel
The grade ia a low alloy steel with exact grade SAE 4130.
Attached is case study of how Whirlpool and Lowes collaborated to .pdf
Attached is case study of how Whirlpool and Lowe\'s collaborated to help manage risk and
uncertainty. Please highlight the most important difference between the stages. Please see the
Rubric for help.
Solution
The collaboration had three stages –
First stage was when the parties involved come up to a decision to form collaboration and give it
a purpose. In this stage they get together and design a strategy and set up a program.
Second stage included establishment of procedures to be followed for the implementation of the
strategy designed. It also involved specifying the needs and searching for alternatives for better
results. Lastly it involves arriving at an agreement to proceed with the implementation.
The last stage involves the control and supervision of the implementation process going as per
planning. If any issues generate along the course how to deal with them..
7. Winter is here. I hope you have enough of the right fatty acids o.pdf
7. Winter is here. I hope you have enough of the right fatty acids on your phospholipids to
maintain membrane fluidity. What does a cell do to its membrane phospholipids to maintain
fluidity in cold temperatures?
41. Two ways to alter the fluidity of a cell membrane are to..
1. 2.
Solution
Cell membrane consists of.
1. Phaspholipids
2. Proteins
3. Carbohydrate and cholesterol.
1- phaspholipids and cholesterol both play important role in the fluidicity of cell membrane with
the variation of temperature.
PHASPHOLIPIDS may be 1. Saturated or 2. Unsaturate
Saturated fats or fatty acid compressed at low temperature and make the membrane rigid. While
unsaturated fats compress in winter and develops folding or kinks. These kinks are responsible
for flexibility because they have vacant space.
With the change of the composition of saturated and unsaturated fat in summer and winter
organism maintain fluidicity.
2_ role of cholesterol.
Cholesterol dampen the effect of temperature and regulates the temperature of membrane to
maintain the fluidicity of membrane. Cholesterol act as buffer for Temp. Change.
2. Formatting Output to FilesSolution#includeiostream #inc.pdf
2. Formatting Output to Files
Solution
#include
#include
#include
#include
#include
using namespace std;
int main()
{
int num;
float root;
ifstream in_stream;
ofstream out_stream;
in_stream.open(\"Lab9B.in\");
if(in_stream.fail())
{
cout << \"ERROR: Unable to open file: Lab9B.in\" << endl;
exit(EXIT_FAILURE);
}
out_stream.open(\"Lab9B.out\");
if(out_stream.fail())
{
cout << \"ERROR: Unable to open file: Lab9B.out\" << endl;
exit(EXIT_FAILURE);
}
while(in_stream >> num)
{
root = sqrt(num);
out_stream << std::left;
out_stream << setprecision(5);
out_stream << setw(15);
out_stream << root << endl;
}
in_stream.close();
out_stream.close();
return 0;
}.
1. What effect does pulmonary edema have on blood oxygenation2. W.pdf
1. What effect does pulmonary edema have on blood oxygenation?
2. What is the consequence to the newborn if the foramen ovale does not close after birth?
Solution
1.
Pulmonary edema occurs due to abnormal accumulation of the fluid in air sacs that is alveoli
which makes the breathing much difficult.
Due to accumulation of the fluid there will be a difficulty in exchange of the gases and it leads to
the respiratory failure.
This pulmonary edema condition is commonly seen in elders.
When heart pumps in abnormal way then the blood back up into the veins and then we can
observe the increase in the blood pressure.
Pulmonary edema occurs mainly by the increase in the blood pressure that causes the damage to
the small blood vessels in the lungs and it leads to the accumulation of watery fluid and it leads
to the respiratory failure.
Thus the effect of pulmonary edema observed on blood oxygenation.
2.
Foramen ovale is actually named as patent foramen ovale (PFO ).
Patent foramen ovale is a hole between the left and right atria of the heart.
This hole can be observed in baby’s when they are in womb and it may disappear when they
comes out from mother’s womb but sometimes it may get failure.
In most of the cases there won’t be any complications but in rare cases it get complicated by
forming the blood clots.
In paradoxical stroke, a blood clot develops in a vein and it travels to the right side of the heart
and then normally continues to the lungs but in PFO people it continues to the left side of the
heart.
Now it pumps outside of the body and travel to the brain and it prevents blood flow to the brain.
Thus the consequences occur in new born if the foramen ovale does not close after birth.
1.
Pulmonary edema occurs due to abnormal accumulation of the fluid in air sacs that is alveoli
which makes the breathing much difficult.
Due to accumulation of the fluid there will be a difficulty in exchange of the gases and it leads to
the respiratory failure.
This pulmonary edema condition is commonly seen in elders.
When heart pumps in abnormal way then the blood back up into the veins and then we can
observe the increase in the blood pressure.
Pulmonary edema occurs mainly by the increase in the blood pressure that causes the damage to
the small blood vessels in the lungs and it leads to the accumulation of watery fluid and it leads
to the respiratory failure.
Thus the effect of pulmonary edema observed on blood oxygenation.
2.
Foramen ovale is actually named as patent foramen ovale (PFO ).
Patent foramen ovale is a hole between the left and right atria of the heart.
This hole can be observed in baby’s when they are in womb and it may disappear when they
comes out from mother’s womb but sometimes it may get failure.
In most of the cases there won’t be any complications but in rare cases it get complicated by
forming the blood clots.
In paradoxical stroke, a blood clot develops in a vein and it travels to the right side of the heart
and then normally continues.
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JUST DO QUESTION 32) You have discussed with the human resource ma.pdf
JUST DO QUESTION 3
2) You have discussed with the human resource manager the new budget. Why is it now
important that you incorporate their suggestions and make the modifications to the budget
promptly?
3) i: What types of resources could be allocated in a budget?
ii: To ensure effective monitoring and reporting of budgets what do you need to do?
Solution
resource allocation aims to ensure that each department has sufficient resources to meet the costs
of all its activities taken together. In isolation individual activities attract more or less budget
than they require. However, when these are looked at together they result in a sufficient level of
resource for all the activities to take place and there will proper record of the resources consumed
.
resource allocation is type of materials , equipment ,services which are required. for all type of
budgets key components are material,labour , machines, suppliers.
ii)steps to be taken are.
Ins struction Use the information that is associated with your name .pdf
Ins struction: Use the information that is associated with your name in the table below to
analyze and journalize the transactions 1 (b) (0 121 (a) . 10,000-1-1,000-1 11,000 1,50012,500
100 115 110 125 1,100 1521,200 11,500 I. Verde Company uses the following accounts from its
chart of accounts: Cash (III), Accounts Receivable (112), Equipment (121) Jake Verde, Capital
(311), Jake Verde, Withdrawal G12), Professional Fees, (411), Utilities Expenses (51 1), and
Wages Expense (512) Record the following transactions Accounts Payable 211) cash and
equipment worth $ a. Jake Verde invested in the business S b. Billed clients for services rendered
S c. Utilities bill due but unpaid, $ kusoo d. Withdrew cash for personal use, S5 e. Paid salaries
expense, S 500 fr his personal assets. -,soo 125 Analysis Accounting a. Investment of Cash and
Equipment [12.5 Points] ACCT Descriptiorn Debit Credit Categorn [Asset, Liabilaies Capital,
Reveaue, Cash Rules Accounts Affee ver hAsst Debit Egwipment t12L llysoo.co
Solution
Date Particulars A.C. No Debit Credit On purchase of equipment Equipment 121
11500 To Cash 111 11500 This is the entry on purchase of equipment..
I how does double fertilization aid in the survival of land plants o.pdf
I how does double fertilization aid in the survival of land plants on land?
Solution
Double fertilization is a process, in which two male. plant Each pollen grain produces two nuclei,
one fuses with an egg and the other fuses with the one or more polar nuclei to form the
megagametophyte or the embryosac to form an endosperm..
how does malpractice affect quality of healthcare service What are .pdf
how does malpractice affect quality of healthcare service? What are two options of malpractice
reform?
Solution
Any sort of unskilled or negligent treatment on the part of healthcare providers, be it a doctor,
dentist, nurse, even the hospital or any other professional of the domain, towards the patients can
be treated as \'malpractice\'. And it can have several adverse effects on the patients as well as
doctors. Following lists a few of them:
The most obvious effect is the reluctance among patients to seek medical help at the hour of
need. This is as a result of the lack of trust in the patients for the whole system of treatment,
which ultimately affects the basis of doctor and patient relationship.
Malpractice claims can also affect the cost of treatment, ultimately making them exorbitantly
high for the patients to be able to afford it. Easy access to helathcare by patients can also become
difficult due to a rise in the insurance premiums.
Claims of negligence by the patients can also lead to a potential threat amongst the doctors. This
results in the latter becoming more conscious or defensive in choosing their line of treatment,
where they end up prescribing all sorts of additional diagnostic tests. The ultimately results in
excess cost incurred in the part of the patients, who then find it increasinly difficult to afford it.
As for the doctors, they could be involved in lawsuits and that can jeopardise their career, induce
stress, and in extreme scenarios, when the cost of malpractice insurance becomes too high, they
can even look for alternative careers.
The most common type of malpractice reform is the traditional tort reform, that can be both
direct as well as indirect. The direct reform puts a cap of the costs incurred in the hospital but it
generally doesnot impact the quality of healthcare that is provided to the potential patient.
Indirect reforms, on the other hand, puts a cap on the liability cost, such as attorney\'s fees in
case of a lawsuit. This as well has no effect on the quality of treatment. The traditional tort
reform can however reduce the occurance of defensive medication. According to Daniel Kessler,
there is a need for a more aggressive reform system that can address issues such as errors on the
part of healthcare provides, transactional costs incurred in the system, and the slow
compensation rate for the injured patients. And in turn he proposed the \"administrative
compensation system\". According to this system, there are two models to be followed for
reforms, the health court and the no fault models..
How can critical researchers claim to represent groups to which they.pdf
How can critical researchers claim to represent groups to which they do not belong?
Solution
A generic term usually applied to any research that challenges those conventional knowledge
bases and methodologies whether quantitative or qualitative – that make claims of scientific
objectivity. Rather, critical social research attempts to reveal the socio-historical specificity of
knowledge and to shed light on how particular knowledges reproduce structural relations of
inequality and oppression. Critical social research, in the sense of offering critiques of social
order, has a long history encompassing the likes of Aristotle, Socrates, Hobbes and Marx. It is
currently evident in the work of a wide variety of social critics, including Marxists, feminists and
poststructuralists and is often ‘hailed’ through attaching the adjective of ‘critical’ to any number
of existing disciplines or methodologies, as in ‘critical sociology’, ‘critical discourse analysis’,
‘critical anthropology’, ‘critical psychiatry’, ‘critical criminology’, ‘critical ethnography’ and so
on. and after than critical researchers claim to repersent group decribe below by critical case
researches study.
I was sitting in a park near my house one day half reading a novel and half watching the people
move around the area. As someone who studies people, I spend a lot of time watching them and
attempting to both make sense of what they do and use these observations to make sense of my
own research and theory development. On this particular day in the park, I saw two children
playing on opposite sides of a typical swing set, and around the time I was getting bored with my
novel one of the little kids asked the other, “are you a boy,” and the other little kid said “no.”
Smiling, the first child said, “oh, then you’re a girl,” but again the second child said “no.” After
staring for a moment, the first child said, “but I thought you had to pick one or the other.”
Climbing into a swing, the second child responded, “My parents don’t make me choose – they
say I can be anything I want.” Smiling, the first child asked, “I wonder why I can’t be anything I
want,” and without missing a beat, the second child responded, “Ask your parents.”
This experience (along with many other observations of children when they don’t think adults
are paying attention) reminds me of an exercise I do in my classes where I ask students to answer
the question “who am I” twenty times. Every time, students (like most humans) respond with
group identities (i.e., \"I’m a son,\" \"I’m white,\" \"I’m gay,\" \"I’m a football player,\" \"I’m an
atheist,\" \"I’m genderqueer,\" \"I’m a boy,\" \"I’m black,\" \"I’m a soccer player,\" \"I’m a
mother,\" \"I’m a Muslim,\" etc.) that they have been taught to use to define themselves. I then
ask my students “Is there anything about you that makes you an individual instead of part of a
bunch of different groups.” While one or two might try to use their names (which come from
languages, .
Discuss Allport’s concept of psychological healthy personality.Des.pdf
Discuss Allport’s concept of psychological healthy personality.
Describe how Freud’s three levels of mental life relate to his concept of the provinces of the
mind.
Solution
According to Allport psychologically healthy humans tend to be motivated by present conscious
drives. Such individuals seek to establish new tensions. It was his belief that individuals are
capable of proactive behavior. This suggests that a person can consciously behave in new as well
as creative ways that help in promotion of their growth and change. As per Allport,
psychologically healthy individuals tend to engage in proactive behaviors. The 6 criteria he gave
for psychological health are given as follows:
1. There is an extension of the sense of self
2. Have warm relationships with other individuals
3. Self acceptance
4. Have a realistic view of world
5. Insight
6. Have a unifying philosophy of life
Allport also believed that people of intrinsic religious orientation are psychologically healthy
whereas those who have an extrinsic religious orientation tend to have poor psychological health.
Several years before Freud developed the notion of the id, ego, and superego, he formulated the
concept of the unconscious, preconscious, and conscious.
The unconscious is that dynamic aspect of mental life which is responsible for a large number of
our behaviors. It not only consists of repressed experiences but also experiences that were never
conscious. The preconscious categorizes those experiences that were less threatening as
compared to those of the unconscious. Such ideas have the tendency of becoming conscious with
different degrees of difficulty and are mainly dependent on their potential threat to ego. The
conscious mind has a minor role comparatively in Freudian psychology. Those ideas that are in
our awareness comprise of the conscious mind.
The id is the completely unconscious amoral side of our nature that serves the pleasure
principle. Ego which is the sense of I, can be unconscious, preconscious, or conscious and serves
the reality principle. The superego is also completely unconscious and serves idealistic as well as
moral principles..
Earning revenue journal entry is recorded asA Increases assets.pdf
Earning revenue journal entry is recorded as:
A: Increases assets, decreases stockholders’ liabilities
B: Decreases assets, increases liabilities
C: Increases assets, increases stockholders’ equity
D: Increases one asset, decrease another asset
Solution
Answer:
C: Increases assets, increases stockholders’ equity is correct.Journal Entry for earning
revenueNatureEffectDateAccountsDebit $Credit $Debtors/CashAmountAssetsIncrease(as it has
been debited)Sales/RevenueAmountStockholders’ equityIncrease(as it has been credited).
Discuss why is it important to use logical and physical data flow di.pdf
Discuss why is it important to use logical and physical data flow diagram (DFDs) to graphically
depict data movement for humans and systems in an organization. Is it worthwhile to share them
with users? Why or why not?
Solution
It is important to use logical and physical data flow diagram (DFDs) to graphically depict data
movement for humans and systems in an organization due to following reason.
Did HBGary’s Aaron Barr have the legal and ethical right to pursue A.pdf
Did HBGary’s Aaron Barr have the legal and ethical right to pursue Anonymous? Did
Anonymous act ethically and legally toward HBGary?
Solution
HBGary’s Aaron Barr have the legal and ethical right to pursue Anonymous and Anonymous did
not
act ethically and legally toward HBGary::-
A little over a year ago, small security firm HBGary Federal made the news for all the wrong
reasons:
it had been hacked, its CEO had been made a laughing stock, and its private e-mails were
splashed across
the Internet. The perpetrators, a group of hackers sympathetic to the Anonymous group, trashed
HBGary Federal\'s
servers and name with impunity, confident that tor and private VPNs would keep their identities
secret
For months, they seemed invincible; most went on to form LulzSec during the summer of 2011,
which infiltrated a
huge number of corporations and police servers, releasing e-mails, taking credit card numbers,
and taunting their
pursuers. But the pursuers kept coming, and this week brought down their quarry with a string
of indictments and
the possibility of lengthy jail terms. With the arrests, the HBGary Federal hack saga is largely
concluded
The HBGary Federal attack
HBGary sells security software for detecting, categorizing, and analyzing malware. Its HBGary
Federal subsidiary
was created to cater to the security and classification needs of federal agencies, and hoped to sell
HBGary\'s
software to the Department of Defense and the numerous three-letter agencies. Federal was
struggling, however,
failing to bring in the lucrative government contracts that HBGary had hoped for
After years of minor trolling and harassment of Scientologists, the Anonymous group had
performed a series of
high-profile denial-of-service attacks on PayPal, MasterCard, and Visa, after the credit card
companies and
payment processor halted all donations in support of WikiLeaks.
Though presenting itself as a faceless collective, Anonymous undoubtedly had ring-leaders,
people within the
group setting the agenda and co-ordinating the attacks. Law enforcement agencies around the
world wanted to
know who was behind the pro-WikiLeaks attacks—and Aaron Barr thought he knew
It was the perfect opportunity to get HBGary Federal\'s name some high profile press and
reinvigorate the business,
and on February 5th, 2011, Barr announced his plans to unmask Anonymous\' main players
The reaction from Anonymous was immediate and brutal. HBGary\'s servers were hacked, and
its e-mail system pillaged.
A server belonging to its CEO, Greg Hoglund, was also compromised and wiped
The hacks revealed basic errors in the configuration and administration of HBGary\'s
systems—embarrassing enough for
a company working in the security sphere. Worse still was the leaking of the e-mails, which laid
bare the company\'s
efforts to solicit government contracts to discredit WikiLeaks and develop undetectable rootkits
for the government..
Define each of the following terms. Be clear whether it is at develop.pdf
Define each of the following terms. Be clear whether it is at developmental STAGE, PROCESS,
or STRUCTURE. Then, place a check to indicate in which of the organisms the term can be
found
Solution
CLEAVAGE:The process by which zygote rapidly divides without growing to become
multicellular. the cleavage is a process,it occurs in birds,reptiles, it occurs in human zygote etc.
MORULA:morula is an early stage of embryo contain cells of blastomeres in a solid ball with in
the zonna pellucida it is a developmental stage,it forms in.human zygote after cleavage.
BLASTULA:blastula is a hollow sphere of cells surrounding by an inner fluid filled cavity called
blastocoele.,it is an embryonic development stage.it occurs in embryonic development in
animals.
GASTRULA:During gastrula single layered blastula is reorganised in to trilamminar structure
known as gastrula.it occurs in early phase in embryonic development stage.it occurs in most of
animals.
NEURALA: It is relating to the Nervous system.it is a folding process in vertebrate
embryos.it gives rise to both the spinal cord and the brain.
Archenteron: It is the rudimentary alimentary cavity of an embryo at the gastrula stage.The
primary gut that forms during gastrulation in the developing zygote is known as the archenteron
or the digestive tube.
Blastocoel: Blastocoel is termed as blastocyst cavity.It is a fluid filled cavity that forms in the
animal hemisphere of early amphibian and echinoderm embryos.It have two major functions in
frog embryos: (1) it permits cell migration during gastrulation, and (2) it prevents the cells
beneath it from interacting prematurely with the cells above it.
Blastomere: It is a cell formed by cleavage of a fertilized ovum.Cells in cleavage stage embryo
are known as blastomeres. Embryo divides without growth ,It undergoes cleavage divisions that
produce separate cells called Blastomeres.
Blastopore: opening of the archenteron in the gastrula that develops into the mouth in
protostomes and the anus in deuterostomes.It is the opening into the archenteron during the
embryonic stages of an organism.
Brain: Human brain is the organ of central nervous system.Located in the head protected by the
skull.The brain is the most complex organ in a vertebrate\'s body.
Ectoderm: The outermost layer of cells or tissue of an embryo in early development, or the parts
derived from this, which include the epidermis, nerve tissue, and nephridia.
Endoderm: The innermost layer of the germ layer which includes the linings of the digestive and
respiratory tracts, parts of the urinary system, the liver, the pancreas, the gallbladder, the thyroid
gland, the parathyroid glands, and the thymus..
Could anyone please explain how CPS1 and CPS2 are used for reliabili.pdf
Could anyone please explain how CPS1 and CPS2 are used for reliability standard. Thanks
Solution
In simple terms, CPS1 assigns each Control Area a “slice” of the responsibility for control of
Interconnection frequency. The amount of responsibility is directly related to Control Area size.
ACE is to a Control Area what frequency is to the Interconnection. Over-generation makes ACE
go positive and frequency increase. A large negative ACE causes frequency to drop. “Noisy”
ACE causes “noisy” frequency. CPS1 captures these relationships.
The CPS1 equation can be simplified as follows:
CPS1 (in percent) = 100* (2 – (a Constant[1])* (frequency error)*(ACE))
Frequency error is deviation from scheduled frequency. Normally this is deviation from 60Hz.
Scheduled frequency is different during a time correction, but for the purposes of this discussion,
assume scheduled frequency is always 60 Hz.
Refer to the equation above. Any minute where the average frequency is exactly on schedule or
Control Area ACE is zero, the quantity ((frequency error)*(ACE)) is zero. Therefore CPS1 =
100* (2-0). CPS1 is exactly 200% whenever frequency is on schedule or ACE is zero.
For any one-minute average where ACE and frequency error are “out of phase”, CPS1 is greater
than 200%. For example, if frequency is low, but ACE is positive (tending to correct frequency
error), the Control Area gets extra CPS1 points.
Conversely, if ACE is aggravating the frequency error, CPS1 will be less than 200%. CPS1 can
even go negative.
The CONSTANT in the equation above is sized such that if a Control Area’s ACE is
proportionally as “noisy” as a benchmark frequency noise, the Control Area will get a CPS1 of
100%. The minimum acceptable long-term score for CPS1 is 100%.
When CPS was established, each Interconnection was given a target or benchmark “frequency
noise”. This target noise is called “Epsilon 1” or 1. Epsilon 1 is nothing more than a statistician’s
variable that means the RMS value of the one-minute averages of frequency.
The target values (in millihz of frequency noise) for each Interconnection are shown in Table 1
below. The NERC Resources Subcommittee monitors each Interconnection’s frequency
performance and can tighten (or loosen) the 1 values should an Interconnection’s frequency
performance decline (improve).
Interconnection
Epsilon 1
Eastern
18.0
Hydro Quebec
21.0
Western
22.8
ERCOT
20.0
Table 1 Target Values of \"One Minute Frequency Noise\"
The Epsilon 1 target initially set for each Interconnection was on the order of 1.6 times historic
frequency noise. This is why “average” Control Areas have been scoring around 160% for CPS1.
Let’s review how CPS1 data can be applied to measure the adequacy of control performance and
the deployment of resources to meet load. NERC refers to these resources as Interconnected
Operating Services (IOS). Although there are some differences in definitions, the FERC calls
these resources Ancillary Services.
Figure 1 shows ACE charts for one hour.
Complete the following code by deallocating the memory. Int ptr1; .pdf
Complete the following code by deallocating the memory. Int *ptr1; int *ptr2; ptr1 = new Int;
ptr2 = new intl[10]; *ptr1 = 10;
Solution
Dear Student,
The memory in c++ is created by a operator call new.
And the memory is deallocated by a operator called delete.
Below is the complete program...
#include
using namespace std;
int main()
{
int *ptr1;
int *ptr2;
ptr1 = new int; //allocate memory for the variable
ptr2= new int[10]; // allocate memory for integer variable which size is 10.
*ptr1=10; // assignment of value to pointer
cout << *ptr1 << endl;
delete ptr1; //Deallocate memory allocated for ptr1
delete ptr2; //Deallocate memory allocated for ptr2
return 0;
}
Output : 10
Note- The above program is tested on g++ compiler under ubuntu 14.04 system.
***** Dear Student if you are satisfied with the answer kindly provide your valubale
feedback******.
Briefly discuss why you are proud to be a mammal and give examples of.pdf
Briefly discuss why you are proud to be a mammal and give examples of mammals that habitat
various water kingdoms?
Solution
Mammals are vertibrate, endothermic amneotes possessing neocortex, hair, three middle year
bones and mammary glands. As mammals are endothermic they can live almost all type of
environments. Produce milk, to feed babies. There are 4000 different species of Mammals. The
smallest mammal is Hog nosed bat and largest one is Blue whale.
Some mammales habit to the water bodies. Eg. Blue whale, Dolphins, polar bears, pinnipeds,
dugongs etc..
AVR data memory consists of (Flash ROM, internal SRAM). True or false.pdf
AVR data memory consists of (Flash ROM, internal SRAM). True or false. The special function
register in AVR is called the I/O register. True or false. The I/O registers are part of the data
memory space. True or false. The general-purpose registers are not part of the data memory
space. True or false. The data memory is the same size in all members of AVR. If we add the I/O
registers, internal RAM, and general purpose register sizes together we should get the total space
for the .
Solution
11> SRAM (Flash has seperate address space)
12> FALSE ( It is called Accumulator)
13> TRUE (SRAM , I/O Register, Register file are part of data memory space)
14> FALSE (It is part of Data memory space. The DMS makes 32 General purpose registers)
15> FALSE
16> RAM but except it cannot be overwritten..
Below is a table of probabilities representing a sample survey of 100.pdf
Below is a table of probabilities representing a sample survey of 1000 adults and their opinions
on whether college education was too expensive or not. They were also ether they had a child in
college or not. What is the probability that a respondent has a child in college or thinks that
college educations is too expensive?
Solution
My choose E.
Based on the Spectroscopy data below, identify the material and it.pdf
Based on the Spectroscopy data below, identify the material and it\'s exact grade. Mn Mo 0.329
0.214 0.300 0.696 0.0791 0.0431 Al Co Cu Nb Pb 0.0070 0.0038 0.329 0.0047 0.0514 0.0277 Sn
Ca Sb Se 0.0135 0.0023 0.00014 0.0074 0.227 0.00037 0.0280 Fe 97.6
Solution
The material is a low carbon steel
The grade ia a low alloy steel with exact grade SAE 4130.
Attached is case study of how Whirlpool and Lowes collaborated to .pdf
Attached is case study of how Whirlpool and Lowe\'s collaborated to help manage risk and
uncertainty. Please highlight the most important difference between the stages. Please see the
Rubric for help.
Solution
The collaboration had three stages –
First stage was when the parties involved come up to a decision to form collaboration and give it
a purpose. In this stage they get together and design a strategy and set up a program.
Second stage included establishment of procedures to be followed for the implementation of the
strategy designed. It also involved specifying the needs and searching for alternatives for better
results. Lastly it involves arriving at an agreement to proceed with the implementation.
The last stage involves the control and supervision of the implementation process going as per
planning. If any issues generate along the course how to deal with them..
7. Winter is here. I hope you have enough of the right fatty acids o.pdf
7. Winter is here. I hope you have enough of the right fatty acids on your phospholipids to
maintain membrane fluidity. What does a cell do to its membrane phospholipids to maintain
fluidity in cold temperatures?
41. Two ways to alter the fluidity of a cell membrane are to..
1. 2.
Solution
Cell membrane consists of.
1. Phaspholipids
2. Proteins
3. Carbohydrate and cholesterol.
1- phaspholipids and cholesterol both play important role in the fluidicity of cell membrane with
the variation of temperature.
PHASPHOLIPIDS may be 1. Saturated or 2. Unsaturate
Saturated fats or fatty acid compressed at low temperature and make the membrane rigid. While
unsaturated fats compress in winter and develops folding or kinks. These kinks are responsible
for flexibility because they have vacant space.
With the change of the composition of saturated and unsaturated fat in summer and winter
organism maintain fluidicity.
2_ role of cholesterol.
Cholesterol dampen the effect of temperature and regulates the temperature of membrane to
maintain the fluidicity of membrane. Cholesterol act as buffer for Temp. Change.
2. Formatting Output to FilesSolution#includeiostream #inc.pdf
2. Formatting Output to Files
Solution
#include
#include
#include
#include
#include
using namespace std;
int main()
{
int num;
float root;
ifstream in_stream;
ofstream out_stream;
in_stream.open(\"Lab9B.in\");
if(in_stream.fail())
{
cout << \"ERROR: Unable to open file: Lab9B.in\" << endl;
exit(EXIT_FAILURE);
}
out_stream.open(\"Lab9B.out\");
if(out_stream.fail())
{
cout << \"ERROR: Unable to open file: Lab9B.out\" << endl;
exit(EXIT_FAILURE);
}
while(in_stream >> num)
{
root = sqrt(num);
out_stream << std::left;
out_stream << setprecision(5);
out_stream << setw(15);
out_stream << root << endl;
}
in_stream.close();
out_stream.close();
return 0;
}.
1. What effect does pulmonary edema have on blood oxygenation2. W.pdf
1. What effect does pulmonary edema have on blood oxygenation?
2. What is the consequence to the newborn if the foramen ovale does not close after birth?
Solution
1.
Pulmonary edema occurs due to abnormal accumulation of the fluid in air sacs that is alveoli
which makes the breathing much difficult.
Due to accumulation of the fluid there will be a difficulty in exchange of the gases and it leads to
the respiratory failure.
This pulmonary edema condition is commonly seen in elders.
When heart pumps in abnormal way then the blood back up into the veins and then we can
observe the increase in the blood pressure.
Pulmonary edema occurs mainly by the increase in the blood pressure that causes the damage to
the small blood vessels in the lungs and it leads to the accumulation of watery fluid and it leads
to the respiratory failure.
Thus the effect of pulmonary edema observed on blood oxygenation.
2.
Foramen ovale is actually named as patent foramen ovale (PFO ).
Patent foramen ovale is a hole between the left and right atria of the heart.
This hole can be observed in baby’s when they are in womb and it may disappear when they
comes out from mother’s womb but sometimes it may get failure.
In most of the cases there won’t be any complications but in rare cases it get complicated by
forming the blood clots.
In paradoxical stroke, a blood clot develops in a vein and it travels to the right side of the heart
and then normally continues to the lungs but in PFO people it continues to the left side of the
heart.
Now it pumps outside of the body and travel to the brain and it prevents blood flow to the brain.
Thus the consequences occur in new born if the foramen ovale does not close after birth.
1.
Pulmonary edema occurs due to abnormal accumulation of the fluid in air sacs that is alveoli
which makes the breathing much difficult.
Due to accumulation of the fluid there will be a difficulty in exchange of the gases and it leads to
the respiratory failure.
This pulmonary edema condition is commonly seen in elders.
When heart pumps in abnormal way then the blood back up into the veins and then we can
observe the increase in the blood pressure.
Pulmonary edema occurs mainly by the increase in the blood pressure that causes the damage to
the small blood vessels in the lungs and it leads to the accumulation of watery fluid and it leads
to the respiratory failure.
Thus the effect of pulmonary edema observed on blood oxygenation.
2.
Foramen ovale is actually named as patent foramen ovale (PFO ).
Patent foramen ovale is a hole between the left and right atria of the heart.
This hole can be observed in baby’s when they are in womb and it may disappear when they
comes out from mother’s womb but sometimes it may get failure.
In most of the cases there won’t be any complications but in rare cases it get complicated by
forming the blood clots.
In paradoxical stroke, a blood clot develops in a vein and it travels to the right side of the heart
and then normally continues.
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Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
How to Build a Module in Odoo 17 Using the Scaffold Method
Odoo provides an option for creating a module by using a single line command. By using this command the user can make a whole structure of a module. It is very easy for a beginner to make a module. There is no need to make each file manually. This slide will show how to create a module using the scaffold method.
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