using System; using System.Collections.Generic; using System.Lin.pdf
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using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class BMI { double weight; double height; public BMI() //default constructor { weight = 0; height = 0; } public BMI(double wt,double ht) //parameterized constructor { weight = wt; height = ht; } public void input() //function to input height and weight { Console.WriteLine(\"Enter weight in kilograms\"); weight = Convert.ToDouble(Console.ReadLine()); Console.WriteLine(\"Enter height in metres\"); height = Convert.ToDouble(Console.ReadLine()); } public void BMIstatus() //function to calculate BMI and display status of person { double bmi; bmi = weight / (height * height); if (bmi<18.5) Console.WriteLine(\"Person is Underweight\"); else if(bmi>18.5 && bmi<24.9) Console.WriteLine(\"Person is normal\"); else if(bmi>25 && bmi<29.9) Console.WriteLine(\"Person is Overweight\"); else if(bmi>=30) Console.WriteLine(\"Person is Obese\"); } } class Program { static void Main(string[] args) { BMI person1=new BMI(); person1.input(); //call functions person1.BMIstatus(); Console.ReadLine(); } } } output: Enter weight in kilograms 70 Enter height in metres 1.57 Person is Overweight Solution using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class BMI { double weight; double height; public BMI() //default constructor { weight = 0; height = 0; } public BMI(double wt,double ht) //parameterized constructor { weight = wt; height = ht; } public void input() //function to input height and weight { Console.WriteLine(\"Enter weight in kilograms\"); weight = Convert.ToDouble(Console.ReadLine()); Console.WriteLine(\"Enter height in metres\"); height = Convert.ToDouble(Console.ReadLine()); } public void BMIstatus() //function to calculate BMI and display status of person { double bmi; bmi = weight / (height * height); if (bmi<18.5) Console.WriteLine(\"Person is Underweight\"); else if(bmi>18.5 && bmi<24.9) Console.WriteLine(\"Person is normal\"); else if(bmi>25 && bmi<29.9) Console.WriteLine(\"Person is Overweight\"); else if(bmi>=30) Console.WriteLine(\"Person is Obese\"); } } class Program { static void Main(string[] args) { BMI person1=new BMI(); person1.input(); //call functions person1.BMIstatus(); Console.ReadLine(); } } } output: Enter weight in kilograms 70 Enter height in metres 1.57 Person is Overweight.
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![else if(bmi>18.5 && bmi<24.9)
Console.WriteLine("Person is normal");
else if(bmi>25 && bmi<29.9)
Console.WriteLine("Person is Overweight");
else if(bmi>=30)
Console.WriteLine("Person is Obese");
}
}
class Program
{
static void Main(string[] args)
{
BMI person1=new BMI();
person1.input(); //call functions
person1.BMIstatus();
Console.ReadLine();
}
}
}
output:
Enter weight in kilograms 70
Enter height in metres 1.57
Person is Overweight
Solution
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication3
{
class BMI
{
double weight;
double height;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
P1.javaimport java.util.Scanner;keyboard inputting package pub.pdf
P1.java
import java.util.Scanner;//keyboard inputting package
public class P1 {//main class
public static void main(String[] args) {//main method
Scanner input = new Scanner (System.in);
//User will input values
System.out.print(\"Enter your weght in pounds:\");
int weight = input.nextInt();//keyboard inputting
//User will input values
System.out.print(\"Enter your feet and inches:\");
int feet = input.nextInt();//keyboard inputting
int inches=input.nextInt();
int totalheightininches=0;
totalheightininches=(feet*12)+inches;//converting feet and inches into total inches
float bmi;
float constant=703f;
bmi = (float) (weight /Math.pow(totalheightininches,2))*constant;//bmi calculation
//Print out results on display
System.out.println(\"BMI is\" + bmi);
if(bmi <18.5)
System.out.println(\"Underweight\");
else if (bmi <25)
System.out.println(\"Normal\");
else if (bmi < 30)
System.out.println(\"Overweight\");
else
System.out.println(\"Obese\");
}
}
output
Enter your weght in pounds:150
Enter your feet and inches:5 5
BMI is24.95858
Normal
Solution
P1.java
import java.util.Scanner;//keyboard inputting package
public class P1 {//main class
public static void main(String[] args) {//main method
Scanner input = new Scanner (System.in);
//User will input values
System.out.print(\"Enter your weght in pounds:\");
int weight = input.nextInt();//keyboard inputting
//User will input values
System.out.print(\"Enter your feet and inches:\");
int feet = input.nextInt();//keyboard inputting
int inches=input.nextInt();
int totalheightininches=0;
totalheightininches=(feet*12)+inches;//converting feet and inches into total inches
float bmi;
float constant=703f;
bmi = (float) (weight /Math.pow(totalheightininches,2))*constant;//bmi calculation
//Print out results on display
System.out.println(\"BMI is\" + bmi);
if(bmi <18.5)
System.out.println(\"Underweight\");
else if (bmi <25)
System.out.println(\"Normal\");
else if (bmi < 30)
System.out.println(\"Overweight\");
else
System.out.println(\"Obese\");
}
}
output
Enter your weght in pounds:150
Enter your feet and inches:5 5
BMI is24.95858
Normal.
S = {0,1,2,3,4,5} P(S) be the set of all nonempty subsets of.pdf
S = {0,1,2,3,4,5}
P(S)* be the set of all nonempty subsets of S
a function m: P(S)* -> S by m(H) = the largest element in H
(a) Is m one-to-one? Why or why not?
P(s) having n=2^6-1 element
and S having m= 6 element
function m is not one to one since n>m. (n be less then or equal to m )
M is not one to one since
{1,3} will map to 3
{2,3} will also map tp 3 // by defination of m
two element having same mapping.(IT shd be unique for each element).
Does m map P(S)* onto S? Why or why not?
yes m is onto funtion
max element of P(s) will be in s since P(s) in subset of S only.
therefore for all the element present in s will be mapping of atleat one element present in P(s).
Solution
S = {0,1,2,3,4,5}
P(S)* be the set of all nonempty subsets of S
a function m: P(S)* -> S by m(H) = the largest element in H
(a) Is m one-to-one? Why or why not?
P(s) having n=2^6-1 element
and S having m= 6 element
function m is not one to one since n>m. (n be less then or equal to m )
M is not one to one since
{1,3} will map to 3
{2,3} will also map tp 3 // by defination of m
two element having same mapping.(IT shd be unique for each element).
Does m map P(S)* onto S? Why or why not?
yes m is onto funtion
max element of P(s) will be in s since P(s) in subset of S only.
therefore for all the element present in s will be mapping of atleat one element present in P(s)..
The java program that prompts user to enter a string and .pdf
/*
* The java program that prompts user to
* enter a string and shift key and then
* converts the string to the encoded string
* and prints the encoded string value to console.
* */
//CeaserCipher.java
import java.util.Scanner;
public class CeaserCipher
{
public static void main(String[] args)
{
Scanner scanner=new Scanner(System.in);
String message;
int shift;
System.out.println(\"Enter a message in small letters,a-z\");
message=scanner.nextLine();
System.out.println(\"Enter shift value\");
shift=scanner.nextInt();
//calling encode method with message, shift value
String encodedMsg=encode(message,shift);
//calling WriteMessage
WriteMessage(encodedMsg);
}
/*Method that prints the encoded text to console*/
private static void WriteMessage(String encodedMsg)
{
System.out.println(\"Encoded text :\"+encodedMsg);
}
//Method that takes string and integer value and returns
//the encoded string to calling method
private static String encode(String message, int shift)
{
StringBuffer sb=new StringBuffer(message);
for (int i = 0; i < message.length(); i++)
{
//shift to back to the alphabets
char encodedkey = (char) (\'a\' + (message.charAt(i) -\'a\' + shift) % (\'z\' - \'a\' + 1));
//set character at index,i
sb.setCharAt(i, encodedkey);
}
//return encoded string to calling method
return new String(sb);
}
}
Sample Output:
Enter a message in small letters,a-z
sunday is holiday
Enter shift value
5
Encoded text :xzsifdYnxYmtqnifd
Solution
/*
* The java program that prompts user to
* enter a string and shift key and then
* converts the string to the encoded string
* and prints the encoded string value to console.
* */
//CeaserCipher.java
import java.util.Scanner;
public class CeaserCipher
{
public static void main(String[] args)
{
Scanner scanner=new Scanner(System.in);
String message;
int shift;
System.out.println(\"Enter a message in small letters,a-z\");
message=scanner.nextLine();
System.out.println(\"Enter shift value\");
shift=scanner.nextInt();
//calling encode method with message, shift value
String encodedMsg=encode(message,shift);
//calling WriteMessage
WriteMessage(encodedMsg);
}
/*Method that prints the encoded text to console*/
private static void WriteMessage(String encodedMsg)
{
System.out.println(\"Encoded text :\"+encodedMsg);
}
//Method that takes string and integer value and returns
//the encoded string to calling method
private static String encode(String message, int shift)
{
StringBuffer sb=new StringBuffer(message);
for (int i = 0; i < message.length(); i++)
{
//shift to back to the alphabets
char encodedkey = (char) (\'a\' + (message.charAt(i) -\'a\' + shift) % (\'z\' - \'a\' + 1));
//set character at index,i
sb.setCharAt(i, encodedkey);
}
//return encoded string to calling method
return new String(sb);
}
}
Sample Output:
Enter a message in small letters,a-z
sunday is holiday
Enter shift value
5
Encoded text :xzsifdYnxYmtqnifd.
The answer is b, theres no increase in H. .pdf
The answer is b, theres no increase in H.
Solution
The answer is b, theres no increase in H..
Step1 white ppt with NaCl(aq) indicates Ag+ Step.pdf
Step1 white ppt with NaCl(aq) indicates Ag+ Step2 Passing H2S in acidic salt
solution ; no ppt being formes indicates absence of group II ; Cu+2 and Cd+2 are absent. Step3
Passing H2S in basic condition ; formation of ppt marks presence of group IV Step4 Possible
ions are Ag+; Ni+2 ;Mn+2 ; Na+
Solution
Step1 white ppt with NaCl(aq) indicates Ag+ Step2 Passing H2S in acidic salt
solution ; no ppt being formes indicates absence of group II ; Cu+2 and Cd+2 are absent. Step3
Passing H2S in basic condition ; formation of ppt marks presence of group IV Step4 Possible
ions are Ag+; Ni+2 ;Mn+2 ; Na+.
Natural rubber is a polymer of isoprene units ; e.pdf
Natural rubber is a polymer of isoprene units ; every monomer unit contains a
double bond which undergoes ozonolysis reaction in presence of ozone. Thus polymer chains
are broken.
Solution
Natural rubber is a polymer of isoprene units ; every monomer unit contains a
double bond which undergoes ozonolysis reaction in presence of ozone. Thus polymer chains
are broken..
no double displacement reactions can be mixing tw.pdf
no double displacement reactions can be mixing two soluble salts whose product
can be an insoluble salt
Solution
no double displacement reactions can be mixing two soluble salts whose product
can be an insoluble salt.
Recommended
P1.javaimport java.util.Scanner;keyboard inputting package pub.pdf
P1.java
import java.util.Scanner;//keyboard inputting package
public class P1 {//main class
public static void main(String[] args) {//main method
Scanner input = new Scanner (System.in);
//User will input values
System.out.print(\"Enter your weght in pounds:\");
int weight = input.nextInt();//keyboard inputting
//User will input values
System.out.print(\"Enter your feet and inches:\");
int feet = input.nextInt();//keyboard inputting
int inches=input.nextInt();
int totalheightininches=0;
totalheightininches=(feet*12)+inches;//converting feet and inches into total inches
float bmi;
float constant=703f;
bmi = (float) (weight /Math.pow(totalheightininches,2))*constant;//bmi calculation
//Print out results on display
System.out.println(\"BMI is\" + bmi);
if(bmi <18.5)
System.out.println(\"Underweight\");
else if (bmi <25)
System.out.println(\"Normal\");
else if (bmi < 30)
System.out.println(\"Overweight\");
else
System.out.println(\"Obese\");
}
}
output
Enter your weght in pounds:150
Enter your feet and inches:5 5
BMI is24.95858
Normal
Solution
P1.java
import java.util.Scanner;//keyboard inputting package
public class P1 {//main class
public static void main(String[] args) {//main method
Scanner input = new Scanner (System.in);
//User will input values
System.out.print(\"Enter your weght in pounds:\");
int weight = input.nextInt();//keyboard inputting
//User will input values
System.out.print(\"Enter your feet and inches:\");
int feet = input.nextInt();//keyboard inputting
int inches=input.nextInt();
int totalheightininches=0;
totalheightininches=(feet*12)+inches;//converting feet and inches into total inches
float bmi;
float constant=703f;
bmi = (float) (weight /Math.pow(totalheightininches,2))*constant;//bmi calculation
//Print out results on display
System.out.println(\"BMI is\" + bmi);
if(bmi <18.5)
System.out.println(\"Underweight\");
else if (bmi <25)
System.out.println(\"Normal\");
else if (bmi < 30)
System.out.println(\"Overweight\");
else
System.out.println(\"Obese\");
}
}
output
Enter your weght in pounds:150
Enter your feet and inches:5 5
BMI is24.95858
Normal.
S = {0,1,2,3,4,5} P(S) be the set of all nonempty subsets of.pdf
S = {0,1,2,3,4,5}
P(S)* be the set of all nonempty subsets of S
a function m: P(S)* -> S by m(H) = the largest element in H
(a) Is m one-to-one? Why or why not?
P(s) having n=2^6-1 element
and S having m= 6 element
function m is not one to one since n>m. (n be less then or equal to m )
M is not one to one since
{1,3} will map to 3
{2,3} will also map tp 3 // by defination of m
two element having same mapping.(IT shd be unique for each element).
Does m map P(S)* onto S? Why or why not?
yes m is onto funtion
max element of P(s) will be in s since P(s) in subset of S only.
therefore for all the element present in s will be mapping of atleat one element present in P(s).
Solution
S = {0,1,2,3,4,5}
P(S)* be the set of all nonempty subsets of S
a function m: P(S)* -> S by m(H) = the largest element in H
(a) Is m one-to-one? Why or why not?
P(s) having n=2^6-1 element
and S having m= 6 element
function m is not one to one since n>m. (n be less then or equal to m )
M is not one to one since
{1,3} will map to 3
{2,3} will also map tp 3 // by defination of m
two element having same mapping.(IT shd be unique for each element).
Does m map P(S)* onto S? Why or why not?
yes m is onto funtion
max element of P(s) will be in s since P(s) in subset of S only.
therefore for all the element present in s will be mapping of atleat one element present in P(s)..
The java program that prompts user to enter a string and .pdf
/*
* The java program that prompts user to
* enter a string and shift key and then
* converts the string to the encoded string
* and prints the encoded string value to console.
* */
//CeaserCipher.java
import java.util.Scanner;
public class CeaserCipher
{
public static void main(String[] args)
{
Scanner scanner=new Scanner(System.in);
String message;
int shift;
System.out.println(\"Enter a message in small letters,a-z\");
message=scanner.nextLine();
System.out.println(\"Enter shift value\");
shift=scanner.nextInt();
//calling encode method with message, shift value
String encodedMsg=encode(message,shift);
//calling WriteMessage
WriteMessage(encodedMsg);
}
/*Method that prints the encoded text to console*/
private static void WriteMessage(String encodedMsg)
{
System.out.println(\"Encoded text :\"+encodedMsg);
}
//Method that takes string and integer value and returns
//the encoded string to calling method
private static String encode(String message, int shift)
{
StringBuffer sb=new StringBuffer(message);
for (int i = 0; i < message.length(); i++)
{
//shift to back to the alphabets
char encodedkey = (char) (\'a\' + (message.charAt(i) -\'a\' + shift) % (\'z\' - \'a\' + 1));
//set character at index,i
sb.setCharAt(i, encodedkey);
}
//return encoded string to calling method
return new String(sb);
}
}
Sample Output:
Enter a message in small letters,a-z
sunday is holiday
Enter shift value
5
Encoded text :xzsifdYnxYmtqnifd
Solution
/*
* The java program that prompts user to
* enter a string and shift key and then
* converts the string to the encoded string
* and prints the encoded string value to console.
* */
//CeaserCipher.java
import java.util.Scanner;
public class CeaserCipher
{
public static void main(String[] args)
{
Scanner scanner=new Scanner(System.in);
String message;
int shift;
System.out.println(\"Enter a message in small letters,a-z\");
message=scanner.nextLine();
System.out.println(\"Enter shift value\");
shift=scanner.nextInt();
//calling encode method with message, shift value
String encodedMsg=encode(message,shift);
//calling WriteMessage
WriteMessage(encodedMsg);
}
/*Method that prints the encoded text to console*/
private static void WriteMessage(String encodedMsg)
{
System.out.println(\"Encoded text :\"+encodedMsg);
}
//Method that takes string and integer value and returns
//the encoded string to calling method
private static String encode(String message, int shift)
{
StringBuffer sb=new StringBuffer(message);
for (int i = 0; i < message.length(); i++)
{
//shift to back to the alphabets
char encodedkey = (char) (\'a\' + (message.charAt(i) -\'a\' + shift) % (\'z\' - \'a\' + 1));
//set character at index,i
sb.setCharAt(i, encodedkey);
}
//return encoded string to calling method
return new String(sb);
}
}
Sample Output:
Enter a message in small letters,a-z
sunday is holiday
Enter shift value
5
Encoded text :xzsifdYnxYmtqnifd.
The answer is b, theres no increase in H. .pdf
The answer is b, theres no increase in H.
Solution
The answer is b, theres no increase in H..
Step1 white ppt with NaCl(aq) indicates Ag+ Step.pdf
Step1 white ppt with NaCl(aq) indicates Ag+ Step2 Passing H2S in acidic salt
solution ; no ppt being formes indicates absence of group II ; Cu+2 and Cd+2 are absent. Step3
Passing H2S in basic condition ; formation of ppt marks presence of group IV Step4 Possible
ions are Ag+; Ni+2 ;Mn+2 ; Na+
Solution
Step1 white ppt with NaCl(aq) indicates Ag+ Step2 Passing H2S in acidic salt
solution ; no ppt being formes indicates absence of group II ; Cu+2 and Cd+2 are absent. Step3
Passing H2S in basic condition ; formation of ppt marks presence of group IV Step4 Possible
ions are Ag+; Ni+2 ;Mn+2 ; Na+.
Natural rubber is a polymer of isoprene units ; e.pdf
Natural rubber is a polymer of isoprene units ; every monomer unit contains a
double bond which undergoes ozonolysis reaction in presence of ozone. Thus polymer chains
are broken.
Solution
Natural rubber is a polymer of isoprene units ; every monomer unit contains a
double bond which undergoes ozonolysis reaction in presence of ozone. Thus polymer chains
are broken..
no double displacement reactions can be mixing tw.pdf
no double displacement reactions can be mixing two soluble salts whose product
can be an insoluble salt
Solution
no double displacement reactions can be mixing two soluble salts whose product
can be an insoluble salt.
Toxicants may move across biological membranes by all the following .pdf
Toxicants may move across biological membranes by all the following mechanisms except
aqueous diffusion. This is because for the diffusion of the toxicant molecules, the aqueous pores
are too small.
Hence, the option a is the correct answer.
Solution
Toxicants may move across biological membranes by all the following mechanisms except
aqueous diffusion. This is because for the diffusion of the toxicant molecules, the aqueous pores
are too small.
Hence, the option a is the correct answer..
time is 18.2yearsdetailed answer i will submit nowSolutionti.pdf
time is 18.2years
detailed answer i will submit now
Solution
time is 18.2years
detailed answer i will submit now.
This is the code for the above 5 public class Input extends JFram.pdf
This is the code for the above 5 :
public class Input extends JFrame{
JRadioButton employee ;
JRadioButton manager;
JPanel panel;
Button button;
public Input(){
button = new Button(\"Enter\");
employee = new JRadioButton(\"Employee\");
manager = new JRadioButton(\"Manager\");
ButtonGroup group = new ButtonGroup();
group.add(employee);
group.add(manager);
employee.setBounds(50,50,80,50);
manager.setBounds(50,100,80,50);
button.setBounds(130, 200,80,25);
panel = new JPanel();
panel.setLayout(null);
add(panel);
panel.add(employee);
panel.add(manager);
panel.add(button);
employee.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
Frame frame = JOptionPane.getFrameForComponent(getParent());
frame.setVisible(true);
frame.setSize(300,300);
}
});
manager.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
}
});
setSize(400,400);
setVisible(true);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
/*public void actionPerformed(ActionEvent event){
//JOptionPane.showMessageDialog(parent,\"Popup\");
//System.out.print(\"action \");
}*/
public static void main(String[] args) {
new Input();
}
}
Solution
This is the code for the above 5 :
public class Input extends JFrame{
JRadioButton employee ;
JRadioButton manager;
JPanel panel;
Button button;
public Input(){
button = new Button(\"Enter\");
employee = new JRadioButton(\"Employee\");
manager = new JRadioButton(\"Manager\");
ButtonGroup group = new ButtonGroup();
group.add(employee);
group.add(manager);
employee.setBounds(50,50,80,50);
manager.setBounds(50,100,80,50);
button.setBounds(130, 200,80,25);
panel = new JPanel();
panel.setLayout(null);
add(panel);
panel.add(employee);
panel.add(manager);
panel.add(button);
employee.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
Frame frame = JOptionPane.getFrameForComponent(getParent());
frame.setVisible(true);
frame.setSize(300,300);
}
});
manager.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
}
});
setSize(400,400);
setVisible(true);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
/*public void actionPerformed(ActionEvent event){
//JOptionPane.showMessageDialog(parent,\"Popup\");
//System.out.print(\"action \");
}*/
public static void main(String[] args) {
new Input();
}
}.
Team public class Team { private String teamId; priva.pdf
Team:
public class Team {
private String teamId;
private String name;
private String firstName;
private String lastName;
private String phoneNumber;
private String emailAddress;
Team(String teamId, String name, String firstName, String lastName, String phoneNumber,
String emailAddress) {
this.teamId = teamId;
this.name = name;
this.firstName = firstName;
this.lastName = lastName;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public String getTeamId() {
return teamId;
}
public void setTeamId(String teamId) {
this.teamId = teamId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(String phoneNumber) {
this.phoneNumber = phoneNumber;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public static boolean checkEmailAddress(String emailAddress) {
return emailAddress.contains(\"@\");
}
@Override
public String toString() {
return \"Team [teamId=\" + teamId + \", name=\" + name + \", firstName=\" + firstName +
\", lastName=\" + lastName
+ \", phoneNumber=\" + phoneNumber + \", emailAddress=\" + emailAddress + \"]\";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((emailAddress == null) ? 0 : emailAddress.hashCode());
result = prime * result + ((firstName == null) ? 0 : firstName.hashCode());
result = prime * result + ((lastName == null) ? 0 : lastName.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
result = prime * result + ((phoneNumber == null) ? 0 : phoneNumber.hashCode());
result = prime * result + ((teamId == null) ? 0 : teamId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Team other = (Team) obj;
if (emailAddress == null) {
if (other.emailAddress != null)
return false;
} else if (!emailAddress.equals(other.emailAddress))
return false;
if (firstName == null) {
if (other.firstName != null)
return false;
} else if (!firstName.equals(other.firstName))
return false;
if (lastName == null) {
if (other.lastName != null)
return false;
} else if (!lastName.equals(other.lastName))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
if (phoneNumber == null) {
if (other.phoneNumber != null)
return false;
} else if (!phoneNumber.equals(other.phoneNumber))
return false;
if (teamId == null) {
if (other.teamId != null)
return false;
} else if (!teamId.equals(other.teamId))
return false;
r.
PollinationFertilization1. Pollination is the transfer of po.pdf
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism)
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism)
Solution
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism)
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism).
Patient.java package A9.toStudents; public class Patient imple.pdf
//Patient.java
package A9.toStudents;
public class Patient implements Comparable
{
//attributes
private int order;
private String name;
private boolean emergencyCase;
//constructor
public Patient(int order, String name, boolean emergencyCase) {
this.order = order;
this.name = name;
this.emergencyCase = emergencyCase;
}
//compareTo
public int compareTo(Patient other) {
if(this.isEmergencyCase() && !other.isEmergencyCase())
return -1; //place this first
else if(!this.isEmergencyCase() && other.isEmergencyCase())
return 1; //place other first
else //if both are emergency or both are not emergency
return this.getOrder()-other.getOrder(); //place smaller order first
}
//getters and setters
public int getOrder() {
return order;
}
public void setOrder(int order) {
this.order = order;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public boolean isEmergencyCase() {
return emergencyCase;
}
public void setEmergencyCase(boolean emergencyCase) {
this.emergencyCase = emergencyCase;
}
public String toString() {
return (isEmergencyCase()?\"*\":\"\") + name;
}
}
----------------------------------------------------------------------------
//PatientComparator.java
package A9.toStudents;
import java.util.Comparator;
public class PatientComparator implements Comparator
{
public int compare(Patient p1, Patient p2)
{
if(p1.isEmergencyCase() && !p2.isEmergencyCase())
return -1; //place p1 first
else if(!p1.isEmergencyCase() && p2.isEmergencyCase())
return 1; //place p2 first
else //if both are emergency or both are not emergency
return p1.getOrder()-p2.getOrder(); //place smaller order first
}
} //end of the PatientComparator
----------------------------------------------------------------------------
/*Sorter class contains static methods that take ArrayList
and sorts the list using bubble sort,insertion sort and
selection sort */
//Sorter.java
package A9.toStudents;
import java.util.ArrayList;
public class Sorter
{
//Bubble sort
public static void bubbleSort(ArrayList list)
{
for (int c = 0; c < ( list.size() - 1 ); c++)
{
for (int d = 0; d < list.size() - c - 1; d++)
{
if (list.get(d).compareTo(list.get(d+1))>0)
/* For ascending order*/
{
Patient temp= list.get(d);
list.set(d, list.get(d+1));
list.set(d+1, temp);
}
}
}
}
//Selection sort
public static void selectionSort(ArrayList list)
{
for (int i = 0; i < list.size() - 1; i++)
{
int index = i;
for (int j = i + 1; j < list.size(); j++)
if (list.get(j).compareTo(list.get(index))<0)
index = j;
Patient tempPatient = list.get(index);
list.set(index, list.get(i));
list.set(i,tempPatient);
}
}
//Insertion sort
public static void insertionSort(ArrayList list)
{
for (int i = 1; i < list.size(); i++)
{
for(int j = i ; j > 0 ; j--)
{
if(list.get(j).compareTo(list.get(j-1))<0)
{
Patient temp = list.get(j);
list.set(j,list.get(j-1));
list.set(j-1,temp);
}
}
}
}
public static void bubbleSort(ArrayList list,
PatientComparator patientComparator) {
for (int c = 0; c < ( list.s.
Non financial performance indicators of United Utilities Group PLC. .pdf
Non financial performance indicators of United Utilities Group PLC. Are :
1. Customer satisfaction: Improvements in customer satisfaction are measured through Ofwat\'s
SIM mechanism.
Strong performance on Ofwat\'s and environment agency KPI Assessment.
Reinvestment of £280 million has been done to outperform customer servicing.
Below inflation growth in household bills for the period of 10 years from 2010-20.
2. Effective delivery of Capital investment programme:
Capex delivery has further improved. Time cost quality ind3x up to 98%.
Initiated 40£million of transitional investment to aid a smoother and most effective start to
AMP6.
3. Strong Financials.
Operating profits up by £37 million to 641£ million.
RCV Gearing went down by 2%, at 58%.
Final dividend of 24.03 pence per share was in line with policy.
4. Growth in Business Retail:
Growth in developing a range of value added services.
Largest new entrant and Second largest water retailer in Scotland.
Solution
Non financial performance indicators of United Utilities Group PLC. Are :
1. Customer satisfaction: Improvements in customer satisfaction are measured through Ofwat\'s
SIM mechanism.
Strong performance on Ofwat\'s and environment agency KPI Assessment.
Reinvestment of £280 million has been done to outperform customer servicing.
Below inflation growth in household bills for the period of 10 years from 2010-20.
2. Effective delivery of Capital investment programme:
Capex delivery has further improved. Time cost quality ind3x up to 98%.
Initiated 40£million of transitional investment to aid a smoother and most effective start to
AMP6.
3. Strong Financials.
Operating profits up by £37 million to 641£ million.
RCV Gearing went down by 2%, at 58%.
Final dividend of 24.03 pence per share was in line with policy.
4. Growth in Business Retail:
Growth in developing a range of value added services.
Largest new entrant and Second largest water retailer in Scotland..
C) III is correct note the configuration keep un.pdf
C) III is correct note: the configuration keep unchanged in first step the inversion of
configuration in 2nd step (SN2)
Solution
C) III is correct note: the configuration keep unchanged in first step the inversion of
configuration in 2nd step (SN2).
LHS =2y+1RHS=-(-2y-1) =2y+1LHS =RHSy=all the real nu.pdf
LHS =2y+1
RHS=-(-2y-1)
=2y+1
LHS =RHS
y=all the real numbers are the solution
Solution
LHS =2y+1
RHS=-(-2y-1)
=2y+1
LHS =RHS
y=all the real numbers are the solution.
import com.rogue.roguer.command.CommandHandler; import com.rogue.r.pdf
import com.rogue.roguer.command.CommandHandler;
import com.rogue.roguer.configuration.Configuration;
import com.rogue.roguer.lstnr.AFKListener;
import com.rogue.roguer.player.PlayerHandler;
import com.rogue.roguer.runnable.AFKRunnable;
import com.rogue.roguer.runnable.UpdateRunnable;
import java.io.File;
import java.util.logging.Level;
import org.bukkit.Bukkit;
import org.bukkit.plugin.java.JavaPlugin;
public class roguer extends JavaPlugin {
private Configuration cnfgs;
private AFKListener lstnr;
private PlayerHandler phndle;
private CommandHandler chndle;
private int dbgg = 0;
@Override
public void onLoad() {
if (!this.getDataFolder().exists()) {
this.getDataFolder().mkdirs();
}
if (!(new File(getDataFolder(), \"cnfg.yml\").exists())) {
this.saveResource(\"cnfg.yml\", true);
}
this.getLogger().log(Level.INFO, \"Loading cnfgs\");
cnfgs = new Configuration();
cnfgs.loadDefaults();
this.getLogger().log(Level.INFO, \"Running update check\");
this.getLogger().log(Level.INFO, \"This can be disabled in your cnfg.yml\");
if (cnfgs.getBoolean(\"update-check\")) {
Bukkit.getScheduler().runTaskLater(this, new UpdateRunnable(), 1);
}
}
@Override
public void onEnable() {
dbgg = cnfgs.getInt(\"general.dbgg-level\");
if (dbgg > 3) {
dbgg = 3;
}
if (dbgg < 0) {
dbgg = 0;
}
if (dbgg >= 1) {
this.getLogger().log(Level.INFO, \"Debug level set to {0}!\", dbgg);
}
this.getLogger().log(Level.INFO, \"Enabling Listener\");
lstnr = new AFKListener(this);
Bukkit.getPluginManager().registerEvents(lstnr, this);
this.getLogger().log(Level.INFO, \"Enabling Player Handler\");
phndle = new PlayerHandler(this, cnfgs.getInt(\"afk.check-interval\"),
cnfgs.getInt(\"afk.timeout\"));
this.getLogger().log(Level.INFO, \"Enabling Command Handler\");
chndle = new CommandHandler();
long interval = this.getConfig().getInt(\"afk.check-interval\") * 20; // multiplied by 20, due to a
server tick being 1/20th of a second
Bukkit.getServer().getScheduler().runTaskTimer(this, new AFKRunnable(this), interval,
interval);
this.getLogger().log(Level.INFO, \"{0} is enabled!\", this.getName());
}
@Override
public void onDisable() {
this.getLogger().log(Level.INFO, \"{0} is disabled!\", this.getName());
}
public int getDebug() {
return dbgg;
}
public static roguer getPlugin() {
return (roguer) Bukkit.getServer().getPluginManager().getPlugin(\"roguer\");
}
public AFKListener getListener() {
return lstnr;
}
public PlayerHandler getPlayerHandler() {
return phndle;
}
public CommandHandler getCommandHandler() {
return chndle;
}
public Configuration getConfiguration() {
return cnfgs;
}
}
Solution
import com.rogue.roguer.command.CommandHandler;
import com.rogue.roguer.configuration.Configuration;
import com.rogue.roguer.lstnr.AFKListener;
import com.rogue.roguer.player.PlayerHandler;
import com.rogue.roguer.runnable.AFKRunnable;
import com.rogue.roguer.runnable.UpdateRunnable;
import java.io.File;
import java.util.logging.Level;
import org.bukkit.Bukkit;
import org.bukkit.plugin.java.JavaPlugin;
public c.
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO3.pdf
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
tend to dissociate in water, attracted by the partial charges of the molecule.
FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
solution...
H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3
Solution
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
tend to dissociate in water, attracted by the partial charges of the molecule.
FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
solution...
H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3.
D the polar covalent bond within methanol cannot form hydrogen bond .pdf
D the polar covalent bond within methanol cannot form hydrogen bond and hense cannot interact
with water molecule hence methyl group hydrophobic in nature.
Solution
D the polar covalent bond within methanol cannot form hydrogen bond and hense cannot interact
with water molecule hence methyl group hydrophobic in nature..
Conflict theory asserts that social problems occur when dominant gro.pdf
Conflict theory asserts that social problems occur when dominant groups mistreat
subordinateones, and thus advocates for a balance of power between genders.Frederich Engels
compared the family structure to the relationship between the bourgeoisie and the proletariat,
suggesting that women had less power than men in the household because they were dependent
on them for wages.Men, like any other group with a power or wealth advantage in Conflict
Theory, fought to maintain their controlover resources(in this case, political and economic
power). Conflict between the two groups caused things like the Women\'sSuffrage Movement
and was responsible for social change.Gender also affected dispute handling mechanisms. The
processes used to resolve disputes for women were less effective than for men. For example,
women were more often transferred laterally instead of resolving the dispute.Women and men
also differed in the ways that they talked about their conflicts. Women talked in-depth and at
length about the context of the dispute, particularly focusing on their involvement in the
relationship with the other party. Men used more rational, linear and legalistic language to talk
about their disputes. Women talked about fairness in a way that incorporated both their material
interests and the network of relationships in the dispute.
Solution
Conflict theory asserts that social problems occur when dominant groups mistreat
subordinateones, and thus advocates for a balance of power between genders.Frederich Engels
compared the family structure to the relationship between the bourgeoisie and the proletariat,
suggesting that women had less power than men in the household because they were dependent
on them for wages.Men, like any other group with a power or wealth advantage in Conflict
Theory, fought to maintain their controlover resources(in this case, political and economic
power). Conflict between the two groups caused things like the Women\'sSuffrage Movement
and was responsible for social change.Gender also affected dispute handling mechanisms. The
processes used to resolve disputes for women were less effective than for men. For example,
women were more often transferred laterally instead of resolving the dispute.Women and men
also differed in the ways that they talked about their conflicts. Women talked in-depth and at
length about the context of the dispute, particularly focusing on their involvement in the
relationship with the other party. Men used more rational, linear and legalistic language to talk
about their disputes. Women talked about fairness in a way that incorporated both their material
interests and the network of relationships in the dispute..
a) units of capacitance if Farads (F)b) unit of Inductance is Henr.pdf
a) units of capacitance if Farads (F)
b) unit of Inductance is Henry (H)
c) unit of impedance is Ohm
Solution
a) units of capacitance if Farads (F)
b) unit of Inductance is Henry (H)
c) unit of impedance is Ohm.
A. An Intranet is a private organization’s network, which can be com.pdf
A. An Intranet is a private organization’s network, which can be composed of Web servers, file
and print servers, and other resources that can only be accessed by company employees for
internal collaboration and information sharing. Typically, you can access the Internet from an
intranet, but external Internet users cannot access the company’s intranet.
Solution
A. An Intranet is a private organization’s network, which can be composed of Web servers, file
and print servers, and other resources that can only be accessed by company employees for
internal collaboration and information sharing. Typically, you can access the Internet from an
intranet, but external Internet users cannot access the company’s intranet..
Introduction to Quality Improvement Essentials
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024.
He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Andreas Schleicher presents at the OECD webinar ‘Digital devices in schools: detrimental distraction or secret to success?’ on 27 May 2024. The presentation was based on findings from PISA 2022 results and the webinar helped launch the PISA in Focus ‘Managing screen time: How to protect and equip students against distraction’ https://www.oecd-ilibrary.org/education/managing-screen-time_7c225af4-en and the OECD Education Policy Perspective ‘Students, digital devices and success’ can be found here - https://oe.cd/il/5yV
Ethnobotany and Ethnopharmacology ......
Ethnobotany and Ethnopharmacology:
Ethnobotany in herbal drug evaluation,
Impact of Ethnobotany in traditional medicine,
New development in herbals,
Bio-prospecting tools for drug discovery,
Role of Ethnopharmacology in drug evaluation,
Reverse Pharmacology.
More Related Content
More from DEEPAKSONI562
Toxicants may move across biological membranes by all the following .pdf
Toxicants may move across biological membranes by all the following mechanisms except
aqueous diffusion. This is because for the diffusion of the toxicant molecules, the aqueous pores
are too small.
Hence, the option a is the correct answer.
Solution
Toxicants may move across biological membranes by all the following mechanisms except
aqueous diffusion. This is because for the diffusion of the toxicant molecules, the aqueous pores
are too small.
Hence, the option a is the correct answer..
time is 18.2yearsdetailed answer i will submit nowSolutionti.pdf
time is 18.2years
detailed answer i will submit now
Solution
time is 18.2years
detailed answer i will submit now.
This is the code for the above 5 public class Input extends JFram.pdf
This is the code for the above 5 :
public class Input extends JFrame{
JRadioButton employee ;
JRadioButton manager;
JPanel panel;
Button button;
public Input(){
button = new Button(\"Enter\");
employee = new JRadioButton(\"Employee\");
manager = new JRadioButton(\"Manager\");
ButtonGroup group = new ButtonGroup();
group.add(employee);
group.add(manager);
employee.setBounds(50,50,80,50);
manager.setBounds(50,100,80,50);
button.setBounds(130, 200,80,25);
panel = new JPanel();
panel.setLayout(null);
add(panel);
panel.add(employee);
panel.add(manager);
panel.add(button);
employee.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
Frame frame = JOptionPane.getFrameForComponent(getParent());
frame.setVisible(true);
frame.setSize(300,300);
}
});
manager.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
}
});
setSize(400,400);
setVisible(true);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
/*public void actionPerformed(ActionEvent event){
//JOptionPane.showMessageDialog(parent,\"Popup\");
//System.out.print(\"action \");
}*/
public static void main(String[] args) {
new Input();
}
}
Solution
This is the code for the above 5 :
public class Input extends JFrame{
JRadioButton employee ;
JRadioButton manager;
JPanel panel;
Button button;
public Input(){
button = new Button(\"Enter\");
employee = new JRadioButton(\"Employee\");
manager = new JRadioButton(\"Manager\");
ButtonGroup group = new ButtonGroup();
group.add(employee);
group.add(manager);
employee.setBounds(50,50,80,50);
manager.setBounds(50,100,80,50);
button.setBounds(130, 200,80,25);
panel = new JPanel();
panel.setLayout(null);
add(panel);
panel.add(employee);
panel.add(manager);
panel.add(button);
employee.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
Frame frame = JOptionPane.getFrameForComponent(getParent());
frame.setVisible(true);
frame.setSize(300,300);
}
});
manager.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
}
});
setSize(400,400);
setVisible(true);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
/*public void actionPerformed(ActionEvent event){
//JOptionPane.showMessageDialog(parent,\"Popup\");
//System.out.print(\"action \");
}*/
public static void main(String[] args) {
new Input();
}
}.
Team public class Team { private String teamId; priva.pdf
Team:
public class Team {
private String teamId;
private String name;
private String firstName;
private String lastName;
private String phoneNumber;
private String emailAddress;
Team(String teamId, String name, String firstName, String lastName, String phoneNumber,
String emailAddress) {
this.teamId = teamId;
this.name = name;
this.firstName = firstName;
this.lastName = lastName;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public String getTeamId() {
return teamId;
}
public void setTeamId(String teamId) {
this.teamId = teamId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(String phoneNumber) {
this.phoneNumber = phoneNumber;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public static boolean checkEmailAddress(String emailAddress) {
return emailAddress.contains(\"@\");
}
@Override
public String toString() {
return \"Team [teamId=\" + teamId + \", name=\" + name + \", firstName=\" + firstName +
\", lastName=\" + lastName
+ \", phoneNumber=\" + phoneNumber + \", emailAddress=\" + emailAddress + \"]\";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((emailAddress == null) ? 0 : emailAddress.hashCode());
result = prime * result + ((firstName == null) ? 0 : firstName.hashCode());
result = prime * result + ((lastName == null) ? 0 : lastName.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
result = prime * result + ((phoneNumber == null) ? 0 : phoneNumber.hashCode());
result = prime * result + ((teamId == null) ? 0 : teamId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Team other = (Team) obj;
if (emailAddress == null) {
if (other.emailAddress != null)
return false;
} else if (!emailAddress.equals(other.emailAddress))
return false;
if (firstName == null) {
if (other.firstName != null)
return false;
} else if (!firstName.equals(other.firstName))
return false;
if (lastName == null) {
if (other.lastName != null)
return false;
} else if (!lastName.equals(other.lastName))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
if (phoneNumber == null) {
if (other.phoneNumber != null)
return false;
} else if (!phoneNumber.equals(other.phoneNumber))
return false;
if (teamId == null) {
if (other.teamId != null)
return false;
} else if (!teamId.equals(other.teamId))
return false;
r.
PollinationFertilization1. Pollination is the transfer of po.pdf
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism)
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism)
Solution
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism)
Pollination
Fertilization
1. Pollination is the transfer of pollen from the male organ (anther)of a flower to the female
organ (stigma)of a flower.
It is the fusion of male gametes and egg cell in embryo sac situated inside the ovule.
2. It takes place before fertilization
It takes place after pollination
3. Need a vector, insects, water, air like agencies are essential
There is no external medium for this process
4. No pollen tube formation
Pollen tube is formed which transfer male gametes up to egg cell
5. It takes place on outer parts of flower (external mechanism)
It occurs inside the flower (internal mechanism).
Patient.java package A9.toStudents; public class Patient imple.pdf
//Patient.java
package A9.toStudents;
public class Patient implements Comparable
{
//attributes
private int order;
private String name;
private boolean emergencyCase;
//constructor
public Patient(int order, String name, boolean emergencyCase) {
this.order = order;
this.name = name;
this.emergencyCase = emergencyCase;
}
//compareTo
public int compareTo(Patient other) {
if(this.isEmergencyCase() && !other.isEmergencyCase())
return -1; //place this first
else if(!this.isEmergencyCase() && other.isEmergencyCase())
return 1; //place other first
else //if both are emergency or both are not emergency
return this.getOrder()-other.getOrder(); //place smaller order first
}
//getters and setters
public int getOrder() {
return order;
}
public void setOrder(int order) {
this.order = order;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public boolean isEmergencyCase() {
return emergencyCase;
}
public void setEmergencyCase(boolean emergencyCase) {
this.emergencyCase = emergencyCase;
}
public String toString() {
return (isEmergencyCase()?\"*\":\"\") + name;
}
}
----------------------------------------------------------------------------
//PatientComparator.java
package A9.toStudents;
import java.util.Comparator;
public class PatientComparator implements Comparator
{
public int compare(Patient p1, Patient p2)
{
if(p1.isEmergencyCase() && !p2.isEmergencyCase())
return -1; //place p1 first
else if(!p1.isEmergencyCase() && p2.isEmergencyCase())
return 1; //place p2 first
else //if both are emergency or both are not emergency
return p1.getOrder()-p2.getOrder(); //place smaller order first
}
} //end of the PatientComparator
----------------------------------------------------------------------------
/*Sorter class contains static methods that take ArrayList
and sorts the list using bubble sort,insertion sort and
selection sort */
//Sorter.java
package A9.toStudents;
import java.util.ArrayList;
public class Sorter
{
//Bubble sort
public static void bubbleSort(ArrayList list)
{
for (int c = 0; c < ( list.size() - 1 ); c++)
{
for (int d = 0; d < list.size() - c - 1; d++)
{
if (list.get(d).compareTo(list.get(d+1))>0)
/* For ascending order*/
{
Patient temp= list.get(d);
list.set(d, list.get(d+1));
list.set(d+1, temp);
}
}
}
}
//Selection sort
public static void selectionSort(ArrayList list)
{
for (int i = 0; i < list.size() - 1; i++)
{
int index = i;
for (int j = i + 1; j < list.size(); j++)
if (list.get(j).compareTo(list.get(index))<0)
index = j;
Patient tempPatient = list.get(index);
list.set(index, list.get(i));
list.set(i,tempPatient);
}
}
//Insertion sort
public static void insertionSort(ArrayList list)
{
for (int i = 1; i < list.size(); i++)
{
for(int j = i ; j > 0 ; j--)
{
if(list.get(j).compareTo(list.get(j-1))<0)
{
Patient temp = list.get(j);
list.set(j,list.get(j-1));
list.set(j-1,temp);
}
}
}
}
public static void bubbleSort(ArrayList list,
PatientComparator patientComparator) {
for (int c = 0; c < ( list.s.
Non financial performance indicators of United Utilities Group PLC. .pdf
Non financial performance indicators of United Utilities Group PLC. Are :
1. Customer satisfaction: Improvements in customer satisfaction are measured through Ofwat\'s
SIM mechanism.
Strong performance on Ofwat\'s and environment agency KPI Assessment.
Reinvestment of £280 million has been done to outperform customer servicing.
Below inflation growth in household bills for the period of 10 years from 2010-20.
2. Effective delivery of Capital investment programme:
Capex delivery has further improved. Time cost quality ind3x up to 98%.
Initiated 40£million of transitional investment to aid a smoother and most effective start to
AMP6.
3. Strong Financials.
Operating profits up by £37 million to 641£ million.
RCV Gearing went down by 2%, at 58%.
Final dividend of 24.03 pence per share was in line with policy.
4. Growth in Business Retail:
Growth in developing a range of value added services.
Largest new entrant and Second largest water retailer in Scotland.
Solution
Non financial performance indicators of United Utilities Group PLC. Are :
1. Customer satisfaction: Improvements in customer satisfaction are measured through Ofwat\'s
SIM mechanism.
Strong performance on Ofwat\'s and environment agency KPI Assessment.
Reinvestment of £280 million has been done to outperform customer servicing.
Below inflation growth in household bills for the period of 10 years from 2010-20.
2. Effective delivery of Capital investment programme:
Capex delivery has further improved. Time cost quality ind3x up to 98%.
Initiated 40£million of transitional investment to aid a smoother and most effective start to
AMP6.
3. Strong Financials.
Operating profits up by £37 million to 641£ million.
RCV Gearing went down by 2%, at 58%.
Final dividend of 24.03 pence per share was in line with policy.
4. Growth in Business Retail:
Growth in developing a range of value added services.
Largest new entrant and Second largest water retailer in Scotland..
C) III is correct note the configuration keep un.pdf
C) III is correct note: the configuration keep unchanged in first step the inversion of
configuration in 2nd step (SN2)
Solution
C) III is correct note: the configuration keep unchanged in first step the inversion of
configuration in 2nd step (SN2).
LHS =2y+1RHS=-(-2y-1) =2y+1LHS =RHSy=all the real nu.pdf
LHS =2y+1
RHS=-(-2y-1)
=2y+1
LHS =RHS
y=all the real numbers are the solution
Solution
LHS =2y+1
RHS=-(-2y-1)
=2y+1
LHS =RHS
y=all the real numbers are the solution.
import com.rogue.roguer.command.CommandHandler; import com.rogue.r.pdf
import com.rogue.roguer.command.CommandHandler;
import com.rogue.roguer.configuration.Configuration;
import com.rogue.roguer.lstnr.AFKListener;
import com.rogue.roguer.player.PlayerHandler;
import com.rogue.roguer.runnable.AFKRunnable;
import com.rogue.roguer.runnable.UpdateRunnable;
import java.io.File;
import java.util.logging.Level;
import org.bukkit.Bukkit;
import org.bukkit.plugin.java.JavaPlugin;
public class roguer extends JavaPlugin {
private Configuration cnfgs;
private AFKListener lstnr;
private PlayerHandler phndle;
private CommandHandler chndle;
private int dbgg = 0;
@Override
public void onLoad() {
if (!this.getDataFolder().exists()) {
this.getDataFolder().mkdirs();
}
if (!(new File(getDataFolder(), \"cnfg.yml\").exists())) {
this.saveResource(\"cnfg.yml\", true);
}
this.getLogger().log(Level.INFO, \"Loading cnfgs\");
cnfgs = new Configuration();
cnfgs.loadDefaults();
this.getLogger().log(Level.INFO, \"Running update check\");
this.getLogger().log(Level.INFO, \"This can be disabled in your cnfg.yml\");
if (cnfgs.getBoolean(\"update-check\")) {
Bukkit.getScheduler().runTaskLater(this, new UpdateRunnable(), 1);
}
}
@Override
public void onEnable() {
dbgg = cnfgs.getInt(\"general.dbgg-level\");
if (dbgg > 3) {
dbgg = 3;
}
if (dbgg < 0) {
dbgg = 0;
}
if (dbgg >= 1) {
this.getLogger().log(Level.INFO, \"Debug level set to {0}!\", dbgg);
}
this.getLogger().log(Level.INFO, \"Enabling Listener\");
lstnr = new AFKListener(this);
Bukkit.getPluginManager().registerEvents(lstnr, this);
this.getLogger().log(Level.INFO, \"Enabling Player Handler\");
phndle = new PlayerHandler(this, cnfgs.getInt(\"afk.check-interval\"),
cnfgs.getInt(\"afk.timeout\"));
this.getLogger().log(Level.INFO, \"Enabling Command Handler\");
chndle = new CommandHandler();
long interval = this.getConfig().getInt(\"afk.check-interval\") * 20; // multiplied by 20, due to a
server tick being 1/20th of a second
Bukkit.getServer().getScheduler().runTaskTimer(this, new AFKRunnable(this), interval,
interval);
this.getLogger().log(Level.INFO, \"{0} is enabled!\", this.getName());
}
@Override
public void onDisable() {
this.getLogger().log(Level.INFO, \"{0} is disabled!\", this.getName());
}
public int getDebug() {
return dbgg;
}
public static roguer getPlugin() {
return (roguer) Bukkit.getServer().getPluginManager().getPlugin(\"roguer\");
}
public AFKListener getListener() {
return lstnr;
}
public PlayerHandler getPlayerHandler() {
return phndle;
}
public CommandHandler getCommandHandler() {
return chndle;
}
public Configuration getConfiguration() {
return cnfgs;
}
}
Solution
import com.rogue.roguer.command.CommandHandler;
import com.rogue.roguer.configuration.Configuration;
import com.rogue.roguer.lstnr.AFKListener;
import com.rogue.roguer.player.PlayerHandler;
import com.rogue.roguer.runnable.AFKRunnable;
import com.rogue.roguer.runnable.UpdateRunnable;
import java.io.File;
import java.util.logging.Level;
import org.bukkit.Bukkit;
import org.bukkit.plugin.java.JavaPlugin;
public c.
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO3.pdf
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
tend to dissociate in water, attracted by the partial charges of the molecule.
FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
solution...
H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3
Solution
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
tend to dissociate in water, attracted by the partial charges of the molecule.
FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
solution...
H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3.
D the polar covalent bond within methanol cannot form hydrogen bond .pdf
D the polar covalent bond within methanol cannot form hydrogen bond and hense cannot interact
with water molecule hence methyl group hydrophobic in nature.
Solution
D the polar covalent bond within methanol cannot form hydrogen bond and hense cannot interact
with water molecule hence methyl group hydrophobic in nature..
Conflict theory asserts that social problems occur when dominant gro.pdf
Conflict theory asserts that social problems occur when dominant groups mistreat
subordinateones, and thus advocates for a balance of power between genders.Frederich Engels
compared the family structure to the relationship between the bourgeoisie and the proletariat,
suggesting that women had less power than men in the household because they were dependent
on them for wages.Men, like any other group with a power or wealth advantage in Conflict
Theory, fought to maintain their controlover resources(in this case, political and economic
power). Conflict between the two groups caused things like the Women\'sSuffrage Movement
and was responsible for social change.Gender also affected dispute handling mechanisms. The
processes used to resolve disputes for women were less effective than for men. For example,
women were more often transferred laterally instead of resolving the dispute.Women and men
also differed in the ways that they talked about their conflicts. Women talked in-depth and at
length about the context of the dispute, particularly focusing on their involvement in the
relationship with the other party. Men used more rational, linear and legalistic language to talk
about their disputes. Women talked about fairness in a way that incorporated both their material
interests and the network of relationships in the dispute.
Solution
Conflict theory asserts that social problems occur when dominant groups mistreat
subordinateones, and thus advocates for a balance of power between genders.Frederich Engels
compared the family structure to the relationship between the bourgeoisie and the proletariat,
suggesting that women had less power than men in the household because they were dependent
on them for wages.Men, like any other group with a power or wealth advantage in Conflict
Theory, fought to maintain their controlover resources(in this case, political and economic
power). Conflict between the two groups caused things like the Women\'sSuffrage Movement
and was responsible for social change.Gender also affected dispute handling mechanisms. The
processes used to resolve disputes for women were less effective than for men. For example,
women were more often transferred laterally instead of resolving the dispute.Women and men
also differed in the ways that they talked about their conflicts. Women talked in-depth and at
length about the context of the dispute, particularly focusing on their involvement in the
relationship with the other party. Men used more rational, linear and legalistic language to talk
about their disputes. Women talked about fairness in a way that incorporated both their material
interests and the network of relationships in the dispute..
a) units of capacitance if Farads (F)b) unit of Inductance is Henr.pdf
a) units of capacitance if Farads (F)
b) unit of Inductance is Henry (H)
c) unit of impedance is Ohm
Solution
a) units of capacitance if Farads (F)
b) unit of Inductance is Henry (H)
c) unit of impedance is Ohm.
A. An Intranet is a private organization’s network, which can be com.pdf
A. An Intranet is a private organization’s network, which can be composed of Web servers, file
and print servers, and other resources that can only be accessed by company employees for
internal collaboration and information sharing. Typically, you can access the Internet from an
intranet, but external Internet users cannot access the company’s intranet.
Solution
A. An Intranet is a private organization’s network, which can be composed of Web servers, file
and print servers, and other resources that can only be accessed by company employees for
internal collaboration and information sharing. Typically, you can access the Internet from an
intranet, but external Internet users cannot access the company’s intranet..
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using System; using System.Collections.Generic; using System.Lin.pdf
- 1. using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class BMI { double weight; double height; public BMI() //default constructor { weight = 0; height = 0; } public BMI(double wt,double ht) //parameterized constructor { weight = wt; height = ht; } public void input() //function to input height and weight { Console.WriteLine("Enter weight in kilograms"); weight = Convert.ToDouble(Console.ReadLine()); Console.WriteLine("Enter height in metres"); height = Convert.ToDouble(Console.ReadLine()); } public void BMIstatus() //function to calculate BMI and display status of person { double bmi; bmi = weight / (height * height); if (bmi<18.5) Console.WriteLine("Person is Underweight");
- 2. else if(bmi>18.5 && bmi<24.9) Console.WriteLine("Person is normal"); else if(bmi>25 && bmi<29.9) Console.WriteLine("Person is Overweight"); else if(bmi>=30) Console.WriteLine("Person is Obese"); } } class Program { static void Main(string[] args) { BMI person1=new BMI(); person1.input(); //call functions person1.BMIstatus(); Console.ReadLine(); } } } output: Enter weight in kilograms 70 Enter height in metres 1.57 Person is Overweight Solution using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class BMI { double weight; double height;
- 3. public BMI() //default constructor { weight = 0; height = 0; } public BMI(double wt,double ht) //parameterized constructor { weight = wt; height = ht; } public void input() //function to input height and weight { Console.WriteLine("Enter weight in kilograms"); weight = Convert.ToDouble(Console.ReadLine()); Console.WriteLine("Enter height in metres"); height = Convert.ToDouble(Console.ReadLine()); } public void BMIstatus() //function to calculate BMI and display status of person { double bmi; bmi = weight / (height * height); if (bmi<18.5) Console.WriteLine("Person is Underweight"); else if(bmi>18.5 && bmi<24.9) Console.WriteLine("Person is normal"); else if(bmi>25 && bmi<29.9) Console.WriteLine("Person is Overweight"); else if(bmi>=30) Console.WriteLine("Person is Obese"); } } class Program { static void Main(string[] args)
- 4. { BMI person1=new BMI(); person1.input(); //call functions person1.BMIstatus(); Console.ReadLine(); } } } output: Enter weight in kilograms 70 Enter height in metres 1.57 Person is Overweight