1. Soalan Latih Tubi Matematik Tahun 6 2010
Skima Kertas 2
1 P = 3 cm + 3 cm + 3 cm + 7 cm + 5 cm + 4 cm + 5 cm = 30 cm
2 2 x 6 = 12 cm
3 x 12 = 36 cm
12 cm + 36 cm = 48 cm
3 9 cm + 9 cm + 15 cm + 9 cm + 15 cm = 57 cm
2
4 P = 14 x 7 = 98 cm
Q = 1 x 5 cm x 7 cm 2
= 25 cm
2
2 2 2
P + Q = 98 cm + 35 cm = 133 cm
5 SR = 11 cm - 6 cm = 5cm
P = 14 cm + 6 cm + 11 cm + 14 cm + 5 cm = 50 cm
6 1
X 16 cm = 4 cm
4
P = 25 cm + 16 cm + 4 cm + 12 cm + 6 cm = 63 cm
7 27 cm ÷ 3 = 9 cm.
P = 9 cm + 9 cm + 9 cm + 9 cm + 9 cm = 45 cm
8 16 cm ÷ 4 = 4 cm
2
Luas 1 segiempat = 4 cm x 4 cm = 16 cm
2 2
Luas 13 segiempat = 13 x 16 cm = 208 cm
3
9 Kubus P = 8 cm x 8 cm x 8 cm = 512 cm
3
Kuboid Q = 8 cm x 8 cm x 4 cm = 256 cm
3 3 3
Jumlah isipadu = 512 cm + 256 cm = 768 cm
Sumbangan Guru Cemerlang Matematik Pahang Page 1

2. Soalan Latih Tubi Matematik Tahun 6 2010
10 24 cm ÷ 3 = 8 cm
2
Luas segi empat sama = 8 cm x 8 cm = 64 cm
2
Luas segi empat tepat = 24 cm x 26 cm = 624 cm
2 2 2
Luas berlorek = 624 cm - 64 cm = 560 cm.
11 18 cm ÷ 2 = 9 cm
1 2
Luas 1 segi tiga = x 9 cm x 12 cm = 54 cm
2
2 2
Luas 3 segi tiga = 54 cm x 3 = 162 cm
3 3 3 3
12 P = 19 cm x 5 cm x 5 cm = 475 cm 800cm – 475 cm – 125 cm
3 3
Q = 5 cm x 5 cm x 5 cm = 125 cm 3 = 200 cm.
3 200 cm
R = 5 cm x 5 cm x …….. = 200 cm = = 8 cm.
25
13 3 cm x 6 = 18 cm
3
Y = 3 cm x 3 cm x 3 cm = 27 cm
3
X = 3 cm x 3 cm x 3 cm = 27 cm
3
W = 18 cm x 3 cm x 3 cm = 162 cm
3 3 3 3
Jumlah = 27 cm + 27 cm + 162 cm = 216 cm.
14 14 cm - 6 cm = 8 cm
2 2
Luas P = 8 cm x 8 cm = 64 cm LuasQ = 6 cm x 6 cm = 36 cm
2 2 2
Jumlah luas = 64 cm + 36 cm = 100 cm
2
15 1 kubus = 5 cm x 5 cm x 5 cm = 125 cm
3 3
24 kubus = 125 cm x 24 = 3 000 cm
Sumbangan Guru Cemerlang Matematik Pahang Page 2